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CHEMISTRY(KCET)

285248 A pair of isoelectric species having bond order of one is:

1

N_{2}, CO

2

N_{2}, {NO}^{+}

3

O_{2}^{2 -}, F_{2}

4

CO, {NO}^{+}

Explanation:

(c)Iso electronic species having same number of electron.
$Unknown environment 'tabular'$
So $O_{2}^{2 -}$ and $F_{2}$ both are isoelectric species and have bond order 1 .

Karnataka CET 2024

CHEMISTRY(KCET)

285249 The correct decreasing order of boiling point of hydrogen halides is

1

HF > HCl > HBr > HI

2

HI > HBr > HCl > HF

3

HF > HI > HBr > HCl

4

HI > HF > HBr > HCl

Explanation:

(c) HF have high boiling point due to strong intermolecular $H -$ bonding because of high electronegativity of F . Hence boiling point of HF is abnormally high. Boiling points of other hydrogen halide gradually increases from HCl to HI due to increase in size of halogens atom from Cl to I which furthur increase the magnitude of van der waal's forces.

Karnataka CET 2024

CHEMISTRY(KCET)

285250 Which of the following statement is INCORRECT?

1 Bond length of

O_{2} >

Bond length of

O_{2}^{2 +}

2 Bond order of

O_{2}^{+} <

Bond order of

O_{2}^{2 -}

3 Bond length of

O_{2} <

Bond length of

O_{2}^{2 -}

4 Bond order of

O_{2} >

Bond order of

O_{2}^{2 -}

Explanation:

(b) $O_{2} = σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2} σ^{*} 2 s^{2} σ 2 p_{z}^{2}$
$π 2 p_{x}^{2} π 2 p_{y}^{2} π^{*} 2 p_{x}^{1} π^{*} 2 p_{y}^{1}$
$\Rightarrow$ B.O. $(O_{2}) = \frac{N_{b} - N_{a}}{2} = \frac{10 - 6}{2} = \frac{4}{2} = 2$
B.O. $(O_{2}^{+}) = \frac{10 - 5}{2} = 2.5$
B.O. $(O_{2}^{2 +}) = \frac{10 - 4}{2} = 3$
B.O. $(O_{2}^{2 -}) = \frac{10 - 8}{2} = 1$

Karnataka CET 2023

CHEMISTRY(KCET)

285251 In oxygen and carbon molecule the bonding is

1

O_{2} : 1 σ, 1 π; C_{2} : 0 σ, 2 π

2

O_{2} : 0 σ, 2 π; C_{2} : 2 σ, 0 π

3

O_{2} : 1 σ, 1 π; C_{2} : 1 σ, 1 π

4

O_{2} : 2 σ, 0 π; C_{2} : 0 σ, 2 π

Explanation:

(a) $O_{2}$ has $1 σ$ and $1 π$ bond and $C_{2}$ molecule has $2 π$ bonds.

Karnataka CET 2022

CHEMISTRY(KCET)

285252 Which of the following is an incorrect statement?

1 Hydrogen bonding is stronger than dispersion force.

2 Sigma bonds are stronger than

π

-bonds.

3 Ionic bonding is non-directional.

4

σ

-electrons are referred to as mobile electrons.

Explanation:

(d) $σ$ -electrons are localised electrons, they do not move in the structure of molecule.

Karnataka CET 2021

CHEMISTRY(KCET)

285248 A pair of isoelectric species having bond order of one is:

1

N_{2}, CO

2

N_{2}, {NO}^{+}

3

O_{2}^{2 -}, F_{2}

4

CO, {NO}^{+}

Explanation:

(c)Iso electronic species having same number of electron.
$Unknown environment 'tabular'$
So $O_{2}^{2 -}$ and $F_{2}$ both are isoelectric species and have bond order 1 .

Karnataka CET 2024

CHEMISTRY(KCET)

285249 The correct decreasing order of boiling point of hydrogen halides is

1

HF > HCl > HBr > HI

2

HI > HBr > HCl > HF

3

HF > HI > HBr > HCl

4

HI > HF > HBr > HCl

Explanation:

(c) HF have high boiling point due to strong intermolecular $H -$ bonding because of high electronegativity of F . Hence boiling point of HF is abnormally high. Boiling points of other hydrogen halide gradually increases from HCl to HI due to increase in size of halogens atom from Cl to I which furthur increase the magnitude of van der waal's forces.

