UNITS & MEASUREMENTS
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Units and Measurements

269026 The mathematical operation in which the accuracy is limited to least accurate term is

1 addition
2 subtraction
3 multiplication\& division
4 both 1 and 2
Units and Measurements

269027 The time period of a seconds pendulum is measured repeatedly forthreetimes by two stop watches \(A, B\). If the readings are asfollows, then
\begin{tabular}{lll}
S.NO & A & B \\
(1)& \(2.01 \mathrm{sec}\) & \(2.56 \mathrm{sec}\) \\
(2)& 2.10 & \(2.55 \mathrm{sec}\) \\
(3)& \(1.98 \mathrm{sec}\) & \(2.57 \mathrm{sec}\)
\end{tabular}

1 \(A\) ismoreaccurate but \(B\) ismore precise
2 \(B\) ismoreaccuratebut \(A\) is more precise
3 \(A, B\) are equally precise
4 A,B areequally accurate
Units and Measurements

269028 If \(Y=a+b\), the maximum percentage error in the measurement of \(Y\) will be

1 \(\left(\frac{\Delta a}{a}+\frac{\Delta b}{b}\right) \times 100\)
2 \(\left(\frac{\Delta a}{a+b}+\frac{\Delta b}{a+b}\right) \times 100\)
3 \(\left(\frac{\Delta a}{a}-\frac{\Delta b}{b}\right) \times 100\)
4 \(\left(\frac{\Delta a}{a-b}-\frac{\Delta b}{a-b}\right) \times 100\)
Units and Measurements

269029 If \(Y=a-b\),themaximum percentage error in the measurement of \(Y\) will be

1 \(\left(\frac{\Delta a}{a}+\frac{\Delta b}{b}\right) \times 100\)
2 \(\left(\frac{\Delta a}{a-b}+\frac{\Delta b}{a-b}\right) \times 100\)
3 \(\left(\frac{\Delta a}{a}-\frac{\Delta b}{b}\right) \times 100\)
4 \(\left(\frac{\Delta a}{a-b}-\frac{\Delta b}{a-b}\right) \times 100\)
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Units and Measurements

269026 The mathematical operation in which the accuracy is limited to least accurate term is

1 addition
2 subtraction
3 multiplication\& division
4 both 1 and 2
Units and Measurements

269027 The time period of a seconds pendulum is measured repeatedly forthreetimes by two stop watches \(A, B\). If the readings are asfollows, then
\begin{tabular}{lll}
S.NO & A & B \\
(1)& \(2.01 \mathrm{sec}\) & \(2.56 \mathrm{sec}\) \\
(2)& 2.10 & \(2.55 \mathrm{sec}\) \\
(3)& \(1.98 \mathrm{sec}\) & \(2.57 \mathrm{sec}\)
\end{tabular}

1 \(A\) ismoreaccurate but \(B\) ismore precise
2 \(B\) ismoreaccuratebut \(A\) is more precise
3 \(A, B\) are equally precise
4 A,B areequally accurate
Units and Measurements

269028 If \(Y=a+b\), the maximum percentage error in the measurement of \(Y\) will be

1 \(\left(\frac{\Delta a}{a}+\frac{\Delta b}{b}\right) \times 100\)
2 \(\left(\frac{\Delta a}{a+b}+\frac{\Delta b}{a+b}\right) \times 100\)
3 \(\left(\frac{\Delta a}{a}-\frac{\Delta b}{b}\right) \times 100\)
4 \(\left(\frac{\Delta a}{a-b}-\frac{\Delta b}{a-b}\right) \times 100\)
Units and Measurements

269029 If \(Y=a-b\),themaximum percentage error in the measurement of \(Y\) will be

1 \(\left(\frac{\Delta a}{a}+\frac{\Delta b}{b}\right) \times 100\)
2 \(\left(\frac{\Delta a}{a-b}+\frac{\Delta b}{a-b}\right) \times 100\)
3 \(\left(\frac{\Delta a}{a}-\frac{\Delta b}{b}\right) \times 100\)
4 \(\left(\frac{\Delta a}{a-b}-\frac{\Delta b}{a-b}\right) \times 100\)
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Units and Measurements

