QBManager

BIOMOLECULES (NEET PYQS)

287123 RNA and DNA are chiral molecules, their chirality is due to

1 chiral bases

2 chiral phosphate ester units

3 D-sugar component

4 L-sugar component.

Explanation:

(c) Each nucleic acid consists of a pentose sugar a heterocyclic base, and phosphoric acid. The sugar present in DNA is -D (-) -2-deoxy ribose and the sugar present in RNA is D $(-)$ - ribose. The chirality of DNA and RNA molecules are due to the presence of sugar components.

NEET 2007

BIOMOLECULES (NEET PYQS)

287124 A sequence of how many nucleotides in messenger RNA makes a codon for an amino acid?

1 Three

2 Four

3 One

4 Two

Explanation:

(a) The sequence of bases in mRNA are read in a serial order in groups of three at a time. Each triplet of nucleotides (having a specific sequence of bases) is known as codon. Each codon specifies one amino acid.
There are four bases A, G, C,T, therefore, $4^{3} = 64$ triplets or codons are possible.

NEET 2004

BIOMOLECULES (NEET PYQS)

287125 Which of the following is correct about H -bonding in nucleotide?

1

A - - A

and

T - - T

2 G --- T and A --- C

3

A - -

G and

T - - C

4 A --- T and G --. C

Explanation:

(di) The hydrogen bonds are formed between the base. Because of size and geometrics of the bases, the only possible pairing in DNA are between $G$ (Guanine) and $C$ (Cytosine) through
three H -bonds and between A (Adenosine) and T (Thymine) through two H -bonds.

NCERT | Page-429 / N-299 | 2001

BIOMOLECULES (NEET PYQS)

287123 RNA and DNA are chiral molecules, their chirality is due to

1 chiral bases

2 chiral phosphate ester units

3 D-sugar component

4 L-sugar component.

Explanation:

(c) Each nucleic acid consists of a pentose sugar a heterocyclic base, and phosphoric acid. The sugar present in DNA is -D (-) -2-deoxy ribose and the sugar present in RNA is D $(-)$ - ribose. The chirality of DNA and RNA molecules are due to the presence of sugar components.

NEET 2007

BIOMOLECULES (NEET PYQS)

287124 A sequence of how many nucleotides in messenger RNA makes a codon for an amino acid?

1 Three

2 Four

3 One

4 Two

Explanation:

(a) The sequence of bases in mRNA are read in a serial order in groups of three at a time. Each triplet of nucleotides (having a specific sequence of bases) is known as codon. Each codon specifies one amino acid.
There are four bases A, G, C,T, therefore, $4^{3} = 64$ triplets or codons are possible.

NEET 2004

BIOMOLECULES (NEET PYQS)

287125 Which of the following is correct about H -bonding in nucleotide?

1

A - - A

and

T - - T

2 G --- T and A --- C

3

A - -

G and

T - - C

4 A --- T and G --. C

Explanation:

(di) The hydrogen bonds are formed between the base. Because of size and geometrics of the bases, the only possible pairing in DNA are between $G$ (Guanine) and $C$ (Cytosine) through
three H -bonds and between A (Adenosine) and T (Thymine) through two H -bonds.

NCERT | Page-429 / N-299 | 2001

BIOMOLECULES (NEET PYQS)

287123 RNA and DNA are chiral molecules, their chirality is due to

1 chiral bases

2 chiral phosphate ester units

3 D-sugar component

4 L-sugar component.

Explanation:

(c) Each nucleic acid consists of a pentose sugar a heterocyclic base, and phosphoric acid. The sugar present in DNA is -D (-) -2-deoxy ribose and the sugar present in RNA is D $(-)$ - ribose. The chirality of DNA and RNA molecules are due to the presence of sugar components.

NEET 2007

BIOMOLECULES (NEET PYQS)

287124 A sequence of how many nucleotides in messenger RNA makes a codon for an amino acid?

1 Three

2 Four

3 One

4 Two

Explanation:

(a) The sequence of bases in mRNA are read in a serial order in groups of three at a time. Each triplet of nucleotides (having a specific sequence of bases) is known as codon. Each codon specifies one amino acid.
There are four bases A, G, C,T, therefore, $4^{3} = 64$ triplets or codons are possible.

NEET 2004

BIOMOLECULES (NEET PYQS)

287125 Which of the following is correct about H -bonding in nucleotide?

1

A - - A

and

T - - T

2 G --- T and A --- C

3

A - -

G and

T - - C

4 A --- T and G --. C

Explanation:

(di) The hydrogen bonds are formed between the base. Because of size and geometrics of the bases, the only possible pairing in DNA are between $G$ (Guanine) and $C$ (Cytosine) through
three H -bonds and between A (Adenosine) and T (Thymine) through two H -bonds.

NCERT | Page-429 / N-299 | 2001

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