297683
Which of the following are reflections of each other?
12
23
34
45
Explanation:
6 Since in the figure (a) the image of one side of the figure is exactly same as the figure on the other side of the line of symmetry.
PRACTICAL GEOMETRY
297684
Mark \((\checkmark)\) against the correct answer. In the given figure, rays OA, OB, OC and OD are such that \(\angle\text{AOB}=50^\circ,\angle\text{BOC}=90^\circ,\angle\text{COD}=70^\circ\) and \(\angle\text{AOD}=\text{x}^\circ.\) 7
1 50°
2 70°
3 150°
4 90°
Explanation:
150° In the figure, \(\angle\text{AOB}=50^\circ,\angle\text{BOC}=90^\circ\) \(\angle\text{COD}=70^\circ,\angle\text{AOD}=\text{x}^\circ.\) But \(\angle\text{AOB}+\angle\text{BOC}+\angle\text{COD}+\angle\text{DOA}\) (Angles at point) \(\Rightarrow50^\circ+90+^\circ+70+\text{x}=360^\circ\) \(\Rightarrow210+\text{x}=360^\circ\) \(\Rightarrow\text{x}=360^\circ-210^\circ\) \(\Rightarrow\text{x}=150^\circ\)
PRACTICAL GEOMETRY
297690
Mark \((\checkmark)\) against the correct answer: In the given figure, AOB is a straignt line, \(\angle\text{AOC}=56^\circ\) and \(\angle\text{BOC}=\text{x}^\circ\) The value of x is: 8
297693
Mark \((\checkmark)\) against the correct answer. In a \(\triangle\text{ABC}\) it is given that \(\angle\text{B}=37^\circ\) and \(\angle\text{C}=29^\circ\) Then, \(\angle\text{A}={}?\)
1 86°
2 66°
3 114°
4 57°
Explanation:
114° In \(\triangle\text{ABC},\angle\text{B}=90^\circ,\angle\text{G}=29^\circ\) But \(\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ\) (angles of a triangle) \(\Rightarrow\angle\text{A}+37^\circ+29^\circ=180^\circ\) \(\Rightarrow\angle\text{A}+66^\circ=180^\circ\) \(\Rightarrow\angle\text{A}=180^\circ-66^\circ=114^\circ\)
PRACTICAL GEOMETRY
297694
The construction of a triangle ABC in which AB = 7cm, \(\angle\text{A}=60\circ\) is not possible when sum of BC and AC is equal to
297683
Which of the following are reflections of each other?
12
23
34
45
Explanation:
6 Since in the figure (a) the image of one side of the figure is exactly same as the figure on the other side of the line of symmetry.
PRACTICAL GEOMETRY
297684
Mark \((\checkmark)\) against the correct answer. In the given figure, rays OA, OB, OC and OD are such that \(\angle\text{AOB}=50^\circ,\angle\text{BOC}=90^\circ,\angle\text{COD}=70^\circ\) and \(\angle\text{AOD}=\text{x}^\circ.\) 7
1 50°
2 70°
3 150°
4 90°
Explanation:
150° In the figure, \(\angle\text{AOB}=50^\circ,\angle\text{BOC}=90^\circ\) \(\angle\text{COD}=70^\circ,\angle\text{AOD}=\text{x}^\circ.\) But \(\angle\text{AOB}+\angle\text{BOC}+\angle\text{COD}+\angle\text{DOA}\) (Angles at point) \(\Rightarrow50^\circ+90+^\circ+70+\text{x}=360^\circ\) \(\Rightarrow210+\text{x}=360^\circ\) \(\Rightarrow\text{x}=360^\circ-210^\circ\) \(\Rightarrow\text{x}=150^\circ\)
PRACTICAL GEOMETRY
297690
Mark \((\checkmark)\) against the correct answer: In the given figure, AOB is a straignt line, \(\angle\text{AOC}=56^\circ\) and \(\angle\text{BOC}=\text{x}^\circ\) The value of x is: 8
297693
Mark \((\checkmark)\) against the correct answer. In a \(\triangle\text{ABC}\) it is given that \(\angle\text{B}=37^\circ\) and \(\angle\text{C}=29^\circ\) Then, \(\angle\text{A}={}?\)
1 86°
2 66°
3 114°
4 57°
Explanation:
114° In \(\triangle\text{ABC},\angle\text{B}=90^\circ,\angle\text{G}=29^\circ\) But \(\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ\) (angles of a triangle) \(\Rightarrow\angle\text{A}+37^\circ+29^\circ=180^\circ\) \(\Rightarrow\angle\text{A}+66^\circ=180^\circ\) \(\Rightarrow\angle\text{A}=180^\circ-66^\circ=114^\circ\)
PRACTICAL GEOMETRY
297694
The construction of a triangle ABC in which AB = 7cm, \(\angle\text{A}=60\circ\) is not possible when sum of BC and AC is equal to
297683
Which of the following are reflections of each other?
