290103
A pentagonal prism has 15 edges. how many vertices does it have?
1 12
2 10
3 15
4 20
Explanation:
10 A pentagonal prism has 15 edges. Vertices = 5 + 5 = 10
09. MENSURATION
290087
The perimeter of a right angled triangle is 60m and its hypotenuse is 26cm then the area of the triangle is:
1 120cm\(^{1}\)
2 121cm\(^{1}\)
3 119cm\(^{1}\)
4 125cm\(^{1}\)
Explanation:
120cm\(^{1}\) Given the perimeter of the right - angle triangle is 60m and the hypotenuse is 26cm Let the base and height of the right - angle triangle is a and b cm Then a\(^{1}\)+ b\(^{1}\) = (26)\(^{1}\) \(^{1}\)\(\therefore\text{a + b} + \text{a}^{2} + \text{b}^{2}={60}\) a + b + 26 = 60 a + b = 60 - 26 a + b = 34 \(\therefore\) (a + b)\(^{1}\)= (34)\(^{1}\) a\(^{1}\) + b\(^{1}\) + 2ab = 1156 2ab = 1156 - (26)\(^{1}\) = 1156 - 676 = 480 ab = 240
09. MENSURATION
290088
If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of the field is 24m, then the breadth of the field is:
1 8m
2 18m
3 24m
4 16m
Explanation:
16m Cost of fencing the rectangular field = Rs. 600 Rate of fencing the field = Rs. 7.50/m Therefore, perimeter of the field \(=\frac{\text{Cost of fencing}}{\text{Rate of fencing}}\) \(=\frac{600}{7.50}=80\text{m}\) Now, length of the field = 24m Therefore, breadth of the field \(=\frac{\text{Perimeter}}{2}-\text{Length}\) \(=\frac{80}{2}-24=16\text{m}\)
09. MENSURATION
290089
The Width W of a rectangle is 2 inches less than half its length L. Express the perimeter P of the rectangle in terms of the length L:
1 3L − 4
2 4L − 4
3 4L
4 3L − 2
Explanation:
3L − 4 As per the given information, \(\text{W} = \frac{\text{L}}{2} - {2}\) The Perimeter of the rectangle in terms of \(\text{L} = {2}\big(\frac{\text{L}}{2} - {2} + \text{L}\big)\) = L - 4 + 2L = 3L - 4
09. MENSURATION
290090
The area of a square field is 7744sq. meter. Find its perimeter:
1 84m
2 176m
3 352m
4 44m
Explanation:
352m We know that the area of square is a\(^{1}\) 7744 = a\(^{1}\) \(^{1}\) a = 88m We know that perimeter of square is 4a \(\therefore\) perimeter = 4 × 88 = 352m
290103
A pentagonal prism has 15 edges. how many vertices does it have?
1 12
2 10
3 15
4 20
Explanation:
10 A pentagonal prism has 15 edges. Vertices = 5 + 5 = 10
09. MENSURATION
290087
The perimeter of a right angled triangle is 60m and its hypotenuse is 26cm then the area of the triangle is:
1 120cm\(^{1}\)
2 121cm\(^{1}\)
3 119cm\(^{1}\)
4 125cm\(^{1}\)
Explanation:
120cm\(^{1}\) Given the perimeter of the right - angle triangle is 60m and the hypotenuse is 26cm Let the base and height of the right - angle triangle is a and b cm Then a\(^{1}\)+ b\(^{1}\) = (26)\(^{1}\) \(^{1}\)\(\therefore\text{a + b} + \text{a}^{2} + \text{b}^{2}={60}\) a + b + 26 = 60 a + b = 60 - 26 a + b = 34 \(\therefore\) (a + b)\(^{1}\)= (34)\(^{1}\) a\(^{1}\) + b\(^{1}\) + 2ab = 1156 2ab = 1156 - (26)\(^{1}\) = 1156 - 676 = 480 ab = 240
09. MENSURATION
290088
If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of the field is 24m, then the breadth of the field is:
1 8m
2 18m
3 24m
4 16m
Explanation:
16m Cost of fencing the rectangular field = Rs. 600 Rate of fencing the field = Rs. 7.50/m Therefore, perimeter of the field \(=\frac{\text{Cost of fencing}}{\text{Rate of fencing}}\) \(=\frac{600}{7.50}=80\text{m}\) Now, length of the field = 24m Therefore, breadth of the field \(=\frac{\text{Perimeter}}{2}-\text{Length}\) \(=\frac{80}{2}-24=16\text{m}\)
09. MENSURATION
290089
The Width W of a rectangle is 2 inches less than half its length L. Express the perimeter P of the rectangle in terms of the length L:
1 3L − 4
2 4L − 4
3 4L
4 3L − 2
Explanation:
3L − 4 As per the given information, \(\text{W} = \frac{\text{L}}{2} - {2}\) The Perimeter of the rectangle in terms of \(\text{L} = {2}\big(\frac{\text{L}}{2} - {2} + \text{L}\big)\) = L - 4 + 2L = 3L - 4
09. MENSURATION
290090
The area of a square field is 7744sq. meter. Find its perimeter:
1 84m
2 176m
3 352m
4 44m
Explanation:
352m We know that the area of square is a\(^{1}\) 7744 = a\(^{1}\) \(^{1}\) a = 88m We know that perimeter of square is 4a \(\therefore\) perimeter = 4 × 88 = 352m
290103
A pentagonal prism has 15 edges. how many vertices does it have?
