282912
The minimum intensity of light to be detected by human eye is \(10^{-10} \mathrm{~W} / \mathrm{m}^2\). The number of photon of wavelength \(5.6 \times 10^{-7} \mathrm{~m}\) entering the eye, with pupil area \(10^{-6} \mathrm{~m}^2\), per second for vision will be nearly
282913
An observer loop at a tree of height \(15 \mathrm{~m}\) with a telescope of magnifying power 10 . To him the tree appears
1 10 times taller
2 15 times taller
3 10 times nearer
4 15 times nearer
Explanation:
C: Given,
Height of tree \((\mathrm{h})=15 \mathrm{~m}\)
Magnifying power \((\mathrm{m})=20\)
The angle subtended at the eye becomes 10 times larger, this happens only when the tree appears 10 times nearer
Manipal UGET-2013
Ray Optics
282914
When the wavelength of sound changes from 1 \(m\) to \(1.01 \mathrm{~m}\), the number of beats heard are 4 . The velocity of sound is
1 \(404 \mathrm{~m} / \mathrm{s}\)
2 \(4.04 \mathrm{~m} / \mathrm{s}\)
3 \(414 \mathrm{~m} / \mathrm{s}\)
4 \(400 \mathrm{~m} / \mathrm{s}\)
Explanation:
A: Given, \(\lambda_1=1 \mathrm{~m}\) and \(\lambda_2=1.01 \mathrm{~m}\) beats \((\mathrm{b})=4\)
No. of beats \((b)=v\left(\frac{1}{\lambda_1}-\frac{1}{\lambda_2}\right)\)
\(4=\mathrm{v}\left(\frac{1}{1}-\frac{1}{1.01}\right)\)
\(\mathrm{v}=\frac{4}{\left(1-\frac{1}{1.01}\right)}\)
\(\mathrm{v}=404 \mathrm{~m} / \mathrm{s}\)
Manipal UGET-2010
Ray Optics
282929
Which of the statements is incorrect about the simple microscope?
1 Biology students use to see the slides.
2 It is not used for magnification of an object at far away from the observer.
3 Magnification of microscope is inversely proportional to the least distance of distinct vision.
4 A convex lens of microscope with sorter focal length yields higher magnification.
Explanation:
C: Magnification,
\(\mathrm{m}=1+\frac{\mathrm{D}}{\mathrm{f}}\)
Where, \(\mathrm{D}=\) least distance of distinct vision
UPSEE - 2016
Ray Optics
282930
The resolving power of telescope depends on
1 focal length of eye lens
2 focal length of objective lens
3 length of the telescope
4 diameter of the objective lens
Explanation:
D: Resolving power \(\alpha=\frac{\mathrm{d}}{1.22 \lambda}\)
Where, \(\mathrm{d}=\) diameter of objective lens.
282912
The minimum intensity of light to be detected by human eye is \(10^{-10} \mathrm{~W} / \mathrm{m}^2\). The number of photon of wavelength \(5.6 \times 10^{-7} \mathrm{~m}\) entering the eye, with pupil area \(10^{-6} \mathrm{~m}^2\), per second for vision will be nearly
282913
An observer loop at a tree of height \(15 \mathrm{~m}\) with a telescope of magnifying power 10 . To him the tree appears
1 10 times taller
2 15 times taller
3 10 times nearer
4 15 times nearer
Explanation:
C: Given,
Height of tree \((\mathrm{h})=15 \mathrm{~m}\)
Magnifying power \((\mathrm{m})=20\)
The angle subtended at the eye becomes 10 times larger, this happens only when the tree appears 10 times nearer
Manipal UGET-2013
Ray Optics
282914
When the wavelength of sound changes from 1 \(m\) to \(1.01 \mathrm{~m}\), the number of beats heard are 4 . The velocity of sound is
1 \(404 \mathrm{~m} / \mathrm{s}\)
2 \(4.04 \mathrm{~m} / \mathrm{s}\)
3 \(414 \mathrm{~m} / \mathrm{s}\)
4 \(400 \mathrm{~m} / \mathrm{s}\)
Explanation:
A: Given, \(\lambda_1=1 \mathrm{~m}\) and \(\lambda_2=1.01 \mathrm{~m}\) beats \((\mathrm{b})=4\)
No. of beats \((b)=v\left(\frac{1}{\lambda_1}-\frac{1}{\lambda_2}\right)\)
\(4=\mathrm{v}\left(\frac{1}{1}-\frac{1}{1.01}\right)\)
\(\mathrm{v}=\frac{4}{\left(1-\frac{1}{1.01}\right)}\)
\(\mathrm{v}=404 \mathrm{~m} / \mathrm{s}\)
Manipal UGET-2010
Ray Optics
282929
Which of the statements is incorrect about the simple microscope?
