285623
Which of the following is least soluble in water at 298K ?
1 \(\mathrm{CH}_3 \mathrm{NH}_2\)
2 \(\left(\mathrm{CH}_3\right)_3 \mathrm{~N}\)
3 \(\left(\mathrm{CH}_3\right)_2 \mathrm{NH}\)
4 \(\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2\)
Explanation:
(d) Aromatic amines are insoluble in water. This is due to the larger hydrocarbon part which tends to retard the formation of H -bond.
Karnataka CET 2019
CHEMISTRY(KCET)
285624
If aniline is treated with\(1: 1\) mixture of conc. \(\mathrm{HNO}_3\) and conc. \(\mathrm{H}_2 \mathrm{SO}_4, p\)-nitroaniline and \(m\)-nitroaniline are formed nearly in equal amounts. This is due to
1 \(m\)-directing property of \(-\mathrm{NH}_2\) group
2 protonation of \(-\mathrm{NH}_2\) which causes deactivation of benzene ring
3 \(m\) - and \(p\)-directing property of \(-\mathrm{NH}_2\) group
4 isomerization of some \(p\)-nitroaniline into \(m\) nitroaniline.
Explanation:
(b)\(-\mathrm{NH}_2\) group in aniline is \(o\), \(p\)-directing and activating while in presence of acids, most of the aniline gets protonated to form anilinium ion i.e.,-\(\mathrm{N}^{+} \mathrm{H}_3\) which is \(m\)-directing and deactivating.
Karnataka CET 2019
CHEMISTRY(KCET)
285625
The reaction ofbenzenediazonium chloride with aniline yields yellow dye. The name of the yellow dye is
1 p-hydroxyazobenzene
2 \(p\)-aminoazobenzene
3 p-nitroazobenzene
4 \(o\)-nitroazobenzene.
Explanation:
(b)
(
\(p\)-aminoazobenzene
Karnataka CET 2018
CHEMISTRY(KCET)
285626
Which of the following is more basic than aniline?
1 Diphenylamine
2 Triphenylamine
3 \(p\)-Nitroaniline
4 Benzylamine
Explanation:
(d)
Diphenylamine (Electrons delocalised in two rings)
Triphenylamine (Electrons delocalised in three rings)
285623
Which of the following is least soluble in water at 298K ?
1 \(\mathrm{CH}_3 \mathrm{NH}_2\)
2 \(\left(\mathrm{CH}_3\right)_3 \mathrm{~N}\)
3 \(\left(\mathrm{CH}_3\right)_2 \mathrm{NH}\)
4 \(\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2\)
Explanation:
(d) Aromatic amines are insoluble in water. This is due to the larger hydrocarbon part which tends to retard the formation of H -bond.
Karnataka CET 2019
CHEMISTRY(KCET)
285624
If aniline is treated with\(1: 1\) mixture of conc. \(\mathrm{HNO}_3\) and conc. \(\mathrm{H}_2 \mathrm{SO}_4, p\)-nitroaniline and \(m\)-nitroaniline are formed nearly in equal amounts. This is due to
1 \(m\)-directing property of \(-\mathrm{NH}_2\) group
2 protonation of \(-\mathrm{NH}_2\) which causes deactivation of benzene ring
3 \(m\) - and \(p\)-directing property of \(-\mathrm{NH}_2\) group
4 isomerization of some \(p\)-nitroaniline into \(m\) nitroaniline.
Explanation:
(b)\(-\mathrm{NH}_2\) group in aniline is \(o\), \(p\)-directing and activating while in presence of acids, most of the aniline gets protonated to form anilinium ion i.e.,-\(\mathrm{N}^{+} \mathrm{H}_3\) which is \(m\)-directing and deactivating.
Karnataka CET 2019
CHEMISTRY(KCET)
285625
The reaction ofbenzenediazonium chloride with aniline yields yellow dye. The name of the yellow dye is
1 p-hydroxyazobenzene
2 \(p\)-aminoazobenzene
3 p-nitroazobenzene
4 \(o\)-nitroazobenzene.
Explanation:
(b)
(
\(p\)-aminoazobenzene
Karnataka CET 2018
CHEMISTRY(KCET)
285626
Which of the following is more basic than aniline?
1 Diphenylamine
2 Triphenylamine
3 \(p\)-Nitroaniline
4 Benzylamine
Explanation:
(d)
Diphenylamine (Electrons delocalised in two rings)
Triphenylamine (Electrons delocalised in three rings)
285623
Which of the following is least soluble in water at 298K ?
1 \(\mathrm{CH}_3 \mathrm{NH}_2\)
2 \(\left(\mathrm{CH}_3\right)_3 \mathrm{~N}\)
3 \(\left(\mathrm{CH}_3\right)_2 \mathrm{NH}\)
4 \(\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2\)
Explanation:
(d) Aromatic amines are insoluble in water. This is due to the larger hydrocarbon part which tends to retard the formation of H -bond.
Karnataka CET 2019
CHEMISTRY(KCET)
285624
If aniline is treated with\(1: 1\) mixture of conc. \(\mathrm{HNO}_3\) and conc. \(\mathrm{H}_2 \mathrm{SO}_4, p\)-nitroaniline and \(m\)-nitroaniline are formed nearly in equal amounts. This is due to
1 \(m\)-directing property of \(-\mathrm{NH}_2\) group
2 protonation of \(-\mathrm{NH}_2\) which causes deactivation of benzene ring
3 \(m\) - and \(p\)-directing property of \(-\mathrm{NH}_2\) group
4 isomerization of some \(p\)-nitroaniline into \(m\) nitroaniline.
