282257
A glass prism of refracting angle \(60^{\circ}\) is immersed in a liquid in which angle of minimum deviation is \(30^{\circ}\). The critical angle of glass with respect to the liquid medium is
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(90^{\circ}\)
Explanation:
B: Given that, \(\mathrm{r}=60^{\circ}, \delta_{\mathrm{m}}=30^{\circ}\)
Refractive index \(\left(\theta_c\right)=\frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin (A / 2)}\)
\(\mu=\frac{\sin \left(\frac{60+30}{2}\right)}{\sin (60 / 2)}\)
\(\mu=\frac{\sin 45^{\circ}}{\sin 30^{\circ}}=\frac{2}{\sqrt{2}}=\sqrt{2}\)
Critical angle \(\left(\theta_c\right)=\sin ^{-1}\left(\frac{1}{\mu}\right)=\sin ^{-1}\left(\frac{1}{\sqrt{2}}\right)\)
\(\theta_{\mathrm{c}}=45^{\circ}\)
CMirage phenomenon is due to total internal reflection. Mirage is a naturally occurring optical phenomenon in which light rays bend via refraction to produce displaced image of distance object or the sky. That's type of phenomenon is occurred in desert region. 350. A fish looking up through the water sees the outside world contained in a circular horizon.
If the refractive index of water is \(\frac{4}{3}\) and fish is \(12 \mathrm{~cm}\) below the surface, the radius of the circle in centimeters is(a) \(12 \times 3 \times \sqrt{5}\)
(b.) \(4 \times \sqrt{5}\)
(c.) \(\frac{12 \times 3}{\sqrt{7}}\)
(d.) \(12 \times \frac{\sqrt{3}}{7}\)
#[examname: VITEEE-2016,CG PET- 2010,AIIMS-2008,BITSAT-2007,Karnataka CET-2003]#
Ans: c
Exp: C: Given, \(\mu_w=\frac{4}{3}\), depth, \(d=12 \mathrm{~cm}\)
Radius of circle, \(r=\frac{d}{\sqrt{\mu^2-1}}\)
\(\begin{aligned}
r=\frac{12}{\sqrt{(4 / 3)^2-1}}=\frac{12 \times 3}{\sqrt{16-9}} \\
r=\frac{12 \times 3}{\sqrt{7}} \mathrm{~cm}
\end{aligned}\)
AMU-2017
Ray Optics
282259
A glass slab \((\mu=1.5)\) of thickness \(6 \mathrm{~cm}\) is placed over a paper. What is the shift in the letters?
D: Total internal reflection takes place in optical fibre
- Diffraction- The interference or bending of waves around the corners of an obstacle or through on aperture into the region of geometrical shadow of the aperture.
- Polarization- It is a property applying to transverse waves that specifies the geometrical orientation of the oscillation. In a transverse wave, the direction of oscillation is perpendicular to the direction of motion of the wave
- Interference- When two light waves from different sources meet together, then the distribution of energy due to one wave is disturbed by each other. This modification in the distribution of light energy due to super position of two light waves is called "interference of light".
Manipal UGET-2010
Ray Optics
282261
A point source of light is placed \(4 \mathrm{~m}\) below the surface of water of refractive index \(5 / 3\). The minimum diameter of a disc, which should be placed over the source, on the surface of water to cut-off all light coming out of water is
282257
A glass prism of refracting angle \(60^{\circ}\) is immersed in a liquid in which angle of minimum deviation is \(30^{\circ}\). The critical angle of glass with respect to the liquid medium is
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(90^{\circ}\)
Explanation:
B: Given that, \(\mathrm{r}=60^{\circ}, \delta_{\mathrm{m}}=30^{\circ}\)
Refractive index \(\left(\theta_c\right)=\frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin (A / 2)}\)
\(\mu=\frac{\sin \left(\frac{60+30}{2}\right)}{\sin (60 / 2)}\)
\(\mu=\frac{\sin 45^{\circ}}{\sin 30^{\circ}}=\frac{2}{\sqrt{2}}=\sqrt{2}\)
Critical angle \(\left(\theta_c\right)=\sin ^{-1}\left(\frac{1}{\mu}\right)=\sin ^{-1}\left(\frac{1}{\sqrt{2}}\right)\)
\(\theta_{\mathrm{c}}=45^{\circ}\)
CMirage phenomenon is due to total internal reflection. Mirage is a naturally occurring optical phenomenon in which light rays bend via refraction to produce displaced image of distance object or the sky. That's type of phenomenon is occurred in desert region. 350. A fish looking up through the water sees the outside world contained in a circular horizon.
