Explanation:
The period of revolution of an electron in \({n^{th}}\) orbit of hydrogen atom is
\({T_n} = \frac{{2\pi {r_n}}}{{{v_n}}} = \frac{{4\varepsilon _0^2{h^3}{n^3}}}{{m{e^4}}}\)
\(\left( {as\,\,{r_n} = \frac{{{n^2}{h^2}{\varepsilon _0}}}{{\pi m{e^2}}},{v_n} = \frac{{{e^2}}}{{2{\varepsilon _0}hn}}} \right)\)
or \({T_n} \propto {n^3}\)
For ground state, \(n = 1\)
and for first excited state, \(n = 2\)
\(\therefore \frac{{{T_2}}}{{{T_1}}} = \frac{{{2^3}}}{{{1^3}}} = 8\,\,\,{\rm{or}}\,\,{T_2} = 8{T_1}\)
But as per question \({T_1} = T\)
\(\therefore {T_2} = 8T\)