GRAVITATIONAL FIELD INTENSITY
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Gravitation

270504 The point at which the gravitational force acting on any mass is zero due to the earth and the moon system is (The mass of the earth is approximately 81 times the mass of the moon and the distance between the earth and the moon is \(3,85,000 \mathrm{~km}\).)

1 \(36,000 \mathrm{~km}\) from the moon
2 \(38,500 \mathrm{~km}\) from the moon
3 \(34500 \mathrm{~km}\) from the moon
4 \(30,000 \mathrm{~km}\) from the moon
Gravitation

270505 Masses \(2 \mathrm{~kg}\) and \(8 \mathrm{~kg}\) are \(18 \mathrm{~cm}\) apart. The point where the gravitational field due to them is zero is

1 \(6 \mathrm{~cm}\) from \(8 \mathrm{~kg}\) mass
2 \(6 \mathrm{~cm}\) from \(2 \mathrm{~kg}\) mass
3 \(1.8 \mathrm{~cm}\) from \(8 \mathrm{~kg}\) mass
4 \(9 \mathrm{~cm}\) from each mass
Gravitation

270506 Particles of masses \(m_{1}\) and \(m_{2}\) are at a fixed distance apart. If the gravitational field strength at \(\mathbf{m}_{1}\) and \(\mathbf{m}_{2}\) are \(\vec{I}_{1}\) and \(\vec{I}_{2}\) respectively. Then,

1 \(m_{1} \overrightarrow{I_{1}}+m_{2} \overrightarrow{I_{2}}=0\)
2 \(m_{1} \overrightarrow{I_{2}}+m_{2} \overrightarrow{I_{1}}=0\)
3 \(m_{1} \overrightarrow{I_{1}}-m_{2} \overrightarrow{I_{2}}=0\)
4 \(m_{1} \overrightarrow{I_{2}}-m_{2} \overrightarrow{I_{1}}=0\)
Gravitation

270555 There are two bodies of masses \(100 \mathrm{Kg}\) and \(1000 \mathrm{Kg}\) separated by a distance \(1 \mathrm{~m}\). The intensity of gravitational field at the mid point of the line joining them will be

1 \(2.4 \times 10^{-6} \mathrm{~N} / \mathrm{kg}\)
2 \(2.4 \times 10^{-7} \mathrm{~N} / \mathrm{kg}\)
3 \(2.4 \times 10^{-8} \mathrm{~N} / \mathrm{kg}\)
4 \(2.4 \times 10^{-9} \mathrm{~N} / \mathrm{kg}\)
Gravitation

270556 Masses \(4 \mathrm{~kg}\) and \(36 \mathrm{~kg}\) are \(16 \mathrm{~cm}\) apart. The point where the gravitational field due to them is zero is

1 \(6 \mathrm{~cm}\) from \(4 \mathrm{~kg}\) mass
2 \(4 \mathrm{~cm}\) from \(4 \mathrm{~kg}\) mass
3 \(1.8 \mathrm{~cm}\) from \(36 \mathrm{~kg}\) mass
4 \(9 \mathrm{~cm}\) from each mass
NEET DIGITAL LIBRARY
Gravitation

270504 The point at which the gravitational force acting on any mass is zero due to the earth and the moon system is (The mass of the earth is approximately 81 times the mass of the moon and the distance between the earth and the moon is \(3,85,000 \mathrm{~km}\).)

1 \(36,000 \mathrm{~km}\) from the moon
2 \(38,500 \mathrm{~km}\) from the moon
3 \(34500 \mathrm{~km}\) from the moon
4 \(30,000 \mathrm{~km}\) from the moon
Gravitation

270505 Masses \(2 \mathrm{~kg}\) and \(8 \mathrm{~kg}\) are \(18 \mathrm{~cm}\) apart. The point where the gravitational field due to them is zero is

1 \(6 \mathrm{~cm}\) from \(8 \mathrm{~kg}\) mass
2 \(6 \mathrm{~cm}\) from \(2 \mathrm{~kg}\) mass
3 \(1.8 \mathrm{~cm}\) from \(8 \mathrm{~kg}\) mass
4 \(9 \mathrm{~cm}\) from each mass
Gravitation

270506 Particles of masses \(m_{1}\) and \(m_{2}\) are at a fixed distance apart. If the gravitational field strength at \(\mathbf{m}_{1}\) and \(\mathbf{m}_{2}\) are \(\vec{I}_{1}\) and \(\vec{I}_{2}\) respectively. Then,

1 \(m_{1} \overrightarrow{I_{1}}+m_{2} \overrightarrow{I_{2}}=0\)
2 \(m_{1} \overrightarrow{I_{2}}+m_{2} \overrightarrow{I_{1}}=0\)
3 \(m_{1} \overrightarrow{I_{1}}-m_{2} \overrightarrow{I_{2}}=0\)
4 \(m_{1} \overrightarrow{I_{2}}-m_{2} \overrightarrow{I_{1}}=0\)
Gravitation

270555 There are two bodies of masses \(100 \mathrm{Kg}\) and \(1000 \mathrm{Kg}\) separated by a distance \(1 \mathrm{~m}\). The intensity of gravitational field at the mid point of the line joining them will be

