QBManager

09. MENSURATION

290103 A pentagonal prism has 15 edges. how many vertices does it have?

1 12

2 10

3 15

4 20

09. MENSURATION

290087 The perimeter of a right angled triangle is 60m and its hypotenuse is 26cm then the area of the triangle is:

1 120cm

^{1}

2 121cm

^{1}

3 119cm

^{1}

4 125cm

^{1}

Explanation:

120cm $^{1}$
Given the perimeter of the right - angle triangle is 60m and the hypotenuse is 26cm
Let the base and height of the right - angle triangle is a and b cm
Then a $^{1}$ + b $^{1}$ = (26) $^{1}$
$^{1}$ $∴ a + b + a^{2} + b^{2} = 60$
a + b + 26 = 60
a + b = 60 - 26
a + b = 34
$∴$ (a + b) $^{1}$ = (34) $^{1}$
a $^{1}$ + b $^{1}$ + 2ab = 1156
2ab = 1156 - (26) $^{1}$ = 1156 - 676 = 480
ab = 240

09. MENSURATION

290088 If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of the field is 24m, then the breadth of the field is:

1 8m

2 18m

3 24m

4 16m

Explanation:

16m
Cost of fencing the rectangular field = Rs. 600
Rate of fencing the field = Rs. 7.50/m
Therefore, perimeter of the field $= \frac{Cost of fencing}{Rate of fencing}$
$= \frac{600}{7.50} = 80 m$
Now, length of the field = 24m
Therefore, breadth of the field $= \frac{Perimeter}{2} - Length$
$= \frac{80}{2} - 24 = 16 m$

09. MENSURATION

290089 The Width W of a rectangle is 2 inches less than half its length L. Express the perimeter P of the rectangle in terms of the length L:

1 3L − 4

2 4L − 4

3 4L

4 3L − 2

Explanation:

3L − 4
As per the given information, $W = \frac{L}{2} - 2$
The Perimeter of the rectangle in terms of $L = 2 (\frac{L}{2} - 2 + L)$
= L - 4 + 2L
= 3L - 4

09. MENSURATION

290090 The area of a square field is 7744sq. meter. Find its perimeter:

1 84m

2 176m

3 352m

4 44m

Explanation:

352m
We know that the area of square is a $^{1}$
7744 = a $^{1}$
$^{1}$
a = 88m
We know that perimeter of square is 4a
$∴$ perimeter = 4 × 88 = 352m

09. MENSURATION

290103 A pentagonal prism has 15 edges. how many vertices does it have?

1 12

2 10

3 15

4 20

09. MENSURATION

290087 The perimeter of a right angled triangle is 60m and its hypotenuse is 26cm then the area of the triangle is:

1 120cm

^{1}

2 121cm

^{1}

3 119cm

^{1}

4 125cm

^{1}

Explanation:

120cm $^{1}$
Given the perimeter of the right - angle triangle is 60m and the hypotenuse is 26cm
Let the base and height of the right - angle triangle is a and b cm
Then a $^{1}$ + b $^{1}$ = (26) $^{1}$
$^{1}$ $∴ a + b + a^{2} + b^{2} = 60$
a + b + 26 = 60
a + b = 60 - 26
a + b = 34
$∴$ (a + b) $^{1}$ = (34) $^{1}$
a $^{1}$ + b $^{1}$ + 2ab = 1156
2ab = 1156 - (26) $^{1}$ = 1156 - 676 = 480
ab = 240

09. MENSURATION

290088 If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of the field is 24m, then the breadth of the field is:

1 8m

2 18m

3 24m

4 16m

Explanation:

16m
Cost of fencing the rectangular field = Rs. 600
Rate of fencing the field = Rs. 7.50/m
Therefore, perimeter of the field $= \frac{Cost of fencing}{Rate of fencing}$
$= \frac{600}{7.50} = 80 m$
Now, length of the field = 24m
Therefore, breadth of the field $= \frac{Perimeter}{2} - Length$
$= \frac{80}{2} - 24 = 16 m$

