NEET Test Series from KOTA - 10 Papers In MS WORD
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CHEMISTRY(KCET)
285367
When the pure solvent diffuses out of the solution through the semipermeable membrane then the process is called
1 sorption
2 dialysis
3 osmosis
4 reverse osmosis.
Explanation:
(d)
Karnataka CET 2017
CHEMISTRY(KCET)
285368
The van't Hoff factor '\(i\) ' accounts for
1 extent of dissolution of solute
2 extent of dissociation of solute
3 extent of mobility of solute
4 extent of solubility of solute.
Explanation:
(b) van't Hoff factor (i) expresses the extent of association or dissociation of solute in the solution.
Karnataka CET 2017
CHEMISTRY(KCET)
285359
Which of the following pair of solutions is isotonic?
1 \(0.001 \mathrm{M} \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3\) and \(0.01 \mathrm{M} \mathrm{BaCl}_2\)
2 \(0.001 \mathrm{M} \mathrm{CaCl}_2\) and \(0.001 \mathrm{M} \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3\)
3 \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and \(0.001 \mathrm{M} \mathrm{CaCl}_2\)
4 \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and 0.015 M NaCl
Explanation:
(d) Isotonic solutions are those which have same osmotic pressure at a given temperature.
For \(0.01 \mathrm{M} \mathrm{BaCl}_2, i=3\)
\(\pi=i C R T=3 \times 0.01 R T=0.03 R T\)
For \(0.015 \mathrm{M} \mathrm{NaCl}, i=2\)
\(\therefore \pi=2 \times 0.015 R T=0.03 R T\)
Therefore, \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and 0.015 M NaCl are isotonic.
Karnataka CET 2020
CHEMISTRY(KCET)
285360
Solute '\(X\) ' dimerises in water to the extent of \(80 \%\), 2.5 g of \({ }^{\prime} X\) ' in 100 g of water increases the boiling point by \(0.3^{\circ} \mathrm{C}\). The molar mass of ' \(X\) ' is \(\left[K_b=0.52\right.\) \(\mathrm{K} \mathrm{kg} \mathrm{mol}^{-1}\) ]
285367
When the pure solvent diffuses out of the solution through the semipermeable membrane then the process is called
1 sorption
2 dialysis
3 osmosis
4 reverse osmosis.
Explanation:
(d)
Karnataka CET 2017
CHEMISTRY(KCET)
285368
The van't Hoff factor '\(i\) ' accounts for
1 extent of dissolution of solute
2 extent of dissociation of solute
3 extent of mobility of solute
4 extent of solubility of solute.
Explanation:
(b) van't Hoff factor (i) expresses the extent of association or dissociation of solute in the solution.
Karnataka CET 2017
CHEMISTRY(KCET)
285359
Which of the following pair of solutions is isotonic?
1 \(0.001 \mathrm{M} \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3\) and \(0.01 \mathrm{M} \mathrm{BaCl}_2\)
2 \(0.001 \mathrm{M} \mathrm{CaCl}_2\) and \(0.001 \mathrm{M} \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3\)
3 \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and \(0.001 \mathrm{M} \mathrm{CaCl}_2\)
4 \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and 0.015 M NaCl
Explanation:
(d) Isotonic solutions are those which have same osmotic pressure at a given temperature.
For \(0.01 \mathrm{M} \mathrm{BaCl}_2, i=3\)
\(\pi=i C R T=3 \times 0.01 R T=0.03 R T\)
For \(0.015 \mathrm{M} \mathrm{NaCl}, i=2\)
\(\therefore \pi=2 \times 0.015 R T=0.03 R T\)
Therefore, \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and 0.015 M NaCl are isotonic.
Karnataka CET 2020
CHEMISTRY(KCET)
285360
Solute '\(X\) ' dimerises in water to the extent of \(80 \%\), 2.5 g of \({ }^{\prime} X\) ' in 100 g of water increases the boiling point by \(0.3^{\circ} \mathrm{C}\). The molar mass of ' \(X\) ' is \(\left[K_b=0.52\right.\) \(\mathrm{K} \mathrm{kg} \mathrm{mol}^{-1}\) ]
285367
When the pure solvent diffuses out of the solution through the semipermeable membrane then the process is called
1 sorption
2 dialysis
3 osmosis
4 reverse osmosis.
