285467
The electronic configuration of transition element\(X\), is +3 , oxidation state is \([\mathrm{Ar}] 3 d^5\). What is its atomic number?
1 25
2 26
3 27
4 24
Explanation:
(b) Electronic configuration of\(X^{3+}:[\mathrm{Ar}] 3 d^5\) Electronic configuration of \(X\) will be: [Ar] \(3 d^6 4 s^2\) Thus, atomic number of transition element is 26.
Karnataka CET 2018
CHEMISTRY(KCET)
285468
\(\mathrm{KMnO}_4\) acts as an oxidising agent in alkaline medium. When alkaline \(\mathrm{KMnO}_4\) is treated with KI , iodide ion is oxidised to
285469
Which of the following statements is wrong regarding lanthanoids?
1 Ln (III) compounds are predominantly ionic in character.
2 Ln (III) hydroxides are mainly basic in nature.
3 The ionic size of Ln (III) ions decreases with increasing atomic number.
4 Ln (III) compounds are generally colourless.
Explanation:
(d) Many of the trivalent ions of lanthanoids are coloured, both in the solid state as well as in solution. The colour of lanthanoid ions arises due to absorption of light from visible region of spectrum resulting in\(f-f\) transitions as lanthanoids have partly filled \(f\)-orbitals.
Karnataka CET 2017
CHEMISTRY(KCET)
285470
The bivalent metal ion having maximum paramagnetic behaviour among the first transition series elements is
1 \(\mathrm{Mn}^{+2}\)
2 \(\mathrm{Cu}^{2+}\)
3 \(\mathrm{Sc}^{2+}\)
4 \(\mathrm{Cu}^{+}\)
Explanation:
(a)\(\mathrm{Mn}^{2+}\left(3 d^5 4 s^0\right) \rightarrow 5\) unpaired electrons \(\mathrm{Cu}^{2+}\left(3 d^9 4 s^0\right) \rightarrow 1\) unpaired electron
\(\mathrm{Sc}^{2+}\left(3 d^1 4 s^0\right) \rightarrow 1\) unpaired electron
\(\mathrm{Cu}^{+}\left(3 d^{10} 4 s^0\right) \rightarrow 0\) unpaired electron
Hence, \(\mathrm{Mn}^{2+}\) has maximum number of unpaired electrons thus, it shows maximum paramagnetic behaviour.
285467
The electronic configuration of transition element\(X\), is +3 , oxidation state is \([\mathrm{Ar}] 3 d^5\). What is its atomic number?
1 25
2 26
3 27
4 24
Explanation:
(b) Electronic configuration of\(X^{3+}:[\mathrm{Ar}] 3 d^5\) Electronic configuration of \(X\) will be: [Ar] \(3 d^6 4 s^2\) Thus, atomic number of transition element is 26.
Karnataka CET 2018
CHEMISTRY(KCET)
285468
\(\mathrm{KMnO}_4\) acts as an oxidising agent in alkaline medium. When alkaline \(\mathrm{KMnO}_4\) is treated with KI , iodide ion is oxidised to
285469
Which of the following statements is wrong regarding lanthanoids?
1 Ln (III) compounds are predominantly ionic in character.
2 Ln (III) hydroxides are mainly basic in nature.
3 The ionic size of Ln (III) ions decreases with increasing atomic number.
4 Ln (III) compounds are generally colourless.
Explanation:
(d) Many of the trivalent ions of lanthanoids are coloured, both in the solid state as well as in solution. The colour of lanthanoid ions arises due to absorption of light from visible region of spectrum resulting in\(f-f\) transitions as lanthanoids have partly filled \(f\)-orbitals.
Karnataka CET 2017
CHEMISTRY(KCET)
285470
The bivalent metal ion having maximum paramagnetic behaviour among the first transition series elements is
1 \(\mathrm{Mn}^{+2}\)
2 \(\mathrm{Cu}^{2+}\)
3 \(\mathrm{Sc}^{2+}\)
4 \(\mathrm{Cu}^{+}\)
Explanation:
(a)\(\mathrm{Mn}^{2+}\left(3 d^5 4 s^0\right) \rightarrow 5\) unpaired electrons \(\mathrm{Cu}^{2+}\left(3 d^9 4 s^0\right) \rightarrow 1\) unpaired electron
\(\mathrm{Sc}^{2+}\left(3 d^1 4 s^0\right) \rightarrow 1\) unpaired electron
\(\mathrm{Cu}^{+}\left(3 d^{10} 4 s^0\right) \rightarrow 0\) unpaired electron
Hence, \(\mathrm{Mn}^{2+}\) has maximum number of unpaired electrons thus, it shows maximum paramagnetic behaviour.
