NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII07:ALTERNATING CURRENT
356006
An alternating current of frequency \('f'\) is flowing in a circuit containing a resistance \(R\) and a choke \(L\) in series. The impedance of this circuit is
356007
An inductor of inductance \(L\) and resistor \(R\) are joined together in series and connected by a source of frequency \(\omega \). The power dissipated in the circuit is
356008
In the circuit shown, a \(30\,V\) d.c. source gives a current \(2.0\,A\) as recorded in the ammeter \(A\) and \(30\,V\) a.c. source of frequency gives a current \(1.2\,V\). The inductive reactance is (in \(ohms\))
1 30
2 20
3 \(5 \sqrt{34}\)
4 40
Explanation:
When \(d.c.\) source, \(R=\dfrac{V}{1}=\dfrac{30}{2}=15 \Omega\) When \(a.c.\) source, \(Z=\dfrac{30}{1.2}=25 \Omega\) We know for \(L-R\) circuit \(Z^{2}=R_{2}^{2}+X_{L}^{2}\) \(X_{L}=\sqrt{(25)^{2}-(15)^{2}}=\sqrt{625-225}=20 \Omega\) So, correct option is (2).
PHXII07:ALTERNATING CURRENT
356009
The current in the shown circuit is found to be \(4\sin \left( {314t - \frac{\pi }{4}} \right)\,A\). Find the value of inductance.
356006
An alternating current of frequency \('f'\) is flowing in a circuit containing a resistance \(R\) and a choke \(L\) in series. The impedance of this circuit is
356007
An inductor of inductance \(L\) and resistor \(R\) are joined together in series and connected by a source of frequency \(\omega \). The power dissipated in the circuit is
356008
In the circuit shown, a \(30\,V\) d.c. source gives a current \(2.0\,A\) as recorded in the ammeter \(A\) and \(30\,V\) a.c. source of frequency gives a current \(1.2\,V\). The inductive reactance is (in \(ohms\))
1 30
2 20
3 \(5 \sqrt{34}\)
4 40
Explanation:
When \(d.c.\) source, \(R=\dfrac{V}{1}=\dfrac{30}{2}=15 \Omega\) When \(a.c.\) source, \(Z=\dfrac{30}{1.2}=25 \Omega\) We know for \(L-R\) circuit \(Z^{2}=R_{2}^{2}+X_{L}^{2}\) \(X_{L}=\sqrt{(25)^{2}-(15)^{2}}=\sqrt{625-225}=20 \Omega\) So, correct option is (2).
PHXII07:ALTERNATING CURRENT
356009
The current in the shown circuit is found to be \(4\sin \left( {314t - \frac{\pi }{4}} \right)\,A\). Find the value of inductance.
356006
An alternating current of frequency \('f'\) is flowing in a circuit containing a resistance \(R\) and a choke \(L\) in series. The impedance of this circuit is
356007
An inductor of inductance \(L\) and resistor \(R\) are joined together in series and connected by a source of frequency \(\omega \). The power dissipated in the circuit is
356008
In the circuit shown, a \(30\,V\) d.c. source gives a current \(2.0\,A\) as recorded in the ammeter \(A\) and \(30\,V\) a.c. source of frequency gives a current \(1.2\,V\). The inductive reactance is (in \(ohms\))
1 30
2 20
3 \(5 \sqrt{34}\)
4 40
Explanation:
When \(d.c.\) source, \(R=\dfrac{V}{1}=\dfrac{30}{2}=15 \Omega\) When \(a.c.\) source, \(Z=\dfrac{30}{1.2}=25 \Omega\) We know for \(L-R\) circuit \(Z^{2}=R_{2}^{2}+X_{L}^{2}\) \(X_{L}=\sqrt{(25)^{2}-(15)^{2}}=\sqrt{625-225}=20 \Omega\) So, correct option is (2).
PHXII07:ALTERNATING CURRENT
356009
The current in the shown circuit is found to be \(4\sin \left( {314t - \frac{\pi }{4}} \right)\,A\). Find the value of inductance.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
PHXII07:ALTERNATING CURRENT
356006
An alternating current of frequency \('f'\) is flowing in a circuit containing a resistance \(R\) and a choke \(L\) in series. The impedance of this circuit is
356007
An inductor of inductance \(L\) and resistor \(R\) are joined together in series and connected by a source of frequency \(\omega \). The power dissipated in the circuit is
356008
In the circuit shown, a \(30\,V\) d.c. source gives a current \(2.0\,A\) as recorded in the ammeter \(A\) and \(30\,V\) a.c. source of frequency gives a current \(1.2\,V\). The inductive reactance is (in \(ohms\))
1 30
2 20
3 \(5 \sqrt{34}\)
4 40
Explanation:
When \(d.c.\) source, \(R=\dfrac{V}{1}=\dfrac{30}{2}=15 \Omega\) When \(a.c.\) source, \(Z=\dfrac{30}{1.2}=25 \Omega\) We know for \(L-R\) circuit \(Z^{2}=R_{2}^{2}+X_{L}^{2}\) \(X_{L}=\sqrt{(25)^{2}-(15)^{2}}=\sqrt{625-225}=20 \Omega\) So, correct option is (2).
PHXII07:ALTERNATING CURRENT
356009
The current in the shown circuit is found to be \(4\sin \left( {314t - \frac{\pi }{4}} \right)\,A\). Find the value of inductance.