LINEAR MOMENTUM OF CENTRE OF MASS
Rotational Motion

269281 Two balls are thrown at the same time in air, while they are in air, the acceleration of their centre of mass

1 depends on masses of the balls
2 depends on the direction of motion of the balls
3 depends on speeds of the balls
4 is equal to acceleration due to gravity
Rotational Motion

269282 Consider a two particle system with the particles having masses\(m_{1}\) and \(m_{2}\). If the first particle is pushed towards the centre of mass through a distance \(d\), by what distance should the second particle be moved, so as to keep the centre of mass at the same position? [MAINS 2006]

1 \(d\)
2 \(\frac{m_{2} d}{m_{1}}\)
3 \(\frac{m_{1} d}{m_{1}+m_{2}}\)
4 \(\frac{m_{1} d}{m_{2}}\)
Rotational Motion

269365 Two bodies of different masses\(2 \mathrm{~kg}\) and \(4 \mathrm{~kg}\) are moving with velocities \(2 \mathrm{~m} / \mathrm{s}\) and \(10 \mathrm{~m} / \mathrm{s}\) towards each other due to mutual gravitational attraction. Then the velocity of the centre of mass is

1 \(5 \mathrm{~ms}^{-1}\)
2 \(6 \mathrm{~ms}^{-1}\)
3 \(8 \mathrm{~ms}^{-1}\)
4 Zero
Rotational Motion

269366 If two particles of masses\(3 \mathrm{~kg}\) and \(6 \mathrm{~kg}\) which are at rest are separated by a distance of \(15 \mathrm{~m}\). The two particles are moving towards each other under a mutual force of attraction. Then the ratio of distances travelled by the particles before collision is

1 \(2: 1\)
2 \(1: 2\)
3 \(1: 3\)
4 \(3: 1\)
Rotational Motion

269367 Two bodies of\(6 \mathbf{~ k g}\) and \(4 \mathbf{~ k g ~ m a s s e s ~ h a v e ~ t h e i r ~}\) velocity \(5 \hat{i}-2 \hat{j}+10 \hat{k}\) and \(10 \hat{i}-2 \hat{j}+5 \hat{k}\) respectively.Then the velocity of their centre of mass is

1 \(5 \hat{i}+2 \hat{j}-8 \hat{k}\)
2 \(7 \hat{i}+2 \hat{j}-8 \hat{k}\)
3 \(7 \hat{i}-2 \hat{j}+8 \hat{k}\)
4 \(5 \hat{i}-2 \hat{j}+8 \hat{k}\)
Rotational Motion

269281 Two balls are thrown at the same time in air, while they are in air, the acceleration of their centre of mass

1 depends on masses of the balls
2 depends on the direction of motion of the balls
3 depends on speeds of the balls
4 is equal to acceleration due to gravity
Rotational Motion

269282 Consider a two particle system with the particles having masses\(m_{1}\) and \(m_{2}\). If the first particle is pushed towards the centre of mass through a distance \(d\), by what distance should the second particle be moved, so as to keep the centre of mass at the same position? [MAINS 2006]

1 \(d\)
2 \(\frac{m_{2} d}{m_{1}}\)
3 \(\frac{m_{1} d}{m_{1}+m_{2}}\)
4 \(\frac{m_{1} d}{m_{2}}\)
Rotational Motion

269365 Two bodies of different masses\(2 \mathrm{~kg}\) and \(4 \mathrm{~kg}\) are moving with velocities \(2 \mathrm{~m} / \mathrm{s}\) and \(10 \mathrm{~m} / \mathrm{s}\) towards each other due to mutual gravitational attraction. Then the velocity of the centre of mass is

1 \(5 \mathrm{~ms}^{-1}\)
2 \(6 \mathrm{~ms}^{-1}\)
3 \(8 \mathrm{~ms}^{-1}\)
4 Zero
Rotational Motion

269366 If two particles of masses\(3 \mathrm{~kg}\) and \(6 \mathrm{~kg}\) which are at rest are separated by a distance of \(15 \mathrm{~m}\). The two particles are moving towards each other under a mutual force of attraction. Then the ratio of distances travelled by the particles before collision is

