Young's Double Slit Experiment (YDSE)
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283375 In the Young's double slit experiment, the central maxima is observed to be \(I_0\). If one of the slits is covered, then the intensity at the central maxima will become:

1 \(\frac{\mathrm{I}_0}{2}\)
2 \(\frac{I_0}{\sqrt{2}}\)
3 \(\frac{\mathrm{I}_0}{4}\)
4 \(\mathrm{I}_0\)
5 \(\mathrm{I}_0^2\)
Kerala CEE 2005
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283376 Assertion: In Young's double slit experiment the two slits are at distance d apart, Interference pattern is observed on a screen at distance \(D\) from the slits. At a point on the screen when it is directly opposite to one of the slits, a dark fringe is observed. Then, the wavelength of wave is proportional to square of distance of two slits.
Reason: For a dark fringe intensity is zero.

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
AIIMS-2008
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283378 In Young's double slit experiment, we get 10 fringes in the field of view of monochromatic light of wavelength \(4000 \AA\). If we use monochromatic light of wave length \(5000 \AA\), then the number of fringes obtained in the same field of view is

1 8
2 10
3 40
4 50
AIIMS-2014
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283380 In Young's expt., the distance between two slits is \(\frac{d}{3}\) and the distance between the screen and the slist is 3D. The number of fringes in \(\frac{1}{3} \mathrm{~m}\) on the screen, formed by monochromatic light of wavelength \(3 \lambda\), will be

1 \(\frac{\mathrm{d}}{9 \mathrm{D} \lambda}\)
2 \(\frac{d}{27 \mathrm{D} \lambda}\)
3 \(\frac{\mathrm{d}}{81 \mathrm{D} \lambda}\)
4 \(\frac{\mathrm{d}}{\mathrm{D} \lambda}\)
AIIMS-2012
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283375 In the Young's double slit experiment, the central maxima is observed to be \(I_0\). If one of the slits is covered, then the intensity at the central maxima will become:

1 \(\frac{\mathrm{I}_0}{2}\)
2 \(\frac{I_0}{\sqrt{2}}\)
3 \(\frac{\mathrm{I}_0}{4}\)
4 \(\mathrm{I}_0\)
5 \(\mathrm{I}_0^2\)
Kerala CEE 2005
WAVE OPTICS

283376 Assertion: In Young's double slit experiment the two slits are at distance d apart, Interference pattern is observed on a screen at distance \(D\) from the slits. At a point on the screen when it is directly opposite to one of the slits, a dark fringe is observed. Then, the wavelength of wave is proportional to square of distance of two slits.
Reason: For a dark fringe intensity is zero.

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
AIIMS-2008
WAVE OPTICS

283378 In Young's double slit experiment, we get 10 fringes in the field of view of monochromatic light of wavelength \(4000 \AA\). If we use monochromatic light of wave length \(5000 \AA\), then the number of fringes obtained in the same field of view is

1 8
2 10
3 40
4 50
AIIMS-2014
WAVE OPTICS

283380 In Young's expt., the distance between two slits is \(\frac{d}{3}\) and the distance between the screen and the slist is 3D. The number of fringes in \(\frac{1}{3} \mathrm{~m}\) on the screen, formed by monochromatic light of wavelength \(3 \lambda\), will be

1 \(\frac{\mathrm{d}}{9 \mathrm{D} \lambda}\)
2 \(\frac{d}{27 \mathrm{D} \lambda}\)
3 \(\frac{\mathrm{d}}{81 \mathrm{D} \lambda}\)
4 \(\frac{\mathrm{d}}{\mathrm{D} \lambda}\)
AIIMS-2012
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283375 In the Young's double slit experiment, the central maxima is observed to be \(I_0\). If one of the slits is covered, then the intensity at the central maxima will become:

1 \(\frac{\mathrm{I}_0}{2}\)
2 \(\frac{I_0}{\sqrt{2}}\)
3 \(\frac{\mathrm{I}_0}{4}\)
4 \(\mathrm{I}_0\)
5 \(\mathrm{I}_0^2\)
Kerala CEE 2005
WAVE OPTICS

283376 Assertion: In Young's double slit experiment the two slits are at distance d apart, Interference pattern is observed on a screen at distance \(D\) from the slits. At a point on the screen when it is directly opposite to one of the slits, a dark fringe is observed. Then, the wavelength of wave is proportional to square of distance of two slits.
Reason: For a dark fringe intensity is zero.

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
AIIMS-2008
WAVE OPTICS

283378 In Young's double slit experiment, we get 10 fringes in the field of view of monochromatic light of wavelength \(4000 \AA\). If we use monochromatic light of wave length \(5000 \AA\), then the number of fringes obtained in the same field of view is

1 8
2 10
3 40
4 50
AIIMS-2014
WAVE OPTICS

283380 In Young's expt., the distance between two slits is \(\frac{d}{3}\) and the distance between the screen and the slist is 3D. The number of fringes in \(\frac{1}{3} \mathrm{~m}\) on the screen, formed by monochromatic light of wavelength \(3 \lambda\), will be

1 \(\frac{\mathrm{d}}{9 \mathrm{D} \lambda}\)
2 \(\frac{d}{27 \mathrm{D} \lambda}\)
3 \(\frac{\mathrm{d}}{81 \mathrm{D} \lambda}\)
4 \(\frac{\mathrm{d}}{\mathrm{D} \lambda}\)
AIIMS-2012
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WAVE OPTICS

283375 In the Young's double slit experiment, the central maxima is observed to be \(I_0\). If one of the slits is covered, then the intensity at the central maxima will become:

1 \(\frac{\mathrm{I}_0}{2}\)
2 \(\frac{I_0}{\sqrt{2}}\)
3 \(\frac{\mathrm{I}_0}{4}\)
4 \(\mathrm{I}_0\)
5 \(\mathrm{I}_0^2\)
Kerala CEE 2005
WAVE OPTICS

283376 Assertion: In Young's double slit experiment the two slits are at distance d apart, Interference pattern is observed on a screen at distance \(D\) from the slits. At a point on the screen when it is directly opposite to one of the slits, a dark fringe is observed. Then, the wavelength of wave is proportional to square of distance of two slits.
Reason: For a dark fringe intensity is zero.

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
AIIMS-2008
WAVE OPTICS

283378 In Young's double slit experiment, we get 10 fringes in the field of view of monochromatic light of wavelength \(4000 \AA\). If we use monochromatic light of wave length \(5000 \AA\), then the number of fringes obtained in the same field of view is

1 8
2 10
3 40
4 50
AIIMS-2014
WAVE OPTICS

283380 In Young's expt., the distance between two slits is \(\frac{d}{3}\) and the distance between the screen and the slist is 3D. The number of fringes in \(\frac{1}{3} \mathrm{~m}\) on the screen, formed by monochromatic light of wavelength \(3 \lambda\), will be

1 \(\frac{\mathrm{d}}{9 \mathrm{D} \lambda}\)
2 \(\frac{d}{27 \mathrm{D} \lambda}\)
3 \(\frac{\mathrm{d}}{81 \mathrm{D} \lambda}\)
4 \(\frac{\mathrm{d}}{\mathrm{D} \lambda}\)
AIIMS-2012
For More Updates join with Us