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Work, Energy and Power

268690 A rubber ball drops from a height ' $h$ '. After rebounding twice from the ground, it rises to $h / 2$ . The co - efficient of restitution is

1

\frac{1}{2}

2

◻ \frac{1}{2} m^{1 / 2}

3

\exists \frac{1}{2} ◻^{1 / 4}

4

◻ \frac{1}{2} H^{1 / 6}

Explanation:

$h_{n} = e^{2 n} h$

Work, Energy and Power

268691 A body dropped freely from a height $h$ o n $t o$ a horizontal plane, bounces up and down and finally comes to rest. The coefficient of restitution is $e$ . The ratio of velocities at the beginning and after two rebounds is

1

1 : e

2 e : 1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$v_{n} = e^{n} v$

Work, Energy and Power

268692 In the above problem, the ratio of times of two consecutive rebounds is

1

1 : e

2 e : 1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$t_{n} = e^{n} t$

Work, Energy and Power

268693 In the above problem the ratio of distances travelled in two consecutive rebounds is

1

1 : e

2 e:1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$h_{n} = e^{2 n_{h}}$

Work, Energy and Power

268694 A ball is dropped onto a horizontal floor. It reaches a height of $144 cm$ on the first bounce and $81 cm$ on the second bounce. The coefficient of restitution is

1 0

2 0.75

3 81/144

4 1

Explanation:

$e = \sqrt{\frac{h_{2}}{h_{1}}}$

Work, Energy and Power

268690 A rubber ball drops from a height ' $h$ '. After rebounding twice from the ground, it rises to $h / 2$ . The co - efficient of restitution is

1

\frac{1}{2}

2

◻ \frac{1}{2} m^{1 / 2}

3

\exists \frac{1}{2} ◻^{1 / 4}

4

◻ \frac{1}{2} H^{1 / 6}

Explanation:

$h_{n} = e^{2 n} h$

Work, Energy and Power

268691 A body dropped freely from a height $h$ o n $t o$ a horizontal plane, bounces up and down and finally comes to rest. The coefficient of restitution is $e$ . The ratio of velocities at the beginning and after two rebounds is

1

1 : e

2 e : 1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$v_{n} = e^{n} v$

Work, Energy and Power

268692 In the above problem, the ratio of times of two consecutive rebounds is

1

1 : e

2 e : 1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$t_{n} = e^{n} t$

Work, Energy and Power

268693 In the above problem the ratio of distances travelled in two consecutive rebounds is

1

1 : e

2 e:1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$h_{n} = e^{2 n_{h}}$

Work, Energy and Power

268694 A ball is dropped onto a horizontal floor. It reaches a height of $144 cm$ on the first bounce and $81 cm$ on the second bounce. The coefficient of restitution is

1 0

2 0.75

3 81/144

4 1

Explanation:

$e = \sqrt{\frac{h_{2}}{h_{1}}}$

Work, Energy and Power

268690 A rubber ball drops from a height ' $h$ '. After rebounding twice from the ground, it rises to $h / 2$ . The co - efficient of restitution is

1

\frac{1}{2}

2

◻ \frac{1}{2} m^{1 / 2}

3

\exists \frac{1}{2} ◻^{1 / 4}

4

◻ \frac{1}{2} H^{1 / 6}

Explanation:

$h_{n} = e^{2 n} h$

Work, Energy and Power

268691 A body dropped freely from a height $h$ o n $t o$ a horizontal plane, bounces up and down and finally comes to rest. The coefficient of restitution is $e$ . The ratio of velocities at the beginning and after two rebounds is

1

1 : e

2 e : 1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$v_{n} = e^{n} v$

Work, Energy and Power

268692 In the above problem, the ratio of times of two consecutive rebounds is

1

1 : e

2 e : 1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$t_{n} = e^{n} t$

Work, Energy and Power

268693 In the above problem the ratio of distances travelled in two consecutive rebounds is

1

1 : e

2 e:1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$h_{n} = e^{2 n_{h}}$

Work, Energy and Power

268694 A ball is dropped onto a horizontal floor. It reaches a height of $144 cm$ on the first bounce and $81 cm$ on the second bounce. The coefficient of restitution is

1 0

2 0.75

3 81/144

4 1

Explanation:

$e = \sqrt{\frac{h_{2}}{h_{1}}}$

Work, Energy and Power

268690 A rubber ball drops from a height ' $h$ '. After rebounding twice from the ground, it rises to $h / 2$ . The co - efficient of restitution is

1

\frac{1}{2}

2

◻ \frac{1}{2} m^{1 / 2}

3

\exists \frac{1}{2} ◻^{1 / 4}

4

◻ \frac{1}{2} H^{1 / 6}

Explanation:

$h_{n} = e^{2 n} h$

Work, Energy and Power

268691 A body dropped freely from a height $h$ o n $t o$ a horizontal plane, bounces up and down and finally comes to rest. The coefficient of restitution is $e$ . The ratio of velocities at the beginning and after two rebounds is

1

1 : e

2 e : 1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$v_{n} = e^{n} v$

Work, Energy and Power

268692 In the above problem, the ratio of times of two consecutive rebounds is

1

1 : e

2 e : 1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$t_{n} = e^{n} t$

Work, Energy and Power

268693 In the above problem the ratio of distances travelled in two consecutive rebounds is

1

1 : e

2 e:1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$h_{n} = e^{2 n_{h}}$

Work, Energy and Power

268694 A ball is dropped onto a horizontal floor. It reaches a height of $144 cm$ on the first bounce and $81 cm$ on the second bounce. The coefficient of restitution is

1 0

2 0.75

3 81/144

4 1

Explanation:

$e = \sqrt{\frac{h_{2}}{h_{1}}}$

Work, Energy and Power

268690 A rubber ball drops from a height ' $h$ '. After rebounding twice from the ground, it rises to $h / 2$ . The co - efficient of restitution is

1

\frac{1}{2}

2

◻ \frac{1}{2} m^{1 / 2}

3

\exists \frac{1}{2} ◻^{1 / 4}

4

◻ \frac{1}{2} H^{1 / 6}

Explanation:

$h_{n} = e^{2 n} h$

Work, Energy and Power

268691 A body dropped freely from a height $h$ o n $t o$ a horizontal plane, bounces up and down and finally comes to rest. The coefficient of restitution is $e$ . The ratio of velocities at the beginning and after two rebounds is

1

1 : e

2 e : 1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$v_{n} = e^{n} v$

Work, Energy and Power

268692 In the above problem, the ratio of times of two consecutive rebounds is

1

1 : e

2 e : 1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$t_{n} = e^{n} t$

Work, Energy and Power

268693 In the above problem the ratio of distances travelled in two consecutive rebounds is

1

1 : e

2 e:1

3

1 : e^{2}

4

e^{2} : 1

Explanation:

$h_{n} = e^{2 n_{h}}$

Work, Energy and Power

268694 A ball is dropped onto a horizontal floor. It reaches a height of $144 cm$ on the first bounce and $81 cm$ on the second bounce. The coefficient of restitution is

1 0

2 0.75

3 81/144

4 1

Explanation:

$e = \sqrt{\frac{h_{2}}{h_{1}}}$

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