COMBINATIONS OF CAPACITORS
Electrostatic Potentials and Capacitance

272294 Three capacitors each of \(4 \mu \mathrm{~F}\) are to be connected in such a way that the effective capacitance is \(6 \mu \mathrm{~F}\). This can be done by connecting them:

1 all in series
2 all in parallel
3 two in parallel and one in series
4 two in series and one in parallel
Electrostatic Potentials and Capacitance

272295 A combination of parallel plate capacitors is maintained at a certain potential difference.
When a 3 mm thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between the plates is increased by 2.4 mm .
Find the dielectric constant of the slab.

1 3
2 4
3 5
4 6
Electrostatic Potentials and Capacitance

272296 A capacitor of capacitance \(C_0\) is charged to a potential \(V_0\) and then isolated. A small capacitor \(C\) is then charged from \(\mathrm{C}_0\), discharged and chaged again; the process being repeated \(n\) times. Due to this, the potential of the larger capacitor is decreased to V . The value of C is

1 \(\mathrm{C}_0\left(\frac{V_0}{V}\right)^{1 / n}\)
2 \(\mathrm{C}_0\left[\left(\frac{V_0}{v}\right)^{1 / 0}-1\right]\)
3 \(\mathrm{C}_0\left[\left(\frac{v}{v_0}\right)-1\right]^{\mathrm{D}}\)
4 \(\mathrm{C}_0\left[\left(\frac{v}{v_0}\right)^{\mathrm{D}}+1\right]\)
Electrostatic Potentials and Capacitance

272297 For the configuration of media of permittivities \(\varepsilon_0, \varepsilon\) and \(\varepsilon_0\) between parallel plates each of area A , as shown in Fig. the equivalent capacitance is

1 \(\varepsilon_0 A / d\)
2 \(\varepsilon \varepsilon_0 \mathrm{~A} / \mathrm{d}\)
3 \(\frac{\varepsilon \varepsilon_0 A}{d\left(\varepsilon+\varepsilon_0\right)}\)
4 \(\frac{\varepsilon \varepsilon_0 A}{\left(2 \varepsilon+\varepsilon_0\right\} d}\)
Electrostatic Potentials and Capacitance

272294 Three capacitors each of \(4 \mu \mathrm{~F}\) are to be connected in such a way that the effective capacitance is \(6 \mu \mathrm{~F}\). This can be done by connecting them:

1 all in series
2 all in parallel
3 two in parallel and one in series
4 two in series and one in parallel
Electrostatic Potentials and Capacitance

272295 A combination of parallel plate capacitors is maintained at a certain potential difference.
When a 3 mm thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between the plates is increased by 2.4 mm .
Find the dielectric constant of the slab.

1 3
2 4
3 5
4 6
Electrostatic Potentials and Capacitance

272296 A capacitor of capacitance \(C_0\) is charged to a potential \(V_0\) and then isolated. A small capacitor \(C\) is then charged from \(\mathrm{C}_0\), discharged and chaged again; the process being repeated \(n\) times. Due to this, the potential of the larger capacitor is decreased to V . The value of C is

1 \(\mathrm{C}_0\left(\frac{V_0}{V}\right)^{1 / n}\)
2 \(\mathrm{C}_0\left[\left(\frac{V_0}{v}\right)^{1 / 0}-1\right]\)
3 \(\mathrm{C}_0\left[\left(\frac{v}{v_0}\right)-1\right]^{\mathrm{D}}\)
4 \(\mathrm{C}_0\left[\left(\frac{v}{v_0}\right)^{\mathrm{D}}+1\right]\)
Electrostatic Potentials and Capacitance

272297 For the configuration of media of permittivities \(\varepsilon_0, \varepsilon\) and \(\varepsilon_0\) between parallel plates each of area A , as shown in Fig. the equivalent capacitance is

1 \(\varepsilon_0 A / d\)
2 \(\varepsilon \varepsilon_0 \mathrm{~A} / \mathrm{d}\)
3 \(\frac{\varepsilon \varepsilon_0 A}{d\left(\varepsilon+\varepsilon_0\right)}\)
4 \(\frac{\varepsilon \varepsilon_0 A}{\left(2 \varepsilon+\varepsilon_0\right\} d}\)
Electrostatic Potentials and Capacitance

272294 Three capacitors each of \(4 \mu \mathrm{~F}\) are to be connected in such a way that the effective capacitance is \(6 \mu \mathrm{~F}\). This can be done by connecting them:

1 all in series
2 all in parallel
3 two in parallel and one in series
4 two in series and one in parallel
Electrostatic Potentials and Capacitance

272295 A combination of parallel plate capacitors is maintained at a certain potential difference.
When a 3 mm thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between the plates is increased by 2.4 mm .
Find the dielectric constant of the slab.

