QBManager

CHEMISTRY(KCET)

285261 Which of the following structures of a moleculeis expected to have three bond pairs and one lone pair of electrons?

1 Trigonal Planar

2 Tetrahedral

3 Octahedral

4 Pyramidal

Explanation:

(d) A molecule with three bond pairs and one lone pair of electrons like ${NH}_{3}$ is $s p^{3}$ hybridised with tetrahedral geometry and trigonal pyramidal structure.
(Tetrahedral structure)

Karnataka CET 2017

CHEMISTRY(KCET)

285262 Which of the following is the correct electron dot structure of $N_{2} O$ molecule?

1

: \ddot{N} = N = \ddot{O}

2

: \ddot{N} - N = \ddot{O}

:

3

: N = N = \ddot{O} :

4

: N = \overset{+}{N} - \overset{⇀}{O} \overset{―}{F}

Explanation:

(d) $\tilde{N} = + \overset{+}{N} = \overset{O}{M} ⟷ N \equiv \overset{+}{N} - \overset{O}{-}$

Karnataka CET 2017

CHEMISTRY(KCET)

285263 Arrange the following in the increasing order of their bond order

$O_{2}, O_{2}^{+}, O_{2}^{-}$ and $O_{2}^{2 -}$

1

O_{2}^{2 -}, O_{2}^{-}, O_{2}^{+}, O_{2}

2

O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}

3

O_{2}, O_{2}^{+}, O_{2}^{-}, O_{2}^{2 -}

4

O_{2}^{2 -}, O_{2}^{-}, O_{2}, O_{2}^{+}

Explanation:

(d) Molecular orbital electronic configuration of $O_{2}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{1} {(π^{*} 2 p_{y})}^{1}$
$∴$ B.O. of $O_{2} = \frac{1}{2} (10 - 6) = 2$
Molecular orbital electronic configuration of $O_{2}^{+}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{1}$
$∴$ B.O. of $O_{2}^{+} = \frac{1}{2} (10 - 5) = 2.5$
Molecular orbital electronic configuration of $O_{2}^{-}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{2} {(π^{*} 2 p_{y})}^{1}$
$∴$ B.O. of $O_{2}^{-} = \frac{1}{2} (10 - 7) = 1.5$
Molecular orbital electronic configuration of $O_{2}^{2 -}$ is: $(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{2} {(π^{*} 2 p_{y})}^{2}$
$∴$ B.O. of $O_{2}^{2 -} = \frac{1}{2} (10 - 8) = 1.0$
$∴$ Increasing order of B.O. is :
$O_{2}^{2 -} < O_{2}^{-} < O_{2} < O_{2}^{+}$

Karnataka CET 2009

CHEMISTRY(KCET)

285264 HCl gas is covalent and NaCl is an ionic compound. This is because

1 sodium is highly electropositive

2 hydrogen is a non-metal

3 HCl is a gas

4 electronegativity difference between H and Cl is less than 2.1 .

Karnataka CET 2016

CHEMISTRY(KCET)

285265 Main axis of diatomic molecule is $z$ . The orbitals $p_{x}$ and $p_{y}$ overlap to form

1

π

-molecular orbital

2

σ

-molecular orbital

3

δ

-molecular orbital

4 no bond is formed.

Explanation:

(d) The $p_{x}$ and $p_{y}$ orbitals do not overlap thus, no bond is formed.

Karnataka CET 2016

CHEMISTRY(KCET)

285261 Which of the following structures of a moleculeis expected to have three bond pairs and one lone pair of electrons?

1 Trigonal Planar

2 Tetrahedral

3 Octahedral

4 Pyramidal

Explanation:

(d) A molecule with three bond pairs and one lone pair of electrons like ${NH}_{3}$ is $s p^{3}$ hybridised with tetrahedral geometry and trigonal pyramidal structure.
(Tetrahedral structure)

Karnataka CET 2017

CHEMISTRY(KCET)

285262 Which of the following is the correct electron dot structure of $N_{2} O$ molecule?

1

: \ddot{N} = N = \ddot{O}

2

: \ddot{N} - N = \ddot{O}

:

3

: N = N = \ddot{O} :

4

: N = \overset{+}{N} - \overset{⇀}{O} \overset{―}{F}

Explanation:

