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Ray Optics

282316 The twinkling effect of star light is due to

1 total internal reflection

2 high dense matter of star

3 constant burning of hydrogen in the star

4 the fluctuating apparent position of the star being slightly different from the actual position of the star

JCECE-2009

Ray Optics

282317 An optical fiber can offer a band width of

1

250 MHz

2

100 GHz

3

750 MHz

4

100 MHz

Explanation:

B: An optical fibre can offer a bond width of $100 GHz$ .
Optical fibre- It is a cylindrical dielectric waveguide (non-conducting waveguide) that transmits light along its axis through the process of total internal reflection.

GUJCET 2016

Ray Optics

282201 Light travels a distance $x$ in time $t_{1}$ in air and $10 x$ in time $t_{2}$ in another denser medium. What is the critical angle for this medium?

1

\sin^{- 1} (\frac{10 t_{1}}{t_{2}})

2

\sin^{- 1} (\frac{t_{2}}{t_{1}})

3

\sin^{- 1} (\frac{10 t_{2}}{t_{1}})

4

\sin^{- 1} (\frac{t_{1}}{10 t_{2}})

Explanation:

A: Let the speed of light through vacuum be c then,
$c = \frac{x}{t_{1}}$
and let the speed of light through the medium be $v$ then-
$v = \frac{10 x}{t_{2}}$
So, absolute refractive index $(μ)$ of the medium can be calculated by -
$\begin{matrix} μ = \frac{c}{v} \\ μ = \frac{\frac{x}{t_{1}}}{\frac{10 x}{t_{2}}} \\ μ = \frac{t_{2}}{10 t_{1}} \end{matrix}$
Now, the critical angle is given by -
$\begin{array}{r} \sin θ_{c} = \frac{1}{μ} \\ \sin θ_{c} = \frac{1}{\frac{t_{2}}{10 t_{1}}} \\ \sin θ_{c} = \frac{10 t_{1}}{t_{2}} \\ θ_{c} = \sin^{- 1} \frac{10 t_{1}}{t_{2}} \end{array}$

NEET (UG) 07.05.2023

Ray Optics

282202 A microscope is focused on an object at the bottom of a bucket. If liquid with refractive index $\frac{5}{3}$ is poured inside the bucket, then microscope have to be raised by $30 cm$ to focus the object again. The height of the liquid in the bucket is:

1

12 cm

2

18 cm

3

50 cm

4

75 cm

Explanation:

D: Given,

Refractive index $(μ) = \frac{5}{3}, d = 30 cm$
We know that,
$\begin{array}{r} d = h (1 - \frac{1}{μ}) \\ 30 = h (1 - \frac{3}{5}) \\ 30 = h (\frac{5 - 3}{5}) \\ 30 = h (\frac{2}{5}) \\ \frac{30 \times 5}{2} = h \\ h = 75 cm \end{array}$

JEE Main-31.01.2023

Ray Optics

282203 A vessel of depth 'd' is half filled with oil of refractive index $n_{1}$ and the other half is filled with water of refractive index $n_{2}$ . The apparent depth of this vessel when viewed from above will be -

1

\frac{{dn}_{1} n_{2}}{(n_{1} + n_{2})}

2

\frac{d (n_{1} + n_{2})}{2 n_{1} n_{2}}

3

\frac{{dn}_{1} n_{2}}{2 (n_{1} + n_{2})}

4

\frac{2 d (n_{1} + n_{2})}{n_{1} n_{2}}

Explanation:

B: Given,
Refractive index of oil $= n_{1}$
Refractive index of water $= n_{2}$

${(d_{app})}_{1} = \frac{d}{2 (\frac{n_{1}}{n_{2}})}$
${(d_{app})}_{1} = \frac{n_{2} d}{2 n_{1}}$
${(d_{app})}_{2} = \frac{{(d_{app})}_{1} + d / 2}{n_{2}}$
$\begin{array}{r} = \frac{(\frac{n_{2}}{n_{1}}) \frac{d}{2} + \frac{d}{2}}{n_{2}} \\ = \frac{d (n_{1} + n_{2})}{2 n_{1} n_{2}} \end{array}$

JEE Main-13.04.2023

Ray Optics

282316 The twinkling effect of star light is due to

1 total internal reflection

2 high dense matter of star

3 constant burning of hydrogen in the star

4 the fluctuating apparent position of the star being slightly different from the actual position of the star

JCECE-2009

Ray Optics

282317 An optical fiber can offer a band width of

1

250 MHz

2

100 GHz

3

750 MHz

4

100 MHz

Explanation:

B: An optical fibre can offer a bond width of $100 GHz$ .
Optical fibre- It is a cylindrical dielectric waveguide (non-conducting waveguide) that transmits light along its axis through the process of total internal reflection.

