270246
A balloon of mass\(M\) is descending at a constant acceleration \(\alpha\). When a mass \(m\) is released from the balloon it starts rising with the same acceleration \(\alpha\). Assuming that its volume does not change, what is the value of \(m\) ?
1 \(\frac{\alpha}{\alpha+g} M\)
2 \(\frac{2 \alpha}{\alpha+g} M\)
3 \(\frac{\alpha+g}{\alpha} M\)
4 \(\frac{\alpha+g}{2 \alpha} M\)
Explanation:
While descending,\(M g-F_{B}=M \alpha\)
While ascending \(F_{B}-(M-m) g=(M-m) \alpha\)
Where ' \(F_{B}\) ' is the buoyant force
Laws of Motion
270247
A monkey of mass\(40 \mathrm{~kg}\) climbs on a massless rope of breaking strength \(600 \mathrm{~N}\). The rope will break if the m onkey. (Take \(\mathrm{g}=10 \mathrm{~m} / \mathbf{s}^{2}\) )
1 climbs up with a uniform speed of\(6 \mathrm{~m} / \mathrm{s}\)
2 climbs up with an acceleration of\(6 \mathrm{~m} / \mathrm{s}^{2}\)
3 climbs down with an acceleration of\(4 \mathrm{~m} / \mathrm{s}^{2}\)
4 climbs down with a uniform speed of\(5 \mathrm{~m} / \mathrm{s}\)
Explanation:
To move up with an acceleration\(a\) the monkey will push the rope downwards with a force of ma.
\(T_{\text {max }}=m g+m a_{\text {max }}\)
Laws of Motion
270248
Two persons are holding a rope of negligible weight tightly at its ends so that it is horizontal. A\(15 \mathrm{~kg}\) weight is attached to rope at the midpoint which now no more remains horizontal. The minimum tension required to completely straighten the rope is
1 \(150 \mathrm{~N}\)
2 \(75 \mathrm{~N}\)
3 \(50 \mathrm{~N}\)
4 Infinitely large
Explanation:
\(T=F, 2 T \cos \theta=m g\)
To make rope straight, \(\theta=90^{\circ}\)
Laws of Motion
270249
A straight rope of length '\(L\) ' is kept on a frictionless horizontal surface and a force ' \(F\) ' is applied to one end of the rope in the direction of its length and away from that end. The tension in the rope at a distance ' \(I\) ' from that end is
270246
A balloon of mass\(M\) is descending at a constant acceleration \(\alpha\). When a mass \(m\) is released from the balloon it starts rising with the same acceleration \(\alpha\). Assuming that its volume does not change, what is the value of \(m\) ?
1 \(\frac{\alpha}{\alpha+g} M\)
2 \(\frac{2 \alpha}{\alpha+g} M\)
3 \(\frac{\alpha+g}{\alpha} M\)
4 \(\frac{\alpha+g}{2 \alpha} M\)
Explanation:
While descending,\(M g-F_{B}=M \alpha\)
While ascending \(F_{B}-(M-m) g=(M-m) \alpha\)
Where ' \(F_{B}\) ' is the buoyant force
Laws of Motion
270247
A monkey of mass\(40 \mathrm{~kg}\) climbs on a massless rope of breaking strength \(600 \mathrm{~N}\). The rope will break if the m onkey. (Take \(\mathrm{g}=10 \mathrm{~m} / \mathbf{s}^{2}\) )
1 climbs up with a uniform speed of\(6 \mathrm{~m} / \mathrm{s}\)
2 climbs up with an acceleration of\(6 \mathrm{~m} / \mathrm{s}^{2}\)
3 climbs down with an acceleration of\(4 \mathrm{~m} / \mathrm{s}^{2}\)
4 climbs down with a uniform speed of\(5 \mathrm{~m} / \mathrm{s}\)
Explanation:
To move up with an acceleration\(a\) the monkey will push the rope downwards with a force of ma.
\(T_{\text {max }}=m g+m a_{\text {max }}\)
Laws of Motion
270248
Two persons are holding a rope of negligible weight tightly at its ends so that it is horizontal. A\(15 \mathrm{~kg}\) weight is attached to rope at the midpoint which now no more remains horizontal. The minimum tension required to completely straighten the rope is
1 \(150 \mathrm{~N}\)
2 \(75 \mathrm{~N}\)
3 \(50 \mathrm{~N}\)
4 Infinitely large
Explanation:
\(T=F, 2 T \cos \theta=m g\)
To make rope straight, \(\theta=90^{\circ}\)
Laws of Motion
270249
A straight rope of length '\(L\) ' is kept on a frictionless horizontal surface and a force ' \(F\) ' is applied to one end of the rope in the direction of its length and away from that end. The tension in the rope at a distance ' \(I\) ' from that end is
270246
A balloon of mass\(M\) is descending at a constant acceleration \(\alpha\). When a mass \(m\) is released from the balloon it starts rising with the same acceleration \(\alpha\). Assuming that its volume does not change, what is the value of \(m\) ?
