285248
A pair of isoelectric species having bond order of one is:
1 \(\mathrm{N}_2, \mathrm{CO}\)
2 \(\mathrm{N}_2, \mathrm{NO}^{+}\)
3 \(\mathrm{O}_2^{2-}, \mathrm{F}_2\)
4 \(\mathrm{CO}, \mathrm{NO}^{+}\)
Explanation:
(c)Iso electronic species having same number of electron.
\begin{tabular}{|c|c|c|}
\hline Molecule/ions & Total electron & Bond order \\
\hline \(\mathrm{N}_2\)
14.3 \\
\hline CO
14. 3 \\
\hline \(\mathrm{NO}^{+}\)
14. 3 \\
\hline \(\mathrm{O}_2{ }^{2-}\)
18.1 \\
\hline \(\mathrm{~F}_2\)
18.1 \\
\hline
\end{tabular}
So \(\mathrm{O}_2^{2-}\) and \(\mathrm{F}_2\) both are isoelectric species and have bond order 1 .
Karnataka CET 2024
CHEMISTRY(KCET)
285249
The correct decreasing order of boiling point of hydrogen halides is
(c) HF have high boiling point due to strong intermolecular\(\mathrm{H}-\) bonding because of high electronegativity of F . Hence boiling point of HF is abnormally high. Boiling points of other hydrogen halide gradually increases from HCl to HI due to increase in size of halogens atom from Cl to I which furthur increase the magnitude of van der waal's forces.
Karnataka CET 2024
CHEMISTRY(KCET)
285250
Which of the following statement is INCORRECT?
1 Bond length of\(\mathrm{O}_2>\) Bond length of \(\mathrm{O}_2^{2+}\)
2 Bond order of\(\mathrm{O}_2^{+}<\)Bond order of \(\mathrm{O}_2^{2-}\)
3 Bond length of\(\mathrm{O}_2<\) Bond length of \(\mathrm{O}_2^{2-}\)
4 Bond order of\(\mathrm{O}_2>\) Bond order of \(\mathrm{O}_2^{2-}\)
285248
A pair of isoelectric species having bond order of one is:
1 \(\mathrm{N}_2, \mathrm{CO}\)
2 \(\mathrm{N}_2, \mathrm{NO}^{+}\)
3 \(\mathrm{O}_2^{2-}, \mathrm{F}_2\)
4 \(\mathrm{CO}, \mathrm{NO}^{+}\)
Explanation:
(c)Iso electronic species having same number of electron.
\begin{tabular}{|c|c|c|}
\hline Molecule/ions & Total electron & Bond order \\
\hline \(\mathrm{N}_2\)
14.3 \\
\hline CO
14. 3 \\
\hline \(\mathrm{NO}^{+}\)
14. 3 \\
\hline \(\mathrm{O}_2{ }^{2-}\)
18.1 \\
\hline \(\mathrm{~F}_2\)
18.1 \\
\hline
\end{tabular}
So \(\mathrm{O}_2^{2-}\) and \(\mathrm{F}_2\) both are isoelectric species and have bond order 1 .
Karnataka CET 2024
CHEMISTRY(KCET)
285249
The correct decreasing order of boiling point of hydrogen halides is
(c) HF have high boiling point due to strong intermolecular\(\mathrm{H}-\) bonding because of high electronegativity of F . Hence boiling point of HF is abnormally high. Boiling points of other hydrogen halide gradually increases from HCl to HI due to increase in size of halogens atom from Cl to I which furthur increase the magnitude of van der waal's forces.
Karnataka CET 2024
CHEMISTRY(KCET)
285250
Which of the following statement is INCORRECT?
1 Bond length of\(\mathrm{O}_2>\) Bond length of \(\mathrm{O}_2^{2+}\)
2 Bond order of\(\mathrm{O}_2^{+}<\)Bond order of \(\mathrm{O}_2^{2-}\)
3 Bond length of\(\mathrm{O}_2<\) Bond length of \(\mathrm{O}_2^{2-}\)
4 Bond order of\(\mathrm{O}_2>\) Bond order of \(\mathrm{O}_2^{2-}\)
285248
A pair of isoelectric species having bond order of one is:
1 \(\mathrm{N}_2, \mathrm{CO}\)
2 \(\mathrm{N}_2, \mathrm{NO}^{+}\)
3 \(\mathrm{O}_2^{2-}, \mathrm{F}_2\)
4 \(\mathrm{CO}, \mathrm{NO}^{+}\)
Explanation:
(c)Iso electronic species having same number of electron.
\begin{tabular}{|c|c|c|}
\hline Molecule/ions & Total electron & Bond order \\
\hline \(\mathrm{N}_2\)
14.3 \\
\hline CO
14. 3 \\
\hline \(\mathrm{NO}^{+}\)
14. 3 \\
\hline \(\mathrm{O}_2{ }^{2-}\)
18.1 \\
\hline \(\mathrm{~F}_2\)
18.1 \\
\hline
\end{tabular}
So \(\mathrm{O}_2^{2-}\) and \(\mathrm{F}_2\) both are isoelectric species and have bond order 1 .