GUJCET 2016

Ray Optics

282201 Light travels a distance $x$ in time $t_{1}$ in air and $10 x$ in time $t_{2}$ in another denser medium. What is the critical angle for this medium?

1

\sin^{- 1} (\frac{10 t_{1}}{t_{2}})

2

\sin^{- 1} (\frac{t_{2}}{t_{1}})

3

\sin^{- 1} (\frac{10 t_{2}}{t_{1}})

4

\sin^{- 1} (\frac{t_{1}}{10 t_{2}})

Explanation:

A: Let the speed of light through vacuum be c then,
$c = \frac{x}{t_{1}}$
and let the speed of light through the medium be $v$ then-
$v = \frac{10 x}{t_{2}}$
So, absolute refractive index $(μ)$ of the medium can be calculated by -
$\begin{matrix} μ = \frac{c}{v} \\ μ = \frac{\frac{x}{t_{1}}}{\frac{10 x}{t_{2}}} \\ μ = \frac{t_{2}}{10 t_{1}} \end{matrix}$
Now, the critical angle is given by -
$\begin{array}{r} \sin θ_{c} = \frac{1}{μ} \\ \sin θ_{c} = \frac{1}{\frac{t_{2}}{10 t_{1}}} \\ \sin θ_{c} = \frac{10 t_{1}}{t_{2}} \\ θ_{c} = \sin^{- 1} \frac{10 t_{1}}{t_{2}} \end{array}$

NEET (UG) 07.05.2023

Ray Optics

282202 A microscope is focused on an object at the bottom of a bucket. If liquid with refractive index $\frac{5}{3}$ is poured inside the bucket, then microscope have to be raised by $30 cm$ to focus the object again. The height of the liquid in the bucket is:

1

12 cm

2

18 cm

3

50 cm

4

75 cm

Explanation:

D: Given,

Refractive index $(μ) = \frac{5}{3}, d = 30 cm$
We know that,
$\begin{array}{r} d = h (1 - \frac{1}{μ}) \\ 30 = h (1 - \frac{3}{5}) \\ 30 = h (\frac{5 - 3}{5}) \\ 30 = h (\frac{2}{5}) \\ \frac{30 \times 5}{2} = h \\ h = 75 cm \end{array}$

JEE Main-31.01.2023

Ray Optics

282203 A vessel of depth 'd' is half filled with oil of refractive index $n_{1}$ and the other half is filled with water of refractive index $n_{2}$ . The apparent depth of this vessel when viewed from above will be -

1

\frac{{dn}_{1} n_{2}}{(n_{1} + n_{2})}

2

\frac{d (n_{1} + n_{2})}{2 n_{1} n_{2}}

3

\frac{{dn}_{1} n_{2}}{2 (n_{1} + n_{2})}

4

\frac{2 d (n_{1} + n_{2})}{n_{1} n_{2}}

Explanation:

B: Given,
Refractive index of oil $= n_{1}$
Refractive index of water $= n_{2}$

${(d_{app})}_{1} = \frac{d}{2 (\frac{n_{1}}{n_{2}})}$
${(d_{app})}_{1} = \frac{n_{2} d}{2 n_{1}}$
${(d_{app})}_{2} = \frac{{(d_{app})}_{1} + d / 2}{n_{2}}$
$\begin{array}{r} = \frac{(\frac{n_{2}}{n_{1}}) \frac{d}{2} + \frac{d}{2}}{n_{2}} \\ = \frac{d (n_{1} + n_{2})}{2 n_{1} n_{2}} \end{array}$

JEE Main-13.04.2023

Ray Optics

282316 The twinkling effect of star light is due to

1 total internal reflection

2 high dense matter of star

3 constant burning of hydrogen in the star

4 the fluctuating apparent position of the star being slightly different from the actual position of the star

JCECE-2009

Ray Optics

282317 An optical fiber can offer a band width of

1

250 MHz

2

100 GHz

3

750 MHz

4

100 MHz

Explanation:

B: An optical fibre can offer a bond width of $100 GHz$ .
Optical fibre- It is a cylindrical dielectric waveguide (non-conducting waveguide) that transmits light along its axis through the process of total internal reflection.

