356308
The transformer ratio of a transformer is 5 . If the primary voltage of the transformer is \(400\;V\), \(50\;Hz\), the secondary voltage will be
1 \(2000\;V,250\;Hz\)
2 \(80\;V,50\;Hz\)
3 \(80\;V,10\;Hz\)
4 \(2000\;V,50\;Hz\)
Explanation:
\({V_s} = ({\rm{turn}}\,\,{\rm{ratio}}){V_p}\) \( = (5)(400) = 2000\;V\) But frequency of secondary voltage will be the same as that of primary voltage. \(\Rightarrow V_{s}\) will have \(50\;Hz\) only. So, the correct option is (4).
PHXII07:ALTERNATING CURRENT
356309
The primary winding of a transformer has 100 turns and its secondary winding has 200 turns. The primary is connected to an \(A.C.\) supply of \(120\;V\) and the current flowing in it is \(10\;A\). The voltage and the current in the secondary are
356310
In a transformer primary voltage is \(220\;V\) and secondary current is \(0.11\;A\) with output power \(60\;W\)
1 Transformer is step up
2 Transformer is step down
3 Transformer is auxiliary
4 None of these
Explanation:
Voltage across the secondary of the transformer: \(\begin{aligned}& \mathrm{V}_{\mathrm{s}}=\dfrac{60 \mathrm{~W}}{0.11 \mathrm{~A}} \approx 545 \mathrm{~V}, \mathrm{~V}_{\mathrm{p}}=220 \text { volt (given) } \\& \because \mathrm{V}_{\mathrm{s}}>\mathrm{V}_{\mathrm{p}} \text { so it is a step up transformer }\end{aligned}\)
JEE - 2021
PHXII07:ALTERNATING CURRENT
356311
An ideal transformer converts 200 \(V\) \(AC\) to 3.3 \(kV\) \(AC\) to transmit a power of 4.4 \(kW\). If primary coil has 600 turns, then alternating current in secondary coil is
356308
The transformer ratio of a transformer is 5 . If the primary voltage of the transformer is \(400\;V\), \(50\;Hz\), the secondary voltage will be
1 \(2000\;V,250\;Hz\)
2 \(80\;V,50\;Hz\)
3 \(80\;V,10\;Hz\)
4 \(2000\;V,50\;Hz\)
Explanation:
\({V_s} = ({\rm{turn}}\,\,{\rm{ratio}}){V_p}\) \( = (5)(400) = 2000\;V\) But frequency of secondary voltage will be the same as that of primary voltage. \(\Rightarrow V_{s}\) will have \(50\;Hz\) only. So, the correct option is (4).
PHXII07:ALTERNATING CURRENT
356309
The primary winding of a transformer has 100 turns and its secondary winding has 200 turns. The primary is connected to an \(A.C.\) supply of \(120\;V\) and the current flowing in it is \(10\;A\). The voltage and the current in the secondary are
356310
In a transformer primary voltage is \(220\;V\) and secondary current is \(0.11\;A\) with output power \(60\;W\)
1 Transformer is step up
2 Transformer is step down
3 Transformer is auxiliary
4 None of these
Explanation:
Voltage across the secondary of the transformer: \(\begin{aligned}& \mathrm{V}_{\mathrm{s}}=\dfrac{60 \mathrm{~W}}{0.11 \mathrm{~A}} \approx 545 \mathrm{~V}, \mathrm{~V}_{\mathrm{p}}=220 \text { volt (given) } \\& \because \mathrm{V}_{\mathrm{s}}>\mathrm{V}_{\mathrm{p}} \text { so it is a step up transformer }\end{aligned}\)
JEE - 2021
PHXII07:ALTERNATING CURRENT
356311
An ideal transformer converts 200 \(V\) \(AC\) to 3.3 \(kV\) \(AC\) to transmit a power of 4.4 \(kW\). If primary coil has 600 turns, then alternating current in secondary coil is
356308
The transformer ratio of a transformer is 5 . If the primary voltage of the transformer is \(400\;V\), \(50\;Hz\), the secondary voltage will be
1 \(2000\;V,250\;Hz\)
2 \(80\;V,50\;Hz\)
3 \(80\;V,10\;Hz\)
4 \(2000\;V,50\;Hz\)
Explanation:
\({V_s} = ({\rm{turn}}\,\,{\rm{ratio}}){V_p}\) \( = (5)(400) = 2000\;V\) But frequency of secondary voltage will be the same as that of primary voltage. \(\Rightarrow V_{s}\) will have \(50\;Hz\) only. So, the correct option is (4).
