290157
Perimeter of a regular octagon of side 6cm is 36cm:
1 True
2 False
Explanation:
False We know that, There are 8 equal sides in a regular hexagon \(\therefore\) Perimeter of hexagon = 8 × ( length of sides ) = 8 × 6cm = 48cm.
09. MENSURATION
290158
The length and breadth of a rectangle are in the ratio 4 : 3 If the diagonal measures 25cm then the perimeter of the rectangle is:
1 56cm
2 60cm
3 70cm
4 80cm
Explanation:
70cm
09. MENSURATION
290159
The width of a rectangular room is \( \frac{4}{7}\) of its length, x, and its perimeter is y. Write an equation connecting x and y. Find the length of the room when the perimeter is 4400cm.
290160
The cost of ploughing a field at Rs. 9 per square metre is Rs. 1872. If the breadth of the field is 13m, then its length is.............
1 8m
2 16m
3 39m
4 3m
Explanation:
16m Total cost = Rs.1872 Cost of ploughing 1sq. m = Rs. 9 \(\therefore\) Area of field = 1872 ÷ 9 = 208sq. m. Length × Breadth = 208sq. m. Length × 13m = 208sq. m. Length = 208 ÷ 13 = 16m.
09. MENSURATION
290211
The length of diagonal of a square is. \({5}\sqrt{2}\) Then its perimeter is .......
1 5
2 50
3 20
4 100
Explanation:
20 Let the side be a a\(^{1}\)+ a\(^{1}\)\(^{1}\) 2a\(^{1}\)= 50 a\(^{1}\)= 25 a = 5 Perimeter = 4a = 4 × 5 = 20
290157
Perimeter of a regular octagon of side 6cm is 36cm:
1 True
2 False
Explanation:
False We know that, There are 8 equal sides in a regular hexagon \(\therefore\) Perimeter of hexagon = 8 × ( length of sides ) = 8 × 6cm = 48cm.
09. MENSURATION
290158
The length and breadth of a rectangle are in the ratio 4 : 3 If the diagonal measures 25cm then the perimeter of the rectangle is:
1 56cm
2 60cm
3 70cm
4 80cm
Explanation:
70cm
09. MENSURATION
290159
The width of a rectangular room is \( \frac{4}{7}\) of its length, x, and its perimeter is y. Write an equation connecting x and y. Find the length of the room when the perimeter is 4400cm.
290160
The cost of ploughing a field at Rs. 9 per square metre is Rs. 1872. If the breadth of the field is 13m, then its length is.............
1 8m
2 16m
3 39m
4 3m
Explanation:
16m Total cost = Rs.1872 Cost of ploughing 1sq. m = Rs. 9 \(\therefore\) Area of field = 1872 ÷ 9 = 208sq. m. Length × Breadth = 208sq. m. Length × 13m = 208sq. m. Length = 208 ÷ 13 = 16m.
09. MENSURATION
290211
The length of diagonal of a square is. \({5}\sqrt{2}\) Then its perimeter is .......
1 5
2 50
3 20
4 100
Explanation:
20 Let the side be a a\(^{1}\)+ a\(^{1}\)\(^{1}\) 2a\(^{1}\)= 50 a\(^{1}\)= 25 a = 5 Perimeter = 4a = 4 × 5 = 20
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
09. MENSURATION
290157
Perimeter of a regular octagon of side 6cm is 36cm:
1 True
2 False
Explanation:
False We know that, There are 8 equal sides in a regular hexagon \(\therefore\) Perimeter of hexagon = 8 × ( length of sides ) = 8 × 6cm = 48cm.
09. MENSURATION
290158
The length and breadth of a rectangle are in the ratio 4 : 3 If the diagonal measures 25cm then the perimeter of the rectangle is:
1 56cm
2 60cm
3 70cm
4 80cm
Explanation:
70cm
09. MENSURATION
290159
The width of a rectangular room is \( \frac{4}{7}\) of its length, x, and its perimeter is y. Write an equation connecting x and y. Find the length of the room when the perimeter is 4400cm.