If the refractive index of water is \(\frac{4}{3}\) and fish is \(12 \mathrm{~cm}\) below the surface, the radius of the circle in centimeters is(a) \(12 \times 3 \times \sqrt{5}\)
(b.) \(4 \times \sqrt{5}\)
(c.) \(\frac{12 \times 3}{\sqrt{7}}\)
(d.) \(12 \times \frac{\sqrt{3}}{7}\)
#[examname: VITEEE-2016,CG PET- 2010,AIIMS-2008,BITSAT-2007,Karnataka CET-2003]#
Ans: c
Exp: C: Given, \(\mu_w=\frac{4}{3}\), depth, \(d=12 \mathrm{~cm}\)
Radius of circle, \(r=\frac{d}{\sqrt{\mu^2-1}}\)
\(\begin{aligned}
r=\frac{12}{\sqrt{(4 / 3)^2-1}}=\frac{12 \times 3}{\sqrt{16-9}} \\
r=\frac{12 \times 3}{\sqrt{7}} \mathrm{~cm}
\end{aligned}\)
AMU-2017
Ray Optics
282259
A glass slab \((\mu=1.5)\) of thickness \(6 \mathrm{~cm}\) is placed over a paper. What is the shift in the letters?
D: Total internal reflection takes place in optical fibre
- Diffraction- The interference or bending of waves around the corners of an obstacle or through on aperture into the region of geometrical shadow of the aperture.
- Polarization- It is a property applying to transverse waves that specifies the geometrical orientation of the oscillation. In a transverse wave, the direction of oscillation is perpendicular to the direction of motion of the wave
- Interference- When two light waves from different sources meet together, then the distribution of energy due to one wave is disturbed by each other. This modification in the distribution of light energy due to super position of two light waves is called "interference of light".
Manipal UGET-2010
Ray Optics
282261
A point source of light is placed \(4 \mathrm{~m}\) below the surface of water of refractive index \(5 / 3\). The minimum diameter of a disc, which should be placed over the source, on the surface of water to cut-off all light coming out of water is
282257
A glass prism of refracting angle \(60^{\circ}\) is immersed in a liquid in which angle of minimum deviation is \(30^{\circ}\). The critical angle of glass with respect to the liquid medium is
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(90^{\circ}\)
Explanation:
B: Given that, \(\mathrm{r}=60^{\circ}, \delta_{\mathrm{m}}=30^{\circ}\)
Refractive index \(\left(\theta_c\right)=\frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin (A / 2)}\)
\(\mu=\frac{\sin \left(\frac{60+30}{2}\right)}{\sin (60 / 2)}\)
\(\mu=\frac{\sin 45^{\circ}}{\sin 30^{\circ}}=\frac{2}{\sqrt{2}}=\sqrt{2}\)
Critical angle \(\left(\theta_c\right)=\sin ^{-1}\left(\frac{1}{\mu}\right)=\sin ^{-1}\left(\frac{1}{\sqrt{2}}\right)\)
\(\theta_{\mathrm{c}}=45^{\circ}\)
CMirage phenomenon is due to total internal reflection. Mirage is a naturally occurring optical phenomenon in which light rays bend via refraction to produce displaced image of distance object or the sky. That's type of phenomenon is occurred in desert region. 350. A fish looking up through the water sees the outside world contained in a circular horizon.
