NEET Test Series from KOTA - 10 Papers In MS WORD
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Ray Optics
282124
Due to atmospheric refraction effects, the day becomes longer by
1 4 minutes
2 0 minute
3 2 minutes
4 1 minute
Explanation:
A: The sun is visible to us about 2 minutes before the actual sunrise and about 2 minutes after the actual sunset because of atmospheric refraction.
The time between the actual sunrise and the apparent sunrise is about 2 minutes. Same as, time between the actual sunset and apparent sunset is also 2 minutes.
Hence, the day become longer by 4 minute due to atmospheric refraction.
J\&K-CET-2018
Ray Optics
282125
A ray of light travels from of refractive index $n_1=3 / 2$ to water of refractive index of $n_2=4 / 3$. The value of incidence angle (i) for total internal reflection will be-
282126
A ray of light strikes a transparent slab of refractive index of $\sqrt{2}$ at an angle of incidence $45^{\circ}$. The angle between the reflected and refracted rays is-
1 $90^{\circ}$
2 $120^{\circ}$
3 $135^{\circ}$
4 $105^{\circ}$
Explanation:
D: Given, $\mu=\sqrt{2}, i=r=45^{\circ}$
We know that,
$\begin{aligned}
\mu=\frac{\sin i}{\sin r} \\
\sin r=\frac{\sin 45^{\circ}}{\sqrt{2}}=\frac{1}{\sqrt{2} \times \sqrt{2}}=\frac{1}{2} \\
r=30^{\circ}
\end{aligned}$
Angle between reflected and refracted ray is -
$\begin{aligned}
=180^{\circ}-(\mathrm{i}+\mathrm{r}) \\
=180^{\circ}-\left(45^{\circ}+30^{\circ}\right) \\
=105^{\circ}
\end{aligned}$
BCECE-2018
Ray Optics
282127
The wavelength of a monochromatic light in vacuum is $\lambda$. It travels from vacuum to a medium of absolute refractive index $\mu$. The ratio of wavelength of the incident and refracted wave is .
282124
Due to atmospheric refraction effects, the day becomes longer by
1 4 minutes
2 0 minute
3 2 minutes
4 1 minute
Explanation:
A: The sun is visible to us about 2 minutes before the actual sunrise and about 2 minutes after the actual sunset because of atmospheric refraction.
The time between the actual sunrise and the apparent sunrise is about 2 minutes. Same as, time between the actual sunset and apparent sunset is also 2 minutes.
Hence, the day become longer by 4 minute due to atmospheric refraction.
J\&K-CET-2018
Ray Optics
282125
A ray of light travels from of refractive index $n_1=3 / 2$ to water of refractive index of $n_2=4 / 3$. The value of incidence angle (i) for total internal reflection will be-
282126
A ray of light strikes a transparent slab of refractive index of $\sqrt{2}$ at an angle of incidence $45^{\circ}$. The angle between the reflected and refracted rays is-
1 $90^{\circ}$
2 $120^{\circ}$
3 $135^{\circ}$
4 $105^{\circ}$
Explanation:
D: Given, $\mu=\sqrt{2}, i=r=45^{\circ}$
We know that,
$\begin{aligned}
\mu=\frac{\sin i}{\sin r} \\
\sin r=\frac{\sin 45^{\circ}}{\sqrt{2}}=\frac{1}{\sqrt{2} \times \sqrt{2}}=\frac{1}{2} \\
r=30^{\circ}
\end{aligned}$
Angle between reflected and refracted ray is -
$\begin{aligned}
=180^{\circ}-(\mathrm{i}+\mathrm{r}) \\
=180^{\circ}-\left(45^{\circ}+30^{\circ}\right) \\
=105^{\circ}
\end{aligned}$
BCECE-2018
Ray Optics
282127
The wavelength of a monochromatic light in vacuum is $\lambda$. It travels from vacuum to a medium of absolute refractive index $\mu$. The ratio of wavelength of the incident and refracted wave is .