GUJCET 2016

Ray Optics

282201 Light travels a distance $x$ in time $t_{1}$ in air and $10 x$ in time $t_{2}$ in another denser medium. What is the critical angle for this medium?

1

\sin^{- 1} (\frac{10 t_{1}}{t_{2}})

2

\sin^{- 1} (\frac{t_{2}}{t_{1}})

3

\sin^{- 1} (\frac{10 t_{2}}{t_{1}})

4

\sin^{- 1} (\frac{t_{1}}{10 t_{2}})

Explanation:

A: Let the speed of light through vacuum be c then,
$c = \frac{x}{t_{1}}$
and let the speed of light through the medium be $v$ then-
$v = \frac{10 x}{t_{2}}$
So, absolute refractive index $(μ)$ of the medium can be calculated by -
$\begin{matrix} μ = \frac{c}{v} \\ μ = \frac{\frac{x}{t_{1}}}{\frac{10 x}{t_{2}}} \\ μ = \frac{t_{2}}{10 t_{1}} \end{matrix}$
Now, the critical angle is given by -
$\begin{array}{r} \sin θ_{c} = \frac{1}{μ} \\ \sin θ_{c} = \frac{1}{\frac{t_{2}}{10 t_{1}}} \\ \sin θ_{c} = \frac{10 t_{1}}{t_{2}} \\ θ_{c} = \sin^{- 1} \frac{10 t_{1}}{t_{2}} \end{array}$

NEET (UG) 07.05.2023

Ray Optics

282202 A microscope is focused on an object at the bottom of a bucket. If liquid with refractive index $\frac{5}{3}$ is poured inside the bucket, then microscope have to be raised by $30 cm$ to focus the object again. The height of the liquid in the bucket is:

1

12 cm

2

18 cm

3

50 cm

4

75 cm

Explanation:

D: Given,

Refractive index $(μ) = \frac{5}{3}, d = 30 cm$
We know that,
$\begin{array}{r} d = h (1 - \frac{1}{μ}) \\ 30 = h (1 - \frac{3}{5}) \\ 30 = h (\frac{5 - 3}{5}) \\ 30 = h (\frac{2}{5}) \\ \frac{30 \times 5}{2} = h \\ h = 75 cm \end{array}$

JEE Main-31.01.2023

Ray Optics

282203 A vessel of depth 'd' is half filled with oil of refractive index $n_{1}$ and the other half is filled with water of refractive index $n_{2}$ . The apparent depth of this vessel when viewed from above will be -

1

\frac{{dn}_{1} n_{2}}{(n_{1} + n_{2})}

2

\frac{d (n_{1} + n_{2})}{2 n_{1} n_{2}}

3

\frac{{dn}_{1} n_{2}}{2 (n_{1} + n_{2})}

4

\frac{2 d (n_{1} + n_{2})}{n_{1} n_{2}}

Explanation:

B: Given,
Refractive index of oil $= n_{1}$
Refractive index of water $= n_{2}$

${(d_{app})}_{1} = \frac{d}{2 (\frac{n_{1}}{n_{2}})}$
${(d_{app})}_{1} = \frac{n_{2} d}{2 n_{1}}$
${(d_{app})}_{2} = \frac{{(d_{app})}_{1} + d / 2}{n_{2}}$
$\begin{array}{r} = \frac{(\frac{n_{2}}{n_{1}}) \frac{d}{2} + \frac{d}{2}}{n_{2}} \\ = \frac{d (n_{1} + n_{2})}{2 n_{1} n_{2}} \end{array}$

JEE Main-13.04.2023

Ray Optics

282316 The twinkling effect of star light is due to

1 total internal reflection

2 high dense matter of star

3 constant burning of hydrogen in the star

4 the fluctuating apparent position of the star being slightly different from the actual position of the star

JCECE-2009

Ray Optics

282317 An optical fiber can offer a band width of

1

250 MHz

2

100 GHz

3

750 MHz

4

100 MHz

Explanation:

B: An optical fibre can offer a bond width of $100 GHz$ .
Optical fibre- It is a cylindrical dielectric waveguide (non-conducting waveguide) that transmits light along its axis through the process of total internal reflection.

