0.333 Given, 0.3, 0.03, 0.003 We need to find sum of all these. \(\therefore\) sum of 0.3 + 0.03 + 0.003 = 0.333
RATIONAL NUMBERS
297812
If a is reciprocal of b, then the reciprocal of b is:
1 a
2 ab
3 a\(^{1}\)
4 None
Explanation:
a If a is reciprocal of b, then the reciprocal of b is a If a is reciprocal of b, then a × b = 1 [Commutative property is true for multiplication] b × a = 1 Thus reciprocal of b is a
RATIONAL NUMBERS
297813
If \(\frac{\text{x}}{3}+\frac{1}{3}=1,\) then x = ?
1 \(\frac{3}{4}\)
2 \(\frac{4}{3}\)
3 \(-\frac{3}{4}\)
4 \(\frac{-4}{3}\)
Explanation:
\(\frac{4}{3}\) \(??\frac{\text{x}}{2}+\frac{1}{3}=1\) \(\Rightarrow\frac{\text{x}}{2}=1-\frac{1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{3\times1-1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{3-1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{2}{3}\) \(\Rightarrow\frac{2\text{x}}{2}=\frac{2\times2}{3}\) (Multiplying both sides by 2) \(\Rightarrow\text{x}=\frac{4}{3}\) Hence, the correct answer is option (b).
RATIONAL NUMBERS
297814
Mark \((\checkmark)\) against the correct answer in the following: Which is greater between \(\frac{-4}{9}\) and \(\frac{-5}{12}?\)
1 \(\frac{-4}{9}\)
2 \(\frac{-5}{12}\)
3 Both are equal.
Explanation:
\(\frac{-5}{12}\) The correct option is (b). \(\frac{-5}{12}\) is greater than \(\frac{-4}{9}\) LCM of 9 and 12 is 36 \(\frac{-5\times3}{12\times3}=\frac{-15}{36}\) \(\frac{-4\times4}{12\times4}=\frac{-16}{36}\) \((-15)>(-16)\) \(\frac{-5}{12}>\frac{-4}{9}\)
0.333 Given, 0.3, 0.03, 0.003 We need to find sum of all these. \(\therefore\) sum of 0.3 + 0.03 + 0.003 = 0.333
RATIONAL NUMBERS
297812
If a is reciprocal of b, then the reciprocal of b is:
1 a
2 ab
3 a\(^{1}\)
4 None
Explanation:
a If a is reciprocal of b, then the reciprocal of b is a If a is reciprocal of b, then a × b = 1 [Commutative property is true for multiplication] b × a = 1 Thus reciprocal of b is a
RATIONAL NUMBERS
297813
If \(\frac{\text{x}}{3}+\frac{1}{3}=1,\) then x = ?
1 \(\frac{3}{4}\)
2 \(\frac{4}{3}\)
3 \(-\frac{3}{4}\)
4 \(\frac{-4}{3}\)
Explanation:
\(\frac{4}{3}\) \(??\frac{\text{x}}{2}+\frac{1}{3}=1\) \(\Rightarrow\frac{\text{x}}{2}=1-\frac{1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{3\times1-1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{3-1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{2}{3}\) \(\Rightarrow\frac{2\text{x}}{2}=\frac{2\times2}{3}\) (Multiplying both sides by 2) \(\Rightarrow\text{x}=\frac{4}{3}\) Hence, the correct answer is option (b).
RATIONAL NUMBERS
297814
Mark \((\checkmark)\) against the correct answer in the following: Which is greater between \(\frac{-4}{9}\) and \(\frac{-5}{12}?\)
1 \(\frac{-4}{9}\)
2 \(\frac{-5}{12}\)
3 Both are equal.
Explanation:
\(\frac{-5}{12}\) The correct option is (b). \(\frac{-5}{12}\) is greater than \(\frac{-4}{9}\) LCM of 9 and 12 is 36 \(\frac{-5\times3}{12\times3}=\frac{-15}{36}\) \(\frac{-4\times4}{12\times4}=\frac{-16}{36}\) \((-15)>(-16)\) \(\frac{-5}{12}>\frac{-4}{9}\)
0.333 Given, 0.3, 0.03, 0.003 We need to find sum of all these. \(\therefore\) sum of 0.3 + 0.03 + 0.003 = 0.333
RATIONAL NUMBERS
297812
If a is reciprocal of b, then the reciprocal of b is:
1 a
2 ab
3 a\(^{1}\)
4 None
Explanation:
a If a is reciprocal of b, then the reciprocal of b is a If a is reciprocal of b, then a × b = 1 [Commutative property is true for multiplication] b × a = 1 Thus reciprocal of b is a
RATIONAL NUMBERS
297813
If \(\frac{\text{x}}{3}+\frac{1}{3}=1,\) then x = ?
