290844
The recurring decimal \(1.\overline{263}...\) in a fraction form is equal to.
1 \(\frac{1262}{90}\)
2 \(\frac{1262}{99}\)
3 \(\frac{1262}{999}\)
4 \(\text{None of these}\)
Explanation:
\(\frac{1262}{99}\) C \(\frac{1262}{999}\) Let x = 1.263263263 [we multiply it by 1000] Here 3 digits are repeated 1000x = 1263.263263.... x = 1.263263... 999x = 1262 \(\Rightarrow\text{x}=\frac{1262}{999}\) The recurring decimal 1.263 in a fraction form is equal to \(\frac{1262}{999}\)
04. DECIMALS
290845
Directions: In the following questions, the Assertions (A) and Reason(s) (R) have been put forward. Read both the statements carefully and choose the correct alternative from the following: Assertion (A): 100rs = 100000 paise. Reason (R): 1 Rs= 100 paise.
1 Both A and R are true and R is the correct explanation of A.
2 Both A and R are true but R is not the correct explanation of A.
3 A is true but R is false.
4 A is false but R is true.
Explanation:
A is false but R is true.
04. DECIMALS
290846
Prerna has Rs. 5000. She bought 2 boxes of chocolates for Rs. 52.98 each, 3 packets of chips for Rs. 12.98 each and 2 books for Rs. 300.05 each. How much money left with her?
1 Rs. 4255
2 Rs. 4750
3 Rs. 4000
4 Rs. 3875
Explanation:
Rs. 4255 Total expenditure = Rs.((2 × 52.98) + (3 × 12.98) + (2 × 300.5)) = Rs.(105.96 + 38.94 + 600.10) = Rs. 745 Amount of money left with her = Rs. (5000 - 745) = Rs. 4255
04. DECIMALS
290847
What is the sum of 11.006 + 34 + 0.72 rounded to the nearest tenths?
1 45.1
2 45.7
3 45.73
4 46
Explanation:
45.1 B 45.7 The sum of 11.006 + 34 + 0.72 is 45.726 Now, the number 45.726 is rounded off as 45.73. Again it is rounded to nearest tenths as 45.7.
290844
The recurring decimal \(1.\overline{263}...\) in a fraction form is equal to.
1 \(\frac{1262}{90}\)
2 \(\frac{1262}{99}\)
3 \(\frac{1262}{999}\)
4 \(\text{None of these}\)
Explanation:
\(\frac{1262}{99}\) C \(\frac{1262}{999}\) Let x = 1.263263263 [we multiply it by 1000] Here 3 digits are repeated 1000x = 1263.263263.... x = 1.263263... 999x = 1262 \(\Rightarrow\text{x}=\frac{1262}{999}\) The recurring decimal 1.263 in a fraction form is equal to \(\frac{1262}{999}\)
04. DECIMALS
290845
Directions: In the following questions, the Assertions (A) and Reason(s) (R) have been put forward. Read both the statements carefully and choose the correct alternative from the following: Assertion (A): 100rs = 100000 paise. Reason (R): 1 Rs= 100 paise.
1 Both A and R are true and R is the correct explanation of A.
2 Both A and R are true but R is not the correct explanation of A.
3 A is true but R is false.
4 A is false but R is true.
Explanation:
A is false but R is true.
04. DECIMALS
290846
Prerna has Rs. 5000. She bought 2 boxes of chocolates for Rs. 52.98 each, 3 packets of chips for Rs. 12.98 each and 2 books for Rs. 300.05 each. How much money left with her?
1 Rs. 4255
2 Rs. 4750
3 Rs. 4000
4 Rs. 3875
Explanation:
Rs. 4255 Total expenditure = Rs.((2 × 52.98) + (3 × 12.98) + (2 × 300.5)) = Rs.(105.96 + 38.94 + 600.10) = Rs. 745 Amount of money left with her = Rs. (5000 - 745) = Rs. 4255
04. DECIMALS
290847
What is the sum of 11.006 + 34 + 0.72 rounded to the nearest tenths?
1 45.1
2 45.7
3 45.73
4 46
Explanation:
45.1 B 45.7 The sum of 11.006 + 34 + 0.72 is 45.726 Now, the number 45.726 is rounded off as 45.73. Again it is rounded to nearest tenths as 45.7.