09. MENSURATION

290089 The Width W of a rectangle is 2 inches less than half its length L. Express the perimeter P of the rectangle in terms of the length L:

1 3L − 4

2 4L − 4

3 4L

4 3L − 2

Explanation:

3L − 4
As per the given information, $W = \frac{L}{2} - 2$
The Perimeter of the rectangle in terms of $L = 2 (\frac{L}{2} - 2 + L)$
= L - 4 + 2L
= 3L - 4

09. MENSURATION

290090 The area of a square field is 7744sq. meter. Find its perimeter:

1 84m

2 176m

3 352m

4 44m

Explanation:

352m
We know that the area of square is a $^{1}$
7744 = a $^{1}$
$^{1}$
a = 88m
We know that perimeter of square is 4a
$∴$ perimeter = 4 × 88 = 352m

09. MENSURATION

290103 A pentagonal prism has 15 edges. how many vertices does it have?

1 12

2 10

3 15

4 20

09. MENSURATION

290087 The perimeter of a right angled triangle is 60m and its hypotenuse is 26cm then the area of the triangle is:

1 120cm

^{1}

2 121cm

^{1}

3 119cm

^{1}

4 125cm

^{1}

Explanation:

120cm $^{1}$
Given the perimeter of the right - angle triangle is 60m and the hypotenuse is 26cm
Let the base and height of the right - angle triangle is a and b cm
Then a $^{1}$ + b $^{1}$ = (26) $^{1}$
$^{1}$ $∴ a + b + a^{2} + b^{2} = 60$
a + b + 26 = 60
a + b = 60 - 26
a + b = 34
$∴$ (a + b) $^{1}$ = (34) $^{1}$
a $^{1}$ + b $^{1}$ + 2ab = 1156
2ab = 1156 - (26) $^{1}$ = 1156 - 676 = 480
ab = 240

09. MENSURATION

290088 If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of the field is 24m, then the breadth of the field is:

1 8m

2 18m

3 24m

4 16m

Explanation:

16m
Cost of fencing the rectangular field = Rs. 600
Rate of fencing the field = Rs. 7.50/m
Therefore, perimeter of the field $= \frac{Cost of fencing}{Rate of fencing}$
$= \frac{600}{7.50} = 80 m$
Now, length of the field = 24m
Therefore, breadth of the field $= \frac{Perimeter}{2} - Length$
$= \frac{80}{2} - 24 = 16 m$

09. MENSURATION

290089 The Width W of a rectangle is 2 inches less than half its length L. Express the perimeter P of the rectangle in terms of the length L:

1 3L − 4

2 4L − 4

3 4L

4 3L − 2

Explanation:

3L − 4
As per the given information, $W = \frac{L}{2} - 2$
The Perimeter of the rectangle in terms of $L = 2 (\frac{L}{2} - 2 + L)$
= L - 4 + 2L
= 3L - 4

09. MENSURATION

290090 The area of a square field is 7744sq. meter. Find its perimeter:

1 84m

2 176m

3 352m

4 44m

Explanation:

352m
We know that the area of square is a $^{1}$
7744 = a $^{1}$
$^{1}$
a = 88m
We know that perimeter of square is 4a
$∴$ perimeter = 4 × 88 = 352m

09. MENSURATION

290103 A pentagonal prism has 15 edges. how many vertices does it have?

1 12

2 10

3 15

4 20

09. MENSURATION

290087 The perimeter of a right angled triangle is 60m and its hypotenuse is 26cm then the area of the triangle is:

1 120cm

^{1}

2 121cm

^{1}

3 119cm

^{1}

4 125cm

^{1}

Explanation:

120cm $^{1}$
Given the perimeter of the right - angle triangle is 60m and the hypotenuse is 26cm
Let the base and height of the right - angle triangle is a and b cm
Then a $^{1}$ + b $^{1}$ = (26) $^{1}$
$^{1}$ $∴ a + b + a^{2} + b^{2} = 60$
a + b + 26 = 60
a + b = 60 - 26
a + b = 34
$∴$ (a + b) $^{1}$ = (34) $^{1}$
a $^{1}$ + b $^{1}$ + 2ab = 1156
2ab = 1156 - (26) $^{1}$ = 1156 - 676 = 480
ab = 240

