NEET Test Series from KOTA - 10 Papers In MS WORD
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Rotational Motion
269572
M.I. of a uniform horizontal solid cylinder of mass \(M\) about an axis passing through its edge and perpendicular to the axis of cylinder when its length is 6 times of its radius \(R\) is
269573
A circular disc of radius \(R\) and thickness \(R / 6\) has moment of inertia \(I\) about an axis passing through its centre and perpendicular to its plane. It is melted and recast into a solid sphere. The M.I. of the sphere about its diameter as axis of rotation is
1 \(I\)
2 \(2 I / 3\)
3 \(I / 5\)
4 \(I / 10\)
Explanation:
\(I=\frac{1}{12} \pi R^{5} \rho ;\) volume of disc \(=\) volume of sphere \(\Rightarrow\) radius of sphere \(\left(R^{1}\right)=\frac{R}{2}\)
Rotational Motion
269574
The moment of inertia of ring about an axis passing through its diameter is \(I\). Then moment of inertia of that ring about an axis passing through its centre and perpendicular to its plane is
1 \(2 I\)
2 \(I\)
3 \(I / 2\)
4 \(\mathrm{I} / 4\)
Explanation:
\(I=\frac{M R^{2}}{2}\) and \(I^{1}=M R^{2}=2 I\)
Rotational Motion
269575
A thin rod of mass \(6 \mathrm{~m}\) and length \(6 \mathrm{~L}\) is bent into regular hexagon. The M.I. of the hexagon about a normal axis to its plane and through centre of system is
269572
M.I. of a uniform horizontal solid cylinder of mass \(M\) about an axis passing through its edge and perpendicular to the axis of cylinder when its length is 6 times of its radius \(R\) is
269573
A circular disc of radius \(R\) and thickness \(R / 6\) has moment of inertia \(I\) about an axis passing through its centre and perpendicular to its plane. It is melted and recast into a solid sphere. The M.I. of the sphere about its diameter as axis of rotation is
1 \(I\)
2 \(2 I / 3\)
3 \(I / 5\)
4 \(I / 10\)
Explanation:
\(I=\frac{1}{12} \pi R^{5} \rho ;\) volume of disc \(=\) volume of sphere \(\Rightarrow\) radius of sphere \(\left(R^{1}\right)=\frac{R}{2}\)
Rotational Motion
269574
The moment of inertia of ring about an axis passing through its diameter is \(I\). Then moment of inertia of that ring about an axis passing through its centre and perpendicular to its plane is
1 \(2 I\)
2 \(I\)
3 \(I / 2\)
4 \(\mathrm{I} / 4\)
Explanation:
\(I=\frac{M R^{2}}{2}\) and \(I^{1}=M R^{2}=2 I\)
Rotational Motion
269575
A thin rod of mass \(6 \mathrm{~m}\) and length \(6 \mathrm{~L}\) is bent into regular hexagon. The M.I. of the hexagon about a normal axis to its plane and through centre of system is
269572
M.I. of a uniform horizontal solid cylinder of mass \(M\) about an axis passing through its edge and perpendicular to the axis of cylinder when its length is 6 times of its radius \(R\) is
269573
A circular disc of radius \(R\) and thickness \(R / 6\) has moment of inertia \(I\) about an axis passing through its centre and perpendicular to its plane. It is melted and recast into a solid sphere. The M.I. of the sphere about its diameter as axis of rotation is
1 \(I\)
2 \(2 I / 3\)
3 \(I / 5\)
4 \(I / 10\)
Explanation:
\(I=\frac{1}{12} \pi R^{5} \rho ;\) volume of disc \(=\) volume of sphere \(\Rightarrow\) radius of sphere \(\left(R^{1}\right)=\frac{R}{2}\)
Rotational Motion
269574
The moment of inertia of ring about an axis passing through its diameter is \(I\). Then moment of inertia of that ring about an axis passing through its centre and perpendicular to its plane is
1 \(2 I\)
2 \(I\)
3 \(I / 2\)
4 \(\mathrm{I} / 4\)
Explanation:
\(I=\frac{M R^{2}}{2}\) and \(I^{1}=M R^{2}=2 I\)
Rotational Motion
269575
A thin rod of mass \(6 \mathrm{~m}\) and length \(6 \mathrm{~L}\) is bent into regular hexagon. The M.I. of the hexagon about a normal axis to its plane and through centre of system is
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Rotational Motion
269572
M.I. of a uniform horizontal solid cylinder of mass \(M\) about an axis passing through its edge and perpendicular to the axis of cylinder when its length is 6 times of its radius \(R\) is
269573
A circular disc of radius \(R\) and thickness \(R / 6\) has moment of inertia \(I\) about an axis passing through its centre and perpendicular to its plane. It is melted and recast into a solid sphere. The M.I. of the sphere about its diameter as axis of rotation is
1 \(I\)
2 \(2 I / 3\)
3 \(I / 5\)
4 \(I / 10\)
Explanation:
\(I=\frac{1}{12} \pi R^{5} \rho ;\) volume of disc \(=\) volume of sphere \(\Rightarrow\) radius of sphere \(\left(R^{1}\right)=\frac{R}{2}\)
Rotational Motion
269574
The moment of inertia of ring about an axis passing through its diameter is \(I\). Then moment of inertia of that ring about an axis passing through its centre and perpendicular to its plane is
1 \(2 I\)
2 \(I\)
3 \(I / 2\)
4 \(\mathrm{I} / 4\)
Explanation:
\(I=\frac{M R^{2}}{2}\) and \(I^{1}=M R^{2}=2 I\)
Rotational Motion
269575
A thin rod of mass \(6 \mathrm{~m}\) and length \(6 \mathrm{~L}\) is bent into regular hexagon. The M.I. of the hexagon about a normal axis to its plane and through centre of system is