1 \(\frac{3}{4}\)
2 \(\frac{4}{3}\)
3 \(-\frac{3}{4}\)
4 \(\frac{-4}{3}\)
Explanation:
\(\frac{4}{3}\) \(??\frac{\text{x}}{2}+\frac{1}{3}=1\) \(\Rightarrow\frac{\text{x}}{2}=1-\frac{1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{3\times1-1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{3-1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{2}{3}\) \(\Rightarrow\frac{2\text{x}}{2}=\frac{2\times2}{3}\) (Multiplying both sides by 2) \(\Rightarrow\text{x}=\frac{4}{3}\) Hence, the correct answer is option (b).
RATIONAL NUMBERS
297814
Mark \((\checkmark)\) against the correct answer in the following: Which is greater between \(\frac{-4}{9}\) and \(\frac{-5}{12}?\)
1 \(\frac{-4}{9}\)
2 \(\frac{-5}{12}\)
3 Both are equal.
Explanation:
\(\frac{-5}{12}\) The correct option is (b). \(\frac{-5}{12}\) is greater than \(\frac{-4}{9}\) LCM of 9 and 12 is 36 \(\frac{-5\times3}{12\times3}=\frac{-15}{36}\) \(\frac{-4\times4}{12\times4}=\frac{-16}{36}\) \((-15)>(-16)\) \(\frac{-5}{12}>\frac{-4}{9}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
RATIONAL NUMBERS
297811
Sum of the numbers 0.3, 0.03 and 0.003 is:
1 0.999
2 0.393
3 0.636
4 0.333
Explanation:
0.333 Given, 0.3, 0.03, 0.003 We need to find sum of all these. \(\therefore\) sum of 0.3 + 0.03 + 0.003 = 0.333
RATIONAL NUMBERS
297812
If a is reciprocal of b, then the reciprocal of b is:
1 a
2 ab
3 a\(^{1}\)
4 None
Explanation:
a If a is reciprocal of b, then the reciprocal of b is a If a is reciprocal of b, then a × b = 1 [Commutative property is true for multiplication] b × a = 1 Thus reciprocal of b is a
RATIONAL NUMBERS
297813
If \(\frac{\text{x}}{3}+\frac{1}{3}=1,\) then x = ?
1 \(\frac{3}{4}\)
2 \(\frac{4}{3}\)
3 \(-\frac{3}{4}\)
4 \(\frac{-4}{3}\)
Explanation:
\(\frac{4}{3}\) \(??\frac{\text{x}}{2}+\frac{1}{3}=1\) \(\Rightarrow\frac{\text{x}}{2}=1-\frac{1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{3\times1-1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{3-1}{3}\) \(\Rightarrow\frac{\text{x}}{2}=\frac{2}{3}\) \(\Rightarrow\frac{2\text{x}}{2}=\frac{2\times2}{3}\) (Multiplying both sides by 2) \(\Rightarrow\text{x}=\frac{4}{3}\) Hence, the correct answer is option (b).
RATIONAL NUMBERS
297814
Mark \((\checkmark)\) against the correct answer in the following: Which is greater between \(\frac{-4}{9}\) and \(\frac{-5}{12}?\)
1 \(\frac{-4}{9}\)
2 \(\frac{-5}{12}\)
3 Both are equal.
Explanation:
\(\frac{-5}{12}\) The correct option is (b). \(\frac{-5}{12}\) is greater than \(\frac{-4}{9}\) LCM of 9 and 12 is 36 \(\frac{-5\times3}{12\times3}=\frac{-15}{36}\) \(\frac{-4\times4}{12\times4}=\frac{-16}{36}\) \((-15)>(-16)\) \(\frac{-5}{12}>\frac{-4}{9}\)