09. MENSURATION

290088 If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of the field is 24m, then the breadth of the field is:

1 8m

2 18m

3 24m

4 16m

Explanation:

16m
Cost of fencing the rectangular field = Rs. 600
Rate of fencing the field = Rs. 7.50/m
Therefore, perimeter of the field $= \frac{Cost of fencing}{Rate of fencing}$
$= \frac{600}{7.50} = 80 m$
Now, length of the field = 24m
Therefore, breadth of the field $= \frac{Perimeter}{2} - Length$
$= \frac{80}{2} - 24 = 16 m$

09. MENSURATION

290089 The Width W of a rectangle is 2 inches less than half its length L. Express the perimeter P of the rectangle in terms of the length L:

1 3L − 4

2 4L − 4

3 4L

4 3L − 2

Explanation:

3L − 4
As per the given information, $W = \frac{L}{2} - 2$
The Perimeter of the rectangle in terms of $L = 2 (\frac{L}{2} - 2 + L)$
= L - 4 + 2L
= 3L - 4

09. MENSURATION

290090 The area of a square field is 7744sq. meter. Find its perimeter:

1 84m

2 176m

3 352m

4 44m

Explanation:

352m
We know that the area of square is a $^{1}$
7744 = a $^{1}$
$^{1}$
a = 88m
We know that perimeter of square is 4a
$∴$ perimeter = 4 × 88 = 352m

09. MENSURATION

290103 A pentagonal prism has 15 edges. how many vertices does it have?

1 12

2 10

3 15

4 20

09. MENSURATION

290087 The perimeter of a right angled triangle is 60m and its hypotenuse is 26cm then the area of the triangle is:

1 120cm

^{1}

2 121cm

^{1}

3 119cm

^{1}

4 125cm

^{1}

Explanation:

120cm $^{1}$
Given the perimeter of the right - angle triangle is 60m and the hypotenuse is 26cm
Let the base and height of the right - angle triangle is a and b cm
Then a $^{1}$ + b $^{1}$ = (26) $^{1}$
$^{1}$ $∴ a + b + a^{2} + b^{2} = 60$
a + b + 26 = 60
a + b = 60 - 26
a + b = 34
$∴$ (a + b) $^{1}$ = (34) $^{1}$
a $^{1}$ + b $^{1}$ + 2ab = 1156
2ab = 1156 - (26) $^{1}$ = 1156 - 676 = 480
ab = 240

09. MENSURATION

290088 If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of the field is 24m, then the breadth of the field is:

1 8m

2 18m

3 24m

4 16m

Explanation:

16m
Cost of fencing the rectangular field = Rs. 600
Rate of fencing the field = Rs. 7.50/m
Therefore, perimeter of the field $= \frac{Cost of fencing}{Rate of fencing}$
$= \frac{600}{7.50} = 80 m$
Now, length of the field = 24m
Therefore, breadth of the field $= \frac{Perimeter}{2} - Length$
$= \frac{80}{2} - 24 = 16 m$

09. MENSURATION

290089 The Width W of a rectangle is 2 inches less than half its length L. Express the perimeter P of the rectangle in terms of the length L:

1 3L − 4

2 4L − 4

3 4L

4 3L − 2

Explanation:

3L − 4
As per the given information, $W = \frac{L}{2} - 2$
The Perimeter of the rectangle in terms of $L = 2 (\frac{L}{2} - 2 + L)$
= L - 4 + 2L
= 3L - 4

09. MENSURATION

290090 The area of a square field is 7744sq. meter. Find its perimeter:

1 84m

2 176m

3 352m

4 44m

Explanation:

352m
We know that the area of square is a $^{1}$
7744 = a $^{1}$
$^{1}$
a = 88m
We know that perimeter of square is 4a
$∴$ perimeter = 4 × 88 = 352m