1 Biology students use to see the slides.
2 It is not used for magnification of an object at far away from the observer.
3 Magnification of microscope is inversely proportional to the least distance of distinct vision.
4 A convex lens of microscope with sorter focal length yields higher magnification.
Explanation:
C: Magnification,
\(\mathrm{m}=1+\frac{\mathrm{D}}{\mathrm{f}}\)
Where, \(\mathrm{D}=\) least distance of distinct vision
UPSEE - 2016
Ray Optics
282930
The resolving power of telescope depends on
1 focal length of eye lens
2 focal length of objective lens
3 length of the telescope
4 diameter of the objective lens
Explanation:
D: Resolving power \(\alpha=\frac{\mathrm{d}}{1.22 \lambda}\)
Where, \(\mathrm{d}=\) diameter of objective lens.
282912
The minimum intensity of light to be detected by human eye is \(10^{-10} \mathrm{~W} / \mathrm{m}^2\). The number of photon of wavelength \(5.6 \times 10^{-7} \mathrm{~m}\) entering the eye, with pupil area \(10^{-6} \mathrm{~m}^2\), per second for vision will be nearly
282913
An observer loop at a tree of height \(15 \mathrm{~m}\) with a telescope of magnifying power 10 . To him the tree appears
1 10 times taller
2 15 times taller
3 10 times nearer
4 15 times nearer
Explanation:
C: Given,
Height of tree \((\mathrm{h})=15 \mathrm{~m}\)
Magnifying power \((\mathrm{m})=20\)
The angle subtended at the eye becomes 10 times larger, this happens only when the tree appears 10 times nearer
Manipal UGET-2013
Ray Optics
282914
When the wavelength of sound changes from 1 \(m\) to \(1.01 \mathrm{~m}\), the number of beats heard are 4 . The velocity of sound is
1 \(404 \mathrm{~m} / \mathrm{s}\)
2 \(4.04 \mathrm{~m} / \mathrm{s}\)
3 \(414 \mathrm{~m} / \mathrm{s}\)
4 \(400 \mathrm{~m} / \mathrm{s}\)
Explanation:
A: Given, \(\lambda_1=1 \mathrm{~m}\) and \(\lambda_2=1.01 \mathrm{~m}\) beats \((\mathrm{b})=4\)
No. of beats \((b)=v\left(\frac{1}{\lambda_1}-\frac{1}{\lambda_2}\right)\)
\(4=\mathrm{v}\left(\frac{1}{1}-\frac{1}{1.01}\right)\)
\(\mathrm{v}=\frac{4}{\left(1-\frac{1}{1.01}\right)}\)
\(\mathrm{v}=404 \mathrm{~m} / \mathrm{s}\)
Manipal UGET-2010
Ray Optics
282929
Which of the statements is incorrect about the simple microscope?
1 Biology students use to see the slides.
2 It is not used for magnification of an object at far away from the observer.
3 Magnification of microscope is inversely proportional to the least distance of distinct vision.
4 A convex lens of microscope with sorter focal length yields higher magnification.
Explanation:
C: Magnification,
\(\mathrm{m}=1+\frac{\mathrm{D}}{\mathrm{f}}\)
Where, \(\mathrm{D}=\) least distance of distinct vision
UPSEE - 2016
Ray Optics
282930
The resolving power of telescope depends on
1 focal length of eye lens
2 focal length of objective lens
3 length of the telescope
4 diameter of the objective lens
Explanation:
D: Resolving power \(\alpha=\frac{\mathrm{d}}{1.22 \lambda}\)
Where, \(\mathrm{d}=\) diameter of objective lens.