Karnataka CET 2024
CHEMISTRY(KCET)
285249
The correct decreasing order of boiling point of hydrogen halides is
(c) HF have high boiling point due to strong intermolecular\(\mathrm{H}-\) bonding because of high electronegativity of F . Hence boiling point of HF is abnormally high. Boiling points of other hydrogen halide gradually increases from HCl to HI due to increase in size of halogens atom from Cl to I which furthur increase the magnitude of van der waal's forces.
Karnataka CET 2024
CHEMISTRY(KCET)
285250
Which of the following statement is INCORRECT?
1 Bond length of\(\mathrm{O}_2>\) Bond length of \(\mathrm{O}_2^{2+}\)
2 Bond order of\(\mathrm{O}_2^{+}<\)Bond order of \(\mathrm{O}_2^{2-}\)
3 Bond length of\(\mathrm{O}_2<\) Bond length of \(\mathrm{O}_2^{2-}\)
4 Bond order of\(\mathrm{O}_2>\) Bond order of \(\mathrm{O}_2^{2-}\)
285248
A pair of isoelectric species having bond order of one is:
1 \(\mathrm{N}_2, \mathrm{CO}\)
2 \(\mathrm{N}_2, \mathrm{NO}^{+}\)
3 \(\mathrm{O}_2^{2-}, \mathrm{F}_2\)
4 \(\mathrm{CO}, \mathrm{NO}^{+}\)
Explanation:
(c)Iso electronic species having same number of electron.
\begin{tabular}{|c|c|c|}
\hline Molecule/ions & Total electron & Bond order \\
\hline \(\mathrm{N}_2\)
14.3 \\
\hline CO
14. 3 \\
\hline \(\mathrm{NO}^{+}\)
14. 3 \\
\hline \(\mathrm{O}_2{ }^{2-}\)
18.1 \\
\hline \(\mathrm{~F}_2\)
18.1 \\
\hline
\end{tabular}
So \(\mathrm{O}_2^{2-}\) and \(\mathrm{F}_2\) both are isoelectric species and have bond order 1 .
Karnataka CET 2024
CHEMISTRY(KCET)
285249
The correct decreasing order of boiling point of hydrogen halides is
(c) HF have high boiling point due to strong intermolecular\(\mathrm{H}-\) bonding because of high electronegativity of F . Hence boiling point of HF is abnormally high. Boiling points of other hydrogen halide gradually increases from HCl to HI due to increase in size of halogens atom from Cl to I which furthur increase the magnitude of van der waal's forces.
Karnataka CET 2024
CHEMISTRY(KCET)
285250
Which of the following statement is INCORRECT?
1 Bond length of\(\mathrm{O}_2>\) Bond length of \(\mathrm{O}_2^{2+}\)
2 Bond order of\(\mathrm{O}_2^{+}<\)Bond order of \(\mathrm{O}_2^{2-}\)
3 Bond length of\(\mathrm{O}_2<\) Bond length of \(\mathrm{O}_2^{2-}\)
4 Bond order of\(\mathrm{O}_2>\) Bond order of \(\mathrm{O}_2^{2-}\)
285248
A pair of isoelectric species having bond order of one is:
1 \(\mathrm{N}_2, \mathrm{CO}\)
2 \(\mathrm{N}_2, \mathrm{NO}^{+}\)
3 \(\mathrm{O}_2^{2-}, \mathrm{F}_2\)
4 \(\mathrm{CO}, \mathrm{NO}^{+}\)
Explanation:
(c)Iso electronic species having same number of electron.
\begin{tabular}{|c|c|c|}
\hline Molecule/ions & Total electron & Bond order \\
\hline \(\mathrm{N}_2\)
14.3 \\
\hline CO
14. 3 \\
\hline \(\mathrm{NO}^{+}\)
14. 3 \\
\hline \(\mathrm{O}_2{ }^{2-}\)
18.1 \\
\hline \(\mathrm{~F}_2\)
18.1 \\
\hline
\end{tabular}
So \(\mathrm{O}_2^{2-}\) and \(\mathrm{F}_2\) both are isoelectric species and have bond order 1 .
Karnataka CET 2024
CHEMISTRY(KCET)
285249
The correct decreasing order of boiling point of hydrogen halides is
(c) HF have high boiling point due to strong intermolecular\(\mathrm{H}-\) bonding because of high electronegativity of F . Hence boiling point of HF is abnormally high. Boiling points of other hydrogen halide gradually increases from HCl to HI due to increase in size of halogens atom from Cl to I which furthur increase the magnitude of van der waal's forces.
Karnataka CET 2024
CHEMISTRY(KCET)
285250
Which of the following statement is INCORRECT?
1 Bond length of\(\mathrm{O}_2>\) Bond length of \(\mathrm{O}_2^{2+}\)
2 Bond order of\(\mathrm{O}_2^{+}<\)Bond order of \(\mathrm{O}_2^{2-}\)
3 Bond length of\(\mathrm{O}_2<\) Bond length of \(\mathrm{O}_2^{2-}\)
4 Bond order of\(\mathrm{O}_2>\) Bond order of \(\mathrm{O}_2^{2-}\)