1 12
2 10
3 15
4 20
Explanation:
10 A pentagonal prism has 15 edges. Vertices = 5 + 5 = 10
09. MENSURATION
290087
The perimeter of a right angled triangle is 60m and its hypotenuse is 26cm then the area of the triangle is:
1 120cm\(^{1}\)
2 121cm\(^{1}\)
3 119cm\(^{1}\)
4 125cm\(^{1}\)
Explanation:
120cm\(^{1}\) Given the perimeter of the right - angle triangle is 60m and the hypotenuse is 26cm Let the base and height of the right - angle triangle is a and b cm Then a\(^{1}\)+ b\(^{1}\) = (26)\(^{1}\) \(^{1}\)\(\therefore\text{a + b} + \text{a}^{2} + \text{b}^{2}={60}\) a + b + 26 = 60 a + b = 60 - 26 a + b = 34 \(\therefore\) (a + b)\(^{1}\)= (34)\(^{1}\) a\(^{1}\) + b\(^{1}\) + 2ab = 1156 2ab = 1156 - (26)\(^{1}\) = 1156 - 676 = 480 ab = 240
09. MENSURATION
290088
If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of the field is 24m, then the breadth of the field is:
1 8m
2 18m
3 24m
4 16m
Explanation:
16m Cost of fencing the rectangular field = Rs. 600 Rate of fencing the field = Rs. 7.50/m Therefore, perimeter of the field \(=\frac{\text{Cost of fencing}}{\text{Rate of fencing}}\) \(=\frac{600}{7.50}=80\text{m}\) Now, length of the field = 24m Therefore, breadth of the field \(=\frac{\text{Perimeter}}{2}-\text{Length}\) \(=\frac{80}{2}-24=16\text{m}\)
09. MENSURATION
290089
The Width W of a rectangle is 2 inches less than half its length L. Express the perimeter P of the rectangle in terms of the length L:
1 3L − 4
2 4L − 4
3 4L
4 3L − 2
Explanation:
3L − 4 As per the given information, \(\text{W} = \frac{\text{L}}{2} - {2}\) The Perimeter of the rectangle in terms of \(\text{L} = {2}\big(\frac{\text{L}}{2} - {2} + \text{L}\big)\) = L - 4 + 2L = 3L - 4
09. MENSURATION
290090
The area of a square field is 7744sq. meter. Find its perimeter:
1 84m
2 176m
3 352m
4 44m
Explanation:
352m We know that the area of square is a\(^{1}\) 7744 = a\(^{1}\) \(^{1}\) a = 88m We know that perimeter of square is 4a \(\therefore\) perimeter = 4 × 88 = 352m
NEET Test Series from KOTA - 10 Papers In MS WORD
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09. MENSURATION
290103
A pentagonal prism has 15 edges. how many vertices does it have?
