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Electric Charges and Fields

272200 Which statement is true for Gauss law-

1 All the charges whether inside or outside thegaussian surface contribute to the electric flux.

2 Electric flux depends upon the geometry of thegaussian surface.

3 Gauss theoremcan be applied to non-uniform electric field.

4 The electric field over thegaussian surface remains continuous and uniform at every point.

NCERT Page-33 / N-29 | CBSE Sample 2021-2022

Electric Charges and Fields

272201 The total electric flux emanating from a closed surface enclosing an $α$ -particle is (e-electronic charge)

1

\frac{2 e}{ε_{0}}

2

\frac{e}{ε_{0}}

3

e ε_{0}

4

\frac{ε_{0} e}{4}

Explanation:

(a) According to Gauss's law total electric flux through a closed surface is $\frac{1}{ε_{0}}$ times the total charge inside that surface.
Electric flux, $ϕ_{E} = \frac{q}{ε_{0}}$
Charge on $α$ -particle $= 2 e ∴ ϕ_{E} = \frac{2 e}{ε_{0}}$

NCERT Page-34 / N-30

Electric Charges and Fields

272202 For a given surface the Gauss's law is stated as $\oint \vec{E} \cdot d \vec{A} = 0$ . From this we can conclude that

1

E

is necessarily zero on the surface

2

E

is perpendicular to the surface at every point

3 the total flux through the surface is zero

4 the flux is only going out of the surface

Explanation:

(c) $\oint \vec{E} \cdot d \vec{A} = 0$ , represents charge inside close surface is zero. Electric field as any point on the surface may be zero.

NCERT Page-33 / N-30

Electric Charges and Fields

272203 The electric field inside a spherical shell of uniform surface charge density is

1 zero

2 constant different from zero

3 proportional to the distance from the curve

4 None of the above

Explanation:

(a) Electric charge resides only on the surface of a spherical shell. According to Gauss's theorem the total electric flux over a closed surface is equal to the $\frac{1}{ε_{0}}$ times the total charge enclosed by the closed surface.

NCERT Page-39 / N-35

Electric Charges and Fields

272200 Which statement is true for Gauss law-

1 All the charges whether inside or outside thegaussian surface contribute to the electric flux.

2 Electric flux depends upon the geometry of thegaussian surface.

3 Gauss theoremcan be applied to non-uniform electric field.

4 The electric field over thegaussian surface remains continuous and uniform at every point.

NCERT Page-33 / N-29 | CBSE Sample 2021-2022

Electric Charges and Fields

272201 The total electric flux emanating from a closed surface enclosing an $α$ -particle is (e-electronic charge)

1

\frac{2 e}{ε_{0}}

2

\frac{e}{ε_{0}}

3

e ε_{0}

4

\frac{ε_{0} e}{4}

Explanation:

(a) According to Gauss's law total electric flux through a closed surface is $\frac{1}{ε_{0}}$ times the total charge inside that surface.
Electric flux, $ϕ_{E} = \frac{q}{ε_{0}}$
Charge on $α$ -particle $= 2 e ∴ ϕ_{E} = \frac{2 e}{ε_{0}}$

NCERT Page-34 / N-30

Electric Charges and Fields

272202 For a given surface the Gauss's law is stated as $\oint \vec{E} \cdot d \vec{A} = 0$ . From this we can conclude that

1

E

is necessarily zero on the surface

2

E

is perpendicular to the surface at every point

3 the total flux through the surface is zero

4 the flux is only going out of the surface

Explanation:

(c) $\oint \vec{E} \cdot d \vec{A} = 0$ , represents charge inside close surface is zero. Electric field as any point on the surface may be zero.

NCERT Page-33 / N-30

Electric Charges and Fields

272203 The electric field inside a spherical shell of uniform surface charge density is

1 zero

2 constant different from zero

3 proportional to the distance from the curve

4 None of the above

Explanation:

(a) Electric charge resides only on the surface of a spherical shell. According to Gauss's theorem the total electric flux over a closed surface is equal to the $\frac{1}{ε_{0}}$ times the total charge enclosed by the closed surface.