1 \(2.4 \times 10^{-6} \mathrm{~N} / \mathrm{kg}\)
2 \(2.4 \times 10^{-7} \mathrm{~N} / \mathrm{kg}\)
3 \(2.4 \times 10^{-8} \mathrm{~N} / \mathrm{kg}\)
4 \(2.4 \times 10^{-9} \mathrm{~N} / \mathrm{kg}\)
Gravitation

270556 Masses \(4 \mathrm{~kg}\) and \(36 \mathrm{~kg}\) are \(16 \mathrm{~cm}\) apart. The point where the gravitational field due to them is zero is

1 \(6 \mathrm{~cm}\) from \(4 \mathrm{~kg}\) mass
2 \(4 \mathrm{~cm}\) from \(4 \mathrm{~kg}\) mass
3 \(1.8 \mathrm{~cm}\) from \(36 \mathrm{~kg}\) mass
4 \(9 \mathrm{~cm}\) from each mass
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Gravitation

270504 The point at which the gravitational force acting on any mass is zero due to the earth and the moon system is (The mass of the earth is approximately 81 times the mass of the moon and the distance between the earth and the moon is \(3,85,000 \mathrm{~km}\).)

1 \(36,000 \mathrm{~km}\) from the moon
2 \(38,500 \mathrm{~km}\) from the moon
3 \(34500 \mathrm{~km}\) from the moon
4 \(30,000 \mathrm{~km}\) from the moon
Gravitation

270505 Masses \(2 \mathrm{~kg}\) and \(8 \mathrm{~kg}\) are \(18 \mathrm{~cm}\) apart. The point where the gravitational field due to them is zero is

1 \(6 \mathrm{~cm}\) from \(8 \mathrm{~kg}\) mass
2 \(6 \mathrm{~cm}\) from \(2 \mathrm{~kg}\) mass
3 \(1.8 \mathrm{~cm}\) from \(8 \mathrm{~kg}\) mass
4 \(9 \mathrm{~cm}\) from each mass
Gravitation

270506 Particles of masses \(m_{1}\) and \(m_{2}\) are at a fixed distance apart. If the gravitational field strength at \(\mathbf{m}_{1}\) and \(\mathbf{m}_{2}\) are \(\vec{I}_{1}\) and \(\vec{I}_{2}\) respectively. Then,

1 \(m_{1} \overrightarrow{I_{1}}+m_{2} \overrightarrow{I_{2}}=0\)
2 \(m_{1} \overrightarrow{I_{2}}+m_{2} \overrightarrow{I_{1}}=0\)
3 \(m_{1} \overrightarrow{I_{1}}-m_{2} \overrightarrow{I_{2}}=0\)
4 \(m_{1} \overrightarrow{I_{2}}-m_{2} \overrightarrow{I_{1}}=0\)
Gravitation

270555 There are two bodies of masses \(100 \mathrm{Kg}\) and \(1000 \mathrm{Kg}\) separated by a distance \(1 \mathrm{~m}\). The intensity of gravitational field at the mid point of the line joining them will be

1 \(2.4 \times 10^{-6} \mathrm{~N} / \mathrm{kg}\)
2 \(2.4 \times 10^{-7} \mathrm{~N} / \mathrm{kg}\)
3 \(2.4 \times 10^{-8} \mathrm{~N} / \mathrm{kg}\)
4 \(2.4 \times 10^{-9} \mathrm{~N} / \mathrm{kg}\)
Gravitation

270556 Masses \(4 \mathrm{~kg}\) and \(36 \mathrm{~kg}\) are \(16 \mathrm{~cm}\) apart. The point where the gravitational field due to them is zero is

1 \(6 \mathrm{~cm}\) from \(4 \mathrm{~kg}\) mass
2 \(4 \mathrm{~cm}\) from \(4 \mathrm{~kg}\) mass
3 \(1.8 \mathrm{~cm}\) from \(36 \mathrm{~kg}\) mass
4 \(9 \mathrm{~cm}\) from each mass
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Gravitation

270504 The point at which the gravitational force acting on any mass is zero due to the earth and the moon system is (The mass of the earth is approximately 81 times the mass of the moon and the distance between the earth and the moon is \(3,85,000 \mathrm{~km}\).)

