NEET Test Series from KOTA - 10 Papers In MS WORD
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Work, Energy and Power
268715
An inelastic ball falls from a height of 100 meters. It loses \(\mathbf{2 0 \%}\) of its total energy due to impact. The ball will now rise to a height of
1 \(80 \mathrm{~m}\)
2 \(120 \mathrm{~m}\)
3 \(60 \mathrm{~m}\)
4 \(9.8 \mathrm{~m}\)
Explanation:
with \(80 \%\) of available energy it can rise to height \(h^{\prime}=0.8 h\)
Work, Energy and Power
268716
A woman weighing \(63 \mathrm{~kg}\) eats plum cake whose energy content is \(\mathbf{9 8 0 0}\) calories. If all this energy could be utilized by her, she can ascend a height of
1 \(1 \mathrm{~m}\)
2 \(67 \mathrm{~m}\)
3 \(100 \mathrm{~m}\)
4 \(42 m\)
Explanation:
\(W=J Q \Rightarrow m g h=J Q(1 \mathrm{cal}=4.2 \mathrm{~J})\)
Work, Energy and Power
268717
A spring of spring constant \(5 \times 10^{3} \mathrm{~N} / \mathrm{m}\) is stretched initially by \(5 \mathrm{~cm}\) from the unstretched position. Then the work required to stretch it further by another \(5 \mathrm{~cm}\) is.
268718
A spring with spring constant \(K\) when stretched through \(1 \mathrm{~cm}\), the potential energy is \(U\). If it is stretched by \(4 \mathrm{~cm}\), the potential energy will be
1 \(4 U\)
2 \(8 U\)
3 \(16 U\)
4 \(2 U\)
Explanation:
\(U=\frac{1}{2} K x^{2} \Rightarrow \frac{\mathrm{U}_{1}}{U_{2}}=\frac{x_{1}{ }^{2}}{x_{2}{ }^{2}}\)
268715
An inelastic ball falls from a height of 100 meters. It loses \(\mathbf{2 0 \%}\) of its total energy due to impact. The ball will now rise to a height of
1 \(80 \mathrm{~m}\)
2 \(120 \mathrm{~m}\)
3 \(60 \mathrm{~m}\)
4 \(9.8 \mathrm{~m}\)
Explanation:
with \(80 \%\) of available energy it can rise to height \(h^{\prime}=0.8 h\)
Work, Energy and Power
268716
A woman weighing \(63 \mathrm{~kg}\) eats plum cake whose energy content is \(\mathbf{9 8 0 0}\) calories. If all this energy could be utilized by her, she can ascend a height of
1 \(1 \mathrm{~m}\)
2 \(67 \mathrm{~m}\)
3 \(100 \mathrm{~m}\)
4 \(42 m\)
Explanation:
\(W=J Q \Rightarrow m g h=J Q(1 \mathrm{cal}=4.2 \mathrm{~J})\)
Work, Energy and Power
268717
A spring of spring constant \(5 \times 10^{3} \mathrm{~N} / \mathrm{m}\) is stretched initially by \(5 \mathrm{~cm}\) from the unstretched position. Then the work required to stretch it further by another \(5 \mathrm{~cm}\) is.
268718
A spring with spring constant \(K\) when stretched through \(1 \mathrm{~cm}\), the potential energy is \(U\). If it is stretched by \(4 \mathrm{~cm}\), the potential energy will be
1 \(4 U\)
2 \(8 U\)
3 \(16 U\)
4 \(2 U\)
Explanation:
\(U=\frac{1}{2} K x^{2} \Rightarrow \frac{\mathrm{U}_{1}}{U_{2}}=\frac{x_{1}{ }^{2}}{x_{2}{ }^{2}}\)
268715
An inelastic ball falls from a height of 100 meters. It loses \(\mathbf{2 0 \%}\) of its total energy due to impact. The ball will now rise to a height of
1 \(80 \mathrm{~m}\)
2 \(120 \mathrm{~m}\)
3 \(60 \mathrm{~m}\)
4 \(9.8 \mathrm{~m}\)
Explanation:
with \(80 \%\) of available energy it can rise to height \(h^{\prime}=0.8 h\)
Work, Energy and Power
268716
A woman weighing \(63 \mathrm{~kg}\) eats plum cake whose energy content is \(\mathbf{9 8 0 0}\) calories. If all this energy could be utilized by her, she can ascend a height of
1 \(1 \mathrm{~m}\)
2 \(67 \mathrm{~m}\)
3 \(100 \mathrm{~m}\)
4 \(42 m\)
Explanation:
\(W=J Q \Rightarrow m g h=J Q(1 \mathrm{cal}=4.2 \mathrm{~J})\)
Work, Energy and Power
268717
A spring of spring constant \(5 \times 10^{3} \mathrm{~N} / \mathrm{m}\) is stretched initially by \(5 \mathrm{~cm}\) from the unstretched position. Then the work required to stretch it further by another \(5 \mathrm{~cm}\) is.
268718
A spring with spring constant \(K\) when stretched through \(1 \mathrm{~cm}\), the potential energy is \(U\). If it is stretched by \(4 \mathrm{~cm}\), the potential energy will be
1 \(4 U\)
2 \(8 U\)
3 \(16 U\)
4 \(2 U\)
Explanation:
\(U=\frac{1}{2} K x^{2} \Rightarrow \frac{\mathrm{U}_{1}}{U_{2}}=\frac{x_{1}{ }^{2}}{x_{2}{ }^{2}}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Work, Energy and Power
268715
An inelastic ball falls from a height of 100 meters. It loses \(\mathbf{2 0 \%}\) of its total energy due to impact. The ball will now rise to a height of
1 \(80 \mathrm{~m}\)
2 \(120 \mathrm{~m}\)
3 \(60 \mathrm{~m}\)
4 \(9.8 \mathrm{~m}\)
Explanation:
with \(80 \%\) of available energy it can rise to height \(h^{\prime}=0.8 h\)
Work, Energy and Power
268716
A woman weighing \(63 \mathrm{~kg}\) eats plum cake whose energy content is \(\mathbf{9 8 0 0}\) calories. If all this energy could be utilized by her, she can ascend a height of
1 \(1 \mathrm{~m}\)
2 \(67 \mathrm{~m}\)
3 \(100 \mathrm{~m}\)
4 \(42 m\)
Explanation:
\(W=J Q \Rightarrow m g h=J Q(1 \mathrm{cal}=4.2 \mathrm{~J})\)
Work, Energy and Power
268717
A spring of spring constant \(5 \times 10^{3} \mathrm{~N} / \mathrm{m}\) is stretched initially by \(5 \mathrm{~cm}\) from the unstretched position. Then the work required to stretch it further by another \(5 \mathrm{~cm}\) is.
268718
A spring with spring constant \(K\) when stretched through \(1 \mathrm{~cm}\), the potential energy is \(U\). If it is stretched by \(4 \mathrm{~cm}\), the potential energy will be
1 \(4 U\)
2 \(8 U\)
3 \(16 U\)
4 \(2 U\)
Explanation:
\(U=\frac{1}{2} K x^{2} \Rightarrow \frac{\mathrm{U}_{1}}{U_{2}}=\frac{x_{1}{ }^{2}}{x_{2}{ }^{2}}\)