SPEED AND VELOCITY
MOTION IN A STRIGHT LINE

269702 If a body covers first half of its journey with uniform speed \(v\) and the second half of the journey with uhiform speed \(v_{2}\), then the average speed is

1 \(v_{1}+v_{2}\)
2 \(\frac{2 v_{1} v_{2}}{v_{1}+v_{2}}\)
3 \(\frac{v_{1} v_{2}}{v_{1}+v_{2}}\)
4 \(\mathrm{V}_{1} \mathrm{v}_{2}\)
MOTION IN A STRIGHT LINE

269703 \(A\) car is moving along a straight line, say \(O P\) in figure. It moves from 0 to \(P\) in \(18 s\) and return from \(P\) to \(Q\) in \(6 \mathrm{~s}\). W hat are the average velocity and average speed of the car in going from \(O\) to \(P\) and back to \(Q\) ?

1 \(10 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
3 \(10 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
4 \(20 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
MOTION IN A STRIGHT LINE

269704 For a body moving with uniform acceleration ' \(a\) ', initial and final velocities in a time interval ' \(t\) ' are ' \(u\) ' and ' \(v\) ' respectively. Then, its average velocity in the time interval '\(t\) ' is

1 \(\left.\left.(v+a t)\)
2 \(\left(v-\frac{a t}{2}\right)\)
3 \((v-a t)\)
4 \(\left(u-\frac{a t}{2}\right)\)
MOTION IN A STRIGHT LINE

269721 For a train that travels from one station to another at a uniform speed of\(40 \mathrm{kmh}^{-1}\) and returns to final station at speed of \(60 \mathrm{kmh}^{-1}\), then its average speed is

1 \(98 \mathrm{~km} / \mathrm{hr}\)
2 \(0 \mathrm{~km} / \mathrm{hr}\)
3 \(50 \mathrm{~km} / \mathrm{hr}\)
4 \(48 \mathrm{~km} / \mathrm{hr}\)
MOTION IN A STRIGHT LINE

269702 If a body covers first half of its journey with uniform speed \(v\) and the second half of the journey with uhiform speed \(v_{2}\), then the average speed is

1 \(v_{1}+v_{2}\)
2 \(\frac{2 v_{1} v_{2}}{v_{1}+v_{2}}\)
3 \(\frac{v_{1} v_{2}}{v_{1}+v_{2}}\)
4 \(\mathrm{V}_{1} \mathrm{v}_{2}\)
MOTION IN A STRIGHT LINE

269703 \(A\) car is moving along a straight line, say \(O P\) in figure. It moves from 0 to \(P\) in \(18 s\) and return from \(P\) to \(Q\) in \(6 \mathrm{~s}\). W hat are the average velocity and average speed of the car in going from \(O\) to \(P\) and back to \(Q\) ?

1 \(10 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
3 \(10 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
4 \(20 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
MOTION IN A STRIGHT LINE

269704 For a body moving with uniform acceleration ' \(a\) ', initial and final velocities in a time interval ' \(t\) ' are ' \(u\) ' and ' \(v\) ' respectively. Then, its average velocity in the time interval '\(t\) ' is

1 \(\left.\left.(v+a t)\)
2 \(\left(v-\frac{a t}{2}\right)\)
3 \((v-a t)\)
4 \(\left(u-\frac{a t}{2}\right)\)
MOTION IN A STRIGHT LINE

269721 For a train that travels from one station to another at a uniform speed of\(40 \mathrm{kmh}^{-1}\) and returns to final station at speed of \(60 \mathrm{kmh}^{-1}\), then its average speed is

1 \(98 \mathrm{~km} / \mathrm{hr}\)
2 \(0 \mathrm{~km} / \mathrm{hr}\)
3 \(50 \mathrm{~km} / \mathrm{hr}\)
4 \(48 \mathrm{~km} / \mathrm{hr}\)
MOTION IN A STRIGHT LINE

269702 If a body covers first half of its journey with uniform speed \(v\) and the second half of the journey with uhiform speed \(v_{2}\), then the average speed is

1 \(v_{1}+v_{2}\)
2 \(\frac{2 v_{1} v_{2}}{v_{1}+v_{2}}\)
3 \(\frac{v_{1} v_{2}}{v_{1}+v_{2}}\)
4 \(\mathrm{V}_{1} \mathrm{v}_{2}\)
MOTION IN A STRIGHT LINE

269703 \(A\) car is moving along a straight line, say \(O P\) in figure. It moves from 0 to \(P\) in \(18 s\) and return from \(P\) to \(Q\) in \(6 \mathrm{~s}\). W hat are the average velocity and average speed of the car in going from \(O\) to \(P\) and back to \(Q\) ?

1 \(10 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
3 \(10 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
4 \(20 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
MOTION IN A STRIGHT LINE

269704 For a body moving with uniform acceleration ' \(a\) ', initial and final velocities in a time interval ' \(t\) ' are ' \(u\) ' and ' \(v\) ' respectively. Then, its average velocity in the time interval '\(t\) ' is

1 \(\left.\left.(v+a t)\)
2 \(\left(v-\frac{a t}{2}\right)\)
3 \((v-a t)\)
4 \(\left(u-\frac{a t}{2}\right)\)
MOTION IN A STRIGHT LINE

269721 For a train that travels from one station to another at a uniform speed of\(40 \mathrm{kmh}^{-1}\) and returns to final station at speed of \(60 \mathrm{kmh}^{-1}\), then its average speed is

1 \(98 \mathrm{~km} / \mathrm{hr}\)
2 \(0 \mathrm{~km} / \mathrm{hr}\)
3 \(50 \mathrm{~km} / \mathrm{hr}\)
4 \(48 \mathrm{~km} / \mathrm{hr}\)
MOTION IN A STRIGHT LINE

269702 If a body covers first half of its journey with uniform speed \(v\) and the second half of the journey with uhiform speed \(v_{2}\), then the average speed is

1 \(v_{1}+v_{2}\)
2 \(\frac{2 v_{1} v_{2}}{v_{1}+v_{2}}\)
3 \(\frac{v_{1} v_{2}}{v_{1}+v_{2}}\)
4 \(\mathrm{V}_{1} \mathrm{v}_{2}\)
MOTION IN A STRIGHT LINE

269703 \(A\) car is moving along a straight line, say \(O P\) in figure. It moves from 0 to \(P\) in \(18 s\) and return from \(P\) to \(Q\) in \(6 \mathrm{~s}\). W hat are the average velocity and average speed of the car in going from \(O\) to \(P\) and back to \(Q\) ?

1 \(10 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
3 \(10 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
4 \(20 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
MOTION IN A STRIGHT LINE

269704 For a body moving with uniform acceleration ' \(a\) ', initial and final velocities in a time interval ' \(t\) ' are ' \(u\) ' and ' \(v\) ' respectively. Then, its average velocity in the time interval '\(t\) ' is

1 \(\left.\left.(v+a t)\)
2 \(\left(v-\frac{a t}{2}\right)\)
3 \((v-a t)\)
4 \(\left(u-\frac{a t}{2}\right)\)
MOTION IN A STRIGHT LINE

269721 For a train that travels from one station to another at a uniform speed of\(40 \mathrm{kmh}^{-1}\) and returns to final station at speed of \(60 \mathrm{kmh}^{-1}\), then its average speed is

1 \(98 \mathrm{~km} / \mathrm{hr}\)
2 \(0 \mathrm{~km} / \mathrm{hr}\)
3 \(50 \mathrm{~km} / \mathrm{hr}\)
4 \(48 \mathrm{~km} / \mathrm{hr}\)