Spherical Surface and Lenses, Lens Formula, Magnification, Combination of Lens.
Ray Optics

282341 Double-convex lenses are to be manufactured from a glass of refractive index 1.55 with both faces of the same radius of curvature. What is the radius of curvature required if the focal length is to be \(20 \mathrm{~cm}\) ?

1 \(44 \mathrm{~cm}\)
2 \(2.2 \mathrm{~cm}\)
3 \(22 \mathrm{~cm}\)
4 \(4.4 \mathrm{~cm}\)
Ray Optics

282342 Light from a point source in air falls on a spherical glass surface \((n=1.5\) and radius of curvature \(=20 \mathrm{~cm}\) ). the distance of the light source from the glass surface is \(100 \mathrm{~cm}\). Find the image distance.

1 \(-100 \mathrm{~cm}\)
2 \(-200 \mathrm{~cm}\)
3 \(200 \mathrm{~cm}\)
4 \(100 \mathrm{~cm}\)
Ray Optics

282343 A convex lens of focal length ' \(f\) ' is placed somewhere in between an object and a screen, the distance between the object and the screen is ' \(x\) '. If the numerical value of the magnification produced by the lens is ' \(m\) ', then the focal length of the lens is

1 \(\frac{(m+1)^2 x}{m}\)
2 \(\frac{(m-1)^2 x}{m}\)
3 \(\frac{\mathrm{mx}}{(\mathrm{m}+1)^2}\)
4 \(\frac{m x}{(m-1)^2}\)
Ray Optics

282344 A thin convex lens made from crown glass \(\left(\mu=\frac{3}{2}\right)\) has focal length \(f\). When it is measured in two different liquids having refractive indices \(\frac{4}{3}\) and \(\frac{5}{3}\) it has the focal lengths \(f_1\) and \(f_2\) respectively. The correct relation between the focal lengths is.

1 \(f_2>\) f.f \(f_1\) becomes negative
2 \(f_1\) and \(f_2\) both become negative
3 \(f_1>f\) and \(f_2\) become negative
4 \(\mathrm{f}_1=\mathrm{f}_2<\mathrm{f}\)
Ray Optics

282341 Double-convex lenses are to be manufactured from a glass of refractive index 1.55 with both faces of the same radius of curvature. What is the radius of curvature required if the focal length is to be \(20 \mathrm{~cm}\) ?

1 \(44 \mathrm{~cm}\)
2 \(2.2 \mathrm{~cm}\)
3 \(22 \mathrm{~cm}\)
4 \(4.4 \mathrm{~cm}\)
Ray Optics

282342 Light from a point source in air falls on a spherical glass surface \((n=1.5\) and radius of curvature \(=20 \mathrm{~cm}\) ). the distance of the light source from the glass surface is \(100 \mathrm{~cm}\). Find the image distance.

1 \(-100 \mathrm{~cm}\)
2 \(-200 \mathrm{~cm}\)
3 \(200 \mathrm{~cm}\)
4 \(100 \mathrm{~cm}\)
Ray Optics

282343 A convex lens of focal length ' \(f\) ' is placed somewhere in between an object and a screen, the distance between the object and the screen is ' \(x\) '. If the numerical value of the magnification produced by the lens is ' \(m\) ', then the focal length of the lens is

1 \(\frac{(m+1)^2 x}{m}\)
2 \(\frac{(m-1)^2 x}{m}\)
3 \(\frac{\mathrm{mx}}{(\mathrm{m}+1)^2}\)
4 \(\frac{m x}{(m-1)^2}\)
Ray Optics

282344 A thin convex lens made from crown glass \(\left(\mu=\frac{3}{2}\right)\) has focal length \(f\). When it is measured in two different liquids having refractive indices \(\frac{4}{3}\) and \(\frac{5}{3}\) it has the focal lengths \(f_1\) and \(f_2\) respectively. The correct relation between the focal lengths is.