285467
The electronic configuration of transition element\(X\), is +3 , oxidation state is \([\mathrm{Ar}] 3 d^5\). What is its atomic number?
1 25
2 26
3 27
4 24
Explanation:
(b) Electronic configuration of\(X^{3+}:[\mathrm{Ar}] 3 d^5\) Electronic configuration of \(X\) will be: [Ar] \(3 d^6 4 s^2\) Thus, atomic number of transition element is 26.
Karnataka CET 2018
CHEMISTRY(KCET)
285468
\(\mathrm{KMnO}_4\) acts as an oxidising agent in alkaline medium. When alkaline \(\mathrm{KMnO}_4\) is treated with KI , iodide ion is oxidised to
285469
Which of the following statements is wrong regarding lanthanoids?
1 Ln (III) compounds are predominantly ionic in character.
2 Ln (III) hydroxides are mainly basic in nature.
3 The ionic size of Ln (III) ions decreases with increasing atomic number.
4 Ln (III) compounds are generally colourless.
Explanation:
(d) Many of the trivalent ions of lanthanoids are coloured, both in the solid state as well as in solution. The colour of lanthanoid ions arises due to absorption of light from visible region of spectrum resulting in\(f-f\) transitions as lanthanoids have partly filled \(f\)-orbitals.
Karnataka CET 2017
CHEMISTRY(KCET)
285470
The bivalent metal ion having maximum paramagnetic behaviour among the first transition series elements is
1 \(\mathrm{Mn}^{+2}\)
2 \(\mathrm{Cu}^{2+}\)
3 \(\mathrm{Sc}^{2+}\)
4 \(\mathrm{Cu}^{+}\)
Explanation:
(a)\(\mathrm{Mn}^{2+}\left(3 d^5 4 s^0\right) \rightarrow 5\) unpaired electrons \(\mathrm{Cu}^{2+}\left(3 d^9 4 s^0\right) \rightarrow 1\) unpaired electron
\(\mathrm{Sc}^{2+}\left(3 d^1 4 s^0\right) \rightarrow 1\) unpaired electron
\(\mathrm{Cu}^{+}\left(3 d^{10} 4 s^0\right) \rightarrow 0\) unpaired electron
Hence, \(\mathrm{Mn}^{2+}\) has maximum number of unpaired electrons thus, it shows maximum paramagnetic behaviour.
285467
The electronic configuration of transition element\(X\), is +3 , oxidation state is \([\mathrm{Ar}] 3 d^5\). What is its atomic number?
1 25
2 26
3 27
4 24
Explanation:
(b) Electronic configuration of\(X^{3+}:[\mathrm{Ar}] 3 d^5\) Electronic configuration of \(X\) will be: [Ar] \(3 d^6 4 s^2\) Thus, atomic number of transition element is 26.
Karnataka CET 2018
CHEMISTRY(KCET)
285468
\(\mathrm{KMnO}_4\) acts as an oxidising agent in alkaline medium. When alkaline \(\mathrm{KMnO}_4\) is treated with KI , iodide ion is oxidised to
285469
Which of the following statements is wrong regarding lanthanoids?
1 Ln (III) compounds are predominantly ionic in character.
2 Ln (III) hydroxides are mainly basic in nature.
3 The ionic size of Ln (III) ions decreases with increasing atomic number.
4 Ln (III) compounds are generally colourless.
Explanation:
(d) Many of the trivalent ions of lanthanoids are coloured, both in the solid state as well as in solution. The colour of lanthanoid ions arises due to absorption of light from visible region of spectrum resulting in\(f-f\) transitions as lanthanoids have partly filled \(f\)-orbitals.
Karnataka CET 2017
CHEMISTRY(KCET)
285470
The bivalent metal ion having maximum paramagnetic behaviour among the first transition series elements is
1 \(\mathrm{Mn}^{+2}\)
2 \(\mathrm{Cu}^{2+}\)
3 \(\mathrm{Sc}^{2+}\)
4 \(\mathrm{Cu}^{+}\)
Explanation:
(a)\(\mathrm{Mn}^{2+}\left(3 d^5 4 s^0\right) \rightarrow 5\) unpaired electrons \(\mathrm{Cu}^{2+}\left(3 d^9 4 s^0\right) \rightarrow 1\) unpaired electron
\(\mathrm{Sc}^{2+}\left(3 d^1 4 s^0\right) \rightarrow 1\) unpaired electron
\(\mathrm{Cu}^{+}\left(3 d^{10} 4 s^0\right) \rightarrow 0\) unpaired electron
Hence, \(\mathrm{Mn}^{2+}\) has maximum number of unpaired electrons thus, it shows maximum paramagnetic behaviour.