GUJCET 2016

Ray Optics

282201 Light travels a distance $x$ in time $t_{1}$ in air and $10 x$ in time $t_{2}$ in another denser medium. What is the critical angle for this medium?

1

\sin^{- 1} (\frac{10 t_{1}}{t_{2}})

2

\sin^{- 1} (\frac{t_{2}}{t_{1}})

3

\sin^{- 1} (\frac{10 t_{2}}{t_{1}})

4

\sin^{- 1} (\frac{t_{1}}{10 t_{2}})

Explanation:

A: Let the speed of light through vacuum be c then,
$c = \frac{x}{t_{1}}$
and let the speed of light through the medium be $v$ then-
$v = \frac{10 x}{t_{2}}$
So, absolute refractive index $(μ)$ of the medium can be calculated by -
$\begin{matrix} μ = \frac{c}{v} \\ μ = \frac{\frac{x}{t_{1}}}{\frac{10 x}{t_{2}}} \\ μ = \frac{t_{2}}{10 t_{1}} \end{matrix}$
Now, the critical angle is given by -
$\begin{array}{r} \sin θ_{c} = \frac{1}{μ} \\ \sin θ_{c} = \frac{1}{\frac{t_{2}}{10 t_{1}}} \\ \sin θ_{c} = \frac{10 t_{1}}{t_{2}} \\ θ_{c} = \sin^{- 1} \frac{10 t_{1}}{t_{2}} \end{array}$

NEET (UG) 07.05.2023

Ray Optics

282202 A microscope is focused on an object at the bottom of a bucket. If liquid with refractive index $\frac{5}{3}$ is poured inside the bucket, then microscope have to be raised by $30 cm$ to focus the object again. The height of the liquid in the bucket is:

1

12 cm

2

18 cm

3

50 cm

4

75 cm

Explanation:

D: Given,

Refractive index $(μ) = \frac{5}{3}, d = 30 cm$
We know that,
$\begin{array}{r} d = h (1 - \frac{1}{μ}) \\ 30 = h (1 - \frac{3}{5}) \\ 30 = h (\frac{5 - 3}{5}) \\ 30 = h (\frac{2}{5}) \\ \frac{30 \times 5}{2} = h \\ h = 75 cm \end{array}$

JEE Main-31.01.2023

Ray Optics

282203 A vessel of depth 'd' is half filled with oil of refractive index $n_{1}$ and the other half is filled with water of refractive index $n_{2}$ . The apparent depth of this vessel when viewed from above will be -

1

\frac{{dn}_{1} n_{2}}{(n_{1} + n_{2})}

2

\frac{d (n_{1} + n_{2})}{2 n_{1} n_{2}}

3

\frac{{dn}_{1} n_{2}}{2 (n_{1} + n_{2})}

4

\frac{2 d (n_{1} + n_{2})}{n_{1} n_{2}}

Explanation:

B: Given,
Refractive index of oil $= n_{1}$
Refractive index of water $= n_{2}$

${(d_{app})}_{1} = \frac{d}{2 (\frac{n_{1}}{n_{2}})}$
${(d_{app})}_{1} = \frac{n_{2} d}{2 n_{1}}$
${(d_{app})}_{2} = \frac{{(d_{app})}_{1} + d / 2}{n_{2}}$
$\begin{array}{r} = \frac{(\frac{n_{2}}{n_{1}}) \frac{d}{2} + \frac{d}{2}}{n_{2}} \\ = \frac{d (n_{1} + n_{2})}{2 n_{1} n_{2}} \end{array}$

JEE Main-13.04.2023

Ray Optics

282316 The twinkling effect of star light is due to

1 total internal reflection

2 high dense matter of star

3 constant burning of hydrogen in the star

4 the fluctuating apparent position of the star being slightly different from the actual position of the star

JCECE-2009

Ray Optics

282317 An optical fiber can offer a band width of

1

250 MHz

2

100 GHz

3

750 MHz

4

100 MHz

Explanation:

B: An optical fibre can offer a bond width of $100 GHz$ .
Optical fibre- It is a cylindrical dielectric waveguide (non-conducting waveguide) that transmits light along its axis through the process of total internal reflection.