(d) $\tilde{N} = + \overset{+}{N} = \overset{O}{M} ⟷ N \equiv \overset{+}{N} - \overset{O}{-}$

Karnataka CET 2017

CHEMISTRY(KCET)

285263 Arrange the following in the increasing order of their bond order

$O_{2}, O_{2}^{+}, O_{2}^{-}$ and $O_{2}^{2 -}$

1

O_{2}^{2 -}, O_{2}^{-}, O_{2}^{+}, O_{2}

2

O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}

3

O_{2}, O_{2}^{+}, O_{2}^{-}, O_{2}^{2 -}

4

O_{2}^{2 -}, O_{2}^{-}, O_{2}, O_{2}^{+}

Explanation:

(d) Molecular orbital electronic configuration of $O_{2}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{1} {(π^{*} 2 p_{y})}^{1}$
$∴$ B.O. of $O_{2} = \frac{1}{2} (10 - 6) = 2$
Molecular orbital electronic configuration of $O_{2}^{+}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{1}$
$∴$ B.O. of $O_{2}^{+} = \frac{1}{2} (10 - 5) = 2.5$
Molecular orbital electronic configuration of $O_{2}^{-}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{2} {(π^{*} 2 p_{y})}^{1}$
$∴$ B.O. of $O_{2}^{-} = \frac{1}{2} (10 - 7) = 1.5$
Molecular orbital electronic configuration of $O_{2}^{2 -}$ is: $(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{2} {(π^{*} 2 p_{y})}^{2}$
$∴$ B.O. of $O_{2}^{2 -} = \frac{1}{2} (10 - 8) = 1.0$
$∴$ Increasing order of B.O. is :
$O_{2}^{2 -} < O_{2}^{-} < O_{2} < O_{2}^{+}$

Karnataka CET 2009

CHEMISTRY(KCET)

285264 HCl gas is covalent and NaCl is an ionic compound. This is because

1 sodium is highly electropositive

2 hydrogen is a non-metal

3 HCl is a gas

4 electronegativity difference between H and Cl is less than 2.1 .

Karnataka CET 2016

CHEMISTRY(KCET)

285265 Main axis of diatomic molecule is $z$ . The orbitals $p_{x}$ and $p_{y}$ overlap to form

1

π

-molecular orbital

2

σ

-molecular orbital

3

δ

-molecular orbital

4 no bond is formed.

Explanation:

(d) The $p_{x}$ and $p_{y}$ orbitals do not overlap thus, no bond is formed.

Karnataka CET 2016

CHEMISTRY(KCET)

285261 Which of the following structures of a moleculeis expected to have three bond pairs and one lone pair of electrons?

1 Trigonal Planar

2 Tetrahedral

3 Octahedral

4 Pyramidal

Explanation:

(d) A molecule with three bond pairs and one lone pair of electrons like ${NH}_{3}$ is $s p^{3}$ hybridised with tetrahedral geometry and trigonal pyramidal structure.
(Tetrahedral structure)

Karnataka CET 2017

CHEMISTRY(KCET)

285262 Which of the following is the correct electron dot structure of $N_{2} O$ molecule?

1

: \ddot{N} = N = \ddot{O}

2

: \ddot{N} - N = \ddot{O}

:

3

: N = N = \ddot{O} :

4

: N = \overset{+}{N} - \overset{⇀}{O} \overset{―}{F}

Explanation:

(d) $\tilde{N} = + \overset{+}{N} = \overset{O}{M} ⟷ N \equiv \overset{+}{N} - \overset{O}{-}$

Karnataka CET 2017

CHEMISTRY(KCET)

285263 Arrange the following in the increasing order of their bond order

$O_{2}, O_{2}^{+}, O_{2}^{-}$ and $O_{2}^{2 -}$

1

O_{2}^{2 -}, O_{2}^{-}, O_{2}^{+}, O_{2}

2

O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}

3

O_{2}, O_{2}^{+}, O_{2}^{-}, O_{2}^{2 -}

4

O_{2}^{2 -}, O_{2}^{-}, O_{2}, O_{2}^{+}

Explanation:

(d) Molecular orbital electronic configuration of $O_{2}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{1} {(π^{*} 2 p_{y})}^{1}$
$∴$ B.O. of $O_{2} = \frac{1}{2} (10 - 6) = 2$
Molecular orbital electronic configuration of $O_{2}^{+}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{1}$
$∴$ B.O. of $O_{2}^{+} = \frac{1}{2} (10 - 5) = 2.5$
Molecular orbital electronic configuration of $O_{2}^{-}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{2} {(π^{*} 2 p_{y})}^{1}$
$∴$ B.O. of $O_{2}^{-} = \frac{1}{2} (10 - 7) = 1.5$
Molecular orbital electronic configuration of $O_{2}^{2 -}$ is: $(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{2} {(π^{*} 2 p_{y})}^{2}$
$∴$ B.O. of $O_{2}^{2 -} = \frac{1}{2} (10 - 8) = 1.0$
$∴$ Increasing order of B.O. is :
$O_{2}^{2 -} < O_{2}^{-} < O_{2} < O_{2}^{+}$

Karnataka CET 2009

CHEMISTRY(KCET)

285264 HCl gas is covalent and NaCl is an ionic compound. This is because

1 sodium is highly electropositive

2 hydrogen is a non-metal

3 HCl is a gas

4 electronegativity difference between H and Cl is less than 2.1 .

Karnataka CET 2016

CHEMISTRY(KCET)

285265 Main axis of diatomic molecule is $z$ . The orbitals $p_{x}$ and $p_{y}$ overlap to form

1

π

-molecular orbital

2

σ

-molecular orbital

3

δ

-molecular orbital

4 no bond is formed.

Explanation:

(d) The $p_{x}$ and $p_{y}$ orbitals do not overlap thus, no bond is formed.

Karnataka CET 2016

CHEMISTRY(KCET)

285261 Which of the following structures of a moleculeis expected to have three bond pairs and one lone pair of electrons?

1 Trigonal Planar

2 Tetrahedral

3 Octahedral

4 Pyramidal

Explanation:

(d) A molecule with three bond pairs and one lone pair of electrons like ${NH}_{3}$ is $s p^{3}$ hybridised with tetrahedral geometry and trigonal pyramidal structure.
(Tetrahedral structure)

Karnataka CET 2017

CHEMISTRY(KCET)

285262 Which of the following is the correct electron dot structure of $N_{2} O$ molecule?

1

: \ddot{N} = N = \ddot{O}

2

: \ddot{N} - N = \ddot{O}

:

3

: N = N = \ddot{O} :

4

: N = \overset{+}{N} - \overset{⇀}{O} \overset{―}{F}

Explanation:

(d) $\tilde{N} = + \overset{+}{N} = \overset{O}{M} ⟷ N \equiv \overset{+}{N} - \overset{O}{-}$

Karnataka CET 2017

CHEMISTRY(KCET)

285263 Arrange the following in the increasing order of their bond order

$O_{2}, O_{2}^{+}, O_{2}^{-}$ and $O_{2}^{2 -}$

1

O_{2}^{2 -}, O_{2}^{-}, O_{2}^{+}, O_{2}

2

O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}

3

O_{2}, O_{2}^{+}, O_{2}^{-}, O_{2}^{2 -}

4

O_{2}^{2 -}, O_{2}^{-}, O_{2}, O_{2}^{+}

Explanation:

(d) Molecular orbital electronic configuration of $O_{2}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{1} {(π^{*} 2 p_{y})}^{1}$
$∴$ B.O. of $O_{2} = \frac{1}{2} (10 - 6) = 2$
Molecular orbital electronic configuration of $O_{2}^{+}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{1}$
$∴$ B.O. of $O_{2}^{+} = \frac{1}{2} (10 - 5) = 2.5$
Molecular orbital electronic configuration of $O_{2}^{-}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{2} {(π^{*} 2 p_{y})}^{1}$
$∴$ B.O. of $O_{2}^{-} = \frac{1}{2} (10 - 7) = 1.5$
Molecular orbital electronic configuration of $O_{2}^{2 -}$ is: $(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{2} {(π^{*} 2 p_{y})}^{2}$
$∴$ B.O. of $O_{2}^{2 -} = \frac{1}{2} (10 - 8) = 1.0$
$∴$ Increasing order of B.O. is :
$O_{2}^{2 -} < O_{2}^{-} < O_{2} < O_{2}^{+}$

Karnataka CET 2009

CHEMISTRY(KCET)

285264 HCl gas is covalent and NaCl is an ionic compound. This is because

1 sodium is highly electropositive

2 hydrogen is a non-metal

3 HCl is a gas

4 electronegativity difference between H and Cl is less than 2.1 .