PHXII07:ALTERNATING CURRENT
356309
The primary winding of a transformer has 100 turns and its secondary winding has 200 turns. The primary is connected to an \(A.C.\) supply of \(120\;V\) and the current flowing in it is \(10\;A\). The voltage and the current in the secondary are
356310
In a transformer primary voltage is \(220\;V\) and secondary current is \(0.11\;A\) with output power \(60\;W\)
1 Transformer is step up
2 Transformer is step down
3 Transformer is auxiliary
4 None of these
Explanation:
Voltage across the secondary of the transformer: \(\begin{aligned}& \mathrm{V}_{\mathrm{s}}=\dfrac{60 \mathrm{~W}}{0.11 \mathrm{~A}} \approx 545 \mathrm{~V}, \mathrm{~V}_{\mathrm{p}}=220 \text { volt (given) } \\& \because \mathrm{V}_{\mathrm{s}}>\mathrm{V}_{\mathrm{p}} \text { so it is a step up transformer }\end{aligned}\)
JEE - 2021
PHXII07:ALTERNATING CURRENT
356311
An ideal transformer converts 200 \(V\) \(AC\) to 3.3 \(kV\) \(AC\) to transmit a power of 4.4 \(kW\). If primary coil has 600 turns, then alternating current in secondary coil is
NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII07:ALTERNATING CURRENT
356308
The transformer ratio of a transformer is 5 . If the primary voltage of the transformer is \(400\;V\), \(50\;Hz\), the secondary voltage will be
1 \(2000\;V,250\;Hz\)
2 \(80\;V,50\;Hz\)
3 \(80\;V,10\;Hz\)
4 \(2000\;V,50\;Hz\)
Explanation:
\({V_s} = ({\rm{turn}}\,\,{\rm{ratio}}){V_p}\) \( = (5)(400) = 2000\;V\) But frequency of secondary voltage will be the same as that of primary voltage. \(\Rightarrow V_{s}\) will have \(50\;Hz\) only. So, the correct option is (4).
PHXII07:ALTERNATING CURRENT
356309
The primary winding of a transformer has 100 turns and its secondary winding has 200 turns. The primary is connected to an \(A.C.\) supply of \(120\;V\) and the current flowing in it is \(10\;A\). The voltage and the current in the secondary are
356310
In a transformer primary voltage is \(220\;V\) and secondary current is \(0.11\;A\) with output power \(60\;W\)
1 Transformer is step up
2 Transformer is step down
3 Transformer is auxiliary
4 None of these
Explanation:
Voltage across the secondary of the transformer: \(\begin{aligned}& \mathrm{V}_{\mathrm{s}}=\dfrac{60 \mathrm{~W}}{0.11 \mathrm{~A}} \approx 545 \mathrm{~V}, \mathrm{~V}_{\mathrm{p}}=220 \text { volt (given) } \\& \because \mathrm{V}_{\mathrm{s}}>\mathrm{V}_{\mathrm{p}} \text { so it is a step up transformer }\end{aligned}\)
JEE - 2021
PHXII07:ALTERNATING CURRENT
356311
An ideal transformer converts 200 \(V\) \(AC\) to 3.3 \(kV\) \(AC\) to transmit a power of 4.4 \(kW\). If primary coil has 600 turns, then alternating current in secondary coil is
