NEET Test Series from KOTA - 10 Papers In MS WORD
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Electrostatic Potentials and Capacitance
272249
If a unit positive charge is taken from one point to another over an equipotential surface, then
1 workis done on the charge
2 workis done by the charge
3 work done is constant
4 no workis done
Explanation:
(d) On the equipotential surface, electric field is normal to the charged surface \{where potential exists\} so that no work will be done.
NCERT Page-61/N-54
Electrostatic Potentials and Capacitance
272250
If the electric potential at any point \((x, y, z) \mathrm{m}\) in space is given by \(V=3 x^2\) volt. The electric field at the point \((1,0,3) m\) will be :
1 \(3 \mathrm{Vm}^{-1}\), directed along positive \(x\)-axis.
2 \(3 \mathrm{Vm}^{-1}\), directed along negative \(x\)-axis.
3 \(6 \mathrm{Vm}^{-1}\), directed along positive \(x\)-axis.
4 \(6 \mathrm{Vm}^{-1}\), directed along negative \(x\)-axis.
Explanation:
(d)
NCERT Page-61/N-55
Electrostatic Potentials and Capacitance
272240
Which of the following figure shows the correct equipotential surfaces of a system of two positive charges?
1
2
3
4
Explanation:
(c) Equipotential surfaces are normal to the electric field lines. The following figure shows the equipotential surfaces along with electric field lines for a system of two positive charges.
NCERT Page-60 / N- 54
Electrostatic Potentials and Capacitance
272239
In moving from A to B along an electric field line, the work done by the electric field on an electron is \(6.4 \times 10^{-19} \mathrm{~J}\). If \(\phi_1\) and \(\phi_2\) are equipotential surfaces, then the potential difference \(V_C-V_A\) is
1 \(-4 V\)
2 4 V
3 zero
4 6.4 V
Explanation:
(b) \(W_{\text {el. }}=g\left(V_i-V_f\right)\) or \(6.4 \times 10^{-19}=-1.6 \times 10^{-19}\left(V_A-V_B\right)\)
or \(\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=-4 \mathrm{~V}\)
or \(\quad V_A-V_C=-4 V \quad\left(\because V_B=V_C\right)\)
or \(V_C-V_A=4 V\)
272249
If a unit positive charge is taken from one point to another over an equipotential surface, then
1 workis done on the charge
2 workis done by the charge
3 work done is constant
4 no workis done
Explanation:
(d) On the equipotential surface, electric field is normal to the charged surface \{where potential exists\} so that no work will be done.
NCERT Page-61/N-54
Electrostatic Potentials and Capacitance
272250
If the electric potential at any point \((x, y, z) \mathrm{m}\) in space is given by \(V=3 x^2\) volt. The electric field at the point \((1,0,3) m\) will be :
1 \(3 \mathrm{Vm}^{-1}\), directed along positive \(x\)-axis.
2 \(3 \mathrm{Vm}^{-1}\), directed along negative \(x\)-axis.
3 \(6 \mathrm{Vm}^{-1}\), directed along positive \(x\)-axis.
4 \(6 \mathrm{Vm}^{-1}\), directed along negative \(x\)-axis.
Explanation:
(d)
NCERT Page-61/N-55
Electrostatic Potentials and Capacitance
272240
Which of the following figure shows the correct equipotential surfaces of a system of two positive charges?
1
2
3
4
Explanation:
(c) Equipotential surfaces are normal to the electric field lines. The following figure shows the equipotential surfaces along with electric field lines for a system of two positive charges.
NCERT Page-60 / N- 54
Electrostatic Potentials and Capacitance
272239
In moving from A to B along an electric field line, the work done by the electric field on an electron is \(6.4 \times 10^{-19} \mathrm{~J}\). If \(\phi_1\) and \(\phi_2\) are equipotential surfaces, then the potential difference \(V_C-V_A\) is
1 \(-4 V\)
2 4 V
3 zero
4 6.4 V
Explanation:
(b) \(W_{\text {el. }}=g\left(V_i-V_f\right)\) or \(6.4 \times 10^{-19}=-1.6 \times 10^{-19}\left(V_A-V_B\right)\)
or \(\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=-4 \mathrm{~V}\)
or \(\quad V_A-V_C=-4 V \quad\left(\because V_B=V_C\right)\)
or \(V_C-V_A=4 V\)
272249
If a unit positive charge is taken from one point to another over an equipotential surface, then
1 workis done on the charge
2 workis done by the charge
3 work done is constant
4 no workis done
Explanation:
(d) On the equipotential surface, electric field is normal to the charged surface \{where potential exists\} so that no work will be done.
