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BIOMOLECULES (NEET PYQS)

287088 Sucrose in water is dextro-rotatory, $[α]_{D} = +$ ${66.4}^{\circ}$ . When boiled with dilute HCl , the solution becomes leavo-rotatory, $[α]_{D} = - 20^{\circ}$ . In this process, the sucrose molecule breaks into

1 L-glucose + D-fructose

2 L-glucose + L-fructose

3 D-glucose + D-fructose

4 D-glucose + L-fructose

Explanation:

(c) The hydrolysis of sucrose by boiling with mineral acid or by enzyme invertase or sucrase produces a mixture of equal molecules of $D (+)$ glucose and $D (-)$ Fructose.

NCERT| Page-417 / N-287| 1996

BIOMOLECULES (NEET PYQS)

287089 The $α - D$ glucose and $β$ -D glucose differ from each other due to difference in carbon atom with respect to its

1 Conformation

2 Configuration

3 Number of OH groups

4 Size of hemiacetal ring

Explanation:

(b) $α - D$ glucose and $β$ -D glucose are the isomers which differ in the orientation (configuration) of H and OH groups around $C_{1}$ atom.

NCERT | Page-415 / N-285 | 1995

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BIOMOLECULES (NEET PYQS)

1 L-glucose + D-fructose

2 L-glucose + L-fructose

3 D-glucose + D-fructose

4 D-glucose + L-fructose

Explanation:

(c) The hydrolysis of sucrose by boiling with mineral acid or by enzyme invertase or sucrase produces a mixture of equal molecules of $D (+)$ glucose and $D (-)$ Fructose.

NCERT| Page-417 / N-287| 1996

BIOMOLECULES (NEET PYQS)

287089 The $α - D$ glucose and $β$ -D glucose differ from each other due to difference in carbon atom with respect to its

1 Conformation

2 Configuration

3 Number of OH groups

4 Size of hemiacetal ring

Explanation:

(b) $α - D$ glucose and $β$ -D glucose are the isomers which differ in the orientation (configuration) of H and OH groups around $C_{1}$ atom.

NCERT | Page-415 / N-285 | 1995

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