GUJCET 2016

Ray Optics

282201 Light travels a distance $x$ in time $t_{1}$ in air and $10 x$ in time $t_{2}$ in another denser medium. What is the critical angle for this medium?

1

\sin^{- 1} (\frac{10 t_{1}}{t_{2}})

2

\sin^{- 1} (\frac{t_{2}}{t_{1}})

3

\sin^{- 1} (\frac{10 t_{2}}{t_{1}})

4

\sin^{- 1} (\frac{t_{1}}{10 t_{2}})

Explanation:

A: Let the speed of light through vacuum be c then,
$c = \frac{x}{t_{1}}$
and let the speed of light through the medium be $v$ then-
$v = \frac{10 x}{t_{2}}$
So, absolute refractive index $(μ)$ of the medium can be calculated by -
$\begin{matrix} μ = \frac{c}{v} \\ μ = \frac{\frac{x}{t_{1}}}{\frac{10 x}{t_{2}}} \\ μ = \frac{t_{2}}{10 t_{1}} \end{matrix}$
Now, the critical angle is given by -
$\begin{array}{r} \sin θ_{c} = \frac{1}{μ} \\ \sin θ_{c} = \frac{1}{\frac{t_{2}}{10 t_{1}}} \\ \sin θ_{c} = \frac{10 t_{1}}{t_{2}} \\ θ_{c} = \sin^{- 1} \frac{10 t_{1}}{t_{2}} \end{array}$

NEET (UG) 07.05.2023

Ray Optics

282202 A microscope is focused on an object at the bottom of a bucket. If liquid with refractive index $\frac{5}{3}$ is poured inside the bucket, then microscope have to be raised by $30 cm$ to focus the object again. The height of the liquid in the bucket is:

1

12 cm

2

18 cm

3

50 cm

4

75 cm

Explanation:

D: Given,

Refractive index $(μ) = \frac{5}{3}, d = 30 cm$
We know that,
$\begin{array}{r} d = h (1 - \frac{1}{μ}) \\ 30 = h (1 - \frac{3}{5}) \\ 30 = h (\frac{5 - 3}{5}) \\ 30 = h (\frac{2}{5}) \\ \frac{30 \times 5}{2} = h \\ h = 75 cm \end{array}$

JEE Main-31.01.2023

Ray Optics

282203 A vessel of depth 'd' is half filled with oil of refractive index $n_{1}$ and the other half is filled with water of refractive index $n_{2}$ . The apparent depth of this vessel when viewed from above will be -

1

\frac{{dn}_{1} n_{2}}{(n_{1} + n_{2})}

2

\frac{d (n_{1} + n_{2})}{2 n_{1} n_{2}}

3

\frac{{dn}_{1} n_{2}}{2 (n_{1} + n_{2})}

4

\frac{2 d (n_{1} + n_{2})}{n_{1} n_{2}}

Explanation:

B: Given,
Refractive index of oil $= n_{1}$
Refractive index of water $= n_{2}$

${(d_{app})}_{1} = \frac{d}{2 (\frac{n_{1}}{n_{2}})}$
${(d_{app})}_{1} = \frac{n_{2} d}{2 n_{1}}$
${(d_{app})}_{2} = \frac{{(d_{app})}_{1} + d / 2}{n_{2}}$
$\begin{array}{r} = \frac{(\frac{n_{2}}{n_{1}}) \frac{d}{2} + \frac{d}{2}}{n_{2}} \\ = \frac{d (n_{1} + n_{2})}{2 n_{1} n_{2}} \end{array}$

JEE Main-13.04.2023

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