1 12
2 10
3 15
4 20
Explanation:
10 A pentagonal prism has 15 edges. Vertices = 5 + 5 = 10
09. MENSURATION
290087
The perimeter of a right angled triangle is 60m and its hypotenuse is 26cm then the area of the triangle is:
1 120cm\(^{1}\)
2 121cm\(^{1}\)
3 119cm\(^{1}\)
4 125cm\(^{1}\)
Explanation:
120cm\(^{1}\) Given the perimeter of the right - angle triangle is 60m and the hypotenuse is 26cm Let the base and height of the right - angle triangle is a and b cm Then a\(^{1}\)+ b\(^{1}\) = (26)\(^{1}\) \(^{1}\)\(\therefore\text{a + b} + \text{a}^{2} + \text{b}^{2}={60}\) a + b + 26 = 60 a + b = 60 - 26 a + b = 34 \(\therefore\) (a + b)\(^{1}\)= (34)\(^{1}\) a\(^{1}\) + b\(^{1}\) + 2ab = 1156 2ab = 1156 - (26)\(^{1}\) = 1156 - 676 = 480 ab = 240
09. MENSURATION
290088
If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of the field is 24m, then the breadth of the field is:
1 8m
2 18m
3 24m
4 16m
Explanation:
16m Cost of fencing the rectangular field = Rs. 600 Rate of fencing the field = Rs. 7.50/m Therefore, perimeter of the field \(=\frac{\text{Cost of fencing}}{\text{Rate of fencing}}\) \(=\frac{600}{7.50}=80\text{m}\) Now, length of the field = 24m Therefore, breadth of the field \(=\frac{\text{Perimeter}}{2}-\text{Length}\) \(=\frac{80}{2}-24=16\text{m}\)
09. MENSURATION
290089
The Width W of a rectangle is 2 inches less than half its length L. Express the perimeter P of the rectangle in terms of the length L:
1 3L − 4
2 4L − 4
3 4L
4 3L − 2
Explanation:
3L − 4 As per the given information, \(\text{W} = \frac{\text{L}}{2} - {2}\) The Perimeter of the rectangle in terms of \(\text{L} = {2}\big(\frac{\text{L}}{2} - {2} + \text{L}\big)\) = L - 4 + 2L = 3L - 4
09. MENSURATION
290090
The area of a square field is 7744sq. meter. Find its perimeter:
1 84m
2 176m
3 352m
4 44m
Explanation:
352m We know that the area of square is a\(^{1}\) 7744 = a\(^{1}\) \(^{1}\) a = 88m We know that perimeter of square is 4a \(\therefore\) perimeter = 4 × 88 = 352m
290103
A pentagonal prism has 15 edges. how many vertices does it have?
1 12
2 10
3 15
4 20
Explanation:
10 A pentagonal prism has 15 edges. Vertices = 5 + 5 = 10
09. MENSURATION
290087
The perimeter of a right angled triangle is 60m and its hypotenuse is 26cm then the area of the triangle is:
1 120cm\(^{1}\)
2 121cm\(^{1}\)
3 119cm\(^{1}\)
4 125cm\(^{1}\)
Explanation:
120cm\(^{1}\) Given the perimeter of the right - angle triangle is 60m and the hypotenuse is 26cm Let the base and height of the right - angle triangle is a and b cm Then a\(^{1}\)+ b\(^{1}\) = (26)\(^{1}\) \(^{1}\)\(\therefore\text{a + b} + \text{a}^{2} + \text{b}^{2}={60}\) a + b + 26 = 60 a + b = 60 - 26 a + b = 34 \(\therefore\) (a + b)\(^{1}\)= (34)\(^{1}\) a\(^{1}\) + b\(^{1}\) + 2ab = 1156 2ab = 1156 - (26)\(^{1}\) = 1156 - 676 = 480 ab = 240
09. MENSURATION
290088
If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of the field is 24m, then the breadth of the field is:
1 8m
2 18m
3 24m
4 16m
Explanation:
16m Cost of fencing the rectangular field = Rs. 600 Rate of fencing the field = Rs. 7.50/m Therefore, perimeter of the field \(=\frac{\text{Cost of fencing}}{\text{Rate of fencing}}\) \(=\frac{600}{7.50}=80\text{m}\) Now, length of the field = 24m Therefore, breadth of the field \(=\frac{\text{Perimeter}}{2}-\text{Length}\) \(=\frac{80}{2}-24=16\text{m}\)
09. MENSURATION
290089
The Width W of a rectangle is 2 inches less than half its length L. Express the perimeter P of the rectangle in terms of the length L:
1 3L − 4
2 4L − 4
3 4L
4 3L − 2
Explanation:
3L − 4 As per the given information, \(\text{W} = \frac{\text{L}}{2} - {2}\) The Perimeter of the rectangle in terms of \(\text{L} = {2}\big(\frac{\text{L}}{2} - {2} + \text{L}\big)\) = L - 4 + 2L = 3L - 4
09. MENSURATION
290090
The area of a square field is 7744sq. meter. Find its perimeter:
1 84m
2 176m
3 352m
4 44m
Explanation:
352m We know that the area of square is a\(^{1}\) 7744 = a\(^{1}\) \(^{1}\) a = 88m We know that perimeter of square is 4a \(\therefore\) perimeter = 4 × 88 = 352m