1 \(2: 1\)
2 \(1: 2\)
3 \(1: 3\)
4 \(3: 1\)
Rotational Motion

269367 Two bodies of\(6 \mathbf{~ k g}\) and \(4 \mathbf{~ k g ~ m a s s e s ~ h a v e ~ t h e i r ~}\) velocity \(5 \hat{i}-2 \hat{j}+10 \hat{k}\) and \(10 \hat{i}-2 \hat{j}+5 \hat{k}\) respectively.Then the velocity of their centre of mass is

1 \(5 \hat{i}+2 \hat{j}-8 \hat{k}\)
2 \(7 \hat{i}+2 \hat{j}-8 \hat{k}\)
3 \(7 \hat{i}-2 \hat{j}+8 \hat{k}\)
4 \(5 \hat{i}-2 \hat{j}+8 \hat{k}\)
Rotational Motion

269281 Two balls are thrown at the same time in air, while they are in air, the acceleration of their centre of mass

1 depends on masses of the balls
2 depends on the direction of motion of the balls
3 depends on speeds of the balls
4 is equal to acceleration due to gravity
Rotational Motion

269282 Consider a two particle system with the particles having masses\(m_{1}\) and \(m_{2}\). If the first particle is pushed towards the centre of mass through a distance \(d\), by what distance should the second particle be moved, so as to keep the centre of mass at the same position? [MAINS 2006]

1 \(d\)
2 \(\frac{m_{2} d}{m_{1}}\)
3 \(\frac{m_{1} d}{m_{1}+m_{2}}\)
4 \(\frac{m_{1} d}{m_{2}}\)
Rotational Motion

269365 Two bodies of different masses\(2 \mathrm{~kg}\) and \(4 \mathrm{~kg}\) are moving with velocities \(2 \mathrm{~m} / \mathrm{s}\) and \(10 \mathrm{~m} / \mathrm{s}\) towards each other due to mutual gravitational attraction. Then the velocity of the centre of mass is

1 \(5 \mathrm{~ms}^{-1}\)
2 \(6 \mathrm{~ms}^{-1}\)
3 \(8 \mathrm{~ms}^{-1}\)
4 Zero
Rotational Motion

269366 If two particles of masses\(3 \mathrm{~kg}\) and \(6 \mathrm{~kg}\) which are at rest are separated by a distance of \(15 \mathrm{~m}\). The two particles are moving towards each other under a mutual force of attraction. Then the ratio of distances travelled by the particles before collision is

1 \(2: 1\)
2 \(1: 2\)
3 \(1: 3\)
4 \(3: 1\)
Rotational Motion

269367 Two bodies of\(6 \mathbf{~ k g}\) and \(4 \mathbf{~ k g ~ m a s s e s ~ h a v e ~ t h e i r ~}\) velocity \(5 \hat{i}-2 \hat{j}+10 \hat{k}\) and \(10 \hat{i}-2 \hat{j}+5 \hat{k}\) respectively.Then the velocity of their centre of mass is

1 \(5 \hat{i}+2 \hat{j}-8 \hat{k}\)
2 \(7 \hat{i}+2 \hat{j}-8 \hat{k}\)
3 \(7 \hat{i}-2 \hat{j}+8 \hat{k}\)
4 \(5 \hat{i}-2 \hat{j}+8 \hat{k}\)
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Rotational Motion

269281 Two balls are thrown at the same time in air, while they are in air, the acceleration of their centre of mass

1 depends on masses of the balls
2 depends on the direction of motion of the balls
3 depends on speeds of the balls
4 is equal to acceleration due to gravity
Rotational Motion

269282 Consider a two particle system with the particles having masses\(m_{1}\) and \(m_{2}\). If the first particle is pushed towards the centre of mass through a distance \(d\), by what distance should the second particle be moved, so as to keep the centre of mass at the same position? [MAINS 2006]

1 \(d\)
2 \(\frac{m_{2} d}{m_{1}}\)
3 \(\frac{m_{1} d}{m_{1}+m_{2}}\)
4 \(\frac{m_{1} d}{m_{2}}\)
Rotational Motion