Explanation:
(d)
Karnataka CET 2017
CHEMISTRY(KCET)
285368
The van't Hoff factor '\(i\) ' accounts for
1 extent of dissolution of solute
2 extent of dissociation of solute
3 extent of mobility of solute
4 extent of solubility of solute.
Explanation:
(b) van't Hoff factor (i) expresses the extent of association or dissociation of solute in the solution.
Karnataka CET 2017
CHEMISTRY(KCET)
285359
Which of the following pair of solutions is isotonic?
1 \(0.001 \mathrm{M} \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3\) and \(0.01 \mathrm{M} \mathrm{BaCl}_2\)
2 \(0.001 \mathrm{M} \mathrm{CaCl}_2\) and \(0.001 \mathrm{M} \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3\)
3 \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and \(0.001 \mathrm{M} \mathrm{CaCl}_2\)
4 \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and 0.015 M NaCl
Explanation:
(d) Isotonic solutions are those which have same osmotic pressure at a given temperature.
For \(0.01 \mathrm{M} \mathrm{BaCl}_2, i=3\)
\(\pi=i C R T=3 \times 0.01 R T=0.03 R T\)
For \(0.015 \mathrm{M} \mathrm{NaCl}, i=2\)
\(\therefore \pi=2 \times 0.015 R T=0.03 R T\)
Therefore, \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and 0.015 M NaCl are isotonic.
Karnataka CET 2020
CHEMISTRY(KCET)
285360
Solute '\(X\) ' dimerises in water to the extent of \(80 \%\), 2.5 g of \({ }^{\prime} X\) ' in 100 g of water increases the boiling point by \(0.3^{\circ} \mathrm{C}\). The molar mass of ' \(X\) ' is \(\left[K_b=0.52\right.\) \(\mathrm{K} \mathrm{kg} \mathrm{mol}^{-1}\) ]
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
CHEMISTRY(KCET)
285367
When the pure solvent diffuses out of the solution through the semipermeable membrane then the process is called
1 sorption
2 dialysis
3 osmosis
4 reverse osmosis.
Explanation:
(d)
Karnataka CET 2017
CHEMISTRY(KCET)
285368
The van't Hoff factor '\(i\) ' accounts for
1 extent of dissolution of solute
2 extent of dissociation of solute
3 extent of mobility of solute
4 extent of solubility of solute.
Explanation:
(b) van't Hoff factor (i) expresses the extent of association or dissociation of solute in the solution.
Karnataka CET 2017
CHEMISTRY(KCET)
285359
Which of the following pair of solutions is isotonic?
1 \(0.001 \mathrm{M} \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3\) and \(0.01 \mathrm{M} \mathrm{BaCl}_2\)
2 \(0.001 \mathrm{M} \mathrm{CaCl}_2\) and \(0.001 \mathrm{M} \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3\)
3 \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and \(0.001 \mathrm{M} \mathrm{CaCl}_2\)
4 \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and 0.015 M NaCl
Explanation:
(d) Isotonic solutions are those which have same osmotic pressure at a given temperature.
For \(0.01 \mathrm{M} \mathrm{BaCl}_2, i=3\)
\(\pi=i C R T=3 \times 0.01 R T=0.03 R T\)
For \(0.015 \mathrm{M} \mathrm{NaCl}, i=2\)
\(\therefore \pi=2 \times 0.015 R T=0.03 R T\)
Therefore, \(0.01 \mathrm{M} \mathrm{BaCl}_2\) and 0.015 M NaCl are isotonic.
Karnataka CET 2020
CHEMISTRY(KCET)
285360
Solute '\(X\) ' dimerises in water to the extent of \(80 \%\), 2.5 g of \({ }^{\prime} X\) ' in 100 g of water increases the boiling point by \(0.3^{\circ} \mathrm{C}\). The molar mass of ' \(X\) ' is \(\left[K_b=0.52\right.\) \(\mathrm{K} \mathrm{kg} \mathrm{mol}^{-1}\) ]