If the refractive index of water is \(\frac{4}{3}\) and fish is \(12 \mathrm{~cm}\) below the surface, the radius of the circle in centimeters is(a) \(12 \times 3 \times \sqrt{5}\)
(b.) \(4 \times \sqrt{5}\)
(c.) \(\frac{12 \times 3}{\sqrt{7}}\)
(d.) \(12 \times \frac{\sqrt{3}}{7}\)
#[examname: VITEEE-2016,CG PET- 2010,AIIMS-2008,BITSAT-2007,Karnataka CET-2003]#
Ans: c
Exp: C: Given, \(\mu_w=\frac{4}{3}\), depth, \(d=12 \mathrm{~cm}\)
Radius of circle, \(r=\frac{d}{\sqrt{\mu^2-1}}\)
\(\begin{aligned}
r=\frac{12}{\sqrt{(4 / 3)^2-1}}=\frac{12 \times 3}{\sqrt{16-9}} \\
r=\frac{12 \times 3}{\sqrt{7}} \mathrm{~cm}
\end{aligned}\)
AMU-2017
Ray Optics
282259
A glass slab \((\mu=1.5)\) of thickness \(6 \mathrm{~cm}\) is placed over a paper. What is the shift in the letters?
D: Total internal reflection takes place in optical fibre
- Diffraction- The interference or bending of waves around the corners of an obstacle or through on aperture into the region of geometrical shadow of the aperture.
- Polarization- It is a property applying to transverse waves that specifies the geometrical orientation of the oscillation. In a transverse wave, the direction of oscillation is perpendicular to the direction of motion of the wave
- Interference- When two light waves from different sources meet together, then the distribution of energy due to one wave is disturbed by each other. This modification in the distribution of light energy due to super position of two light waves is called "interference of light".
Manipal UGET-2010
Ray Optics
282261
A point source of light is placed \(4 \mathrm{~m}\) below the surface of water of refractive index \(5 / 3\). The minimum diameter of a disc, which should be placed over the source, on the surface of water to cut-off all light coming out of water is
NEET Test Series from KOTA - 10 Papers In MS WORD
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Ray Optics
282257
A glass prism of refracting angle \(60^{\circ}\) is immersed in a liquid in which angle of minimum deviation is \(30^{\circ}\). The critical angle of glass with respect to the liquid medium is
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(90^{\circ}\)
Explanation:
B: Given that, \(\mathrm{r}=60^{\circ}, \delta_{\mathrm{m}}=30^{\circ}\)
Refractive index \(\left(\theta_c\right)=\frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin (A / 2)}\)
\(\mu=\frac{\sin \left(\frac{60+30}{2}\right)}{\sin (60 / 2)}\)
\(\mu=\frac{\sin 45^{\circ}}{\sin 30^{\circ}}=\frac{2}{\sqrt{2}}=\sqrt{2}\)
Critical angle \(\left(\theta_c\right)=\sin ^{-1}\left(\frac{1}{\mu}\right)=\sin ^{-1}\left(\frac{1}{\sqrt{2}}\right)\)
\(\theta_{\mathrm{c}}=45^{\circ}\)
CMirage phenomenon is due to total internal reflection. Mirage is a naturally occurring optical phenomenon in which light rays bend via refraction to produce displaced image of distance object or the sky. That's type of phenomenon is occurred in desert region. 350. A fish looking up through the water sees the outside world contained in a circular horizon.
If the refractive index of water is \(\frac{4}{3}\) and fish is \(12 \mathrm{~cm}\) below the surface, the radius of the circle in centimeters is(a) \(12 \times 3 \times \sqrt{5}\)
(b.) \(4 \times \sqrt{5}\)
(c.) \(\frac{12 \times 3}{\sqrt{7}}\)
(d.) \(12 \times \frac{\sqrt{3}}{7}\)
#[examname: VITEEE-2016,CG PET- 2010,AIIMS-2008,BITSAT-2007,Karnataka CET-2003]#
Ans: c
Exp: C: Given, \(\mu_w=\frac{4}{3}\), depth, \(d=12 \mathrm{~cm}\)
Radius of circle, \(r=\frac{d}{\sqrt{\mu^2-1}}\)
\(\begin{aligned}
r=\frac{12}{\sqrt{(4 / 3)^2-1}}=\frac{12 \times 3}{\sqrt{16-9}} \\
r=\frac{12 \times 3}{\sqrt{7}} \mathrm{~cm}
\end{aligned}\)
AMU-2017
Ray Optics
282259
A glass slab \((\mu=1.5)\) of thickness \(6 \mathrm{~cm}\) is placed over a paper. What is the shift in the letters?
