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PHXII12:ATOMS

356348 Assertion :
Large angle of scattering of alpha particles led to the discovery of atomic nucleus.
Reason :
Entire positive charge of atom is concentrated in the central core.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.

2 Both assertion and reason are correct but reason is not the correct explanation of assertion.

3 Assertion is correct but reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

$α -$ particle is positively charged, so is the nucleus, so the large angle of scattering of $α -$ particle shows that the nucleus is positively charged and concentrated in the central core. So option (1) is correct.

PHXII12:ATOMS

356350 The trajectory of an $α$ -particle can be computed by employing:

1 Newton's second law of motion.

2 Coulomb's law for electrostatic force of repulsion between the

α

-particle and the positively charges nucleus.

3 Both of these.

4 None of these.

PHXII12:ATOMS

356351 When an $α -$ particle of mass $^{'} m^{'}$ moving with velocity $^{'} v^{'}$ bombards on a heavy nucleus of charge $^{'} Z e^{'}$ , its distance of closest approach from the nucleus depends on $m$ as:

1

\frac{1}{m}

2

\frac{1}{\sqrt{m}}

3

\frac{1}{m^{2}}

4

m

Explanation:

At closest distance of approach, the kinetic energy of the particle will convert completely into electrostatic potential energy.
$\Rightarrow \frac{1}{2} m v^{2} = \frac{K Q q}{d} \Rightarrow d \propto \frac{1}{m}$

NEET - 2016

PHXII12:ATOMS

356352 Statement A :
The trajectory traced by an incident particle depends on the impact parameter of collision.
Statement B :
The impact parameter is the perpendicular distance of the initial velocity vector of the incident particle from the centre of the target nucleus.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both Statements are correct.

4 Both Statements are incorrect.

PHXII12:ATOMS

356348 Assertion :
Large angle of scattering of alpha particles led to the discovery of atomic nucleus.
Reason :
Entire positive charge of atom is concentrated in the central core.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.

2 Both assertion and reason are correct but reason is not the correct explanation of assertion.

3 Assertion is correct but reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

$α -$ particle is positively charged, so is the nucleus, so the large angle of scattering of $α -$ particle shows that the nucleus is positively charged and concentrated in the central core. So option (1) is correct.

PHXII12:ATOMS

356350 The trajectory of an $α$ -particle can be computed by employing:

1 Newton's second law of motion.

2 Coulomb's law for electrostatic force of repulsion between the

α

-particle and the positively charges nucleus.

3 Both of these.

4 None of these.

PHXII12:ATOMS

356351 When an $α -$ particle of mass $^{'} m^{'}$ moving with velocity $^{'} v^{'}$ bombards on a heavy nucleus of charge $^{'} Z e^{'}$ , its distance of closest approach from the nucleus depends on $m$ as:

1

\frac{1}{m}

2

\frac{1}{\sqrt{m}}

3

\frac{1}{m^{2}}

4

m

Explanation:

At closest distance of approach, the kinetic energy of the particle will convert completely into electrostatic potential energy.
$\Rightarrow \frac{1}{2} m v^{2} = \frac{K Q q}{d} \Rightarrow d \propto \frac{1}{m}$

NEET - 2016

PHXII12:ATOMS

356352 Statement A :
The trajectory traced by an incident particle depends on the impact parameter of collision.
Statement B :
The impact parameter is the perpendicular distance of the initial velocity vector of the incident particle from the centre of the target nucleus.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both Statements are correct.

4 Both Statements are incorrect.

PHXII12:ATOMS

356348 Assertion :
Large angle of scattering of alpha particles led to the discovery of atomic nucleus.
Reason :
Entire positive charge of atom is concentrated in the central core.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.

2 Both assertion and reason are correct but reason is not the correct explanation of assertion.

3 Assertion is correct but reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

$α -$ particle is positively charged, so is the nucleus, so the large angle of scattering of $α -$ particle shows that the nucleus is positively charged and concentrated in the central core. So option (1) is correct.

PHXII12:ATOMS

356350 The trajectory of an $α$ -particle can be computed by employing:

1 Newton's second law of motion.

2 Coulomb's law for electrostatic force of repulsion between the

α

-particle and the positively charges nucleus.

3 Both of these.

4 None of these.

PHXII12:ATOMS

356351 When an $α -$ particle of mass $^{'} m^{'}$ moving with velocity $^{'} v^{'}$ bombards on a heavy nucleus of charge $^{'} Z e^{'}$ , its distance of closest approach from the nucleus depends on $m$ as:

1

\frac{1}{m}

2

\frac{1}{\sqrt{m}}

3

\frac{1}{m^{2}}

4

m

Explanation:

At closest distance of approach, the kinetic energy of the particle will convert completely into electrostatic potential energy.
$\Rightarrow \frac{1}{2} m v^{2} = \frac{K Q q}{d} \Rightarrow d \propto \frac{1}{m}$

NEET - 2016

PHXII12:ATOMS

356352 Statement A :
The trajectory traced by an incident particle depends on the impact parameter of collision.
Statement B :
The impact parameter is the perpendicular distance of the initial velocity vector of the incident particle from the centre of the target nucleus.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both Statements are correct.

4 Both Statements are incorrect.

PHXII12:ATOMS

356348 Assertion :
Large angle of scattering of alpha particles led to the discovery of atomic nucleus.
Reason :
Entire positive charge of atom is concentrated in the central core.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.

2 Both assertion and reason are correct but reason is not the correct explanation of assertion.

3 Assertion is correct but reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

$α -$ particle is positively charged, so is the nucleus, so the large angle of scattering of $α -$ particle shows that the nucleus is positively charged and concentrated in the central core. So option (1) is correct.

PHXII12:ATOMS

356350 The trajectory of an $α$ -particle can be computed by employing:

1 Newton's second law of motion.

2 Coulomb's law for electrostatic force of repulsion between the

α

-particle and the positively charges nucleus.

3 Both of these.

4 None of these.

PHXII12:ATOMS

356351 When an $α -$ particle of mass $^{'} m^{'}$ moving with velocity $^{'} v^{'}$ bombards on a heavy nucleus of charge $^{'} Z e^{'}$ , its distance of closest approach from the nucleus depends on $m$ as:

1

\frac{1}{m}

2

\frac{1}{\sqrt{m}}

3

\frac{1}{m^{2}}

4

m

Explanation:

At closest distance of approach, the kinetic energy of the particle will convert completely into electrostatic potential energy.
$\Rightarrow \frac{1}{2} m v^{2} = \frac{K Q q}{d} \Rightarrow d \propto \frac{1}{m}$

NEET - 2016

PHXII12:ATOMS

356352 Statement A :
The trajectory traced by an incident particle depends on the impact parameter of collision.
Statement B :
The impact parameter is the perpendicular distance of the initial velocity vector of the incident particle from the centre of the target nucleus.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both Statements are correct.

4 Both Statements are incorrect.