297658 The order of rotational symmetry in the figure given below is:
0

297659 Mark \((\checkmark)\) against the correct answer.
In a \(\triangle\text{ABC},\) if \(\angle\text{A}+\angle\text{B}=65^\circ\) and \(\angle\text{B}+\angle\text{C}=140^\circ.\) Then, \(\angle\text{B}={}?\)

297660 A/an ___________connect a vertex of a triangle to the mid-point of the opposite side.

297661 Mark \((\checkmark)\) against the correct answer.
The angle of a triangle are (3x)°, (2x - 7)° and (4x - 11)°. Then, x =?

297662 For construction of a \(\triangle{\text{PQR}}\) when QR = 6cm, PR = 10cm and \(\angle{\text{Q}}\) = 90° its steps for construction is given below in jumbled form. Identify the fifth step from the following.
1. At point Q, draw an angle of 90°
2. From R cut an arc of length PR = 10.0cm PR = 10.0cm using a compass.
3. Name the point of intersection of the arm of the angle 90° and the arc drawn in step 3, as P.
4. Join P to Q. PQR is the required triangle.
5. Draw the base side QR = 6cm

297658 The order of rotational symmetry in the figure given below is:
0

297659 Mark \((\checkmark)\) against the correct answer.
In a \(\triangle\text{ABC},\) if \(\angle\text{A}+\angle\text{B}=65^\circ\) and \(\angle\text{B}+\angle\text{C}=140^\circ.\) Then, \(\angle\text{B}={}?\)

297660 A/an ___________connect a vertex of a triangle to the mid-point of the opposite side.

297661 Mark \((\checkmark)\) against the correct answer.
The angle of a triangle are (3x)°, (2x - 7)° and (4x - 11)°. Then, x =?

297662 For construction of a \(\triangle{\text{PQR}}\) when QR = 6cm, PR = 10cm and \(\angle{\text{Q}}\) = 90° its steps for construction is given below in jumbled form. Identify the fifth step from the following.
1. At point Q, draw an angle of 90°
2. From R cut an arc of length PR = 10.0cm PR = 10.0cm using a compass.
3. Name the point of intersection of the arm of the angle 90° and the arc drawn in step 3, as P.
4. Join P to Q. PQR is the required triangle.
5. Draw the base side QR = 6cm

297658 The order of rotational symmetry in the figure given below is:
0

297659 Mark \((\checkmark)\) against the correct answer.
In a \(\triangle\text{ABC},\) if \(\angle\text{A}+\angle\text{B}=65^\circ\) and \(\angle\text{B}+\angle\text{C}=140^\circ.\) Then, \(\angle\text{B}={}?\)

297660 A/an ___________connect a vertex of a triangle to the mid-point of the opposite side.

297661 Mark \((\checkmark)\) against the correct answer.
The angle of a triangle are (3x)°, (2x - 7)° and (4x - 11)°. Then, x =?

297662 For construction of a \(\triangle{\text{PQR}}\) when QR = 6cm, PR = 10cm and \(\angle{\text{Q}}\) = 90° its steps for construction is given below in jumbled form. Identify the fifth step from the following.
1. At point Q, draw an angle of 90°
2. From R cut an arc of length PR = 10.0cm PR = 10.0cm using a compass.
3. Name the point of intersection of the arm of the angle 90° and the arc drawn in step 3, as P.
4. Join P to Q. PQR is the required triangle.
5. Draw the base side QR = 6cm

297658 The order of rotational symmetry in the figure given below is:
0

297659 Mark \((\checkmark)\) against the correct answer.
In a \(\triangle\text{ABC},\) if \(\angle\text{A}+\angle\text{B}=65^\circ\) and \(\angle\text{B}+\angle\text{C}=140^\circ.\) Then, \(\angle\text{B}={}?\)

297660 A/an ___________connect a vertex of a triangle to the mid-point of the opposite side.

297661 Mark \((\checkmark)\) against the correct answer.
The angle of a triangle are (3x)°, (2x - 7)° and (4x - 11)°. Then, x =?

297662 For construction of a \(\triangle{\text{PQR}}\) when QR = 6cm, PR = 10cm and \(\angle{\text{Q}}\) = 90° its steps for construction is given below in jumbled form. Identify the fifth step from the following.
1. At point Q, draw an angle of 90°
2. From R cut an arc of length PR = 10.0cm PR = 10.0cm using a compass.
3. Name the point of intersection of the arm of the angle 90° and the arc drawn in step 3, as P.
4. Join P to Q. PQR is the required triangle.
5. Draw the base side QR = 6cm

297658 The order of rotational symmetry in the figure given below is:
0

297659 Mark \((\checkmark)\) against the correct answer.
In a \(\triangle\text{ABC},\) if \(\angle\text{A}+\angle\text{B}=65^\circ\) and \(\angle\text{B}+\angle\text{C}=140^\circ.\) Then, \(\angle\text{B}={}?\)

297660 A/an ___________connect a vertex of a triangle to the mid-point of the opposite side.

297661 Mark \((\checkmark)\) against the correct answer.
The angle of a triangle are (3x)°, (2x - 7)° and (4x - 11)°. Then, x =?

297662 For construction of a \(\triangle{\text{PQR}}\) when QR = 6cm, PR = 10cm and \(\angle{\text{Q}}\) = 90° its steps for construction is given below in jumbled form. Identify the fifth step from the following.
1. At point Q, draw an angle of 90°
2. From R cut an arc of length PR = 10.0cm PR = 10.0cm using a compass.
3. Name the point of intersection of the arm of the angle 90° and the arc drawn in step 3, as P.
4. Join P to Q. PQR is the required triangle.
5. Draw the base side QR = 6cm