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MOTION IN A STRIGHT LINE

269735 The distance moved by a freely falling body (starting from rest) during the $15 t$ , 2nd and 3rd ... nth second of its motion, are proportional to

1

(n - 1)

2

(2 n - 1)

3

(n^{2} - 1)

4

(2 n - 1) / n^{2}

Explanation:

$s_{n} = g (n - \frac{1}{2});$ Ratio $= \frac{g}{2} : \frac{3 g}{2} : \frac{5 g}{2} \dots . . (2 n - 1) \frac{g}{2}$ $s_{n} \propto (2 n - 1)$

MOTION IN A STRIGHT LINE

269736 A ball released from a height ' $n$ ' touches the ground in ' $t$ 's. After $t / 25$ sincedropping, the height of thebody from the ground

1

\frac{h}{2}

2

\frac{h}{4}

3

\frac{3 h}{4}

4

\frac{3 h}{2}

Explanation:

$h = \frac{1}{2} g t^{2}$

MOTION IN A STRIGHT LINE

269737 A boy standing at the top of a tower of $20 m$ height drops a stone A ssuming $g = 10 {ms}^{- 2}$ , thevelocity with which it hits the ground is

1

20 {ms}^{- 1}

2

40 {ms}^{- 1}

3

5 {ms}^{- 1}

4

10 {ms}^{- 1}

Explanation:

$v = \sqrt{2 g h}$

AIPMT 2011

MOTION IN A STRIGHT LINE

269738 A ball thrown vertically upwards with an initial velocity of $1.4 m / s$ returns in $2 s$ . The to-
tal displacement of the ball is

1

22.4 cm

2 zero

3

44.8 m

4

33.6 m

MOTION IN A STRIGHT LINE

269735 The distance moved by a freely falling body (starting from rest) during the $15 t$ , 2nd and 3rd ... nth second of its motion, are proportional to

1

(n - 1)

2

(2 n - 1)

3

(n^{2} - 1)

4

(2 n - 1) / n^{2}

Explanation:

$s_{n} = g (n - \frac{1}{2});$ Ratio $= \frac{g}{2} : \frac{3 g}{2} : \frac{5 g}{2} \dots . . (2 n - 1) \frac{g}{2}$ $s_{n} \propto (2 n - 1)$

MOTION IN A STRIGHT LINE

269736 A ball released from a height ' $n$ ' touches the ground in ' $t$ 's. After $t / 25$ sincedropping, the height of thebody from the ground

1

\frac{h}{2}

2

\frac{h}{4}

3

\frac{3 h}{4}

4

\frac{3 h}{2}

Explanation:

$h = \frac{1}{2} g t^{2}$

MOTION IN A STRIGHT LINE

269737 A boy standing at the top of a tower of $20 m$ height drops a stone A ssuming $g = 10 {ms}^{- 2}$ , thevelocity with which it hits the ground is

1

20 {ms}^{- 1}

2

40 {ms}^{- 1}

3

5 {ms}^{- 1}

4

10 {ms}^{- 1}

Explanation:

$v = \sqrt{2 g h}$

AIPMT 2011

MOTION IN A STRIGHT LINE

269738 A ball thrown vertically upwards with an initial velocity of $1.4 m / s$ returns in $2 s$ . The to-
tal displacement of the ball is

1

22.4 cm

2 zero

3

44.8 m

4

33.6 m

MOTION IN A STRIGHT LINE

269735 The distance moved by a freely falling body (starting from rest) during the $15 t$ , 2nd and 3rd ... nth second of its motion, are proportional to

1

(n - 1)

2

(2 n - 1)

3

(n^{2} - 1)

4

(2 n - 1) / n^{2}

Explanation:

$s_{n} = g (n - \frac{1}{2});$ Ratio $= \frac{g}{2} : \frac{3 g}{2} : \frac{5 g}{2} \dots . . (2 n - 1) \frac{g}{2}$ $s_{n} \propto (2 n - 1)$

MOTION IN A STRIGHT LINE

269736 A ball released from a height ' $n$ ' touches the ground in ' $t$ 's. After $t / 25$ sincedropping, the height of thebody from the ground

1

\frac{h}{2}

2

\frac{h}{4}

3

\frac{3 h}{4}

4

\frac{3 h}{2}

Explanation:

$h = \frac{1}{2} g t^{2}$

MOTION IN A STRIGHT LINE

269737 A boy standing at the top of a tower of $20 m$ height drops a stone A ssuming $g = 10 {ms}^{- 2}$ , thevelocity with which it hits the ground is

1

20 {ms}^{- 1}

2

40 {ms}^{- 1}

3

5 {ms}^{- 1}

4

10 {ms}^{- 1}

Explanation:

$v = \sqrt{2 g h}$

AIPMT 2011

MOTION IN A STRIGHT LINE

269738 A ball thrown vertically upwards with an initial velocity of $1.4 m / s$ returns in $2 s$ . The to-
tal displacement of the ball is

1

22.4 cm

2 zero

3

44.8 m

4

33.6 m

MOTION IN A STRIGHT LINE

269735 The distance moved by a freely falling body (starting from rest) during the $15 t$ , 2nd and 3rd ... nth second of its motion, are proportional to

1

(n - 1)

2

(2 n - 1)

3

(n^{2} - 1)

4

(2 n - 1) / n^{2}

Explanation:

$s_{n} = g (n - \frac{1}{2});$ Ratio $= \frac{g}{2} : \frac{3 g}{2} : \frac{5 g}{2} \dots . . (2 n - 1) \frac{g}{2}$ $s_{n} \propto (2 n - 1)$

MOTION IN A STRIGHT LINE

269736 A ball released from a height ' $n$ ' touches the ground in ' $t$ 's. After $t / 25$ sincedropping, the height of thebody from the ground

1

\frac{h}{2}

2

\frac{h}{4}

3

\frac{3 h}{4}

4

\frac{3 h}{2}

Explanation:

$h = \frac{1}{2} g t^{2}$

MOTION IN A STRIGHT LINE

269737 A boy standing at the top of a tower of $20 m$ height drops a stone A ssuming $g = 10 {ms}^{- 2}$ , thevelocity with which it hits the ground is

1

20 {ms}^{- 1}

2

40 {ms}^{- 1}

3

5 {ms}^{- 1}

4

10 {ms}^{- 1}

Explanation:

$v = \sqrt{2 g h}$

AIPMT 2011

MOTION IN A STRIGHT LINE

269738 A ball thrown vertically upwards with an initial velocity of $1.4 m / s$ returns in $2 s$ . The to-
tal displacement of the ball is

1

22.4 cm

2 zero

3

44.8 m

4

33.6 m

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