269702
If a body covers first half of its journey with uniform speed \(v\) and the second half of the journey with uhiform speed \(v_{2}\), then the average speed is
269703
\(A\) car is moving along a straight line, say \(O P\) in figure. It moves from 0 to \(P\) in \(18 s\) and return from \(P\) to \(Q\) in \(6 \mathrm{~s}\). W hat are the average velocity and average speed of the car in going from \(O\) to \(P\) and back to \(Q\) ?
1 \(10 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
3 \(10 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
4 \(20 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
Explanation:
\(\mathrm{v}_{\mathrm{avg}}=\frac{\text { total displacement }}{\text { total time }}=\frac{\mathrm{S}_{1}+\mathrm{S}_{2}}{\mathrm{t}_{1}+\mathrm{t}_{2}}\)
MOTION IN A STRIGHT LINE
269704
For a body moving with uniform acceleration ' \(a\) ', initial and final velocities in a time interval ' \(t\) ' are ' \(u\) ' and ' \(v\) ' respectively. Then, its average velocity in the time interval '\(t\) ' is
269721
For a train that travels from one station to another at a uniform speed of\(40 \mathrm{kmh}^{-1}\) and returns to final station at speed of \(60 \mathrm{kmh}^{-1}\), then its average speed is
269702
If a body covers first half of its journey with uniform speed \(v\) and the second half of the journey with uhiform speed \(v_{2}\), then the average speed is
269703
\(A\) car is moving along a straight line, say \(O P\) in figure. It moves from 0 to \(P\) in \(18 s\) and return from \(P\) to \(Q\) in \(6 \mathrm{~s}\). W hat are the average velocity and average speed of the car in going from \(O\) to \(P\) and back to \(Q\) ?
1 \(10 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
3 \(10 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
4 \(20 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
Explanation:
\(\mathrm{v}_{\mathrm{avg}}=\frac{\text { total displacement }}{\text { total time }}=\frac{\mathrm{S}_{1}+\mathrm{S}_{2}}{\mathrm{t}_{1}+\mathrm{t}_{2}}\)
MOTION IN A STRIGHT LINE
269704
For a body moving with uniform acceleration ' \(a\) ', initial and final velocities in a time interval ' \(t\) ' are ' \(u\) ' and ' \(v\) ' respectively. Then, its average velocity in the time interval '\(t\) ' is
269721
For a train that travels from one station to another at a uniform speed of\(40 \mathrm{kmh}^{-1}\) and returns to final station at speed of \(60 \mathrm{kmh}^{-1}\), then its average speed is
269702
If a body covers first half of its journey with uniform speed \(v\) and the second half of the journey with uhiform speed \(v_{2}\), then the average speed is
269703
\(A\) car is moving along a straight line, say \(O P\) in figure. It moves from 0 to \(P\) in \(18 s\) and return from \(P\) to \(Q\) in \(6 \mathrm{~s}\). W hat are the average velocity and average speed of the car in going from \(O\) to \(P\) and back to \(Q\) ?
1 \(10 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
3 \(10 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
4 \(20 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
Explanation:
\(\mathrm{v}_{\mathrm{avg}}=\frac{\text { total displacement }}{\text { total time }}=\frac{\mathrm{S}_{1}+\mathrm{S}_{2}}{\mathrm{t}_{1}+\mathrm{t}_{2}}\)
MOTION IN A STRIGHT LINE
269704
For a body moving with uniform acceleration ' \(a\) ', initial and final velocities in a time interval ' \(t\) ' are ' \(u\) ' and ' \(v\) ' respectively. Then, its average velocity in the time interval '\(t\) ' is
269721
For a train that travels from one station to another at a uniform speed of\(40 \mathrm{kmh}^{-1}\) and returns to final station at speed of \(60 \mathrm{kmh}^{-1}\), then its average speed is
269702
If a body covers first half of its journey with uniform speed \(v\) and the second half of the journey with uhiform speed \(v_{2}\), then the average speed is
269703
\(A\) car is moving along a straight line, say \(O P\) in figure. It moves from 0 to \(P\) in \(18 s\) and return from \(P\) to \(Q\) in \(6 \mathrm{~s}\). W hat are the average velocity and average speed of the car in going from \(O\) to \(P\) and back to \(Q\) ?
1 \(10 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
3 \(10 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\)
4 \(20 \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\)
Explanation:
\(\mathrm{v}_{\mathrm{avg}}=\frac{\text { total displacement }}{\text { total time }}=\frac{\mathrm{S}_{1}+\mathrm{S}_{2}}{\mathrm{t}_{1}+\mathrm{t}_{2}}\)
MOTION IN A STRIGHT LINE
269704
For a body moving with uniform acceleration ' \(a\) ', initial and final velocities in a time interval ' \(t\) ' are ' \(u\) ' and ' \(v\) ' respectively. Then, its average velocity in the time interval '\(t\) ' is
269721
For a train that travels from one station to another at a uniform speed of\(40 \mathrm{kmh}^{-1}\) and returns to final station at speed of \(60 \mathrm{kmh}^{-1}\), then its average speed is