Explanation:
(b)\(-\mathrm{NH}_2\) group in aniline is \(o\), \(p\)-directing and activating while in presence of acids, most of the aniline gets protonated to form anilinium ion i.e.,-\(\mathrm{N}^{+} \mathrm{H}_3\) which is \(m\)-directing and deactivating.
Karnataka CET 2019
CHEMISTRY(KCET)
285625
The reaction ofbenzenediazonium chloride with aniline yields yellow dye. The name of the yellow dye is
1 p-hydroxyazobenzene
2 \(p\)-aminoazobenzene
3 p-nitroazobenzene
4 \(o\)-nitroazobenzene.
Explanation:
(b)
(
\(p\)-aminoazobenzene
Karnataka CET 2018
CHEMISTRY(KCET)
285626
Which of the following is more basic than aniline?
1 Diphenylamine
2 Triphenylamine
3 \(p\)-Nitroaniline
4 Benzylamine
Explanation:
(d)
Diphenylamine (Electrons delocalised in two rings)
Triphenylamine (Electrons delocalised in three rings)
285623
Which of the following is least soluble in water at 298K ?
1 \(\mathrm{CH}_3 \mathrm{NH}_2\)
2 \(\left(\mathrm{CH}_3\right)_3 \mathrm{~N}\)
3 \(\left(\mathrm{CH}_3\right)_2 \mathrm{NH}\)
4 \(\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2\)
Explanation:
(d) Aromatic amines are insoluble in water. This is due to the larger hydrocarbon part which tends to retard the formation of H -bond.
Karnataka CET 2019
CHEMISTRY(KCET)
285624
If aniline is treated with\(1: 1\) mixture of conc. \(\mathrm{HNO}_3\) and conc. \(\mathrm{H}_2 \mathrm{SO}_4, p\)-nitroaniline and \(m\)-nitroaniline are formed nearly in equal amounts. This is due to
1 \(m\)-directing property of \(-\mathrm{NH}_2\) group
2 protonation of \(-\mathrm{NH}_2\) which causes deactivation of benzene ring
3 \(m\) - and \(p\)-directing property of \(-\mathrm{NH}_2\) group
4 isomerization of some \(p\)-nitroaniline into \(m\) nitroaniline.
Explanation:
(b)\(-\mathrm{NH}_2\) group in aniline is \(o\), \(p\)-directing and activating while in presence of acids, most of the aniline gets protonated to form anilinium ion i.e.,-\(\mathrm{N}^{+} \mathrm{H}_3\) which is \(m\)-directing and deactivating.
Karnataka CET 2019
CHEMISTRY(KCET)
285625
The reaction ofbenzenediazonium chloride with aniline yields yellow dye. The name of the yellow dye is
1 p-hydroxyazobenzene
2 \(p\)-aminoazobenzene
3 p-nitroazobenzene
4 \(o\)-nitroazobenzene.
Explanation:
(b)
(
\(p\)-aminoazobenzene
Karnataka CET 2018
CHEMISTRY(KCET)
285626
Which of the following is more basic than aniline?
1 Diphenylamine
2 Triphenylamine
3 \(p\)-Nitroaniline
4 Benzylamine
Explanation:
(d)
Diphenylamine (Electrons delocalised in two rings)
Triphenylamine (Electrons delocalised in three rings)
285623
Which of the following is least soluble in water at 298K ?
1 \(\mathrm{CH}_3 \mathrm{NH}_2\)
2 \(\left(\mathrm{CH}_3\right)_3 \mathrm{~N}\)
3 \(\left(\mathrm{CH}_3\right)_2 \mathrm{NH}\)
4 \(\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2\)
Explanation:
(d) Aromatic amines are insoluble in water. This is due to the larger hydrocarbon part which tends to retard the formation of H -bond.
Karnataka CET 2019
CHEMISTRY(KCET)
285624
If aniline is treated with\(1: 1\) mixture of conc. \(\mathrm{HNO}_3\) and conc. \(\mathrm{H}_2 \mathrm{SO}_4, p\)-nitroaniline and \(m\)-nitroaniline are formed nearly in equal amounts. This is due to
1 \(m\)-directing property of \(-\mathrm{NH}_2\) group
2 protonation of \(-\mathrm{NH}_2\) which causes deactivation of benzene ring
3 \(m\) - and \(p\)-directing property of \(-\mathrm{NH}_2\) group
4 isomerization of some \(p\)-nitroaniline into \(m\) nitroaniline.
Explanation:
(b)\(-\mathrm{NH}_2\) group in aniline is \(o\), \(p\)-directing and activating while in presence of acids, most of the aniline gets protonated to form anilinium ion i.e.,-\(\mathrm{N}^{+} \mathrm{H}_3\) which is \(m\)-directing and deactivating.
Karnataka CET 2019
CHEMISTRY(KCET)
285625
The reaction ofbenzenediazonium chloride with aniline yields yellow dye. The name of the yellow dye is
1 p-hydroxyazobenzene
2 \(p\)-aminoazobenzene
3 p-nitroazobenzene
4 \(o\)-nitroazobenzene.
Explanation:
(b)
(
\(p\)-aminoazobenzene
Karnataka CET 2018
CHEMISTRY(KCET)
285626
Which of the following is more basic than aniline?
1 Diphenylamine
2 Triphenylamine
3 \(p\)-Nitroaniline
4 Benzylamine
Explanation:
(d)
Diphenylamine (Electrons delocalised in two rings)
Triphenylamine (Electrons delocalised in three rings)