285355 Henry's law constant for the solubility of\(\mathrm{N}_2\) gas in water at 298 K is \(1.0 \times 10^5 \mathrm{~atm}\). The mole fraction of \(\mathrm{N}_2\) in air is 0.8 . The number of moles of \(\mathrm{N}_2\) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is
285355 Henry's law constant for the solubility of\(\mathrm{N}_2\) gas in water at 298 K is \(1.0 \times 10^5 \mathrm{~atm}\). The mole fraction of \(\mathrm{N}_2\) in air is 0.8 . The number of moles of \(\mathrm{N}_2\) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is
285355 Henry's law constant for the solubility of\(\mathrm{N}_2\) gas in water at 298 K is \(1.0 \times 10^5 \mathrm{~atm}\). The mole fraction of \(\mathrm{N}_2\) in air is 0.8 . The number of moles of \(\mathrm{N}_2\) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is
285355 Henry's law constant for the solubility of\(\mathrm{N}_2\) gas in water at 298 K is \(1.0 \times 10^5 \mathrm{~atm}\). The mole fraction of \(\mathrm{N}_2\) in air is 0.8 . The number of moles of \(\mathrm{N}_2\) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is
285355 Henry's law constant for the solubility of\(\mathrm{N}_2\) gas in water at 298 K is \(1.0 \times 10^5 \mathrm{~atm}\). The mole fraction of \(\mathrm{N}_2\) in air is 0.8 . The number of moles of \(\mathrm{N}_2\) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is