D: Total internal reflection takes place in optical fibre
- Diffraction- The interference or bending of waves around the corners of an obstacle or through on aperture into the region of geometrical shadow of the aperture.
- Polarization- It is a property applying to transverse waves that specifies the geometrical orientation of the oscillation. In a transverse wave, the direction of oscillation is perpendicular to the direction of motion of the wave
- Interference- When two light waves from different sources meet together, then the distribution of energy due to one wave is disturbed by each other. This modification in the distribution of light energy due to super position of two light waves is called "interference of light".
Manipal UGET-2010
Ray Optics
282261
A point source of light is placed \(4 \mathrm{~m}\) below the surface of water of refractive index \(5 / 3\). The minimum diameter of a disc, which should be placed over the source, on the surface of water to cut-off all light coming out of water is
282257
A glass prism of refracting angle \(60^{\circ}\) is immersed in a liquid in which angle of minimum deviation is \(30^{\circ}\). The critical angle of glass with respect to the liquid medium is
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(90^{\circ}\)
Explanation:
B: Given that, \(\mathrm{r}=60^{\circ}, \delta_{\mathrm{m}}=30^{\circ}\)
Refractive index \(\left(\theta_c\right)=\frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin (A / 2)}\)
\(\mu=\frac{\sin \left(\frac{60+30}{2}\right)}{\sin (60 / 2)}\)
\(\mu=\frac{\sin 45^{\circ}}{\sin 30^{\circ}}=\frac{2}{\sqrt{2}}=\sqrt{2}\)
Critical angle \(\left(\theta_c\right)=\sin ^{-1}\left(\frac{1}{\mu}\right)=\sin ^{-1}\left(\frac{1}{\sqrt{2}}\right)\)
\(\theta_{\mathrm{c}}=45^{\circ}\)
CMirage phenomenon is due to total internal reflection. Mirage is a naturally occurring optical phenomenon in which light rays bend via refraction to produce displaced image of distance object or the sky. That's type of phenomenon is occurred in desert region. 350. A fish looking up through the water sees the outside world contained in a circular horizon.
If the refractive index of water is \(\frac{4}{3}\) and fish is \(12 \mathrm{~cm}\) below the surface, the radius of the circle in centimeters is(a) \(12 \times 3 \times \sqrt{5}\)
(b.) \(4 \times \sqrt{5}\)
(c.) \(\frac{12 \times 3}{\sqrt{7}}\)
(d.) \(12 \times \frac{\sqrt{3}}{7}\)
#[examname: VITEEE-2016,CG PET- 2010,AIIMS-2008,BITSAT-2007,Karnataka CET-2003]#
Ans: c
Exp: C: Given, \(\mu_w=\frac{4}{3}\), depth, \(d=12 \mathrm{~cm}\)
Radius of circle, \(r=\frac{d}{\sqrt{\mu^2-1}}\)
\(\begin{aligned}
r=\frac{12}{\sqrt{(4 / 3)^2-1}}=\frac{12 \times 3}{\sqrt{16-9}} \\
r=\frac{12 \times 3}{\sqrt{7}} \mathrm{~cm}
\end{aligned}\)
AMU-2017
Ray Optics
282259
A glass slab \((\mu=1.5)\) of thickness \(6 \mathrm{~cm}\) is placed over a paper. What is the shift in the letters?
D: Total internal reflection takes place in optical fibre
- Diffraction- The interference or bending of waves around the corners of an obstacle or through on aperture into the region of geometrical shadow of the aperture.
- Polarization- It is a property applying to transverse waves that specifies the geometrical orientation of the oscillation. In a transverse wave, the direction of oscillation is perpendicular to the direction of motion of the wave
- Interference- When two light waves from different sources meet together, then the distribution of energy due to one wave is disturbed by each other. This modification in the distribution of light energy due to super position of two light waves is called "interference of light".
Manipal UGET-2010
Ray Optics
282261
A point source of light is placed \(4 \mathrm{~m}\) below the surface of water of refractive index \(5 / 3\). The minimum diameter of a disc, which should be placed over the source, on the surface of water to cut-off all light coming out of water is