268643
A lawn roller is pulled along a horizontal surface through a distance of \(20 \mathrm{~m}\) by a rope with a force of \(200 \mathrm{~N}\). If the rope makes an angle of \(60^{\circ}\) with the vertical while pulling, the amount of work done by pulling force is
1 \(4000 \mathrm{~J}\)
2 \(1000 \mathrm{~J}\)
3 \(2000 \sqrt{3}\)
4 \(2000 \mathrm{~J}\)
Explanation:
\(\quad W=\vec{F} \cdot \vec{S}=F S \cos \theta\)
Work, Energy and Power
268698
If a force \(\vec{F}=(\vec{i}+2 \vec{j}+\vec{k}) \mathbf{N}\) acts on a body produces a displacement of \(\vec{S}=(4 \vec{i}+\vec{j}+7 \vec{k}) \mathbf{m}\), then the work done is
1 \(9 \mathrm{~J}\)
2 \(13 \mathrm{~J}\)
3 \(5 \mathrm{~J}\)
4 \(1 \mathrm{~J}\)
Explanation:
\(\quad W=\vec{F} \cdot \vec{S}\)
Work, Energy and Power
268699
Work done by the gravitational force on a body of mass " \(m\) " moving on a smooth horizontal surface through a distance ' \(s\) ' is
1 \(\mathrm{mgs}\)
2 -mgs
3 0
4 \(2 \mathrm{mgs}\)
Explanation:
\(\cdot W=\vec{F} \cdot \vec{S}=F S \cos \theta\) and \(\theta=90^{\circ}\)
Work, Energy and Power
268700
A body of mass \(1 \mathrm{~kg}\) is made to travel with a uniform acceleration of \(30 \mathrm{~cm} / \mathrm{s}^{2}\) over a distance of \(2 \mathrm{~m}\), then work to be done is
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Work, Energy and Power
268643
A lawn roller is pulled along a horizontal surface through a distance of \(20 \mathrm{~m}\) by a rope with a force of \(200 \mathrm{~N}\). If the rope makes an angle of \(60^{\circ}\) with the vertical while pulling, the amount of work done by pulling force is
1 \(4000 \mathrm{~J}\)
2 \(1000 \mathrm{~J}\)
3 \(2000 \sqrt{3}\)
4 \(2000 \mathrm{~J}\)
Explanation:
\(\quad W=\vec{F} \cdot \vec{S}=F S \cos \theta\)
Work, Energy and Power
268698
If a force \(\vec{F}=(\vec{i}+2 \vec{j}+\vec{k}) \mathbf{N}\) acts on a body produces a displacement of \(\vec{S}=(4 \vec{i}+\vec{j}+7 \vec{k}) \mathbf{m}\), then the work done is
1 \(9 \mathrm{~J}\)
2 \(13 \mathrm{~J}\)
3 \(5 \mathrm{~J}\)
4 \(1 \mathrm{~J}\)
Explanation:
\(\quad W=\vec{F} \cdot \vec{S}\)
Work, Energy and Power
268699
Work done by the gravitational force on a body of mass " \(m\) " moving on a smooth horizontal surface through a distance ' \(s\) ' is
1 \(\mathrm{mgs}\)
2 -mgs
3 0
4 \(2 \mathrm{mgs}\)
Explanation:
\(\cdot W=\vec{F} \cdot \vec{S}=F S \cos \theta\) and \(\theta=90^{\circ}\)
Work, Energy and Power
268700
A body of mass \(1 \mathrm{~kg}\) is made to travel with a uniform acceleration of \(30 \mathrm{~cm} / \mathrm{s}^{2}\) over a distance of \(2 \mathrm{~m}\), then work to be done is
268643
A lawn roller is pulled along a horizontal surface through a distance of \(20 \mathrm{~m}\) by a rope with a force of \(200 \mathrm{~N}\). If the rope makes an angle of \(60^{\circ}\) with the vertical while pulling, the amount of work done by pulling force is
1 \(4000 \mathrm{~J}\)
2 \(1000 \mathrm{~J}\)
3 \(2000 \sqrt{3}\)
4 \(2000 \mathrm{~J}\)
Explanation:
\(\quad W=\vec{F} \cdot \vec{S}=F S \cos \theta\)
Work, Energy and Power
268698
If a force \(\vec{F}=(\vec{i}+2 \vec{j}+\vec{k}) \mathbf{N}\) acts on a body produces a displacement of \(\vec{S}=(4 \vec{i}+\vec{j}+7 \vec{k}) \mathbf{m}\), then the work done is
1 \(9 \mathrm{~J}\)
2 \(13 \mathrm{~J}\)
3 \(5 \mathrm{~J}\)
4 \(1 \mathrm{~J}\)
Explanation:
\(\quad W=\vec{F} \cdot \vec{S}\)
Work, Energy and Power
268699
Work done by the gravitational force on a body of mass " \(m\) " moving on a smooth horizontal surface through a distance ' \(s\) ' is
1 \(\mathrm{mgs}\)
2 -mgs
3 0
4 \(2 \mathrm{mgs}\)
Explanation:
\(\cdot W=\vec{F} \cdot \vec{S}=F S \cos \theta\) and \(\theta=90^{\circ}\)
Work, Energy and Power
268700
A body of mass \(1 \mathrm{~kg}\) is made to travel with a uniform acceleration of \(30 \mathrm{~cm} / \mathrm{s}^{2}\) over a distance of \(2 \mathrm{~m}\), then work to be done is
268643
A lawn roller is pulled along a horizontal surface through a distance of \(20 \mathrm{~m}\) by a rope with a force of \(200 \mathrm{~N}\). If the rope makes an angle of \(60^{\circ}\) with the vertical while pulling, the amount of work done by pulling force is
1 \(4000 \mathrm{~J}\)
2 \(1000 \mathrm{~J}\)
3 \(2000 \sqrt{3}\)
4 \(2000 \mathrm{~J}\)
Explanation:
\(\quad W=\vec{F} \cdot \vec{S}=F S \cos \theta\)
Work, Energy and Power
268698
If a force \(\vec{F}=(\vec{i}+2 \vec{j}+\vec{k}) \mathbf{N}\) acts on a body produces a displacement of \(\vec{S}=(4 \vec{i}+\vec{j}+7 \vec{k}) \mathbf{m}\), then the work done is
1 \(9 \mathrm{~J}\)
2 \(13 \mathrm{~J}\)
3 \(5 \mathrm{~J}\)
4 \(1 \mathrm{~J}\)
Explanation:
\(\quad W=\vec{F} \cdot \vec{S}\)
Work, Energy and Power
268699
Work done by the gravitational force on a body of mass " \(m\) " moving on a smooth horizontal surface through a distance ' \(s\) ' is
1 \(\mathrm{mgs}\)
2 -mgs
3 0
4 \(2 \mathrm{mgs}\)
Explanation:
\(\cdot W=\vec{F} \cdot \vec{S}=F S \cos \theta\) and \(\theta=90^{\circ}\)
Work, Energy and Power
268700
A body of mass \(1 \mathrm{~kg}\) is made to travel with a uniform acceleration of \(30 \mathrm{~cm} / \mathrm{s}^{2}\) over a distance of \(2 \mathrm{~m}\), then work to be done is