268328
12 cells of each emf \(2 \mathrm{~V}\) areconnected in series among them, if 3 cells are connected wrongly. Then the effective emf. of the combination is
1 \(18 \mathrm{~V}\)
2 \(12 \mathrm{~V}\)
3 \(24 \mathrm{~V}\)
4 \(6 \mathrm{~V}\)
Explanation:
\(E_{e q}=(N-2 m) E\)
Current Electricity
268329
When a battery connected across a resistor of \(16 \Omega\), the voltage across the resistor is 12V.W hen the same battery is connected across a resistor of \(10 \Omega\), voltage across it is \(11 \mathrm{~V}\). The internal resistance of the battery in ohms is
1 \(10 / 7\)
2 \(20 / 7\)
3 \(25 / 7\)
4 \(30 / 7\)
Explanation:
\(r=\left(\frac{E-V_{1}}{V_{1}}\right) R_{1}=\left(\frac{E-V_{2}}{V_{2}}\right) R_{2}\). Solve for \(E\) and substitutefor \(r\)
Current Electricity
268388
A cell of emf \(6 \mathrm{~V}\) is being charged by \(1 \mathrm{~A}\) current. If the internal resistance of the cell is 1 ohm, the potential difference across the terminals of the cell is
1 \(5 \mathrm{~V}\)
2 \(7 \mathrm{~N}\)
3 \(6 \mathrm{~V}\)
4 \(8 \mathrm{~V}\)
Explanation:
\(V=E+i r\)
Current Electricity
268389
When two identical cells are connected either in series or in parallel across 2 ohm resistor they send the same current through it. The internal resistance of each cell is
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Current Electricity
268328
12 cells of each emf \(2 \mathrm{~V}\) areconnected in series among them, if 3 cells are connected wrongly. Then the effective emf. of the combination is
1 \(18 \mathrm{~V}\)
2 \(12 \mathrm{~V}\)
3 \(24 \mathrm{~V}\)
4 \(6 \mathrm{~V}\)
Explanation:
\(E_{e q}=(N-2 m) E\)
Current Electricity
268329
When a battery connected across a resistor of \(16 \Omega\), the voltage across the resistor is 12V.W hen the same battery is connected across a resistor of \(10 \Omega\), voltage across it is \(11 \mathrm{~V}\). The internal resistance of the battery in ohms is
1 \(10 / 7\)
2 \(20 / 7\)
3 \(25 / 7\)
4 \(30 / 7\)
Explanation:
\(r=\left(\frac{E-V_{1}}{V_{1}}\right) R_{1}=\left(\frac{E-V_{2}}{V_{2}}\right) R_{2}\). Solve for \(E\) and substitutefor \(r\)
Current Electricity
268388
A cell of emf \(6 \mathrm{~V}\) is being charged by \(1 \mathrm{~A}\) current. If the internal resistance of the cell is 1 ohm, the potential difference across the terminals of the cell is
1 \(5 \mathrm{~V}\)
2 \(7 \mathrm{~N}\)
3 \(6 \mathrm{~V}\)
4 \(8 \mathrm{~V}\)
Explanation:
\(V=E+i r\)
Current Electricity
268389
When two identical cells are connected either in series or in parallel across 2 ohm resistor they send the same current through it. The internal resistance of each cell is
268328
12 cells of each emf \(2 \mathrm{~V}\) areconnected in series among them, if 3 cells are connected wrongly. Then the effective emf. of the combination is
1 \(18 \mathrm{~V}\)
2 \(12 \mathrm{~V}\)
3 \(24 \mathrm{~V}\)
4 \(6 \mathrm{~V}\)
Explanation:
\(E_{e q}=(N-2 m) E\)
Current Electricity
268329
When a battery connected across a resistor of \(16 \Omega\), the voltage across the resistor is 12V.W hen the same battery is connected across a resistor of \(10 \Omega\), voltage across it is \(11 \mathrm{~V}\). The internal resistance of the battery in ohms is
1 \(10 / 7\)
2 \(20 / 7\)
3 \(25 / 7\)
4 \(30 / 7\)
Explanation:
\(r=\left(\frac{E-V_{1}}{V_{1}}\right) R_{1}=\left(\frac{E-V_{2}}{V_{2}}\right) R_{2}\). Solve for \(E\) and substitutefor \(r\)
Current Electricity
268388
A cell of emf \(6 \mathrm{~V}\) is being charged by \(1 \mathrm{~A}\) current. If the internal resistance of the cell is 1 ohm, the potential difference across the terminals of the cell is
1 \(5 \mathrm{~V}\)
2 \(7 \mathrm{~N}\)
3 \(6 \mathrm{~V}\)
4 \(8 \mathrm{~V}\)
Explanation:
\(V=E+i r\)
Current Electricity
268389
When two identical cells are connected either in series or in parallel across 2 ohm resistor they send the same current through it. The internal resistance of each cell is
268328
12 cells of each emf \(2 \mathrm{~V}\) areconnected in series among them, if 3 cells are connected wrongly. Then the effective emf. of the combination is
1 \(18 \mathrm{~V}\)
2 \(12 \mathrm{~V}\)
3 \(24 \mathrm{~V}\)
4 \(6 \mathrm{~V}\)
Explanation:
\(E_{e q}=(N-2 m) E\)
Current Electricity
268329
When a battery connected across a resistor of \(16 \Omega\), the voltage across the resistor is 12V.W hen the same battery is connected across a resistor of \(10 \Omega\), voltage across it is \(11 \mathrm{~V}\). The internal resistance of the battery in ohms is
1 \(10 / 7\)
2 \(20 / 7\)
3 \(25 / 7\)
4 \(30 / 7\)
Explanation:
\(r=\left(\frac{E-V_{1}}{V_{1}}\right) R_{1}=\left(\frac{E-V_{2}}{V_{2}}\right) R_{2}\). Solve for \(E\) and substitutefor \(r\)
Current Electricity
268388
A cell of emf \(6 \mathrm{~V}\) is being charged by \(1 \mathrm{~A}\) current. If the internal resistance of the cell is 1 ohm, the potential difference across the terminals of the cell is
1 \(5 \mathrm{~V}\)
2 \(7 \mathrm{~N}\)
3 \(6 \mathrm{~V}\)
4 \(8 \mathrm{~V}\)
Explanation:
\(V=E+i r\)
Current Electricity
268389
When two identical cells are connected either in series or in parallel across 2 ohm resistor they send the same current through it. The internal resistance of each cell is