356257
In an \(L-C-R\) series AC circuit, the voltage across each of the components \(L, C\) and \(R\) is \(50 \mathrm{~V}\). The voltage across the \(L-C\) combination will be
1 \(50\;V\)
2 \(50\sqrt 2 \;V\)
3 \(100\;V\)
4 zero
Explanation:
In an \(L-C-R\) series AC circuit, the voltage across inductor \(L\) leads the current by \(90^{\circ}\) and the voltage across capacitor \(C\) lags behind the current by \(90^{\circ}\).
Hence, the voltage across \(L-C\) combination will be zero.
PHXII07:ALTERNATING CURRENT
356258
An ideal resistance \(R\), ideal inductance \(L\), ideal capacitance \(C\) and \(AC\) voltmeters \({V_1},{V_2},{V_3}\) and \({V_4}\) are connected to an \(AC\) source as shown. At resonance
1 Reading in \({V_3} = \) reading in \({V_1}\)
2 Reading in \({V_1} = \) reading in \({V_2}\)
3 Reading in \({V_2} = \) reading in \({V_4}\)
4 None of these
Explanation:
At resonance, Voltage across \(L\) = Voltage across \(C\) Reading in \({V_2} = \) Reading in \({V_3}\)
PHXII07:ALTERNATING CURRENT
356259
An \(LCR\) series circuit is at resonance with \(10\,V\), each across \({L, C}\), and \({R}\). If the resistance is halved the respective voltages across \({L, C}\), and \({R}\) are
1 \({10 {~V}, 10 {~V}}\), and \(10\,V\)
2 \({20 {~V}, 20 {~V}}\), and \(5\,V\)
3 \({20 {~V}, 20 {~V}}\), and \(10\,V\)
4 \({5 {~V}, 5 {~V}}\), and \(5\,V\)
Explanation:
\({V_{L}=V_{C} \Rightarrow X_{L}=X_{C}}\) \({i_{\text {max }}=\dfrac{V}{R}}\) If \({R}\) is halved, then current will be doubled and \({V_{L}=V_{C}=2(10)=20 {~V}}\) \({V_{R}=I R=2 I \times \dfrac{R}{2}=I R=V_{R}=10 {~V}}\)
PHXII07:ALTERNATING CURRENT
356260
Obtain the resonant frequency \(\omega \) of a series \(L - C - R\) circuit with \(L = 2.0\,H,C = 32\mu F\) and \(R = 10\Omega \) What is the Q-value of this circuit?
356257
In an \(L-C-R\) series AC circuit, the voltage across each of the components \(L, C\) and \(R\) is \(50 \mathrm{~V}\). The voltage across the \(L-C\) combination will be
1 \(50\;V\)
2 \(50\sqrt 2 \;V\)
3 \(100\;V\)
4 zero
Explanation:
In an \(L-C-R\) series AC circuit, the voltage across inductor \(L\) leads the current by \(90^{\circ}\) and the voltage across capacitor \(C\) lags behind the current by \(90^{\circ}\).
Hence, the voltage across \(L-C\) combination will be zero.
PHXII07:ALTERNATING CURRENT
356258
An ideal resistance \(R\), ideal inductance \(L\), ideal capacitance \(C\) and \(AC\) voltmeters \({V_1},{V_2},{V_3}\) and \({V_4}\) are connected to an \(AC\) source as shown. At resonance
1 Reading in \({V_3} = \) reading in \({V_1}\)
2 Reading in \({V_1} = \) reading in \({V_2}\)
3 Reading in \({V_2} = \) reading in \({V_4}\)
4 None of these
Explanation:
At resonance, Voltage across \(L\) = Voltage across \(C\) Reading in \({V_2} = \) Reading in \({V_3}\)
PHXII07:ALTERNATING CURRENT
356259
An \(LCR\) series circuit is at resonance with \(10\,V\), each across \({L, C}\), and \({R}\). If the resistance is halved the respective voltages across \({L, C}\), and \({R}\) are
1 \({10 {~V}, 10 {~V}}\), and \(10\,V\)
2 \({20 {~V}, 20 {~V}}\), and \(5\,V\)
3 \({20 {~V}, 20 {~V}}\), and \(10\,V\)
4 \({5 {~V}, 5 {~V}}\), and \(5\,V\)
Explanation:
\({V_{L}=V_{C} \Rightarrow X_{L}=X_{C}}\) \({i_{\text {max }}=\dfrac{V}{R}}\) If \({R}\) is halved, then current will be doubled and \({V_{L}=V_{C}=2(10)=20 {~V}}\) \({V_{R}=I R=2 I \times \dfrac{R}{2}=I R=V_{R}=10 {~V}}\)
PHXII07:ALTERNATING CURRENT
356260
Obtain the resonant frequency \(\omega \) of a series \(L - C - R\) circuit with \(L = 2.0\,H,C = 32\mu F\) and \(R = 10\Omega \) What is the Q-value of this circuit?