Karnataka CET 2016

CHEMISTRY(KCET)

285265 Main axis of diatomic molecule is $z$ . The orbitals $p_{x}$ and $p_{y}$ overlap to form

1

π

-molecular orbital

2

σ

-molecular orbital

3

δ

-molecular orbital

4 no bond is formed.

Explanation:

(d) The $p_{x}$ and $p_{y}$ orbitals do not overlap thus, no bond is formed.

Karnataka CET 2016

CHEMISTRY(KCET)

285261 Which of the following structures of a moleculeis expected to have three bond pairs and one lone pair of electrons?

1 Trigonal Planar

2 Tetrahedral

3 Octahedral

4 Pyramidal

Explanation:

(d) A molecule with three bond pairs and one lone pair of electrons like ${NH}_{3}$ is $s p^{3}$ hybridised with tetrahedral geometry and trigonal pyramidal structure.
(Tetrahedral structure)

Karnataka CET 2017

CHEMISTRY(KCET)

285262 Which of the following is the correct electron dot structure of $N_{2} O$ molecule?

1

: \ddot{N} = N = \ddot{O}

2

: \ddot{N} - N = \ddot{O}

:

3

: N = N = \ddot{O} :

4

: N = \overset{+}{N} - \overset{⇀}{O} \overset{―}{F}

Explanation:

(d) $\tilde{N} = + \overset{+}{N} = \overset{O}{M} ⟷ N \equiv \overset{+}{N} - \overset{O}{-}$

Karnataka CET 2017

CHEMISTRY(KCET)

285263 Arrange the following in the increasing order of their bond order

$O_{2}, O_{2}^{+}, O_{2}^{-}$ and $O_{2}^{2 -}$

1

O_{2}^{2 -}, O_{2}^{-}, O_{2}^{+}, O_{2}

2

O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}

3

O_{2}, O_{2}^{+}, O_{2}^{-}, O_{2}^{2 -}

4

O_{2}^{2 -}, O_{2}^{-}, O_{2}, O_{2}^{+}

Explanation:

(d) Molecular orbital electronic configuration of $O_{2}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{1} {(π^{*} 2 p_{y})}^{1}$
$∴$ B.O. of $O_{2} = \frac{1}{2} (10 - 6) = 2$
Molecular orbital electronic configuration of $O_{2}^{+}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{1}$
$∴$ B.O. of $O_{2}^{+} = \frac{1}{2} (10 - 5) = 2.5$
Molecular orbital electronic configuration of $O_{2}^{-}$ is:
$(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{2} {(π^{*} 2 p_{y})}^{1}$
$∴$ B.O. of $O_{2}^{-} = \frac{1}{2} (10 - 7) = 1.5$
Molecular orbital electronic configuration of $O_{2}^{2 -}$ is: $(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2}$
${(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2} {(π^{*} 2 p_{x})}^{2} {(π^{*} 2 p_{y})}^{2}$
$∴$ B.O. of $O_{2}^{2 -} = \frac{1}{2} (10 - 8) = 1.0$
$∴$ Increasing order of B.O. is :
$O_{2}^{2 -} < O_{2}^{-} < O_{2} < O_{2}^{+}$

Karnataka CET 2009

CHEMISTRY(KCET)

285264 HCl gas is covalent and NaCl is an ionic compound. This is because

1 sodium is highly electropositive

2 hydrogen is a non-metal

3 HCl is a gas

4 electronegativity difference between H and Cl is less than 2.1 .

Karnataka CET 2016

CHEMISTRY(KCET)

285265 Main axis of diatomic molecule is $z$ . The orbitals $p_{x}$ and $p_{y}$ overlap to form

1

π

-molecular orbital

2

σ

-molecular orbital

3

δ

-molecular orbital

4 no bond is formed.

Explanation:

(d) The $p_{x}$ and $p_{y}$ orbitals do not overlap thus, no bond is formed.

Karnataka CET 2016