1 \(\frac{\alpha}{\alpha+g} M\)
2 \(\frac{2 \alpha}{\alpha+g} M\)
3 \(\frac{\alpha+g}{\alpha} M\)
4 \(\frac{\alpha+g}{2 \alpha} M\)
Explanation:
While descending,\(M g-F_{B}=M \alpha\)
While ascending \(F_{B}-(M-m) g=(M-m) \alpha\)
Where ' \(F_{B}\) ' is the buoyant force
Laws of Motion
270247
A monkey of mass\(40 \mathrm{~kg}\) climbs on a massless rope of breaking strength \(600 \mathrm{~N}\). The rope will break if the m onkey. (Take \(\mathrm{g}=10 \mathrm{~m} / \mathbf{s}^{2}\) )
1 climbs up with a uniform speed of\(6 \mathrm{~m} / \mathrm{s}\)
2 climbs up with an acceleration of\(6 \mathrm{~m} / \mathrm{s}^{2}\)
3 climbs down with an acceleration of\(4 \mathrm{~m} / \mathrm{s}^{2}\)
4 climbs down with a uniform speed of\(5 \mathrm{~m} / \mathrm{s}\)
Explanation:
To move up with an acceleration\(a\) the monkey will push the rope downwards with a force of ma.
\(T_{\text {max }}=m g+m a_{\text {max }}\)
Laws of Motion
270248
Two persons are holding a rope of negligible weight tightly at its ends so that it is horizontal. A\(15 \mathrm{~kg}\) weight is attached to rope at the midpoint which now no more remains horizontal. The minimum tension required to completely straighten the rope is
1 \(150 \mathrm{~N}\)
2 \(75 \mathrm{~N}\)
3 \(50 \mathrm{~N}\)
4 Infinitely large
Explanation:
\(T=F, 2 T \cos \theta=m g\)
To make rope straight, \(\theta=90^{\circ}\)
Laws of Motion
270249
A straight rope of length '\(L\) ' is kept on a frictionless horizontal surface and a force ' \(F\) ' is applied to one end of the rope in the direction of its length and away from that end. The tension in the rope at a distance ' \(I\) ' from that end is
270246
A balloon of mass\(M\) is descending at a constant acceleration \(\alpha\). When a mass \(m\) is released from the balloon it starts rising with the same acceleration \(\alpha\). Assuming that its volume does not change, what is the value of \(m\) ?
1 \(\frac{\alpha}{\alpha+g} M\)
2 \(\frac{2 \alpha}{\alpha+g} M\)
3 \(\frac{\alpha+g}{\alpha} M\)
4 \(\frac{\alpha+g}{2 \alpha} M\)
Explanation:
While descending,\(M g-F_{B}=M \alpha\)
While ascending \(F_{B}-(M-m) g=(M-m) \alpha\)
Where ' \(F_{B}\) ' is the buoyant force
Laws of Motion
270247
A monkey of mass\(40 \mathrm{~kg}\) climbs on a massless rope of breaking strength \(600 \mathrm{~N}\). The rope will break if the m onkey. (Take \(\mathrm{g}=10 \mathrm{~m} / \mathbf{s}^{2}\) )
1 climbs up with a uniform speed of\(6 \mathrm{~m} / \mathrm{s}\)
2 climbs up with an acceleration of\(6 \mathrm{~m} / \mathrm{s}^{2}\)
3 climbs down with an acceleration of\(4 \mathrm{~m} / \mathrm{s}^{2}\)
4 climbs down with a uniform speed of\(5 \mathrm{~m} / \mathrm{s}\)
Explanation:
To move up with an acceleration\(a\) the monkey will push the rope downwards with a force of ma.
\(T_{\text {max }}=m g+m a_{\text {max }}\)
Laws of Motion
270248
Two persons are holding a rope of negligible weight tightly at its ends so that it is horizontal. A\(15 \mathrm{~kg}\) weight is attached to rope at the midpoint which now no more remains horizontal. The minimum tension required to completely straighten the rope is
1 \(150 \mathrm{~N}\)
2 \(75 \mathrm{~N}\)
3 \(50 \mathrm{~N}\)
4 Infinitely large
Explanation:
\(T=F, 2 T \cos \theta=m g\)
To make rope straight, \(\theta=90^{\circ}\)
Laws of Motion
270249
A straight rope of length '\(L\) ' is kept on a frictionless horizontal surface and a force ' \(F\) ' is applied to one end of the rope in the direction of its length and away from that end. The tension in the rope at a distance ' \(I\) ' from that end is