269365 Two bodies of different masses\(2 \mathrm{~kg}\) and \(4 \mathrm{~kg}\) are moving with velocities \(2 \mathrm{~m} / \mathrm{s}\) and \(10 \mathrm{~m} / \mathrm{s}\) towards each other due to mutual gravitational attraction. Then the velocity of the centre of mass is

1 \(5 \mathrm{~ms}^{-1}\)
2 \(6 \mathrm{~ms}^{-1}\)
3 \(8 \mathrm{~ms}^{-1}\)
4 Zero
Rotational Motion

269366 If two particles of masses\(3 \mathrm{~kg}\) and \(6 \mathrm{~kg}\) which are at rest are separated by a distance of \(15 \mathrm{~m}\). The two particles are moving towards each other under a mutual force of attraction. Then the ratio of distances travelled by the particles before collision is

1 \(2: 1\)
2 \(1: 2\)
3 \(1: 3\)
4 \(3: 1\)
Rotational Motion

269367 Two bodies of\(6 \mathbf{~ k g}\) and \(4 \mathbf{~ k g ~ m a s s e s ~ h a v e ~ t h e i r ~}\) velocity \(5 \hat{i}-2 \hat{j}+10 \hat{k}\) and \(10 \hat{i}-2 \hat{j}+5 \hat{k}\) respectively.Then the velocity of their centre of mass is

1 \(5 \hat{i}+2 \hat{j}-8 \hat{k}\)
2 \(7 \hat{i}+2 \hat{j}-8 \hat{k}\)
3 \(7 \hat{i}-2 \hat{j}+8 \hat{k}\)
4 \(5 \hat{i}-2 \hat{j}+8 \hat{k}\)
Rotational Motion

269281 Two balls are thrown at the same time in air, while they are in air, the acceleration of their centre of mass

1 depends on masses of the balls
2 depends on the direction of motion of the balls
3 depends on speeds of the balls
4 is equal to acceleration due to gravity
Rotational Motion

269282 Consider a two particle system with the particles having masses\(m_{1}\) and \(m_{2}\). If the first particle is pushed towards the centre of mass through a distance \(d\), by what distance should the second particle be moved, so as to keep the centre of mass at the same position? [MAINS 2006]

1 \(d\)
2 \(\frac{m_{2} d}{m_{1}}\)
3 \(\frac{m_{1} d}{m_{1}+m_{2}}\)
4 \(\frac{m_{1} d}{m_{2}}\)
Rotational Motion

269365 Two bodies of different masses\(2 \mathrm{~kg}\) and \(4 \mathrm{~kg}\) are moving with velocities \(2 \mathrm{~m} / \mathrm{s}\) and \(10 \mathrm{~m} / \mathrm{s}\) towards each other due to mutual gravitational attraction. Then the velocity of the centre of mass is

1 \(5 \mathrm{~ms}^{-1}\)
2 \(6 \mathrm{~ms}^{-1}\)
3 \(8 \mathrm{~ms}^{-1}\)
4 Zero
Rotational Motion

269366 If two particles of masses\(3 \mathrm{~kg}\) and \(6 \mathrm{~kg}\) which are at rest are separated by a distance of \(15 \mathrm{~m}\). The two particles are moving towards each other under a mutual force of attraction. Then the ratio of distances travelled by the particles before collision is

1 \(2: 1\)
2 \(1: 2\)
3 \(1: 3\)
4 \(3: 1\)
Rotational Motion

269367 Two bodies of\(6 \mathbf{~ k g}\) and \(4 \mathbf{~ k g ~ m a s s e s ~ h a v e ~ t h e i r ~}\) velocity \(5 \hat{i}-2 \hat{j}+10 \hat{k}\) and \(10 \hat{i}-2 \hat{j}+5 \hat{k}\) respectively.Then the velocity of their centre of mass is

1 \(5 \hat{i}+2 \hat{j}-8 \hat{k}\)
2 \(7 \hat{i}+2 \hat{j}-8 \hat{k}\)
3 \(7 \hat{i}-2 \hat{j}+8 \hat{k}\)
4 \(5 \hat{i}-2 \hat{j}+8 \hat{k}\)