NEET Test Series from KOTA - 10 Papers In MS WORD
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MOTION IN A STRIGHT LINE
269787
Astonethrown vertically up from theground reaches a maximum height of \(50 \mathrm{~m}\) in \(10 \mathrm{~s}\). Time taken by the stoneto reach theground from maximum height is
1 \(5 \mathrm{~s}\)
2 \(10 s\)
3 \(20 \mathrm{~s}\)
4 \(25 \mathrm{~s}\)
Explanation:
\(t_{a}=t_{d}\)
MOTION IN A STRIGHT LINE
269789
A bodyis projected with a velocity u. It passes through a certain point above the ground in \(t\) sec. Thetimeafter which thebody passesthrough thesamepointduring thereturn journey
1 \(\left(\frac{u}{g}-t_{1}^{2}\right)\)
2 \(2\left(\frac{u}{g}-t_{1}\right)\)
3 \(3\left(\frac{u^{2}}{g}-t_{1}\right)\)
4 \(3\left(\frac{u^{2}}{g^{2}}-t_{1}\right)\)
Explanation:
MOTION IN A STRIGHT LINE
269790
A boy throws a ball in air in such a manner that when the ball is at its maximum heighthethrows another ball. If theballs sarethrown with the timedifference 1 second, the maximum height attained by each ball is
1 \(9.8 \mathrm{~m}\)
2 \(19.6 \mathrm{~m}\)
3 \(4.9 \mathrm{~m}\)
4 \(2.45 \mathrm{~m}\)
Explanation:
\(h=\frac{g}{2 n^{2}}\)
MOTION IN A STRIGHT LINE
269803
The friction of the air causes a vertical retardation equal to\(10 \%\) of the acceleration due to gravity. Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\). The maximum height and time to reach the maximum height will bedecreased by
269787
Astonethrown vertically up from theground reaches a maximum height of \(50 \mathrm{~m}\) in \(10 \mathrm{~s}\). Time taken by the stoneto reach theground from maximum height is
1 \(5 \mathrm{~s}\)
2 \(10 s\)
3 \(20 \mathrm{~s}\)
4 \(25 \mathrm{~s}\)
Explanation:
\(t_{a}=t_{d}\)
MOTION IN A STRIGHT LINE
269789
A bodyis projected with a velocity u. It passes through a certain point above the ground in \(t\) sec. Thetimeafter which thebody passesthrough thesamepointduring thereturn journey
1 \(\left(\frac{u}{g}-t_{1}^{2}\right)\)
2 \(2\left(\frac{u}{g}-t_{1}\right)\)
3 \(3\left(\frac{u^{2}}{g}-t_{1}\right)\)
4 \(3\left(\frac{u^{2}}{g^{2}}-t_{1}\right)\)
Explanation:
MOTION IN A STRIGHT LINE
269790
A boy throws a ball in air in such a manner that when the ball is at its maximum heighthethrows another ball. If theballs sarethrown with the timedifference 1 second, the maximum height attained by each ball is
1 \(9.8 \mathrm{~m}\)
2 \(19.6 \mathrm{~m}\)
3 \(4.9 \mathrm{~m}\)
4 \(2.45 \mathrm{~m}\)
Explanation:
\(h=\frac{g}{2 n^{2}}\)
MOTION IN A STRIGHT LINE
269803
The friction of the air causes a vertical retardation equal to\(10 \%\) of the acceleration due to gravity. Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\). The maximum height and time to reach the maximum height will bedecreased by
269787
Astonethrown vertically up from theground reaches a maximum height of \(50 \mathrm{~m}\) in \(10 \mathrm{~s}\). Time taken by the stoneto reach theground from maximum height is
1 \(5 \mathrm{~s}\)
2 \(10 s\)
3 \(20 \mathrm{~s}\)
4 \(25 \mathrm{~s}\)
Explanation:
\(t_{a}=t_{d}\)
MOTION IN A STRIGHT LINE
269789
A bodyis projected with a velocity u. It passes through a certain point above the ground in \(t\) sec. Thetimeafter which thebody passesthrough thesamepointduring thereturn journey
1 \(\left(\frac{u}{g}-t_{1}^{2}\right)\)
2 \(2\left(\frac{u}{g}-t_{1}\right)\)
3 \(3\left(\frac{u^{2}}{g}-t_{1}\right)\)
4 \(3\left(\frac{u^{2}}{g^{2}}-t_{1}\right)\)
Explanation:
MOTION IN A STRIGHT LINE
269790
A boy throws a ball in air in such a manner that when the ball is at its maximum heighthethrows another ball. If theballs sarethrown with the timedifference 1 second, the maximum height attained by each ball is
1 \(9.8 \mathrm{~m}\)
2 \(19.6 \mathrm{~m}\)
3 \(4.9 \mathrm{~m}\)
4 \(2.45 \mathrm{~m}\)
Explanation:
\(h=\frac{g}{2 n^{2}}\)
MOTION IN A STRIGHT LINE
269803
The friction of the air causes a vertical retardation equal to\(10 \%\) of the acceleration due to gravity. Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\). The maximum height and time to reach the maximum height will bedecreased by
269787
Astonethrown vertically up from theground reaches a maximum height of \(50 \mathrm{~m}\) in \(10 \mathrm{~s}\). Time taken by the stoneto reach theground from maximum height is
1 \(5 \mathrm{~s}\)
2 \(10 s\)
3 \(20 \mathrm{~s}\)
4 \(25 \mathrm{~s}\)
Explanation:
\(t_{a}=t_{d}\)
MOTION IN A STRIGHT LINE
269789
A bodyis projected with a velocity u. It passes through a certain point above the ground in \(t\) sec. Thetimeafter which thebody passesthrough thesamepointduring thereturn journey
1 \(\left(\frac{u}{g}-t_{1}^{2}\right)\)
2 \(2\left(\frac{u}{g}-t_{1}\right)\)
3 \(3\left(\frac{u^{2}}{g}-t_{1}\right)\)
4 \(3\left(\frac{u^{2}}{g^{2}}-t_{1}\right)\)
Explanation:
MOTION IN A STRIGHT LINE
269790
A boy throws a ball in air in such a manner that when the ball is at its maximum heighthethrows another ball. If theballs sarethrown with the timedifference 1 second, the maximum height attained by each ball is
1 \(9.8 \mathrm{~m}\)
2 \(19.6 \mathrm{~m}\)
3 \(4.9 \mathrm{~m}\)
4 \(2.45 \mathrm{~m}\)
Explanation:
\(h=\frac{g}{2 n^{2}}\)
MOTION IN A STRIGHT LINE
269803
The friction of the air causes a vertical retardation equal to\(10 \%\) of the acceleration due to gravity. Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\). The maximum height and time to reach the maximum height will bedecreased by