NCERT Page-61/N-54
Electrostatic Potentials and Capacitance
272250
If the electric potential at any point \((x, y, z) \mathrm{m}\) in space is given by \(V=3 x^2\) volt. The electric field at the point \((1,0,3) m\) will be :
1 \(3 \mathrm{Vm}^{-1}\), directed along positive \(x\)-axis.
2 \(3 \mathrm{Vm}^{-1}\), directed along negative \(x\)-axis.
3 \(6 \mathrm{Vm}^{-1}\), directed along positive \(x\)-axis.
4 \(6 \mathrm{Vm}^{-1}\), directed along negative \(x\)-axis.
Explanation:
(d)
NCERT Page-61/N-55
Electrostatic Potentials and Capacitance
272240
Which of the following figure shows the correct equipotential surfaces of a system of two positive charges?
1
2
3
4
Explanation:
(c) Equipotential surfaces are normal to the electric field lines. The following figure shows the equipotential surfaces along with electric field lines for a system of two positive charges.
NCERT Page-60 / N- 54
Electrostatic Potentials and Capacitance
272239
In moving from A to B along an electric field line, the work done by the electric field on an electron is \(6.4 \times 10^{-19} \mathrm{~J}\). If \(\phi_1\) and \(\phi_2\) are equipotential surfaces, then the potential difference \(V_C-V_A\) is
1 \(-4 V\)
2 4 V
3 zero
4 6.4 V
Explanation:
(b) \(W_{\text {el. }}=g\left(V_i-V_f\right)\) or \(6.4 \times 10^{-19}=-1.6 \times 10^{-19}\left(V_A-V_B\right)\)
or \(\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=-4 \mathrm{~V}\)
or \(\quad V_A-V_C=-4 V \quad\left(\because V_B=V_C\right)\)
or \(V_C-V_A=4 V\)
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Electrostatic Potentials and Capacitance
272249
If a unit positive charge is taken from one point to another over an equipotential surface, then
1 workis done on the charge
2 workis done by the charge
3 work done is constant
4 no workis done
Explanation:
(d) On the equipotential surface, electric field is normal to the charged surface \{where potential exists\} so that no work will be done.
NCERT Page-61/N-54
Electrostatic Potentials and Capacitance
272250
If the electric potential at any point \((x, y, z) \mathrm{m}\) in space is given by \(V=3 x^2\) volt. The electric field at the point \((1,0,3) m\) will be :
1 \(3 \mathrm{Vm}^{-1}\), directed along positive \(x\)-axis.
2 \(3 \mathrm{Vm}^{-1}\), directed along negative \(x\)-axis.
3 \(6 \mathrm{Vm}^{-1}\), directed along positive \(x\)-axis.
4 \(6 \mathrm{Vm}^{-1}\), directed along negative \(x\)-axis.
Explanation:
(d)
NCERT Page-61/N-55
Electrostatic Potentials and Capacitance
272240
Which of the following figure shows the correct equipotential surfaces of a system of two positive charges?
1
2
3
4
Explanation:
(c) Equipotential surfaces are normal to the electric field lines. The following figure shows the equipotential surfaces along with electric field lines for a system of two positive charges.
NCERT Page-60 / N- 54
Electrostatic Potentials and Capacitance
272239
In moving from A to B along an electric field line, the work done by the electric field on an electron is \(6.4 \times 10^{-19} \mathrm{~J}\). If \(\phi_1\) and \(\phi_2\) are equipotential surfaces, then the potential difference \(V_C-V_A\) is
1 \(-4 V\)
2 4 V
3 zero
4 6.4 V
Explanation:
(b) \(W_{\text {el. }}=g\left(V_i-V_f\right)\) or \(6.4 \times 10^{-19}=-1.6 \times 10^{-19}\left(V_A-V_B\right)\)
or \(\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=-4 \mathrm{~V}\)
or \(\quad V_A-V_C=-4 V \quad\left(\because V_B=V_C\right)\)
or \(V_C-V_A=4 V\)