NCERT Page-39 / N-35

Electric Charges and Fields

272200 Which statement is true for Gauss law-

1 All the charges whether inside or outside thegaussian surface contribute to the electric flux.

2 Electric flux depends upon the geometry of thegaussian surface.

3 Gauss theoremcan be applied to non-uniform electric field.

4 The electric field over thegaussian surface remains continuous and uniform at every point.

NCERT Page-33 / N-29 | CBSE Sample 2021-2022

Electric Charges and Fields

272201 The total electric flux emanating from a closed surface enclosing an $α$ -particle is (e-electronic charge)

1

\frac{2 e}{ε_{0}}

2

\frac{e}{ε_{0}}

3

e ε_{0}

4

\frac{ε_{0} e}{4}

Explanation:

(a) According to Gauss's law total electric flux through a closed surface is $\frac{1}{ε_{0}}$ times the total charge inside that surface.
Electric flux, $ϕ_{E} = \frac{q}{ε_{0}}$
Charge on $α$ -particle $= 2 e ∴ ϕ_{E} = \frac{2 e}{ε_{0}}$

NCERT Page-34 / N-30

Electric Charges and Fields

272202 For a given surface the Gauss's law is stated as $\oint \vec{E} \cdot d \vec{A} = 0$ . From this we can conclude that

1

E

is necessarily zero on the surface

2

E

is perpendicular to the surface at every point

3 the total flux through the surface is zero

4 the flux is only going out of the surface

Explanation:

(c) $\oint \vec{E} \cdot d \vec{A} = 0$ , represents charge inside close surface is zero. Electric field as any point on the surface may be zero.

NCERT Page-33 / N-30

Electric Charges and Fields

272203 The electric field inside a spherical shell of uniform surface charge density is

1 zero

2 constant different from zero

3 proportional to the distance from the curve

4 None of the above

Explanation:

(a) Electric charge resides only on the surface of a spherical shell. According to Gauss's theorem the total electric flux over a closed surface is equal to the $\frac{1}{ε_{0}}$ times the total charge enclosed by the closed surface.

NCERT Page-39 / N-35

Electric Charges and Fields

272200 Which statement is true for Gauss law-

1 All the charges whether inside or outside thegaussian surface contribute to the electric flux.

2 Electric flux depends upon the geometry of thegaussian surface.

3 Gauss theoremcan be applied to non-uniform electric field.

4 The electric field over thegaussian surface remains continuous and uniform at every point.

NCERT Page-33 / N-29 | CBSE Sample 2021-2022

Electric Charges and Fields

272201 The total electric flux emanating from a closed surface enclosing an $α$ -particle is (e-electronic charge)

1

\frac{2 e}{ε_{0}}

2

\frac{e}{ε_{0}}

3

e ε_{0}

4

\frac{ε_{0} e}{4}

Explanation:

(a) According to Gauss's law total electric flux through a closed surface is $\frac{1}{ε_{0}}$ times the total charge inside that surface.
Electric flux, $ϕ_{E} = \frac{q}{ε_{0}}$
Charge on $α$ -particle $= 2 e ∴ ϕ_{E} = \frac{2 e}{ε_{0}}$

NCERT Page-34 / N-30

Electric Charges and Fields

272202 For a given surface the Gauss's law is stated as $\oint \vec{E} \cdot d \vec{A} = 0$ . From this we can conclude that

1

E

is necessarily zero on the surface

2

E

is perpendicular to the surface at every point

3 the total flux through the surface is zero

4 the flux is only going out of the surface

Explanation:

(c) $\oint \vec{E} \cdot d \vec{A} = 0$ , represents charge inside close surface is zero. Electric field as any point on the surface may be zero.

NCERT Page-33 / N-30

Electric Charges and Fields

272203 The electric field inside a spherical shell of uniform surface charge density is

1 zero

2 constant different from zero

3 proportional to the distance from the curve

4 None of the above

Explanation:

(a) Electric charge resides only on the surface of a spherical shell. According to Gauss's theorem the total electric flux over a closed surface is equal to the $\frac{1}{ε_{0}}$ times the total charge enclosed by the closed surface.

NCERT Page-39 / N-35

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