12
23
34
45
Explanation:
6 Since in the figure (a) the image of one side of the figure is exactly same as the figure on the other side of the line of symmetry.
PRACTICAL GEOMETRY
297684
Mark \((\checkmark)\) against the correct answer. In the given figure, rays OA, OB, OC and OD are such that \(\angle\text{AOB}=50^\circ,\angle\text{BOC}=90^\circ,\angle\text{COD}=70^\circ\) and \(\angle\text{AOD}=\text{x}^\circ.\) 7
1 50°
2 70°
3 150°
4 90°
Explanation:
150° In the figure, \(\angle\text{AOB}=50^\circ,\angle\text{BOC}=90^\circ\) \(\angle\text{COD}=70^\circ,\angle\text{AOD}=\text{x}^\circ.\) But \(\angle\text{AOB}+\angle\text{BOC}+\angle\text{COD}+\angle\text{DOA}\) (Angles at point) \(\Rightarrow50^\circ+90+^\circ+70+\text{x}=360^\circ\) \(\Rightarrow210+\text{x}=360^\circ\) \(\Rightarrow\text{x}=360^\circ-210^\circ\) \(\Rightarrow\text{x}=150^\circ\)
PRACTICAL GEOMETRY
297690
Mark \((\checkmark)\) against the correct answer: In the given figure, AOB is a straignt line, \(\angle\text{AOC}=56^\circ\) and \(\angle\text{BOC}=\text{x}^\circ\) The value of x is: 8
297693
Mark \((\checkmark)\) against the correct answer. In a \(\triangle\text{ABC}\) it is given that \(\angle\text{B}=37^\circ\) and \(\angle\text{C}=29^\circ\) Then, \(\angle\text{A}={}?\)
1 86°
2 66°
3 114°
4 57°
Explanation:
114° In \(\triangle\text{ABC},\angle\text{B}=90^\circ,\angle\text{G}=29^\circ\) But \(\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ\) (angles of a triangle) \(\Rightarrow\angle\text{A}+37^\circ+29^\circ=180^\circ\) \(\Rightarrow\angle\text{A}+66^\circ=180^\circ\) \(\Rightarrow\angle\text{A}=180^\circ-66^\circ=114^\circ\)
PRACTICAL GEOMETRY
297694
The construction of a triangle ABC in which AB = 7cm, \(\angle\text{A}=60\circ\) is not possible when sum of BC and AC is equal to
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
PRACTICAL GEOMETRY
297683
Which of the following are reflections of each other?
12
23
34
45
Explanation:
6 Since in the figure (a) the image of one side of the figure is exactly same as the figure on the other side of the line of symmetry.
