270552
A particle hanging from a massless spring stretches it by \(2 \mathbf{~ c m}\) at earth's surface. How much will the same particle stretch the spring at a height of \(2624 \mathrm{Km}\) from the surface of the earth? (Radius of earth \(=6400 \mathrm{Km})\)
1 \(1 \mathrm{~cm}\)
2 \(2 \mathrm{~cm}\)
3 \(3 \mathrm{~cm}\)
4 \(4 \mathrm{~cm}\)
Explanation:
\(\mathrm{mg}=\mathrm{Kx}, x \propto g\) Here, \(\frac{g_{h}}{g}=\frac{R^{2}}{(R+h)^{2}}\)
Gravitation
270553
The value of acceleration due to gravity ' \(g\) ' on the surface of a planet with radius double that of earth and same mean density as that of the earth is \(\left(g_{e}=\right.\) acceleration due to gravity on the surface of earth)
1 \(g_{p}=2 g_{e}\)
2 \(g_{p}=g_{e} / 2\)
3 \(.g_{p}=g_{e} / 4\)
4 \( g_{p}=4 g_{e}\)
Explanation:
\(g=\frac{4}{3} G \pi R \rho \Rightarrow g \propto R \rho\)
Gravitation
270554
If \(\mathbf{g}\) is acceleration due to gravity on the surface of the earth, having radius \(R\), the height at which the acceleration due to gravity reduces to \(\mathrm{g} / 2\) is
1 \(R / 2\)
2 \(\sqrt{2} R\)
3 \(\frac{R}{\sqrt{2}}\)
4 \((\sqrt{2}-1) R\)
Explanation:
\(\quad \frac{g_{h}}{g}=\frac{R^{2}}{(R+h)^{2}} \quad\) Given \(g_{h}=\frac{g}{2}\)
Gravitation
270635
The difference in the value of ' \(g\) ' at poles and at a place of latitude \(45^{\circ}\) is
270552
A particle hanging from a massless spring stretches it by \(2 \mathbf{~ c m}\) at earth's surface. How much will the same particle stretch the spring at a height of \(2624 \mathrm{Km}\) from the surface of the earth? (Radius of earth \(=6400 \mathrm{Km})\)
1 \(1 \mathrm{~cm}\)
2 \(2 \mathrm{~cm}\)
3 \(3 \mathrm{~cm}\)
4 \(4 \mathrm{~cm}\)
Explanation:
\(\mathrm{mg}=\mathrm{Kx}, x \propto g\) Here, \(\frac{g_{h}}{g}=\frac{R^{2}}{(R+h)^{2}}\)
Gravitation
270553
The value of acceleration due to gravity ' \(g\) ' on the surface of a planet with radius double that of earth and same mean density as that of the earth is \(\left(g_{e}=\right.\) acceleration due to gravity on the surface of earth)
1 \(g_{p}=2 g_{e}\)
2 \(g_{p}=g_{e} / 2\)
3 \(.g_{p}=g_{e} / 4\)
4 \( g_{p}=4 g_{e}\)
Explanation:
\(g=\frac{4}{3} G \pi R \rho \Rightarrow g \propto R \rho\)
Gravitation
270554
If \(\mathbf{g}\) is acceleration due to gravity on the surface of the earth, having radius \(R\), the height at which the acceleration due to gravity reduces to \(\mathrm{g} / 2\) is
1 \(R / 2\)
2 \(\sqrt{2} R\)
3 \(\frac{R}{\sqrt{2}}\)
4 \((\sqrt{2}-1) R\)
Explanation:
\(\quad \frac{g_{h}}{g}=\frac{R^{2}}{(R+h)^{2}} \quad\) Given \(g_{h}=\frac{g}{2}\)
Gravitation
270635
The difference in the value of ' \(g\) ' at poles and at a place of latitude \(45^{\circ}\) is
270552
A particle hanging from a massless spring stretches it by \(2 \mathbf{~ c m}\) at earth's surface. How much will the same particle stretch the spring at a height of \(2624 \mathrm{Km}\) from the surface of the earth? (Radius of earth \(=6400 \mathrm{Km})\)
1 \(1 \mathrm{~cm}\)
2 \(2 \mathrm{~cm}\)
3 \(3 \mathrm{~cm}\)
4 \(4 \mathrm{~cm}\)
Explanation:
\(\mathrm{mg}=\mathrm{Kx}, x \propto g\) Here, \(\frac{g_{h}}{g}=\frac{R^{2}}{(R+h)^{2}}\)
Gravitation
270553
The value of acceleration due to gravity ' \(g\) ' on the surface of a planet with radius double that of earth and same mean density as that of the earth is \(\left(g_{e}=\right.\) acceleration due to gravity on the surface of earth)
1 \(g_{p}=2 g_{e}\)
2 \(g_{p}=g_{e} / 2\)
3 \(.g_{p}=g_{e} / 4\)
4 \( g_{p}=4 g_{e}\)
Explanation:
\(g=\frac{4}{3} G \pi R \rho \Rightarrow g \propto R \rho\)
Gravitation
270554
If \(\mathbf{g}\) is acceleration due to gravity on the surface of the earth, having radius \(R\), the height at which the acceleration due to gravity reduces to \(\mathrm{g} / 2\) is
1 \(R / 2\)
2 \(\sqrt{2} R\)
3 \(\frac{R}{\sqrt{2}}\)
4 \((\sqrt{2}-1) R\)
Explanation:
\(\quad \frac{g_{h}}{g}=\frac{R^{2}}{(R+h)^{2}} \quad\) Given \(g_{h}=\frac{g}{2}\)
Gravitation
270635
The difference in the value of ' \(g\) ' at poles and at a place of latitude \(45^{\circ}\) is
270552
A particle hanging from a massless spring stretches it by \(2 \mathbf{~ c m}\) at earth's surface. How much will the same particle stretch the spring at a height of \(2624 \mathrm{Km}\) from the surface of the earth? (Radius of earth \(=6400 \mathrm{Km})\)
1 \(1 \mathrm{~cm}\)
2 \(2 \mathrm{~cm}\)
3 \(3 \mathrm{~cm}\)
4 \(4 \mathrm{~cm}\)
Explanation:
\(\mathrm{mg}=\mathrm{Kx}, x \propto g\) Here, \(\frac{g_{h}}{g}=\frac{R^{2}}{(R+h)^{2}}\)
Gravitation
270553
The value of acceleration due to gravity ' \(g\) ' on the surface of a planet with radius double that of earth and same mean density as that of the earth is \(\left(g_{e}=\right.\) acceleration due to gravity on the surface of earth)
1 \(g_{p}=2 g_{e}\)
2 \(g_{p}=g_{e} / 2\)
3 \(.g_{p}=g_{e} / 4\)
4 \( g_{p}=4 g_{e}\)
Explanation:
\(g=\frac{4}{3} G \pi R \rho \Rightarrow g \propto R \rho\)
Gravitation
270554
If \(\mathbf{g}\) is acceleration due to gravity on the surface of the earth, having radius \(R\), the height at which the acceleration due to gravity reduces to \(\mathrm{g} / 2\) is
1 \(R / 2\)
2 \(\sqrt{2} R\)
3 \(\frac{R}{\sqrt{2}}\)
4 \((\sqrt{2}-1) R\)
Explanation:
\(\quad \frac{g_{h}}{g}=\frac{R^{2}}{(R+h)^{2}} \quad\) Given \(g_{h}=\frac{g}{2}\)
Gravitation
270635
The difference in the value of ' \(g\) ' at poles and at a place of latitude \(45^{\circ}\) is