282912
The minimum intensity of light to be detected by human eye is \(10^{-10} \mathrm{~W} / \mathrm{m}^2\). The number of photon of wavelength \(5.6 \times 10^{-7} \mathrm{~m}\) entering the eye, with pupil area \(10^{-6} \mathrm{~m}^2\), per second for vision will be nearly
282913
An observer loop at a tree of height \(15 \mathrm{~m}\) with a telescope of magnifying power 10 . To him the tree appears
1 10 times taller
2 15 times taller
3 10 times nearer
4 15 times nearer
Explanation:
C: Given,
Height of tree \((\mathrm{h})=15 \mathrm{~m}\)
Magnifying power \((\mathrm{m})=20\)
The angle subtended at the eye becomes 10 times larger, this happens only when the tree appears 10 times nearer
Manipal UGET-2013
Ray Optics
282914
When the wavelength of sound changes from 1 \(m\) to \(1.01 \mathrm{~m}\), the number of beats heard are 4 . The velocity of sound is
1 \(404 \mathrm{~m} / \mathrm{s}\)
2 \(4.04 \mathrm{~m} / \mathrm{s}\)
3 \(414 \mathrm{~m} / \mathrm{s}\)
4 \(400 \mathrm{~m} / \mathrm{s}\)
Explanation:
A: Given, \(\lambda_1=1 \mathrm{~m}\) and \(\lambda_2=1.01 \mathrm{~m}\) beats \((\mathrm{b})=4\)
No. of beats \((b)=v\left(\frac{1}{\lambda_1}-\frac{1}{\lambda_2}\right)\)
\(4=\mathrm{v}\left(\frac{1}{1}-\frac{1}{1.01}\right)\)
\(\mathrm{v}=\frac{4}{\left(1-\frac{1}{1.01}\right)}\)
\(\mathrm{v}=404 \mathrm{~m} / \mathrm{s}\)
Manipal UGET-2010
Ray Optics
282929
Which of the statements is incorrect about the simple microscope?
1 Biology students use to see the slides.
2 It is not used for magnification of an object at far away from the observer.
3 Magnification of microscope is inversely proportional to the least distance of distinct vision.
4 A convex lens of microscope with sorter focal length yields higher magnification.
Explanation:
C: Magnification,
\(\mathrm{m}=1+\frac{\mathrm{D}}{\mathrm{f}}\)
Where, \(\mathrm{D}=\) least distance of distinct vision
UPSEE - 2016
Ray Optics
282930
The resolving power of telescope depends on
1 focal length of eye lens
2 focal length of objective lens
3 length of the telescope
4 diameter of the objective lens
Explanation:
D: Resolving power \(\alpha=\frac{\mathrm{d}}{1.22 \lambda}\)
Where, \(\mathrm{d}=\) diameter of objective lens.
282912
The minimum intensity of light to be detected by human eye is \(10^{-10} \mathrm{~W} / \mathrm{m}^2\). The number of photon of wavelength \(5.6 \times 10^{-7} \mathrm{~m}\) entering the eye, with pupil area \(10^{-6} \mathrm{~m}^2\), per second for vision will be nearly
282913
An observer loop at a tree of height \(15 \mathrm{~m}\) with a telescope of magnifying power 10 . To him the tree appears
1 10 times taller
2 15 times taller
3 10 times nearer
4 15 times nearer
Explanation:
C: Given,
Height of tree \((\mathrm{h})=15 \mathrm{~m}\)
Magnifying power \((\mathrm{m})=20\)
The angle subtended at the eye becomes 10 times larger, this happens only when the tree appears 10 times nearer
Manipal UGET-2013
Ray Optics
282914
When the wavelength of sound changes from 1 \(m\) to \(1.01 \mathrm{~m}\), the number of beats heard are 4 . The velocity of sound is
1 \(404 \mathrm{~m} / \mathrm{s}\)
2 \(4.04 \mathrm{~m} / \mathrm{s}\)
3 \(414 \mathrm{~m} / \mathrm{s}\)
4 \(400 \mathrm{~m} / \mathrm{s}\)
Explanation:
A: Given, \(\lambda_1=1 \mathrm{~m}\) and \(\lambda_2=1.01 \mathrm{~m}\) beats \((\mathrm{b})=4\)
No. of beats \((b)=v\left(\frac{1}{\lambda_1}-\frac{1}{\lambda_2}\right)\)
\(4=\mathrm{v}\left(\frac{1}{1}-\frac{1}{1.01}\right)\)
\(\mathrm{v}=\frac{4}{\left(1-\frac{1}{1.01}\right)}\)
\(\mathrm{v}=404 \mathrm{~m} / \mathrm{s}\)
Manipal UGET-2010
Ray Optics
282929
Which of the statements is incorrect about the simple microscope?
1 Biology students use to see the slides.
2 It is not used for magnification of an object at far away from the observer.
3 Magnification of microscope is inversely proportional to the least distance of distinct vision.
4 A convex lens of microscope with sorter focal length yields higher magnification.
Explanation:
C: Magnification,
\(\mathrm{m}=1+\frac{\mathrm{D}}{\mathrm{f}}\)
Where, \(\mathrm{D}=\) least distance of distinct vision
UPSEE - 2016
Ray Optics
282930
The resolving power of telescope depends on
1 focal length of eye lens
2 focal length of objective lens
3 length of the telescope
4 diameter of the objective lens
Explanation:
D: Resolving power \(\alpha=\frac{\mathrm{d}}{1.22 \lambda}\)
Where, \(\mathrm{d}=\) diameter of objective lens.