PRACTICAL GEOMETRY
297684
Mark \((\checkmark)\) against the correct answer. In the given figure, rays OA, OB, OC and OD are such that \(\angle\text{AOB}=50^\circ,\angle\text{BOC}=90^\circ,\angle\text{COD}=70^\circ\) and \(\angle\text{AOD}=\text{x}^\circ.\) 7
1 50°
2 70°
3 150°
4 90°
Explanation:
150° In the figure, \(\angle\text{AOB}=50^\circ,\angle\text{BOC}=90^\circ\) \(\angle\text{COD}=70^\circ,\angle\text{AOD}=\text{x}^\circ.\) But \(\angle\text{AOB}+\angle\text{BOC}+\angle\text{COD}+\angle\text{DOA}\) (Angles at point) \(\Rightarrow50^\circ+90+^\circ+70+\text{x}=360^\circ\) \(\Rightarrow210+\text{x}=360^\circ\) \(\Rightarrow\text{x}=360^\circ-210^\circ\) \(\Rightarrow\text{x}=150^\circ\)
PRACTICAL GEOMETRY
297690
Mark \((\checkmark)\) against the correct answer: In the given figure, AOB is a straignt line, \(\angle\text{AOC}=56^\circ\) and \(\angle\text{BOC}=\text{x}^\circ\) The value of x is: 8
297693
Mark \((\checkmark)\) against the correct answer. In a \(\triangle\text{ABC}\) it is given that \(\angle\text{B}=37^\circ\) and \(\angle\text{C}=29^\circ\) Then, \(\angle\text{A}={}?\)
1 86°
2 66°
3 114°
4 57°
Explanation:
114° In \(\triangle\text{ABC},\angle\text{B}=90^\circ,\angle\text{G}=29^\circ\) But \(\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ\) (angles of a triangle) \(\Rightarrow\angle\text{A}+37^\circ+29^\circ=180^\circ\) \(\Rightarrow\angle\text{A}+66^\circ=180^\circ\) \(\Rightarrow\angle\text{A}=180^\circ-66^\circ=114^\circ\)
PRACTICAL GEOMETRY
297694
The construction of a triangle ABC in which AB = 7cm, \(\angle\text{A}=60\circ\) is not possible when sum of BC and AC is equal to
297683
Which of the following are reflections of each other?
12
23
34
45
Explanation:
6 Since in the figure (a) the image of one side of the figure is exactly same as the figure on the other side of the line of symmetry.
PRACTICAL GEOMETRY
297684
Mark \((\checkmark)\) against the correct answer. In the given figure, rays OA, OB, OC and OD are such that \(\angle\text{AOB}=50^\circ,\angle\text{BOC}=90^\circ,\angle\text{COD}=70^\circ\) and \(\angle\text{AOD}=\text{x}^\circ.\) 7
1 50°
2 70°
3 150°
4 90°
Explanation:
150° In the figure, \(\angle\text{AOB}=50^\circ,\angle\text{BOC}=90^\circ\) \(\angle\text{COD}=70^\circ,\angle\text{AOD}=\text{x}^\circ.\) But \(\angle\text{AOB}+\angle\text{BOC}+\angle\text{COD}+\angle\text{DOA}\) (Angles at point) \(\Rightarrow50^\circ+90+^\circ+70+\text{x}=360^\circ\) \(\Rightarrow210+\text{x}=360^\circ\) \(\Rightarrow\text{x}=360^\circ-210^\circ\) \(\Rightarrow\text{x}=150^\circ\)
PRACTICAL GEOMETRY
297690
Mark \((\checkmark)\) against the correct answer: In the given figure, AOB is a straignt line, \(\angle\text{AOC}=56^\circ\) and \(\angle\text{BOC}=\text{x}^\circ\) The value of x is: 8
297693
Mark \((\checkmark)\) against the correct answer. In a \(\triangle\text{ABC}\) it is given that \(\angle\text{B}=37^\circ\) and \(\angle\text{C}=29^\circ\) Then, \(\angle\text{A}={}?\)
1 86°
2 66°
3 114°
4 57°
Explanation:
114° In \(\triangle\text{ABC},\angle\text{B}=90^\circ,\angle\text{G}=29^\circ\) But \(\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ\) (angles of a triangle) \(\Rightarrow\angle\text{A}+37^\circ+29^\circ=180^\circ\) \(\Rightarrow\angle\text{A}+66^\circ=180^\circ\) \(\Rightarrow\angle\text{A}=180^\circ-66^\circ=114^\circ\)
PRACTICAL GEOMETRY
297694
The construction of a triangle ABC in which AB = 7cm, \(\angle\text{A}=60\circ\) is not possible when sum of BC and AC is equal to
2