Karnataka CET 2024

CHEMISTRY(KCET)

285250 Which of the following statement is INCORRECT?

1 Bond length of

O_{2} >

Bond length of

O_{2}^{2 +}

2 Bond order of

O_{2}^{+} <

Bond order of

O_{2}^{2 -}

3 Bond length of

O_{2} <

Bond length of

O_{2}^{2 -}

4 Bond order of

O_{2} >

Bond order of

O_{2}^{2 -}

Explanation:

(b) $O_{2} = σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2} σ^{*} 2 s^{2} σ 2 p_{z}^{2}$
$π 2 p_{x}^{2} π 2 p_{y}^{2} π^{*} 2 p_{x}^{1} π^{*} 2 p_{y}^{1}$
$\Rightarrow$ B.O. $(O_{2}) = \frac{N_{b} - N_{a}}{2} = \frac{10 - 6}{2} = \frac{4}{2} = 2$
B.O. $(O_{2}^{+}) = \frac{10 - 5}{2} = 2.5$
B.O. $(O_{2}^{2 +}) = \frac{10 - 4}{2} = 3$
B.O. $(O_{2}^{2 -}) = \frac{10 - 8}{2} = 1$

Karnataka CET 2023

CHEMISTRY(KCET)

285251 In oxygen and carbon molecule the bonding is

1

O_{2} : 1 σ, 1 π; C_{2} : 0 σ, 2 π

2

O_{2} : 0 σ, 2 π; C_{2} : 2 σ, 0 π

3

O_{2} : 1 σ, 1 π; C_{2} : 1 σ, 1 π

4

O_{2} : 2 σ, 0 π; C_{2} : 0 σ, 2 π

Explanation:

(a) $O_{2}$ has $1 σ$ and $1 π$ bond and $C_{2}$ molecule has $2 π$ bonds.

Karnataka CET 2022

CHEMISTRY(KCET)

285252 Which of the following is an incorrect statement?

1 Hydrogen bonding is stronger than dispersion force.

2 Sigma bonds are stronger than

π

-bonds.

3 Ionic bonding is non-directional.

4

σ

-electrons are referred to as mobile electrons.

Explanation:

(d) $σ$ -electrons are localised electrons, they do not move in the structure of molecule.

Karnataka CET 2021

CHEMISTRY(KCET)

285248 A pair of isoelectric species having bond order of one is:

1

N_{2}, CO

2

N_{2}, {NO}^{+}

3

O_{2}^{2 -}, F_{2}

4

CO, {NO}^{+}

Explanation:

(c)Iso electronic species having same number of electron.
$Unknown environment 'tabular'$
So $O_{2}^{2 -}$ and $F_{2}$ both are isoelectric species and have bond order 1 .

Karnataka CET 2024

CHEMISTRY(KCET)

285249 The correct decreasing order of boiling point of hydrogen halides is

1

HF > HCl > HBr > HI

2

HI > HBr > HCl > HF

3

HF > HI > HBr > HCl

4

HI > HF > HBr > HCl

Explanation:

(c) HF have high boiling point due to strong intermolecular $H -$ bonding because of high electronegativity of F . Hence boiling point of HF is abnormally high. Boiling points of other hydrogen halide gradually increases from HCl to HI due to increase in size of halogens atom from Cl to I which furthur increase the magnitude of van der waal's forces.