356257
In an \(L-C-R\) series AC circuit, the voltage across each of the components \(L, C\) and \(R\) is \(50 \mathrm{~V}\). The voltage across the \(L-C\) combination will be
1 \(50\;V\)
2 \(50\sqrt 2 \;V\)
3 \(100\;V\)
4 zero
Explanation:
In an \(L-C-R\) series AC circuit, the voltage across inductor \(L\) leads the current by \(90^{\circ}\) and the voltage across capacitor \(C\) lags behind the current by \(90^{\circ}\).
Hence, the voltage across \(L-C\) combination will be zero.
PHXII07:ALTERNATING CURRENT
356258
An ideal resistance \(R\), ideal inductance \(L\), ideal capacitance \(C\) and \(AC\) voltmeters \({V_1},{V_2},{V_3}\) and \({V_4}\) are connected to an \(AC\) source as shown. At resonance
1 Reading in \({V_3} = \) reading in \({V_1}\)
2 Reading in \({V_1} = \) reading in \({V_2}\)
3 Reading in \({V_2} = \) reading in \({V_4}\)
4 None of these
Explanation:
At resonance, Voltage across \(L\) = Voltage across \(C\) Reading in \({V_2} = \) Reading in \({V_3}\)
PHXII07:ALTERNATING CURRENT
356259
An \(LCR\) series circuit is at resonance with \(10\,V\), each across \({L, C}\), and \({R}\). If the resistance is halved the respective voltages across \({L, C}\), and \({R}\) are
1 \({10 {~V}, 10 {~V}}\), and \(10\,V\)
2 \({20 {~V}, 20 {~V}}\), and \(5\,V\)
3 \({20 {~V}, 20 {~V}}\), and \(10\,V\)
4 \({5 {~V}, 5 {~V}}\), and \(5\,V\)
Explanation:
\({V_{L}=V_{C} \Rightarrow X_{L}=X_{C}}\) \({i_{\text {max }}=\dfrac{V}{R}}\) If \({R}\) is halved, then current will be doubled and \({V_{L}=V_{C}=2(10)=20 {~V}}\) \({V_{R}=I R=2 I \times \dfrac{R}{2}=I R=V_{R}=10 {~V}}\)
PHXII07:ALTERNATING CURRENT
356260
Obtain the resonant frequency \(\omega \) of a series \(L - C - R\) circuit with \(L = 2.0\,H,C = 32\mu F\) and \(R = 10\Omega \) What is the Q-value of this circuit?
356257
In an \(L-C-R\) series AC circuit, the voltage across each of the components \(L, C\) and \(R\) is \(50 \mathrm{~V}\). The voltage across the \(L-C\) combination will be
1 \(50\;V\)
2 \(50\sqrt 2 \;V\)
3 \(100\;V\)
4 zero
Explanation:
In an \(L-C-R\) series AC circuit, the voltage across inductor \(L\) leads the current by \(90^{\circ}\) and the voltage across capacitor \(C\) lags behind the current by \(90^{\circ}\).
Hence, the voltage across \(L-C\) combination will be zero.
PHXII07:ALTERNATING CURRENT
356258
An ideal resistance \(R\), ideal inductance \(L\), ideal capacitance \(C\) and \(AC\) voltmeters \({V_1},{V_2},{V_3}\) and \({V_4}\) are connected to an \(AC\) source as shown. At resonance
1 Reading in \({V_3} = \) reading in \({V_1}\)
2 Reading in \({V_1} = \) reading in \({V_2}\)
3 Reading in \({V_2} = \) reading in \({V_4}\)
4 None of these
Explanation:
At resonance, Voltage across \(L\) = Voltage across \(C\) Reading in \({V_2} = \) Reading in \({V_3}\)
PHXII07:ALTERNATING CURRENT
356259
An \(LCR\) series circuit is at resonance with \(10\,V\), each across \({L, C}\), and \({R}\). If the resistance is halved the respective voltages across \({L, C}\), and \({R}\) are
1 \({10 {~V}, 10 {~V}}\), and \(10\,V\)
2 \({20 {~V}, 20 {~V}}\), and \(5\,V\)
3 \({20 {~V}, 20 {~V}}\), and \(10\,V\)
4 \({5 {~V}, 5 {~V}}\), and \(5\,V\)
Explanation:
\({V_{L}=V_{C} \Rightarrow X_{L}=X_{C}}\) \({i_{\text {max }}=\dfrac{V}{R}}\) If \({R}\) is halved, then current will be doubled and \({V_{L}=V_{C}=2(10)=20 {~V}}\) \({V_{R}=I R=2 I \times \dfrac{R}{2}=I R=V_{R}=10 {~V}}\)
PHXII07:ALTERNATING CURRENT
356260
Obtain the resonant frequency \(\omega \) of a series \(L - C - R\) circuit with \(L = 2.0\,H,C = 32\mu F\) and \(R = 10\Omega \) What is the Q-value of this circuit?