1 \(f_2>\) f.f \(f_1\) becomes negative
2 \(f_1\) and \(f_2\) both become negative
3 \(f_1>f\) and \(f_2\) become negative
4 \(\mathrm{f}_1=\mathrm{f}_2<\mathrm{f}\)
Ray Optics

282341 Double-convex lenses are to be manufactured from a glass of refractive index 1.55 with both faces of the same radius of curvature. What is the radius of curvature required if the focal length is to be \(20 \mathrm{~cm}\) ?

1 \(44 \mathrm{~cm}\)
2 \(2.2 \mathrm{~cm}\)
3 \(22 \mathrm{~cm}\)
4 \(4.4 \mathrm{~cm}\)
Ray Optics

282342 Light from a point source in air falls on a spherical glass surface \((n=1.5\) and radius of curvature \(=20 \mathrm{~cm}\) ). the distance of the light source from the glass surface is \(100 \mathrm{~cm}\). Find the image distance.

1 \(-100 \mathrm{~cm}\)
2 \(-200 \mathrm{~cm}\)
3 \(200 \mathrm{~cm}\)
4 \(100 \mathrm{~cm}\)
Ray Optics

282343 A convex lens of focal length ' \(f\) ' is placed somewhere in between an object and a screen, the distance between the object and the screen is ' \(x\) '. If the numerical value of the magnification produced by the lens is ' \(m\) ', then the focal length of the lens is

1 \(\frac{(m+1)^2 x}{m}\)
2 \(\frac{(m-1)^2 x}{m}\)
3 \(\frac{\mathrm{mx}}{(\mathrm{m}+1)^2}\)
4 \(\frac{m x}{(m-1)^2}\)
Ray Optics

282344 A thin convex lens made from crown glass \(\left(\mu=\frac{3}{2}\right)\) has focal length \(f\). When it is measured in two different liquids having refractive indices \(\frac{4}{3}\) and \(\frac{5}{3}\) it has the focal lengths \(f_1\) and \(f_2\) respectively. The correct relation between the focal lengths is.

1 \(f_2>\) f.f \(f_1\) becomes negative
2 \(f_1\) and \(f_2\) both become negative
3 \(f_1>f\) and \(f_2\) become negative
4 \(\mathrm{f}_1=\mathrm{f}_2<\mathrm{f}\)
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Ray Optics

282341 Double-convex lenses are to be manufactured from a glass of refractive index 1.55 with both faces of the same radius of curvature. What is the radius of curvature required if the focal length is to be \(20 \mathrm{~cm}\) ?

1 \(44 \mathrm{~cm}\)
2 \(2.2 \mathrm{~cm}\)
3 \(22 \mathrm{~cm}\)
4 \(4.4 \mathrm{~cm}\)
Ray Optics

282342 Light from a point source in air falls on a spherical glass surface \((n=1.5\) and radius of curvature \(=20 \mathrm{~cm}\) ). the distance of the light source from the glass surface is \(100 \mathrm{~cm}\). Find the image distance.

1 \(-100 \mathrm{~cm}\)
2 \(-200 \mathrm{~cm}\)
3 \(200 \mathrm{~cm}\)
4 \(100 \mathrm{~cm}\)
Ray Optics

282343 A convex lens of focal length ' \(f\) ' is placed somewhere in between an object and a screen, the distance between the object and the screen is ' \(x\) '. If the numerical value of the magnification produced by the lens is ' \(m\) ', then the focal length of the lens is

1 \(\frac{(m+1)^2 x}{m}\)
2 \(\frac{(m-1)^2 x}{m}\)
3 \(\frac{\mathrm{mx}}{(\mathrm{m}+1)^2}\)
4 \(\frac{m x}{(m-1)^2}\)
Ray Optics

282344 A thin convex lens made from crown glass \(\left(\mu=\frac{3}{2}\right)\) has focal length \(f\). When it is measured in two different liquids having refractive indices \(\frac{4}{3}\) and \(\frac{5}{3}\) it has the focal lengths \(f_1\) and \(f_2\) respectively. The correct relation between the focal lengths is.

1 \(f_2>\) f.f \(f_1\) becomes negative
2 \(f_1\) and \(f_2\) both become negative
3 \(f_1>f\) and \(f_2\) become negative
4 \(\mathrm{f}_1=\mathrm{f}_2<\mathrm{f}\)