282124
Due to atmospheric refraction effects, the day becomes longer by
1 4 minutes
2 0 minute
3 2 minutes
4 1 minute
Explanation:
A: The sun is visible to us about 2 minutes before the actual sunrise and about 2 minutes after the actual sunset because of atmospheric refraction.
The time between the actual sunrise and the apparent sunrise is about 2 minutes. Same as, time between the actual sunset and apparent sunset is also 2 minutes.
Hence, the day become longer by 4 minute due to atmospheric refraction.
J\&K-CET-2018
Ray Optics
282125
A ray of light travels from of refractive index $n_1=3 / 2$ to water of refractive index of $n_2=4 / 3$. The value of incidence angle (i) for total internal reflection will be-
282126
A ray of light strikes a transparent slab of refractive index of $\sqrt{2}$ at an angle of incidence $45^{\circ}$. The angle between the reflected and refracted rays is-
1 $90^{\circ}$
2 $120^{\circ}$
3 $135^{\circ}$
4 $105^{\circ}$
Explanation:
D: Given, $\mu=\sqrt{2}, i=r=45^{\circ}$
We know that,
$\begin{aligned}
\mu=\frac{\sin i}{\sin r} \\
\sin r=\frac{\sin 45^{\circ}}{\sqrt{2}}=\frac{1}{\sqrt{2} \times \sqrt{2}}=\frac{1}{2} \\
r=30^{\circ}
\end{aligned}$
Angle between reflected and refracted ray is -
$\begin{aligned}
=180^{\circ}-(\mathrm{i}+\mathrm{r}) \\
=180^{\circ}-\left(45^{\circ}+30^{\circ}\right) \\
=105^{\circ}
\end{aligned}$
BCECE-2018
Ray Optics
282127
The wavelength of a monochromatic light in vacuum is $\lambda$. It travels from vacuum to a medium of absolute refractive index $\mu$. The ratio of wavelength of the incident and refracted wave is .
282124
Due to atmospheric refraction effects, the day becomes longer by
1 4 minutes
2 0 minute
3 2 minutes
4 1 minute
Explanation:
A: The sun is visible to us about 2 minutes before the actual sunrise and about 2 minutes after the actual sunset because of atmospheric refraction.
The time between the actual sunrise and the apparent sunrise is about 2 minutes. Same as, time between the actual sunset and apparent sunset is also 2 minutes.
Hence, the day become longer by 4 minute due to atmospheric refraction.
J\&K-CET-2018
Ray Optics
282125
A ray of light travels from of refractive index $n_1=3 / 2$ to water of refractive index of $n_2=4 / 3$. The value of incidence angle (i) for total internal reflection will be-
282126
A ray of light strikes a transparent slab of refractive index of $\sqrt{2}$ at an angle of incidence $45^{\circ}$. The angle between the reflected and refracted rays is-
1 $90^{\circ}$
2 $120^{\circ}$
3 $135^{\circ}$
4 $105^{\circ}$
Explanation:
D: Given, $\mu=\sqrt{2}, i=r=45^{\circ}$
We know that,
$\begin{aligned}
\mu=\frac{\sin i}{\sin r} \\
\sin r=\frac{\sin 45^{\circ}}{\sqrt{2}}=\frac{1}{\sqrt{2} \times \sqrt{2}}=\frac{1}{2} \\
r=30^{\circ}
\end{aligned}$
Angle between reflected and refracted ray is -
$\begin{aligned}
=180^{\circ}-(\mathrm{i}+\mathrm{r}) \\
=180^{\circ}-\left(45^{\circ}+30^{\circ}\right) \\
=105^{\circ}
\end{aligned}$
BCECE-2018
Ray Optics
282127
The wavelength of a monochromatic light in vacuum is $\lambda$. It travels from vacuum to a medium of absolute refractive index $\mu$. The ratio of wavelength of the incident and refracted wave is .