269026 The mathematical operation in which the accuracy is limited to least accurate term is

1 addition
2 subtraction
3 multiplication\& division
4 both 1 and 2
Units and Measurements

269027 The time period of a seconds pendulum is measured repeatedly forthreetimes by two stop watches \(A, B\). If the readings are asfollows, then
\begin{tabular}{lll}
S.NO & A & B \\
(1)& \(2.01 \mathrm{sec}\) & \(2.56 \mathrm{sec}\) \\
(2)& 2.10 & \(2.55 \mathrm{sec}\) \\
(3)& \(1.98 \mathrm{sec}\) & \(2.57 \mathrm{sec}\)
\end{tabular}

1 \(A\) ismoreaccurate but \(B\) ismore precise
2 \(B\) ismoreaccuratebut \(A\) is more precise
3 \(A, B\) are equally precise
4 A,B areequally accurate
Units and Measurements

269028 If \(Y=a+b\), the maximum percentage error in the measurement of \(Y\) will be

1 \(\left(\frac{\Delta a}{a}+\frac{\Delta b}{b}\right) \times 100\)
2 \(\left(\frac{\Delta a}{a+b}+\frac{\Delta b}{a+b}\right) \times 100\)
3 \(\left(\frac{\Delta a}{a}-\frac{\Delta b}{b}\right) \times 100\)
4 \(\left(\frac{\Delta a}{a-b}-\frac{\Delta b}{a-b}\right) \times 100\)
Units and Measurements

269029 If \(Y=a-b\),themaximum percentage error in the measurement of \(Y\) will be

1 \(\left(\frac{\Delta a}{a}+\frac{\Delta b}{b}\right) \times 100\)
2 \(\left(\frac{\Delta a}{a-b}+\frac{\Delta b}{a-b}\right) \times 100\)
3 \(\left(\frac{\Delta a}{a}-\frac{\Delta b}{b}\right) \times 100\)
4 \(\left(\frac{\Delta a}{a-b}-\frac{\Delta b}{a-b}\right) \times 100\)
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Units and Measurements

269026 The mathematical operation in which the accuracy is limited to least accurate term is

1 addition
2 subtraction
3 multiplication\& division
4 both 1 and 2
Units and Measurements

269027 The time period of a seconds pendulum is measured repeatedly forthreetimes by two stop watches \(A, B\). If the readings are asfollows, then
\begin{tabular}{lll}
S.NO & A & B \\
(1)& \(2.01 \mathrm{sec}\) & \(2.56 \mathrm{sec}\) \\
(2)& 2.10 & \(2.55 \mathrm{sec}\) \\
(3)& \(1.98 \mathrm{sec}\) & \(2.57 \mathrm{sec}\)
\end{tabular}

1 \(A\) ismoreaccurate but \(B\) ismore precise
2 \(B\) ismoreaccuratebut \(A\) is more precise
3 \(A, B\) are equally precise
4 A,B areequally accurate
Units and Measurements

269028 If \(Y=a+b\), the maximum percentage error in the measurement of \(Y\) will be

1 \(\left(\frac{\Delta a}{a}+\frac{\Delta b}{b}\right) \times 100\)
2 \(\left(\frac{\Delta a}{a+b}+\frac{\Delta b}{a+b}\right) \times 100\)
3 \(\left(\frac{\Delta a}{a}-\frac{\Delta b}{b}\right) \times 100\)
4 \(\left(\frac{\Delta a}{a-b}-\frac{\Delta b}{a-b}\right) \times 100\)
Units and Measurements

269029 If \(Y=a-b\),themaximum percentage error in the measurement of \(Y\) will be

1 \(\left(\frac{\Delta a}{a}+\frac{\Delta b}{b}\right) \times 100\)
2 \(\left(\frac{\Delta a}{a-b}+\frac{\Delta b}{a-b}\right) \times 100\)
3 \(\left(\frac{\Delta a}{a}-\frac{\Delta b}{b}\right) \times 100\)
4 \(\left(\frac{\Delta a}{a-b}-\frac{\Delta b}{a-b}\right) \times 100\)
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