Karnataka CET 2024

CHEMISTRY(KCET)

285250 Which of the following statement is INCORRECT?

1 Bond length of

O_{2} >

Bond length of

O_{2}^{2 +}

2 Bond order of

O_{2}^{+} <

Bond order of

O_{2}^{2 -}

3 Bond length of

O_{2} <

Bond length of

O_{2}^{2 -}

4 Bond order of

O_{2} >

Bond order of

O_{2}^{2 -}

Explanation:

(b) $O_{2} = σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2} σ^{*} 2 s^{2} σ 2 p_{z}^{2}$
$π 2 p_{x}^{2} π 2 p_{y}^{2} π^{*} 2 p_{x}^{1} π^{*} 2 p_{y}^{1}$
$\Rightarrow$ B.O. $(O_{2}) = \frac{N_{b} - N_{a}}{2} = \frac{10 - 6}{2} = \frac{4}{2} = 2$
B.O. $(O_{2}^{+}) = \frac{10 - 5}{2} = 2.5$
B.O. $(O_{2}^{2 +}) = \frac{10 - 4}{2} = 3$
B.O. $(O_{2}^{2 -}) = \frac{10 - 8}{2} = 1$

Karnataka CET 2023

CHEMISTRY(KCET)

285251 In oxygen and carbon molecule the bonding is

1

O_{2} : 1 σ, 1 π; C_{2} : 0 σ, 2 π

2

O_{2} : 0 σ, 2 π; C_{2} : 2 σ, 0 π

3

O_{2} : 1 σ, 1 π; C_{2} : 1 σ, 1 π

4

O_{2} : 2 σ, 0 π; C_{2} : 0 σ, 2 π

Explanation:

(a) $O_{2}$ has $1 σ$ and $1 π$ bond and $C_{2}$ molecule has $2 π$ bonds.

Karnataka CET 2022

CHEMISTRY(KCET)

285252 Which of the following is an incorrect statement?

1 Hydrogen bonding is stronger than dispersion force.

2 Sigma bonds are stronger than

π

-bonds.

3 Ionic bonding is non-directional.

4

σ

-electrons are referred to as mobile electrons.

Explanation:

(d) $σ$ -electrons are localised electrons, they do not move in the structure of molecule.

Karnataka CET 2021

CHEMISTRY(KCET)

285248 A pair of isoelectric species having bond order of one is:

1

N_{2}, CO

2

N_{2}, {NO}^{+}

3

O_{2}^{2 -}, F_{2}

4

CO, {NO}^{+}

Explanation:

(c)Iso electronic species having same number of electron.
$Unknown environment 'tabular'$
So $O_{2}^{2 -}$ and $F_{2}$ both are isoelectric species and have bond order 1 .

Karnataka CET 2024

CHEMISTRY(KCET)

285249 The correct decreasing order of boiling point of hydrogen halides is

1

HF > HCl > HBr > HI

2

HI > HBr > HCl > HF

3

HF > HI > HBr > HCl

4

HI > HF > HBr > HCl

Explanation:

(c) HF have high boiling point due to strong intermolecular $H -$ bonding because of high electronegativity of F . Hence boiling point of HF is abnormally high. Boiling points of other hydrogen halide gradually increases from HCl to HI due to increase in size of halogens atom from Cl to I which furthur increase the magnitude of van der waal's forces.

Karnataka CET 2024

CHEMISTRY(KCET)

285250 Which of the following statement is INCORRECT?

1 Bond length of

O_{2} >

Bond length of

O_{2}^{2 +}

2 Bond order of

O_{2}^{+} <

Bond order of

O_{2}^{2 -}

3 Bond length of

O_{2} <

Bond length of

O_{2}^{2 -}

4 Bond order of

O_{2} >

Bond order of

O_{2}^{2 -}

Explanation:

(b) $O_{2} = σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2} σ^{*} 2 s^{2} σ 2 p_{z}^{2}$
$π 2 p_{x}^{2} π 2 p_{y}^{2} π^{*} 2 p_{x}^{1} π^{*} 2 p_{y}^{1}$
$\Rightarrow$ B.O. $(O_{2}) = \frac{N_{b} - N_{a}}{2} = \frac{10 - 6}{2} = \frac{4}{2} = 2$
B.O. $(O_{2}^{+}) = \frac{10 - 5}{2} = 2.5$
B.O. $(O_{2}^{2 +}) = \frac{10 - 4}{2} = 3$
B.O. $(O_{2}^{2 -}) = \frac{10 - 8}{2} = 1$

Karnataka CET 2023

CHEMISTRY(KCET)

285251 In oxygen and carbon molecule the bonding is

1

O_{2} : 1 σ, 1 π; C_{2} : 0 σ, 2 π

2

O_{2} : 0 σ, 2 π; C_{2} : 2 σ, 0 π

3

O_{2} : 1 σ, 1 π; C_{2} : 1 σ, 1 π

4

O_{2} : 2 σ, 0 π; C_{2} : 0 σ, 2 π

Explanation:

(a) $O_{2}$ has $1 σ$ and $1 π$ bond and $C_{2}$ molecule has $2 π$ bonds.