1 3
2 4
3 5
4 6
Electrostatic Potentials and Capacitance

272296 A capacitor of capacitance \(C_0\) is charged to a potential \(V_0\) and then isolated. A small capacitor \(C\) is then charged from \(\mathrm{C}_0\), discharged and chaged again; the process being repeated \(n\) times. Due to this, the potential of the larger capacitor is decreased to V . The value of C is

1 \(\mathrm{C}_0\left(\frac{V_0}{V}\right)^{1 / n}\)
2 \(\mathrm{C}_0\left[\left(\frac{V_0}{v}\right)^{1 / 0}-1\right]\)
3 \(\mathrm{C}_0\left[\left(\frac{v}{v_0}\right)-1\right]^{\mathrm{D}}\)
4 \(\mathrm{C}_0\left[\left(\frac{v}{v_0}\right)^{\mathrm{D}}+1\right]\)
Electrostatic Potentials and Capacitance

272297 For the configuration of media of permittivities \(\varepsilon_0, \varepsilon\) and \(\varepsilon_0\) between parallel plates each of area A , as shown in Fig. the equivalent capacitance is

1 \(\varepsilon_0 A / d\)
2 \(\varepsilon \varepsilon_0 \mathrm{~A} / \mathrm{d}\)
3 \(\frac{\varepsilon \varepsilon_0 A}{d\left(\varepsilon+\varepsilon_0\right)}\)
4 \(\frac{\varepsilon \varepsilon_0 A}{\left(2 \varepsilon+\varepsilon_0\right\} d}\)
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Electrostatic Potentials and Capacitance

272294 Three capacitors each of \(4 \mu \mathrm{~F}\) are to be connected in such a way that the effective capacitance is \(6 \mu \mathrm{~F}\). This can be done by connecting them:

1 all in series
2 all in parallel
3 two in parallel and one in series
4 two in series and one in parallel
Electrostatic Potentials and Capacitance

272295 A combination of parallel plate capacitors is maintained at a certain potential difference.
When a 3 mm thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between the plates is increased by 2.4 mm .
Find the dielectric constant of the slab.

1 3
2 4
3 5
4 6
Electrostatic Potentials and Capacitance

272296 A capacitor of capacitance \(C_0\) is charged to a potential \(V_0\) and then isolated. A small capacitor \(C\) is then charged from \(\mathrm{C}_0\), discharged and chaged again; the process being repeated \(n\) times. Due to this, the potential of the larger capacitor is decreased to V . The value of C is

1 \(\mathrm{C}_0\left(\frac{V_0}{V}\right)^{1 / n}\)
2 \(\mathrm{C}_0\left[\left(\frac{V_0}{v}\right)^{1 / 0}-1\right]\)
3 \(\mathrm{C}_0\left[\left(\frac{v}{v_0}\right)-1\right]^{\mathrm{D}}\)
4 \(\mathrm{C}_0\left[\left(\frac{v}{v_0}\right)^{\mathrm{D}}+1\right]\)
Electrostatic Potentials and Capacitance

272297 For the configuration of media of permittivities \(\varepsilon_0, \varepsilon\) and \(\varepsilon_0\) between parallel plates each of area A , as shown in Fig. the equivalent capacitance is

1 \(\varepsilon_0 A / d\)
2 \(\varepsilon \varepsilon_0 \mathrm{~A} / \mathrm{d}\)
3 \(\frac{\varepsilon \varepsilon_0 A}{d\left(\varepsilon+\varepsilon_0\right)}\)
4 \(\frac{\varepsilon \varepsilon_0 A}{\left(2 \varepsilon+\varepsilon_0\right\} d}\)