Units and Measurements
269162
If\(L=2.06 \mathrm{~cm} \pm 0.02 \mathrm{~cm}\), \(B=1.11 \mathrm{~cm} \pm 0.03 \mathrm{~cm}\), then \(\mathbf{L}+\boldsymbol{B}\) equals to
1 \(3.17 \mathrm{~cm} \pm 0.05 \mathrm{~cm}\),
2 \(2.06 \mathrm{~cm} \pm 0.05 \mathrm{~cm}\)
3 \(3.17 \mathrm{~cm} \pm 0.02 \mathrm{~cm}\),
4 \(3.17 \mathrm{~cm} \pm 0.03 \mathrm{~cm}\),
Explanation:
\(L \in x=L+B=3.17 ; \Delta x=\Delta L+\Delta B=0.05\)
\(\therefore x \pm \Delta x=3.17 \pm 0.05\)