Karnataka CET 2022

CHEMISTRY(KCET)

285252 Which of the following is an incorrect statement?

1 Hydrogen bonding is stronger than dispersion force.

2 Sigma bonds are stronger than

π

-bonds.

3 Ionic bonding is non-directional.

4

σ

-electrons are referred to as mobile electrons.

Explanation:

(d) $σ$ -electrons are localised electrons, they do not move in the structure of molecule.

Karnataka CET 2021

CHEMISTRY(KCET)

285248 A pair of isoelectric species having bond order of one is:

1

N_{2}, CO

2

N_{2}, {NO}^{+}

3

O_{2}^{2 -}, F_{2}

4

CO, {NO}^{+}

Explanation:

(c)Iso electronic species having same number of electron.
$Unknown environment 'tabular'$
So $O_{2}^{2 -}$ and $F_{2}$ both are isoelectric species and have bond order 1 .

Karnataka CET 2024

CHEMISTRY(KCET)

285249 The correct decreasing order of boiling point of hydrogen halides is

1

HF > HCl > HBr > HI

2

HI > HBr > HCl > HF

3

HF > HI > HBr > HCl

4

HI > HF > HBr > HCl

Explanation:

(c) HF have high boiling point due to strong intermolecular $H -$ bonding because of high electronegativity of F . Hence boiling point of HF is abnormally high. Boiling points of other hydrogen halide gradually increases from HCl to HI due to increase in size of halogens atom from Cl to I which furthur increase the magnitude of van der waal's forces.

Karnataka CET 2024

CHEMISTRY(KCET)

285250 Which of the following statement is INCORRECT?

1 Bond length of

O_{2} >

Bond length of

O_{2}^{2 +}

2 Bond order of

O_{2}^{+} <

Bond order of

O_{2}^{2 -}

3 Bond length of

O_{2} <

Bond length of

O_{2}^{2 -}

4 Bond order of

O_{2} >

Bond order of

O_{2}^{2 -}

Explanation:

(b) $O_{2} = σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2} σ^{*} 2 s^{2} σ 2 p_{z}^{2}$
$π 2 p_{x}^{2} π 2 p_{y}^{2} π^{*} 2 p_{x}^{1} π^{*} 2 p_{y}^{1}$
$\Rightarrow$ B.O. $(O_{2}) = \frac{N_{b} - N_{a}}{2} = \frac{10 - 6}{2} = \frac{4}{2} = 2$
B.O. $(O_{2}^{+}) = \frac{10 - 5}{2} = 2.5$
B.O. $(O_{2}^{2 +}) = \frac{10 - 4}{2} = 3$
B.O. $(O_{2}^{2 -}) = \frac{10 - 8}{2} = 1$

Karnataka CET 2023

CHEMISTRY(KCET)

285251 In oxygen and carbon molecule the bonding is

1

O_{2} : 1 σ, 1 π; C_{2} : 0 σ, 2 π

2

O_{2} : 0 σ, 2 π; C_{2} : 2 σ, 0 π

3

O_{2} : 1 σ, 1 π; C_{2} : 1 σ, 1 π

4

O_{2} : 2 σ, 0 π; C_{2} : 0 σ, 2 π

Explanation:

(a) $O_{2}$ has $1 σ$ and $1 π$ bond and $C_{2}$ molecule has $2 π$ bonds.

Karnataka CET 2022

CHEMISTRY(KCET)

285252 Which of the following is an incorrect statement?

1 Hydrogen bonding is stronger than dispersion force.

2 Sigma bonds are stronger than

π

-bonds.

3 Ionic bonding is non-directional.

4

σ

-electrons are referred to as mobile electrons.

Explanation:

(d) $σ$ -electrons are localised electrons, they do not move in the structure of molecule.

Karnataka CET 2021

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