290844
The recurring decimal \(1.\overline{263}...\) in a fraction form is equal to.
1 \(\frac{1262}{90}\)
2 \(\frac{1262}{99}\)
3 \(\frac{1262}{999}\)
4 \(\text{None of these}\)
Explanation:
\(\frac{1262}{99}\) C \(\frac{1262}{999}\) Let x = 1.263263263 [we multiply it by 1000] Here 3 digits are repeated 1000x = 1263.263263.... x = 1.263263... 999x = 1262 \(\Rightarrow\text{x}=\frac{1262}{999}\) The recurring decimal 1.263 in a fraction form is equal to \(\frac{1262}{999}\)
04. DECIMALS
290845
Directions: In the following questions, the Assertions (A) and Reason(s) (R) have been put forward. Read both the statements carefully and choose the correct alternative from the following: Assertion (A): 100rs = 100000 paise. Reason (R): 1 Rs= 100 paise.
1 Both A and R are true and R is the correct explanation of A.
2 Both A and R are true but R is not the correct explanation of A.
3 A is true but R is false.
4 A is false but R is true.
Explanation:
A is false but R is true.
04. DECIMALS
290846
Prerna has Rs. 5000. She bought 2 boxes of chocolates for Rs. 52.98 each, 3 packets of chips for Rs. 12.98 each and 2 books for Rs. 300.05 each. How much money left with her?
1 Rs. 4255
2 Rs. 4750
3 Rs. 4000
4 Rs. 3875
Explanation:
Rs. 4255 Total expenditure = Rs.((2 × 52.98) + (3 × 12.98) + (2 × 300.5)) = Rs.(105.96 + 38.94 + 600.10) = Rs. 745 Amount of money left with her = Rs. (5000 - 745) = Rs. 4255
04. DECIMALS
290847
What is the sum of 11.006 + 34 + 0.72 rounded to the nearest tenths?
1 45.1
2 45.7
3 45.73
4 46
Explanation:
45.1 B 45.7 The sum of 11.006 + 34 + 0.72 is 45.726 Now, the number 45.726 is rounded off as 45.73. Again it is rounded to nearest tenths as 45.7.
290844
The recurring decimal \(1.\overline{263}...\) in a fraction form is equal to.
1 \(\frac{1262}{90}\)
2 \(\frac{1262}{99}\)
3 \(\frac{1262}{999}\)
4 \(\text{None of these}\)
Explanation:
\(\frac{1262}{99}\) C \(\frac{1262}{999}\) Let x = 1.263263263 [we multiply it by 1000] Here 3 digits are repeated 1000x = 1263.263263.... x = 1.263263... 999x = 1262 \(\Rightarrow\text{x}=\frac{1262}{999}\) The recurring decimal 1.263 in a fraction form is equal to \(\frac{1262}{999}\)
04. DECIMALS
290845
Directions: In the following questions, the Assertions (A) and Reason(s) (R) have been put forward. Read both the statements carefully and choose the correct alternative from the following: Assertion (A): 100rs = 100000 paise. Reason (R): 1 Rs= 100 paise.
1 Both A and R are true and R is the correct explanation of A.
2 Both A and R are true but R is not the correct explanation of A.
3 A is true but R is false.
4 A is false but R is true.
Explanation:
A is false but R is true.
04. DECIMALS
290846
Prerna has Rs. 5000. She bought 2 boxes of chocolates for Rs. 52.98 each, 3 packets of chips for Rs. 12.98 each and 2 books for Rs. 300.05 each. How much money left with her?
1 Rs. 4255
2 Rs. 4750
3 Rs. 4000
4 Rs. 3875
Explanation:
Rs. 4255 Total expenditure = Rs.((2 × 52.98) + (3 × 12.98) + (2 × 300.5)) = Rs.(105.96 + 38.94 + 600.10) = Rs. 745 Amount of money left with her = Rs. (5000 - 745) = Rs. 4255
04. DECIMALS
290847
What is the sum of 11.006 + 34 + 0.72 rounded to the nearest tenths?
1 45.1
2 45.7
3 45.73
4 46
Explanation:
45.1 B 45.7 The sum of 11.006 + 34 + 0.72 is 45.726 Now, the number 45.726 is rounded off as 45.73. Again it is rounded to nearest tenths as 45.7.
