COMBINATIONS OF CAPACITORS
Electrostatic Potentials and Capacitance

272298 The charge on capacitor of capacitance \(15 \mu \mathrm{~F}\) in the figure given below is:

1 \(60 \mu \mathrm{c}\)
2 \(130 \mu \mathrm{c}\)
3 \(260 \mu \mathrm{c}\)
4 \(585 \mu \mathrm{c}\)
Electrostatic Potentials and Capacitance

272299 From a supply of identical capacitors rated \(8 \mathrm{mF}, 250 \mathrm{~V}\), the minimum number of capacitors required to form a composite \(16 \mathrm{mF}, 1000 \mathrm{~V}\) is

1 2
2 4
3 16
4 32
Electrostatic Potentials and Capacitance

272300 Two capacitors of capacitances \(3 \mu \mathrm{~F}\) and \(6 \mu \mathrm{~F}\) are charged to a potential of 12 V each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be

1 zero
2 4 V
3 6 V
4 12 V
Electrostatic Potentials and Capacitance

272276 A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is \(\mathrm{Am}^2\) and the separation is tm . The dielectric constants are \(k_1\) and \(k_2\) respectively. Its capacitance in farad will be

1 \(\frac{\varepsilon_0 A}{t}\left(k_1+k_2\right)\)
2 \(\frac{\varepsilon_0 A}{t}, \frac{k_1+k_2}{2}\)
3 \(\frac{2 \varepsilon_1 A}{t}\left(k_1+k_2\right)\)
4 \(\frac{\varepsilon_0 A}{t}, \frac{k_1-k_2}{2}\)
Electrostatic Potentials and Capacitance

272298 The charge on capacitor of capacitance \(15 \mu \mathrm{~F}\) in the figure given below is:

1 \(60 \mu \mathrm{c}\)
2 \(130 \mu \mathrm{c}\)
3 \(260 \mu \mathrm{c}\)
4 \(585 \mu \mathrm{c}\)
Electrostatic Potentials and Capacitance

272299 From a supply of identical capacitors rated \(8 \mathrm{mF}, 250 \mathrm{~V}\), the minimum number of capacitors required to form a composite \(16 \mathrm{mF}, 1000 \mathrm{~V}\) is

1 2
2 4
3 16
4 32
Electrostatic Potentials and Capacitance

272300 Two capacitors of capacitances \(3 \mu \mathrm{~F}\) and \(6 \mu \mathrm{~F}\) are charged to a potential of 12 V each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be

1 zero
2 4 V
3 6 V
4 12 V
Electrostatic Potentials and Capacitance

272276 A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is \(\mathrm{Am}^2\) and the separation is tm . The dielectric constants are \(k_1\) and \(k_2\) respectively. Its capacitance in farad will be

1 \(\frac{\varepsilon_0 A}{t}\left(k_1+k_2\right)\)
2 \(\frac{\varepsilon_0 A}{t}, \frac{k_1+k_2}{2}\)
3 \(\frac{2 \varepsilon_1 A}{t}\left(k_1+k_2\right)\)
4 \(\frac{\varepsilon_0 A}{t}, \frac{k_1-k_2}{2}\)
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Electrostatic Potentials and Capacitance

272298 The charge on capacitor of capacitance \(15 \mu \mathrm{~F}\) in the figure given below is:

1 \(60 \mu \mathrm{c}\)
2 \(130 \mu \mathrm{c}\)
3 \(260 \mu \mathrm{c}\)
4 \(585 \mu \mathrm{c}\)
Electrostatic Potentials and Capacitance

272299 From a supply of identical capacitors rated \(8 \mathrm{mF}, 250 \mathrm{~V}\), the minimum number of capacitors required to form a composite \(16 \mathrm{mF}, 1000 \mathrm{~V}\) is

1 2
2 4
3 16
4 32
Electrostatic Potentials and Capacitance

272300 Two capacitors of capacitances \(3 \mu \mathrm{~F}\) and \(6 \mu \mathrm{~F}\) are charged to a potential of 12 V each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be

1 zero
2 4 V
3 6 V
4 12 V
Electrostatic Potentials and Capacitance

272276 A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is \(\mathrm{Am}^2\) and the separation is tm . The dielectric constants are \(k_1\) and \(k_2\) respectively. Its capacitance in farad will be

1 \(\frac{\varepsilon_0 A}{t}\left(k_1+k_2\right)\)
2 \(\frac{\varepsilon_0 A}{t}, \frac{k_1+k_2}{2}\)
3 \(\frac{2 \varepsilon_1 A}{t}\left(k_1+k_2\right)\)
4 \(\frac{\varepsilon_0 A}{t}, \frac{k_1-k_2}{2}\)
Electrostatic Potentials and Capacitance

272298 The charge on capacitor of capacitance \(15 \mu \mathrm{~F}\) in the figure given below is:

1 \(60 \mu \mathrm{c}\)
2 \(130 \mu \mathrm{c}\)
3 \(260 \mu \mathrm{c}\)
4 \(585 \mu \mathrm{c}\)
Electrostatic Potentials and Capacitance

272299 From a supply of identical capacitors rated \(8 \mathrm{mF}, 250 \mathrm{~V}\), the minimum number of capacitors required to form a composite \(16 \mathrm{mF}, 1000 \mathrm{~V}\) is

1 2
2 4
3 16
4 32
Electrostatic Potentials and Capacitance

272300 Two capacitors of capacitances \(3 \mu \mathrm{~F}\) and \(6 \mu \mathrm{~F}\) are charged to a potential of 12 V each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be

1 zero
2 4 V
3 6 V
4 12 V
Electrostatic Potentials and Capacitance

272276 A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is \(\mathrm{Am}^2\) and the separation is tm . The dielectric constants are \(k_1\) and \(k_2\) respectively. Its capacitance in farad will be

1 \(\frac{\varepsilon_0 A}{t}\left(k_1+k_2\right)\)
2 \(\frac{\varepsilon_0 A}{t}, \frac{k_1+k_2}{2}\)
3 \(\frac{2 \varepsilon_1 A}{t}\left(k_1+k_2\right)\)
4 \(\frac{\varepsilon_0 A}{t}, \frac{k_1-k_2}{2}\)