269146 According to Bernoulli's theorem$\frac{p}{d}+\frac{v^2}{2}+gh=$ constant. The dimensional formula of the constant is ( $P$ is pressure, $d$ is density, $h$ is height, $v$ is velocity and $g$ is acceleration due to gravity) (2005 M )

269185 The acceleration of an object varies with time as$a=A{T}^2+BT+C$ taking the unit of time as $1\sec$ and acceleration as ${\mathrm{ms}}^{-2}$ then the units of $A,B,C$ respectively are

269186 If$\eta =\frac{A}{B}\log (Bx+C)$ is dimensionally true, then (here $\eta$ is the coefficient of viscosity and $x$ is the distance)

269187 If the velocity$(v)$ of a body in time ' $t$ ' is given by $V=A{T}^3+B{T}^2+CT+D$ then the dimensions of $C$ are

269145 $\mu =A+\frac{B}{\lambda }+\frac{C}{{\lambda }^2}$ is dimensionally correct. The dimensions of $\mathbf{A},\mathbf{B}$ and $\mathbf{C}$ respectively are $(\mu$, A, B, C are constants) where $\lambda$ is wave length of wave

269146 According to Bernoulli's theorem$\frac{p}{d}+\frac{v^2}{2}+gh=$ constant. The dimensional formula of the constant is ( $P$ is pressure, $d$ is density, $h$ is height, $v$ is velocity and $g$ is acceleration due to gravity) (2005 M )

269185 The acceleration of an object varies with time as$a=A{T}^2+BT+C$ taking the unit of time as $1\sec$ and acceleration as ${\mathrm{ms}}^{-2}$ then the units of $A,B,C$ respectively are

269186 If$\eta =\frac{A}{B}\log (Bx+C)$ is dimensionally true, then (here $\eta$ is the coefficient of viscosity and $x$ is the distance)

269187 If the velocity$(v)$ of a body in time ' $t$ ' is given by $V=A{T}^3+B{T}^2+CT+D$ then the dimensions of $C$ are

269145 $\mu =A+\frac{B}{\lambda }+\frac{C}{{\lambda }^2}$ is dimensionally correct. The dimensions of $\mathbf{A},\mathbf{B}$ and $\mathbf{C}$ respectively are $(\mu$, A, B, C are constants) where $\lambda$ is wave length of wave

269146 According to Bernoulli's theorem$\frac{p}{d}+\frac{v^2}{2}+gh=$ constant. The dimensional formula of the constant is ( $P$ is pressure, $d$ is density, $h$ is height, $v$ is velocity and $g$ is acceleration due to gravity) (2005 M )

269185 The acceleration of an object varies with time as$a=A{T}^2+BT+C$ taking the unit of time as $1\sec$ and acceleration as ${\mathrm{ms}}^{-2}$ then the units of $A,B,C$ respectively are

269186 If$\eta =\frac{A}{B}\log (Bx+C)$ is dimensionally true, then (here $\eta$ is the coefficient of viscosity and $x$ is the distance)

269187 If the velocity$(v)$ of a body in time ' $t$ ' is given by $V=A{T}^3+B{T}^2+CT+D$ then the dimensions of $C$ are

269145 $\mu =A+\frac{B}{\lambda }+\frac{C}{{\lambda }^2}$ is dimensionally correct. The dimensions of $\mathbf{A},\mathbf{B}$ and $\mathbf{C}$ respectively are $(\mu$, A, B, C are constants) where $\lambda$ is wave length of wave

269146 According to Bernoulli's theorem$\frac{p}{d}+\frac{v^2}{2}+gh=$ constant. The dimensional formula of the constant is ( $P$ is pressure, $d$ is density, $h$ is height, $v$ is velocity and $g$ is acceleration due to gravity) (2005 M )

269185 The acceleration of an object varies with time as$a=A{T}^2+BT+C$ taking the unit of time as $1\sec$ and acceleration as ${\mathrm{ms}}^{-2}$ then the units of $A,B,C$ respectively are

269186 If$\eta =\frac{A}{B}\log (Bx+C)$ is dimensionally true, then (here $\eta$ is the coefficient of viscosity and $x$ is the distance)

269187 If the velocity$(v)$ of a body in time ' $t$ ' is given by $V=A{T}^3+B{T}^2+CT+D$ then the dimensions of $C$ are

269145 $\mu =A+\frac{B}{\lambda }+\frac{C}{{\lambda }^2}$ is dimensionally correct. The dimensions of $\mathbf{A},\mathbf{B}$ and $\mathbf{C}$ respectively are $(\mu$, A, B, C are constants) where $\lambda$ is wave length of wave

269146 According to Bernoulli's theorem$\frac{p}{d}+\frac{v^2}{2}+gh=$ constant. The dimensional formula of the constant is ( $P$ is pressure, $d$ is density, $h$ is height, $v$ is velocity and $g$ is acceleration due to gravity) (2005 M )

269185 The acceleration of an object varies with time as$a=A{T}^2+BT+C$ taking the unit of time as $1\sec$ and acceleration as ${\mathrm{ms}}^{-2}$ then the units of $A,B,C$ respectively are

269186 If$\eta =\frac{A}{B}\log (Bx+C)$ is dimensionally true, then (here $\eta$ is the coefficient of viscosity and $x$ is the distance)

269187 If the velocity$(v)$ of a body in time ' $t$ ' is given by $V=A{T}^3+B{T}^2+CT+D$ then the dimensions of $C$ are