1 \(36,000 \mathrm{~km}\) from the moon
2 \(38,500 \mathrm{~km}\) from the moon
3 \(34500 \mathrm{~km}\) from the moon
4 \(30,000 \mathrm{~km}\) from the moon
Gravitation

270505 Masses \(2 \mathrm{~kg}\) and \(8 \mathrm{~kg}\) are \(18 \mathrm{~cm}\) apart. The point where the gravitational field due to them is zero is

1 \(6 \mathrm{~cm}\) from \(8 \mathrm{~kg}\) mass
2 \(6 \mathrm{~cm}\) from \(2 \mathrm{~kg}\) mass
3 \(1.8 \mathrm{~cm}\) from \(8 \mathrm{~kg}\) mass
4 \(9 \mathrm{~cm}\) from each mass
Gravitation

270506 Particles of masses \(m_{1}\) and \(m_{2}\) are at a fixed distance apart. If the gravitational field strength at \(\mathbf{m}_{1}\) and \(\mathbf{m}_{2}\) are \(\vec{I}_{1}\) and \(\vec{I}_{2}\) respectively. Then,

1 \(m_{1} \overrightarrow{I_{1}}+m_{2} \overrightarrow{I_{2}}=0\)
2 \(m_{1} \overrightarrow{I_{2}}+m_{2} \overrightarrow{I_{1}}=0\)
3 \(m_{1} \overrightarrow{I_{1}}-m_{2} \overrightarrow{I_{2}}=0\)
4 \(m_{1} \overrightarrow{I_{2}}-m_{2} \overrightarrow{I_{1}}=0\)
Gravitation

270555 There are two bodies of masses \(100 \mathrm{Kg}\) and \(1000 \mathrm{Kg}\) separated by a distance \(1 \mathrm{~m}\). The intensity of gravitational field at the mid point of the line joining them will be

1 \(2.4 \times 10^{-6} \mathrm{~N} / \mathrm{kg}\)
2 \(2.4 \times 10^{-7} \mathrm{~N} / \mathrm{kg}\)
3 \(2.4 \times 10^{-8} \mathrm{~N} / \mathrm{kg}\)
4 \(2.4 \times 10^{-9} \mathrm{~N} / \mathrm{kg}\)
Gravitation

270556 Masses \(4 \mathrm{~kg}\) and \(36 \mathrm{~kg}\) are \(16 \mathrm{~cm}\) apart. The point where the gravitational field due to them is zero is

1 \(6 \mathrm{~cm}\) from \(4 \mathrm{~kg}\) mass
2 \(4 \mathrm{~cm}\) from \(4 \mathrm{~kg}\) mass
3 \(1.8 \mathrm{~cm}\) from \(36 \mathrm{~kg}\) mass
4 \(9 \mathrm{~cm}\) from each mass
NEET DIGITAL LIBRARY
Gravitation

270504 The point at which the gravitational force acting on any mass is zero due to the earth and the moon system is (The mass of the earth is approximately 81 times the mass of the moon and the distance between the earth and the moon is \(3,85,000 \mathrm{~km}\).)

1 \(36,000 \mathrm{~km}\) from the moon
2 \(38,500 \mathrm{~km}\) from the moon
3 \(34500 \mathrm{~km}\) from the moon
4 \(30,000 \mathrm{~km}\) from the moon
Gravitation

270505 Masses \(2 \mathrm{~kg}\) and \(8 \mathrm{~kg}\) are \(18 \mathrm{~cm}\) apart. The point where the gravitational field due to them is zero is

1 \(6 \mathrm{~cm}\) from \(8 \mathrm{~kg}\) mass
2 \(6 \mathrm{~cm}\) from \(2 \mathrm{~kg}\) mass
3 \(1.8 \mathrm{~cm}\) from \(8 \mathrm{~kg}\) mass
4 \(9 \mathrm{~cm}\) from each mass
Gravitation

270506 Particles of masses \(m_{1}\) and \(m_{2}\) are at a fixed distance apart. If the gravitational field strength at \(\mathbf{m}_{1}\) and \(\mathbf{m}_{2}\) are \(\vec{I}_{1}\) and \(\vec{I}_{2}\) respectively. Then,

1 \(m_{1} \overrightarrow{I_{1}}+m_{2} \overrightarrow{I_{2}}=0\)
2 \(m_{1} \overrightarrow{I_{2}}+m_{2} \overrightarrow{I_{1}}=0\)
3 \(m_{1} \overrightarrow{I_{1}}-m_{2} \overrightarrow{I_{2}}=0\)
4 \(m_{1} \overrightarrow{I_{2}}-m_{2} \overrightarrow{I_{1}}=0\)
Gravitation

270555 There are two bodies of masses \(100 \mathrm{Kg}\) and \(1000 \mathrm{Kg}\) separated by a distance \(1 \mathrm{~m}\). The intensity of gravitational field at the mid point of the line joining them will be

1 \(2.4 \times 10^{-6} \mathrm{~N} / \mathrm{kg}\)
2 \(2.4 \times 10^{-7} \mathrm{~N} / \mathrm{kg}\)
3 \(2.4 \times 10^{-8} \mathrm{~N} / \mathrm{kg}\)
4 \(2.4 \times 10^{-9} \mathrm{~N} / \mathrm{kg}\)
Gravitation

270556 Masses \(4 \mathrm{~kg}\) and \(36 \mathrm{~kg}\) are \(16 \mathrm{~cm}\) apart. The point where the gravitational field due to them is zero is

1 \(6 \mathrm{~cm}\) from \(4 \mathrm{~kg}\) mass
2 \(4 \mathrm{~cm}\) from \(4 \mathrm{~kg}\) mass
3 \(1.8 \mathrm{~cm}\) from \(36 \mathrm{~kg}\) mass
4 \(9 \mathrm{~cm}\) from each mass