356145 In series LCR circuit \(R = 18\Omega \) and impedance is \(33\Omega \). An rms voltage 220\(V\) is applied across the circuit. The true power consumed in \(AC\) circuit is

356146 A series LCR circuit with a resistance of \(100 \sqrt{5} \Omega\) is connected to an ac source of \(200\;\,V\). When the capacitor is removed from the circuit, current lags behind emf by \(45^{\circ}\). When the inductor is removed from the circuit keeping the capacitor and resistor in the circuit, current leads by an angle of \(\tan ^{-1}\left(\dfrac{1}{2}\right)\). Calculate the power dissipated in LCR circuit.

356147 A series \(LCR\) circuit is connected to a voltage source. When \(L\) is removed from the circuit, the phase difference between current and voltage is \(\frac{\pi }{3}\). If instead \(C\) is removed from the circuit, the phase difference is again \(\frac{\pi }{3}\) between current and voltage. The power factor of the circuit is:

356148 In a series \(L R\) circuit with \(X_{L}=R\), power factor is \(P_{1}\). If a capacitor of capacitance \(C\) with \(X_{C}=X_{L}\) is added to the circuit the power factor becomes \(P_{2}\). The ratio of \(P_{1}\) to \(P_{2}\) will be

356145 In series LCR circuit \(R = 18\Omega \) and impedance is \(33\Omega \). An rms voltage 220\(V\) is applied across the circuit. The true power consumed in \(AC\) circuit is

356146 A series LCR circuit with a resistance of \(100 \sqrt{5} \Omega\) is connected to an ac source of \(200\;\,V\). When the capacitor is removed from the circuit, current lags behind emf by \(45^{\circ}\). When the inductor is removed from the circuit keeping the capacitor and resistor in the circuit, current leads by an angle of \(\tan ^{-1}\left(\dfrac{1}{2}\right)\). Calculate the power dissipated in LCR circuit.

356147 A series \(LCR\) circuit is connected to a voltage source. When \(L\) is removed from the circuit, the phase difference between current and voltage is \(\frac{\pi }{3}\). If instead \(C\) is removed from the circuit, the phase difference is again \(\frac{\pi }{3}\) between current and voltage. The power factor of the circuit is:

356148 In a series \(L R\) circuit with \(X_{L}=R\), power factor is \(P_{1}\). If a capacitor of capacitance \(C\) with \(X_{C}=X_{L}\) is added to the circuit the power factor becomes \(P_{2}\). The ratio of \(P_{1}\) to \(P_{2}\) will be

356145 In series LCR circuit \(R = 18\Omega \) and impedance is \(33\Omega \). An rms voltage 220\(V\) is applied across the circuit. The true power consumed in \(AC\) circuit is

356146 A series LCR circuit with a resistance of \(100 \sqrt{5} \Omega\) is connected to an ac source of \(200\;\,V\). When the capacitor is removed from the circuit, current lags behind emf by \(45^{\circ}\). When the inductor is removed from the circuit keeping the capacitor and resistor in the circuit, current leads by an angle of \(\tan ^{-1}\left(\dfrac{1}{2}\right)\). Calculate the power dissipated in LCR circuit.

356147 A series \(LCR\) circuit is connected to a voltage source. When \(L\) is removed from the circuit, the phase difference between current and voltage is \(\frac{\pi }{3}\). If instead \(C\) is removed from the circuit, the phase difference is again \(\frac{\pi }{3}\) between current and voltage. The power factor of the circuit is:

356148 In a series \(L R\) circuit with \(X_{L}=R\), power factor is \(P_{1}\). If a capacitor of capacitance \(C\) with \(X_{C}=X_{L}\) is added to the circuit the power factor becomes \(P_{2}\). The ratio of \(P_{1}\) to \(P_{2}\) will be

356145 In series LCR circuit \(R = 18\Omega \) and impedance is \(33\Omega \). An rms voltage 220\(V\) is applied across the circuit. The true power consumed in \(AC\) circuit is

356146 A series LCR circuit with a resistance of \(100 \sqrt{5} \Omega\) is connected to an ac source of \(200\;\,V\). When the capacitor is removed from the circuit, current lags behind emf by \(45^{\circ}\). When the inductor is removed from the circuit keeping the capacitor and resistor in the circuit, current leads by an angle of \(\tan ^{-1}\left(\dfrac{1}{2}\right)\). Calculate the power dissipated in LCR circuit.

356147 A series \(LCR\) circuit is connected to a voltage source. When \(L\) is removed from the circuit, the phase difference between current and voltage is \(\frac{\pi }{3}\). If instead \(C\) is removed from the circuit, the phase difference is again \(\frac{\pi }{3}\) between current and voltage. The power factor of the circuit is:

356148 In a series \(L R\) circuit with \(X_{L}=R\), power factor is \(P_{1}\). If a capacitor of capacitance \(C\) with \(X_{C}=X_{L}\) is added to the circuit the power factor becomes \(P_{2}\). The ratio of \(P_{1}\) to \(P_{2}\) will be