ROLLING MOTION \&ROTATIONAL KINETIC ENERGY
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Rotational Motion

269345 A particle performs uniform circular motion with an angular momentum\(\mathrm{L}\). If the angular frequency \(f\) of the particle is doubled, and kinetic energy is halved, its angular momentum becomes :

1 \(4 \mathrm{~L}\)
2 \(2 \mathrm{~L}\)
3 \(\frac{L}{2}\)
4 \(\frac{L}{4}\)
Rotational Motion

269346 If\(\mathrm{V}\) is velocity of centre of mass of a rolling body then velocity of lowest point of that body is

1 \(\sqrt{2} \mathrm{~V}\)
2 \(\mathrm{V}\)
3 \(2 \mathrm{~V}\)
4 Zero
Rotational Motion

269347 If the velocity of centre of mass of a rolling body is \(\mathrm{V}\) then velocity of highest point of that body is

1 \(\sqrt{2} \mathrm{~V}\)
2 \(\mathrm{V}\)
3 \(2 \mathrm{~V}\)
4 \(\frac{V}{\sqrt{2}}\)
Rotational Motion

269348 If\(x\) is ratio of rotational kinetic energy and translational kinetic energy of rolling body then the following is true

1 \(x=1\)
2 \(x \leq 1\)
3 \(x \geq 1\)
4 \(x=\frac{1}{2}\)
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NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Rotational Motion

269345 A particle performs uniform circular motion with an angular momentum\(\mathrm{L}\). If the angular frequency \(f\) of the particle is doubled, and kinetic energy is halved, its angular momentum becomes :

1 \(4 \mathrm{~L}\)
2 \(2 \mathrm{~L}\)
3 \(\frac{L}{2}\)
4 \(\frac{L}{4}\)
Rotational Motion

269346 If\(\mathrm{V}\) is velocity of centre of mass of a rolling body then velocity of lowest point of that body is

1 \(\sqrt{2} \mathrm{~V}\)
2 \(\mathrm{V}\)
3 \(2 \mathrm{~V}\)
4 Zero
Rotational Motion

269347 If the velocity of centre of mass of a rolling body is \(\mathrm{V}\) then velocity of highest point of that body is

1 \(\sqrt{2} \mathrm{~V}\)
2 \(\mathrm{V}\)
3 \(2 \mathrm{~V}\)
4 \(\frac{V}{\sqrt{2}}\)
Rotational Motion

269348 If\(x\) is ratio of rotational kinetic energy and translational kinetic energy of rolling body then the following is true

1 \(x=1\)
2 \(x \leq 1\)
3 \(x \geq 1\)
4 \(x=\frac{1}{2}\)
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Rotational Motion

269345 A particle performs uniform circular motion with an angular momentum\(\mathrm{L}\). If the angular frequency \(f\) of the particle is doubled, and kinetic energy is halved, its angular momentum becomes :

1 \(4 \mathrm{~L}\)
2 \(2 \mathrm{~L}\)
3 \(\frac{L}{2}\)
4 \(\frac{L}{4}\)
Rotational Motion

269346 If\(\mathrm{V}\) is velocity of centre of mass of a rolling body then velocity of lowest point of that body is

1 \(\sqrt{2} \mathrm{~V}\)
2 \(\mathrm{V}\)
3 \(2 \mathrm{~V}\)
4 Zero
Rotational Motion

269347 If the velocity of centre of mass of a rolling body is \(\mathrm{V}\) then velocity of highest point of that body is

1 \(\sqrt{2} \mathrm{~V}\)
2 \(\mathrm{V}\)
3 \(2 \mathrm{~V}\)
4 \(\frac{V}{\sqrt{2}}\)
Rotational Motion

269348 If\(x\) is ratio of rotational kinetic energy and translational kinetic energy of rolling body then the following is true

1 \(x=1\)
2 \(x \leq 1\)
3 \(x \geq 1\)
4 \(x=\frac{1}{2}\)
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Rotational Motion

269345 A particle performs uniform circular motion with an angular momentum\(\mathrm{L}\). If the angular frequency \(f\) of the particle is doubled, and kinetic energy is halved, its angular momentum becomes :

1 \(4 \mathrm{~L}\)
2 \(2 \mathrm{~L}\)
3 \(\frac{L}{2}\)
4 \(\frac{L}{4}\)
Rotational Motion

269346 If\(\mathrm{V}\) is velocity of centre of mass of a rolling body then velocity of lowest point of that body is

1 \(\sqrt{2} \mathrm{~V}\)
2 \(\mathrm{V}\)
3 \(2 \mathrm{~V}\)
4 Zero
Rotational Motion

269347 If the velocity of centre of mass of a rolling body is \(\mathrm{V}\) then velocity of highest point of that body is

1 \(\sqrt{2} \mathrm{~V}\)
2 \(\mathrm{V}\)
3 \(2 \mathrm{~V}\)
4 \(\frac{V}{\sqrt{2}}\)
Rotational Motion

269348 If\(x\) is ratio of rotational kinetic energy and translational kinetic energy of rolling body then the following is true

1 \(x=1\)
2 \(x \leq 1\)
3 \(x \geq 1\)
4 \(x=\frac{1}{2}\)
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