285501
\(\left[\mathrm{Fe}\left(\mathrm{NO}_2\right)_3 \mathrm{Cl}_3\right]\) and \(\left[\mathrm{Fe}(\mathrm{O}-\mathrm{NO})_3 \mathrm{Cl}_3\right]\) shows
1 linkage isomerism
2 geometrical isomerism
3 optical isomerism
4 hydrate isomerism.
Explanation:
(a)
Karnataka CET 2018
CHEMISTRY(KCET)
285502
The coordination number and the oxidation state of the element '\(M\) ' in the complex \(\left[M(e n)_2\left(\mathrm{C}_2 \mathrm{O}_4\right)\right] \mathrm{NO}_2\) (where, \(e n\) is ethane-1, 2-diamine) are respectively
1 6 and 2
2 4 and 2
3 6 and 3
4 4 and 3
Explanation:
(c) Let the oxidation state of metal '\(M\) ' be \(x\).
For complex,
\(\left[M(e n)_2\left(\mathrm{C}_2 \mathrm{O}_4\right)\right] \mathrm{NO}_2\)
\(x+0-2=+1\)
\(\Rightarrow x=+3\)
Also, ethylenediamine and \(\mathrm{C}_2 \mathrm{O}_4^{2-}\) both are bidentate ligands. Thus, coordination number will be ' 6 '.
Karnataka CET 2017
CHEMISTRY(KCET)
285503
Square planar complex of the type\(M_{A X B L}\) (where \(A\), \(B, X\) and \(L\) are unidentate ligands) shows following set of isomers
1 two cis and one trans
2 two trans and one cis
3 two cis and two trans
4 three cis and one trans.
Explanation:
(a) Square planar complex of type\(M_{A X B L}\) will show two-cis and one-trans isomers.
These above three isomers are formed by fixing the position of one ligand, \(A\).
285501
\(\left[\mathrm{Fe}\left(\mathrm{NO}_2\right)_3 \mathrm{Cl}_3\right]\) and \(\left[\mathrm{Fe}(\mathrm{O}-\mathrm{NO})_3 \mathrm{Cl}_3\right]\) shows
1 linkage isomerism
2 geometrical isomerism
3 optical isomerism
4 hydrate isomerism.
Explanation:
(a)
Karnataka CET 2018
CHEMISTRY(KCET)
285502
The coordination number and the oxidation state of the element '\(M\) ' in the complex \(\left[M(e n)_2\left(\mathrm{C}_2 \mathrm{O}_4\right)\right] \mathrm{NO}_2\) (where, \(e n\) is ethane-1, 2-diamine) are respectively
1 6 and 2
2 4 and 2
3 6 and 3
4 4 and 3
Explanation:
(c) Let the oxidation state of metal '\(M\) ' be \(x\).
For complex,
\(\left[M(e n)_2\left(\mathrm{C}_2 \mathrm{O}_4\right)\right] \mathrm{NO}_2\)
\(x+0-2=+1\)
\(\Rightarrow x=+3\)
Also, ethylenediamine and \(\mathrm{C}_2 \mathrm{O}_4^{2-}\) both are bidentate ligands. Thus, coordination number will be ' 6 '.
Karnataka CET 2017
CHEMISTRY(KCET)
285503
Square planar complex of the type\(M_{A X B L}\) (where \(A\), \(B, X\) and \(L\) are unidentate ligands) shows following set of isomers
1 two cis and one trans
2 two trans and one cis
3 two cis and two trans
4 three cis and one trans.
Explanation:
(a) Square planar complex of type\(M_{A X B L}\) will show two-cis and one-trans isomers.
These above three isomers are formed by fixing the position of one ligand, \(A\).
285501
\(\left[\mathrm{Fe}\left(\mathrm{NO}_2\right)_3 \mathrm{Cl}_3\right]\) and \(\left[\mathrm{Fe}(\mathrm{O}-\mathrm{NO})_3 \mathrm{Cl}_3\right]\) shows
1 linkage isomerism
2 geometrical isomerism
3 optical isomerism
4 hydrate isomerism.
Explanation:
(a)
Karnataka CET 2018
CHEMISTRY(KCET)
285502
The coordination number and the oxidation state of the element '\(M\) ' in the complex \(\left[M(e n)_2\left(\mathrm{C}_2 \mathrm{O}_4\right)\right] \mathrm{NO}_2\) (where, \(e n\) is ethane-1, 2-diamine) are respectively
1 6 and 2
2 4 and 2
3 6 and 3
4 4 and 3
Explanation:
(c) Let the oxidation state of metal '\(M\) ' be \(x\).
For complex,
\(\left[M(e n)_2\left(\mathrm{C}_2 \mathrm{O}_4\right)\right] \mathrm{NO}_2\)
\(x+0-2=+1\)
\(\Rightarrow x=+3\)
Also, ethylenediamine and \(\mathrm{C}_2 \mathrm{O}_4^{2-}\) both are bidentate ligands. Thus, coordination number will be ' 6 '.
Karnataka CET 2017
CHEMISTRY(KCET)
285503
Square planar complex of the type\(M_{A X B L}\) (where \(A\), \(B, X\) and \(L\) are unidentate ligands) shows following set of isomers
1 two cis and one trans
2 two trans and one cis
3 two cis and two trans
4 three cis and one trans.
Explanation:
(a) Square planar complex of type\(M_{A X B L}\) will show two-cis and one-trans isomers.
These above three isomers are formed by fixing the position of one ligand, \(A\).
285501
\(\left[\mathrm{Fe}\left(\mathrm{NO}_2\right)_3 \mathrm{Cl}_3\right]\) and \(\left[\mathrm{Fe}(\mathrm{O}-\mathrm{NO})_3 \mathrm{Cl}_3\right]\) shows
1 linkage isomerism
2 geometrical isomerism
3 optical isomerism
4 hydrate isomerism.
Explanation:
(a)
Karnataka CET 2018
CHEMISTRY(KCET)
285502
The coordination number and the oxidation state of the element '\(M\) ' in the complex \(\left[M(e n)_2\left(\mathrm{C}_2 \mathrm{O}_4\right)\right] \mathrm{NO}_2\) (where, \(e n\) is ethane-1, 2-diamine) are respectively
1 6 and 2
2 4 and 2
3 6 and 3
4 4 and 3
Explanation:
(c) Let the oxidation state of metal '\(M\) ' be \(x\).
For complex,
\(\left[M(e n)_2\left(\mathrm{C}_2 \mathrm{O}_4\right)\right] \mathrm{NO}_2\)
\(x+0-2=+1\)
\(\Rightarrow x=+3\)
Also, ethylenediamine and \(\mathrm{C}_2 \mathrm{O}_4^{2-}\) both are bidentate ligands. Thus, coordination number will be ' 6 '.
Karnataka CET 2017
CHEMISTRY(KCET)
285503
Square planar complex of the type\(M_{A X B L}\) (where \(A\), \(B, X\) and \(L\) are unidentate ligands) shows following set of isomers
1 two cis and one trans
2 two trans and one cis
3 two cis and two trans
4 three cis and one trans.
Explanation:
(a) Square planar complex of type\(M_{A X B L}\) will show two-cis and one-trans isomers.
These above three isomers are formed by fixing the position of one ligand, \(A\).