290160
The cost of ploughing a field at Rs. 9 per square metre is Rs. 1872. If the breadth of the field is 13m, then its length is.............
1 8m
2 16m
3 39m
4 3m
Explanation:
16m Total cost = Rs.1872 Cost of ploughing 1sq. m = Rs. 9 \(\therefore\) Area of field = 1872 ÷ 9 = 208sq. m. Length × Breadth = 208sq. m. Length × 13m = 208sq. m. Length = 208 ÷ 13 = 16m.
09. MENSURATION
290211
The length of diagonal of a square is. \({5}\sqrt{2}\) Then its perimeter is .......
1 5
2 50
3 20
4 100
Explanation:
20 Let the side be a a\(^{1}\)+ a\(^{1}\)\(^{1}\) 2a\(^{1}\)= 50 a\(^{1}\)= 25 a = 5 Perimeter = 4a = 4 × 5 = 20
290157
Perimeter of a regular octagon of side 6cm is 36cm:
1 True
2 False
Explanation:
False We know that, There are 8 equal sides in a regular hexagon \(\therefore\) Perimeter of hexagon = 8 × ( length of sides ) = 8 × 6cm = 48cm.
09. MENSURATION
290158
The length and breadth of a rectangle are in the ratio 4 : 3 If the diagonal measures 25cm then the perimeter of the rectangle is:
1 56cm
2 60cm
3 70cm
4 80cm
Explanation:
70cm
09. MENSURATION
290159
The width of a rectangular room is \( \frac{4}{7}\) of its length, x, and its perimeter is y. Write an equation connecting x and y. Find the length of the room when the perimeter is 4400cm.
290160
The cost of ploughing a field at Rs. 9 per square metre is Rs. 1872. If the breadth of the field is 13m, then its length is.............
1 8m
2 16m
3 39m
4 3m
Explanation:
16m Total cost = Rs.1872 Cost of ploughing 1sq. m = Rs. 9 \(\therefore\) Area of field = 1872 ÷ 9 = 208sq. m. Length × Breadth = 208sq. m. Length × 13m = 208sq. m. Length = 208 ÷ 13 = 16m.
09. MENSURATION
290211
The length of diagonal of a square is. \({5}\sqrt{2}\) Then its perimeter is .......
1 5
2 50
3 20
4 100
Explanation:
20 Let the side be a a\(^{1}\)+ a\(^{1}\)\(^{1}\) 2a\(^{1}\)= 50 a\(^{1}\)= 25 a = 5 Perimeter = 4a = 4 × 5 = 20
290157
Perimeter of a regular octagon of side 6cm is 36cm:
1 True
2 False
Explanation:
False We know that, There are 8 equal sides in a regular hexagon \(\therefore\) Perimeter of hexagon = 8 × ( length of sides ) = 8 × 6cm = 48cm.
09. MENSURATION
290158
The length and breadth of a rectangle are in the ratio 4 : 3 If the diagonal measures 25cm then the perimeter of the rectangle is:
1 56cm
2 60cm
3 70cm
4 80cm
Explanation:
70cm
09. MENSURATION
290159
The width of a rectangular room is \( \frac{4}{7}\) of its length, x, and its perimeter is y. Write an equation connecting x and y. Find the length of the room when the perimeter is 4400cm.
290160
The cost of ploughing a field at Rs. 9 per square metre is Rs. 1872. If the breadth of the field is 13m, then its length is.............
1 8m
2 16m
3 39m
4 3m
Explanation:
16m Total cost = Rs.1872 Cost of ploughing 1sq. m = Rs. 9 \(\therefore\) Area of field = 1872 ÷ 9 = 208sq. m. Length × Breadth = 208sq. m. Length × 13m = 208sq. m. Length = 208 ÷ 13 = 16m.
09. MENSURATION
290211
The length of diagonal of a square is. \({5}\sqrt{2}\) Then its perimeter is .......
1 5
2 50
3 20
4 100
Explanation:
20 Let the side be a a\(^{1}\)+ a\(^{1}\)\(^{1}\) 2a\(^{1}\)= 50 a\(^{1}\)= 25 a = 5 Perimeter = 4a = 4 × 5 = 20