283370 If the distance between the first maxima and fifth minima of a double slit pattern is \(7 \mathrm{~mm}\) and the slits are separated by \(0.15 \mathrm{~mm}\) with the screen \(50 \mathrm{~cm}\). from the slits, then the wavelength of the light used is :

283371 In Young's double slit experiment 10th order maximum is obtained at the point of observation in the interference pattern for \(\lambda=\) \(7000 \AA\). If the source is replaced by another one of wavelength \(5000 \AA\) then the order of maximum at the same point will be-

283373 Calculate the wavelength of light used in an interference experiment from the following data: Fringe width \(=0.03 \mathrm{~cm}\). Distance between the slits and eyepiece through which the interference pattern is observed is \(1 \mathrm{~m}\). Distance between the images of the virtual source when a convex lens of focal length \(16 \mathrm{~cm}\) is used at a distance of \(80 \mathrm{~cm}\) from the eyepiece is \(0.8 \mathrm{~cm}\).

283374 In a YDSE, the light of wavelength \(\lambda=5000 \AA\) is used, which emerges in phase from two slits a distance \(d=3 \times 10^{-7} \mathrm{~m}\) apart. A transparent sheet of thickness \(t=1.5 \times 10^{-7} \mathrm{~m}\) refractive index \(\mu=1.17\) is placed over one of the slits what is the new angular position of the central maxima of the interference pattern, from the centre of the screen? Find the value of \(y\).

283370 If the distance between the first maxima and fifth minima of a double slit pattern is \(7 \mathrm{~mm}\) and the slits are separated by \(0.15 \mathrm{~mm}\) with the screen \(50 \mathrm{~cm}\). from the slits, then the wavelength of the light used is :

283371 In Young's double slit experiment 10th order maximum is obtained at the point of observation in the interference pattern for \(\lambda=\) \(7000 \AA\). If the source is replaced by another one of wavelength \(5000 \AA\) then the order of maximum at the same point will be-

283373 Calculate the wavelength of light used in an interference experiment from the following data: Fringe width \(=0.03 \mathrm{~cm}\). Distance between the slits and eyepiece through which the interference pattern is observed is \(1 \mathrm{~m}\). Distance between the images of the virtual source when a convex lens of focal length \(16 \mathrm{~cm}\) is used at a distance of \(80 \mathrm{~cm}\) from the eyepiece is \(0.8 \mathrm{~cm}\).

283374 In a YDSE, the light of wavelength \(\lambda=5000 \AA\) is used, which emerges in phase from two slits a distance \(d=3 \times 10^{-7} \mathrm{~m}\) apart. A transparent sheet of thickness \(t=1.5 \times 10^{-7} \mathrm{~m}\) refractive index \(\mu=1.17\) is placed over one of the slits what is the new angular position of the central maxima of the interference pattern, from the centre of the screen? Find the value of \(y\).

283370 If the distance between the first maxima and fifth minima of a double slit pattern is \(7 \mathrm{~mm}\) and the slits are separated by \(0.15 \mathrm{~mm}\) with the screen \(50 \mathrm{~cm}\). from the slits, then the wavelength of the light used is :

283371 In Young's double slit experiment 10th order maximum is obtained at the point of observation in the interference pattern for \(\lambda=\) \(7000 \AA\). If the source is replaced by another one of wavelength \(5000 \AA\) then the order of maximum at the same point will be-

283373 Calculate the wavelength of light used in an interference experiment from the following data: Fringe width \(=0.03 \mathrm{~cm}\). Distance between the slits and eyepiece through which the interference pattern is observed is \(1 \mathrm{~m}\). Distance between the images of the virtual source when a convex lens of focal length \(16 \mathrm{~cm}\) is used at a distance of \(80 \mathrm{~cm}\) from the eyepiece is \(0.8 \mathrm{~cm}\).

283374 In a YDSE, the light of wavelength \(\lambda=5000 \AA\) is used, which emerges in phase from two slits a distance \(d=3 \times 10^{-7} \mathrm{~m}\) apart. A transparent sheet of thickness \(t=1.5 \times 10^{-7} \mathrm{~m}\) refractive index \(\mu=1.17\) is placed over one of the slits what is the new angular position of the central maxima of the interference pattern, from the centre of the screen? Find the value of \(y\).

283370 If the distance between the first maxima and fifth minima of a double slit pattern is \(7 \mathrm{~mm}\) and the slits are separated by \(0.15 \mathrm{~mm}\) with the screen \(50 \mathrm{~cm}\). from the slits, then the wavelength of the light used is :

283371 In Young's double slit experiment 10th order maximum is obtained at the point of observation in the interference pattern for \(\lambda=\) \(7000 \AA\). If the source is replaced by another one of wavelength \(5000 \AA\) then the order of maximum at the same point will be-

283373 Calculate the wavelength of light used in an interference experiment from the following data: Fringe width \(=0.03 \mathrm{~cm}\). Distance between the slits and eyepiece through which the interference pattern is observed is \(1 \mathrm{~m}\). Distance between the images of the virtual source when a convex lens of focal length \(16 \mathrm{~cm}\) is used at a distance of \(80 \mathrm{~cm}\) from the eyepiece is \(0.8 \mathrm{~cm}\).

283374 In a YDSE, the light of wavelength \(\lambda=5000 \AA\) is used, which emerges in phase from two slits a distance \(d=3 \times 10^{-7} \mathrm{~m}\) apart. A transparent sheet of thickness \(t=1.5 \times 10^{-7} \mathrm{~m}\) refractive index \(\mu=1.17\) is placed over one of the slits what is the new angular position of the central maxima of the interference pattern, from the centre of the screen? Find the value of \(y\).